I've made some bespoke pages in my admin of my site and they as the first segment of the URL.
e.g
/property-hartlepool
I thought of adding a trap all route into my routes file :
Route::get('{any?}', 'PagesController#view');
The problem I have is it's totally overwriting my other routes, I guess that's the name of a trap all route. However I'd like it to skip if it can't find a match.
I had a route for admin
/admin
But now it throws a 404 Error...
My PagesController#view method is :
public function view(Request $request)
{
$route = $request->segment(1); // $request->path();
// get page content
$page = Page::where('route', $route)->firstOrFail();
// If not full width, get four latest properties
//$properties = Property::latest_properties_for_frontend();
//metadata
$meta = get_metadata($page);
//page is Temporary
return view('frontend.'.themeOptions().'.page', [
'route' => $route,
'meta' => $meta,
'page' => $page
]);
}
Is their a better way of doing this, I do have other routes that sit at "top" level too. e.g...
Route::get('/property/{property}/{propertyId}', 'PropertiesController#property');
declare your trap Route as the last route.
Route::get('/admin', 'AdminController#view');
...
...
Route::get('{any?}', 'PagesController#view');
Related
I have route like
Route::get('admin/selfcontacteditdata','SelfcontectController#edit')->name('selfcontectedit');
Route::post('admin/selfcontactupdatedata','SelfcontectController#update')->name('selfcontectupdate');
If i just go to my browser and right admin/selfcontacteditdata it redirect me to
admin/newsshowdata
And my index function is
public function __construct()
{
return $this->middleware('auth');
}
public function index()
{
request()->validate([
'email' => 'required',
'mobileno' => 'required',
'facebook'=>'required',
'google'=>'required',
'map'=>'required',
]);
$data = selfcontect::find(1);
return view('/admin/selfcontectedit',compact('data'));
}
And my middleware is
protected function redirectTo($request)
{
if (! $request->expectsJson()) {
return route('login');
}
}
My rest admin routes are working fine.
I had the same problem but I was writing table name wrong and my file was not saved as .blade please check are you also doing the same thing and there is no meaning of validation in edit function your edit function must be like
public function edit()
{
$data = selfcontect::find(1);
return view('/admin/selfcontectedit',compact('data'));
}
and your function name should be edit
You should use Accept key not Content/type
You can't redirect through view, actually your are calling view.
Correct syntax is
return view('view_name',compact('data'));
If you want to redirect to any route you have to call like this
return redirect()->to('admin/selfcontacteditdata');
Redirect to a Route
If in your routes.php file you have a route with a name, you can redirect a user to this particular route, whatever its URL is:
app/Http/routes.php:
get('books', ['as' => 'books_list', 'uses' => 'BooksController#index']);
app/Http/Controllers/SomeController.php
return redirect()->route('books');
This is really useful if in the future you want to change the URL structure – all you would need to change is routes.php (for example, get(‘books’, … to get(‘books_list’, …), and all the redirects would refer to that route and therefore would change automatically.
And you can also use parameters for the routes, if you have any:
app/Http/routes.php:
get('book/{id}', ['as' => 'book_view', 'uses' => 'BooksController#show']);
app/Http/Controllers/SomeController.php
return redirect()->route('book_view', 1);
In case of more parameters – you can use an array:
app/Http/routes.php:
get('book/{category}/{id}', ['as' => 'book_view', 'uses' =>
'BooksController#show']);
app/Http/Controllers/SomeController.php
return redirect()->route('book_view', [513, 1]);
Or you can specify names of the parameters:
return redirect()->route('book_view', ['category'=>513, 'id'=>1]);
I am new in laravel framework now I'm working fully developed website using Laravel. I have changed blog url form {id} to {id}/{name} like www.example.com/news/203 to www.example.com/news/203/title. It's working fine. but i need to redirect if old url enter into current url opened from cache or something else.
Route::get('{id}/{name}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
You can define another route in which you will find the model by id and use its title to redirect the user to the new route:
Route::get('{id}', function ($id) {
$model = Model::findOrFail($id);
return redirect()->route('events-detail', ['id' => $id, 'name' => $model->name]);
});
Note that you have to change Model with the class you use for this route.
