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Bash if or statement, command not found
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Why do I get "command not found" with the NOT operator in a Bash conditional?
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Using jq to parse JSON in launchd
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In Jenkins while executing some code its throwing an error "jq command not found"
(1 answer)
Closed 3 years ago.
I am having problems streaming data into a unix pipe.
Here is my command:
curl http://stream.meetup.com/2/rsvps | jq '.event.event_name'
Here is the error I get:
zsh: command not found: jq
Can someone please help?
edit: jq is installed properly as shown by:
~ which jq
/usr/local/bin/jq
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I made a bash script for Ubuntu server with C-style if-then clause if (( $var = 6 )). It works perfectly from command line, but stuck when I made cronjob for this script. I changed it to if [ $var -gt 6 ] and then cron began to work. I assume that cron uses different shell, but what type and what other differences with bash?
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From my bash shell, I am able to run this following command successfully - scp <local-folder>/* <user>#<remote-host>:/var/tmp. All files in my <local-folder> are copied onto the remote location.
Now I am trying to run the above same command from my Go program, with exec.Command() but scp complains of "no such file / directory - <local-folder>/*' - the '*' is literally taken as a filename. I want to replicate the same behaviour of scp I get when I run it from my Bash shell. Here is the code snippet I am using:
pushCmd := exec.Command("scp", "<local-folder>/*", "<user>#<remote-host>:/var/tmp")
pushCmdOutput, err = pushCmd.CombinedOutput()
fmt.Fprintln(os.Stderr, string(pushCmdOutput))
Thanks in advance.
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Error With Bash Script [duplicate]
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Are shell scripts sensitive to encoding and line endings?
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Difference between sh and Bash
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I'm trying to run a script called autogen.sh on my Ubuntu system (WSL) which begins with
#!/bin/sh
set -xe
type autoreconf > /dev/null || exit 1
type pkg-config > /dev/null || exit 1
You can get the full script by running git clone https://github.com/universal-ctags/ctags.git
And it gives me
mark#surface-19:~/ctags$ ./autogen.sh
: not foundh: 2: ./autogen.sh:
./autogen.sh: 3: set: Illegal option -
I'm having a hard time understanding the error message "not foundh". It seems to be a typo of "not found" but what exactly is not being found?
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How to execute a bash command stored as a string with quotes and asterisk [duplicate]
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Why does shell ignore quoting characters in arguments passed to it through variables? [duplicate]
(3 answers)
Closed 4 years ago.
I'm trying to assemble an rsync command in a bash variable and then execute it.
It looks something like this:
CMD="$RSYNC -a $REMOTE $LOCAL $LINK_DEST"
It gets executed like this
RSYNC_RESULT=$($CMD)
This works fine until I try to add add --rsync-path="sudo /usr/local/bin/rsync" to the mix (so that rsync runs as root on the remote).
RSYNC_PATH='--rsync-path="sudo /usr/local/bin/rsync"'
CMD="$RSYNC -a $RSYNC_PATH $REMOTE $LOCAL $LINK_DEST"
Now I get an error
Unexpected remote arg: user#remote.local:/Users/user/files/
rsync error: syntax or usage error (code 1) at main.c(1343) [sender=3.1.2]
I'm fairly certain it's connected to the quoting in the $RSYNC_PATH var and/or the $($CMD) bit, because I can paste the resulting command into a shell and it runs successfully.
Any ideas what I can do to make this work?
This question already has answers here:
get values from 'time' command via bash script [duplicate]
(4 answers)
How to store a substring of the output of "time" function in bash script
(3 answers)
Closed 5 years ago.
I'm looking to capture the execution time of an rsync transfer and then store that time in a variable for a later step in my bash script.
I have tried the following:
ELAPSED=$(time $(rsync -azh source/ dest &> /dev/null)) to no avail. The elapsed time is printed to the screen, but it is not saved in the ELAPSED variable.
I have also tried: ELAPSED=$(/usr/bin/time sh -c "rsync -azh source/ dest &> /dev/null") but this actually takes the sh output and stores that output into the variable, not the time.
Any insights on a better method or corrections to my attempts are appreciated in advance!