How can one get the class a method was defined in?
I've found how to look up descendents and ansestors: Look up all descendants of a class in Ruby
But that doesn't necessarily get me the defining class (last defining class really).
I've found how to get the calling class:
Ruby Inheritance Get Caller Class Name
But I want the opposite. I would like how to get the defining class.
I've also tried Module.nesting. That gets me what I want in this case, but I worry it will be inconsistent and not acceptable in a larger codebase of which I don't have ultimate control.
puts RUBY_VERSION
# Test class vs super.
class Super
def test_func
puts "#{self.class}, #{ __method__}"
end
end
class Child < Super
def test_func2
self.test_func
end
end
Child.new.test_func
I had hoped for:
1.8.7
Super, test_func
But got:
1.8.7
Child, test_func
You asked self.class of Child object and you got it.
You need use Method#owner to return the class or module that defines the method.
class Super
def test_func
puts "#{method(__method__).owner}, #{ __method__}"
end
end
class Child < Super
def test_func2
self.test_func
end
end
Child.new.test_func
# will print: Super, test_func
or just
Child.new.method(:test_func).owner
#=> Super
Related
I want a piece of code to run before any other static methods run, is it possible to do something in the spirit of the following?
class MyClass
def self.initialize
#stuff = 1
end
def self.print_stuff
puts #stuff
end
end
My Ruby version of interest is 2.3.
Every chunk of code in Ruby is an expression. Even a class definition is a series of expressions: method definitions are expressions that have the side-effect of adding the method to the class.
This is how meta-programming methods work. attr_reader is a private method call where the implicit self is the class. So, long story short, you aren't restricted inside a class body, you can put whatever code you want to run in the context of the class:
class MyClass
#stuff = 1
def self.print_stuff
puts #stuff
end
end
There's no such thing as an explicit metaclass initializer. The class itself is "initialized" as it's defined, so it's perfectly valid to do this:
class MyClass
# Code here will be executed as the class itself is defined.
#stuff = 1
def self.print_stuff
puts #stuff
end
end
MyClass.print_stuff
Remember that def itself is a form of method call and defining a class in Ruby involves sending a bunch of messages (method calls) around to the proper context objects, such as the class itself as it's being defined.
My goal is:
class Bermuda
class << self
def grass
puts self.superclass.name
end
end
end
# my goal is that this expression
Bermuda.grass
# will output a string of the class name it resides in
=> "Bermuda"
I cannot display the name of the class that holds a singleton method. I have tried a number of different stabs and standard library searches but haven't found an answer.
This is partially pointless because you would not need a class method to display the information that you would need in the first place to call that method. I'm curious if it's possible or I'm completely missing the scope.
Just call name on self
class Bermuda
class << self
def grass
puts self.name
end
end
end
This sort of an implementation isn't recommended since all you have to do to get the class name is call Bermuda.name
Please see the answer given below by #MatthewCliatt for more info.
It's as simple as:
self.class.name
But, the catch is that this isn't for class methods, it's for instance methods.
That means you don't declare it with self. This was your code:
class Bermuda
class << self
def grass
puts self.superclass.name
end
end
end
And that will make the grass method a class method. You would have to call it like Bermuda.grass.
But, if you can call class methods like the one above, you could just as easily write: Bermuda.name.
I'm assuming you can't call class methods, probably because you're working with an instance. So you want to write this method as such:
class Bermuda
def grass
puts self.class.name
end
end
You say you're creating a singleton method, but I don't think your method is a singleton method in the usual sense (i.e. a method on an object that is an instance of a class, but not itself a class).
I believe the class << self notation you use merely results in a class method being defined, identical to:
def self.grass
puts name
end
In irb:
2.3.0 :003 > class Bermuda; def self.grass; puts name; end; end
=> :grass
2.3.0 :004 > Bermuda.grass
Bermuda
While creating a class, we use the keyword class like:
class Abc
Z = 5
def add
puts "anything here"
end
end
In console, Abc.class # => Class
How does Abc internally become a class? What is the difference between class and Class?
It would be great if anyone could explain how class constants and method are internally called, and if a method is not defined, then how we get the exception "undefined class method". What is the internal logic behind it?
There are three different things here:
class is a keyword, which is used to define or reopen a class
Object#class is a method, which returns the class of a given object
Class is the class which all classes are an instance of (including Class itself)
ndn's answer gives a nice overview of the different things "class" could refer to.
To answer your specific question:
How does Abc internally become a class?
Almost like any other object.
class Abc
end
is equivalent to:
Abc = Class.new do
end
It creates a new instance of Class and assigns it to the constant Abc.
To see what the different "class" things in Ruby mean, check out my other answer.
As for how methods are looked up:
There are multiple places a method can come from:
The class of the object
The parent of the class of the object
Modules, which are included/prepended
The singleton class of the object
The order of lookup is the following:
If it exists, the singleton class
Prepended modules
Methods defined in the class
Included modules
Recursively, the above rules for the parent class
There are a few things that have to be noted here:
If multiple modules are included/prepended, they will be looked up in the reverse order of how they were included/prepended
If a module was already included/prepended in one of the parrents, it won't be included/prepended again
If using these rules the method was not found til the very start of the hierarchy (BasicObject), the ancestor chain is searched again for a different method, called method_missing
BasicObject#method_missing is defined so that it throws a NoMethodError and that is where the error comes from
module M1
def foo
puts 'Defined in M1'
end
end
module M2
def foo
puts 'Defined in M2'
end
end
class C
include M1
prepend M2
def foo
puts 'Defined in C'
end
def method_missing(method_name)
puts 'Method missing' if method_name == :foo
end
end
c = C.new
# singleton method
def c.foo
puts "Defined in c's singleton"
end
puts c.singleton_class.ancestors
# => [#<Class:#<C:0xa2d0f8>>, M2, C, M1, Object, Kernel, BasicObject]
# ^ the singleton class,
# the prepended module,
# the C class itself,
# the included module,
# the rest of the hierarchy
# (Object is the implicit parent of all classes with no explicit parent)
with class Abc you define a class.