Create 2 routes and add below code.
Route::get('{id}/{name}', function () {
//new URL as you want
return redirect()->route({id}/{name});
});
Route::get('{id}', function () {
//as you want for simple URL
});
I'm assuming the name portion is not really used at all, except for SEO/friendlier urls. If this is the case, just make the name parameter optional, and there will be no need for a redirect:
Route::get('{id}/{name?}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
This route will match /203 and /203/news-title.
I am returning an API response inside a Categories controller in Laravel 5.5 like this...
public function get(Request $request) {
$categories = Category::all();
return Response::json(array(
'error' => false,
'categories_data' => $categories,
));
}
Now I am trying to also have the option to return a specific category, how can I do this as I am already using the get request in this controller?
Do I need to create a new route or can I modify this one to return a specific category only if an ID is supplied, if not then it returns all?
Better case is to create a new route, but you can also change the current one to retrieve all models if the parameter is not supplied. You first gotta choose which approach you will be using. For splitting it into multiple calls you can see Resource controllers and for using one method you can follow Optional Route Parameters
It will be much cleaner if you will create another route. For example
/categories --> That you have
/categories/{id} -> this you need to create
And then add method at same controller
public function show($id) {
$categories = Category::find($id);
return Response::json(array(
'error' => false,
'categories_data' => $categories,
));
}
But if you still want to do it at one route you can try something like this:
/categories -> will list all categories
/categories?id=2 -> will give you category of ID 2
Try this:
public function get(Request $request) {
$id = $request->get('id');
$categories = $id ? Category::find($id) : Category::all();
return Response::json(array(
'error' => false,
'categories_data' => $categories,
));
}
I have RESTful API built on Laravel.
Now I'm passing parameter like
http://www.compute.com/api/GetAPI/1/1
but I want to pass parameter like
http://www.compute.com/api/GetAPI?id=1&page_no=1
Is there a way to change Laravel routes/functions to support this?
you can use link_to_route() and link_to_action() methods too.
(source)
link_to_route take three parameters (name, title and parameters). you can use it like following:
link_to_route('api.GetAPI', 'get api', [
'page_no' => $page_no,
'id' => $id
]);
If you want to use an action, link_to_action() is very similar but it uses action name instead of route.
link_to_action('ApiController#getApi', 'get api', [
'page_no' => $page_no,
'id' => $id
]);
href text
with these methods anything after the expected number of parameters is exceeded, the remaining arguments will be added as a query string.
Or you can use traditional concatination like following:
create a route in routes.php
Route::get('api/GetAPI', [
'as' => 'get_api', 'uses' => 'ApiController#getApi'
]);
while using it append query string like this. you can use route method to get url for required method in controller. I prefer action method.
$url = action('ApiController#getApi'). '?id=1&page_no=1';
and in your controller access these variables by following methods.
public function getApi(Request $request) {
if($request->has('page_no')){
$page = $request->input('page_no');
}
// ...your stuff
}
Or by Input Class
public function getApi() {
if(Input::get('page_no')){
$page = Input::get('page_no');
}
// ...your stuff
}
Yes you can use those parameters, then in your controllers you can get their values using the Request object.
public function index(Request $request) {
if($request->has('page_no')){
$page = $request->input('page_no');
}
// ...
}
I have a multilingue website created using Laravel 4, and I have lot of pages such as : "policy, "terms", "how it works" in database, so to access thoses pages I use this route:
// Group by locale
Route::group(
array( 'prefix' => $locale ), function () {
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
// Website routes
});
And then I search for the given slug and the current locale.
My is problem is that I can't add for example a page link in the footer because the slug is dynamic. so is there any solution to resolve that.
It's make a sense ?
Thanks
You are already catching the slug in
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
part. all you need is to inject this slug into controller like this:
class PageController extends BaseController {
public function show($slug)
{
return 'showing slug ' . $slug;
}
}
and whatever value the route receive for {slug} part in route laravel will automatically inject that value into the controller.