Abc.class is returning the Type, and the type of Abc is a Class
another example:
1337.class
=> Fixnum
"hi babe!".class
=> String
12.55.class
=> Float
(1..12).class
=> Range
so as you can see, each "datatype" is a class. in your case Abc is also a Datatype. And for the end of that chain, the class of a class is Class! :-)
Answering second par of the question, undefined class method happens when method you called is not present in such class - classes are just objects in Ruby, and as such they have their own set of methods. Ruby has several ways to define class methods, most common is probably
class Klass
def self.klass_method
...
end
end
the other is
class Klass
# some ordinary instance methods here
class << self
def klass_method
# this is class method
end
end
end
Some Rubyists prefer the latter, as it keeps all class methods in single block, but they are equivalent.
I have read this question at url In Ruby or Rails, why is "include" sometimes inside the class and sometimes outside the class?. As per the answer of this question i am expecting the method print2 of module Calculation should be accessible to the class Addition and ABc .but i am getting error as undefined methodprint2' for Addition:Class (NoMethodError)`
module Calculation
def print2
puts "print2"
end
end
require '/home/sanjay/Desktop/m'
extend Calculation;
class Addition
end
class Abc
end
Addition.print2
Abc.print2
Please explain why this error is comming??
Thanks
The receiver of extend should be each class, so you want Addition.extend Calculation and Abc.extend Calculation (after the class definitions). The semicolon is not required.
module D
def dog
puts "woof"
end
end
class A; end
A.extend D
A.dog #=> "woof"
class B; end
B.extend D
B.dog #=> "woof"
My hunch is that your extend (outside any class) extends the Eigenclass of main. Main being the instance of Object that is your current runtime environment. An Eigenclass is the class of an object whose only instance is the given object. Each object in Ruby has a Eigenclass. Nothing inherits from an Eigenclass. So your extend is not inherited to any other classes.
I have some base class A with a method that is not to be overridden.
class A
def dont_override_me
puts 'class A saying, "Thank you for not overriding me!"'
end
end
And another class B that extends A and tries to override the dont_override_me method.
class B < A
def dont_override_me
puts 'class B saying, "This is my implementation!"'
end
end
If I instantiate B and call dont_override_me, class B's instance method will be called.
b = B.new
b.dont_override_me # => class B saying, "This is my implementation!"
This is because of ruby's properties. Understandable.
However, how do I force the base class method dont_override_me to be non-overridable by it's derived classes? I could not find a keyword like final in java for ruby. In C++, the base class methods can be made non-virtual so that they become non-overridable by the derived classes. How do I achieve this in ruby?
You can do it, by hooking the change event and changing it back, but it seems a bit smelly to me:
http://scie.nti.st/2008/9/17/making-methods-immutable-in-ruby
It's one of those things that sort of defines Ruby, so fighting against it seems a little pointless imo. If someone redefines something so it breaks horribly.. that's their problem ;-)
Here's a way to do it:
http://www.thesorensens.org/2006/10/06/final-methods-in-ruby-prevent-method-override/
This has also been packaged into a gem called "finalizer" (gem install finalizer)
This makes use of the method_added callback and compares the new method name with a list of methods that you wish to make final.
I recommend:
class A #This is just as you've already defined it.
def dont_override_me
puts 'class A saying, "Thank you for not overriding me!"'
end
end
module BehaviorForB
def dont_override_me
puts 'class B saying, "This is my implementation!"'
end
def greet
"Hello, Friend."
end
end
class B < A
include BehaviorForB
end
b = B.new
b.dont_override_me #=> class A saying, "Thank you for not overriding me!"
b.greet #=> Hello, Friend.
By keeping B's methods tucked away in an mixin, you get exactly what you desire. Any method of B's methods that are not already in A will be available. Methods that are already in A will not be overridden.
One way to prevent a method from being overridden by a subclass (but not recommend) :
class Class
def frozen_method(method)
if class_variable_defined?(:##__frozen_methods__)
add= class_variable_get(:##__frozen_methods__) | [method]
class_variable_set(:##__frozen_methods__,add)
else
class_variable_set(:##__frozen_methods__,[method])
end
class << self
def inherited(child)
def method_added(method)
if class_variable_get(:##__frozen_methods__).include? method
send(:remove_method, method)
error="Cannot change method #{method} because it's not overridde"
raise TypeError, error
end
end
end
end
end
end
class Foo
def hello
'hello'
end
def foo
'foo'
end
frozen_method :foo
end
class Bar < Foo
def foo
'new foo'
end
end
#=> TypeError: Cannot change method foo because it's not overridde
Bar.new.foo #=> 'foo'
Warning: this example is not complete. If you add frozen_method for a previously defined method in the subclass, when this method will be modified in the subclass, it will lose its implementation.