I want to check something in if, and if that condition is true I want to update the record that was fetched before.
$resultQuery = DB::table('cards')->where('api_id', $card->id)->first();
if (this condition will pass I want to update this record) {
$resultQuery->update(array('price_usd' => $card->prices->usd));
}
When I use the ->update() like this, I get an error:
Call to undefined method stdClass::update();
How can I do this ?
The first() function on laravel query builder returns a stdClass meaning Standard Class.
There is no function called update() in stdClass in php. You have called update() on stdClass, and that causes the error.
There are several ways to achieve your goal.
Use Laravel query builder update() function.
$resultQuery = DB::table('cards')->where('api_id', $card->id)->first();
if (your_condition) {
Db::table('cards')
->where('api_id', $card->id)
->update([
'price_usd' => $card->prices->usd
]);
}
If you don't want to fetch the card data, don't call first()
$resultQuery = DB::table('cards')->where('api_id', $card->id);
if (your_condition) {
$resultQuery
->update([
'price_usd' => $card->prices->usd
]);
}
Use Eloquent models (Laravel's preferred way)
Create an Eloquent model for Cards (if you have not done already).
public class Card extends Model
{
}
Use eloquent query builder to fetch data. And use model update() function to update data.
$resultingCard = Card::where('api_id', $card->id)->first();
if (your_condition) {
$resultingCard->update([
'price_usd' => $card->prices->usd,
]);
}
If you're using model
You can add in card controller
$card = Card::where('api_id', $card->id)->first();
if (someConditional)
{
// Use card properties, number is a example.
$card->number = 10
// This line update this card.
$card->save();
}
You can learn more about eloquent here.
Something like this:
$resultQuery = DB::table('cards')->where('api_id', $card->id);
if ($resultQuery->count()) {
$object = $resultQuery->first();
$object->price_usd = $card->prices->usd;
$object->save();
}
Or look for an alternative solutions here: Eloquent ->first() if ->exists()
Related
I'm trying to get the right data from the database, I'm retriving a model with a media relation via eloquent, but I want to return a photo that contains the 'main' tag stored in JSON, if this tag is missing, then I would like to return the first photo assigned to this model.
how i assign tags to media
I had 3 ideas:
Use orWhere() method, but i want more likely 'xor' than 'or'
$models = Model::with(['media' => function ($query) {
$query->whereJsonContains('custom_properties->tags', 'main')->orWhere();
}]);
return $models->paginate(self::PER_PAGE);
Raw SQL, but i don't really know how to do this i tried something with JSON_EXTRACT and IF/ELSE statement, but it was to hard for me and it was a disaster
Last idea was to make 2 queries and just add media from second query if there is no tag 'main'
$models = Model::with(['media' => function ($query) {
$query->whereJsonContains('custom_properties->tags', 'main');
}]);
$models_all_media = Model:: with(['media']);
return $models->paginate(self::PER_PAGE);
but i tried something like
for($i=0; $i<count($models); $i++) {
$models->media = $models_all_media
}
but i can't do this without get() method, beacuse i don't know how to change this to LengthAwarePaginator class after using get()
try using whereHas https://laravel.com/docs/9.x/eloquent-relationships
Model::with('media')
->whereHas('media',fn($media)=>$media->whereJsonContains('custom_properties->tags', 'main'))
->paginate(self::PER_PAGE);
as per your comment you can use
$models = Model::with(['media' => function ($query) {
$query->whereJsonContains('custom_properties->tags', 'main');
}])
->leftJoin('media', function ($join) {
$join->on('models.id', '=', 'media.model_id')
->whereNull('media.custom_properties->tags->main');
})
->groupBy('models.id')
->paginate(self::PER_PAGE);
return $models;
Eloquent has a firstOrCreate method which gets a model based on a condition, or creates it if it doesn't exist.
Is there any equivalent method in Laravel's query builder (i.e. NOT in Eloquent)? For example:
$row = DB::table('users')->where('user_id', 5)->firstOrCreate('name' => 'Peter', 'last_name' => 'Pan');
That would try to get a row from users with 'user_id'==5. If it doesn't exist, it would insert a row with that id number, plus the other mentioned fields.
EDIT: I'm not trying to apply my question with users. I used users as an example to make as clear as possible what I'm looking for.
updateOrInsert function with empty values give me the result like firstOrCreate
Nope, Laravel firstOrCreate is function, that says next:
public function firstOrCreate(array $attributes, array $values = [])
{
if (! is_null($instance = $this->where($attributes)->first())) {
return $instance;
}
return tap($this->newModelInstance($attributes + $values), function ($instance) {
$instance->save();
});
}
But you can add it with query micro:
DB::query()->macro('firstOrCreate', function (array $attributes, array $values = [])
{
if ($record = $this->first()) {
// return model instance
}
// create model instance
});
So than you will be able to call it same way you do with Eloquent.
$record= DB::table('records')->where('alias', $alias)->firstOrFail();
Yeah of course! Just use normal SQL and ->selectRaw( your conditions ) and look for if there is a entry where your specifications are.
https://laravel.com/docs/5.7/queries#raw-expressions
I want to send variable $typeid to function categories to use it in query is there a way Knowing that when I try to use new instance of class in my controller like that:
$cat= new Main_category();
$categories = $cat->categories()->get();
it returns empty array
the following code is working well when I manually add the typeid inside the model function I want to have it as a variable sent from controller
controller:
$categories = Main_category::with('categories')->get();
Model
public function categories()//($typeid)
{
$query = $this->hasMany(Category::class, 'main_cat_id')
->join('category_type','category_type.cat_id','=', 'categories.cat_id')
->join('main_categories','main_categories.main_cat_id','=', 'categories.main_cat_id')
->where('category_type.type_id', '1'); // I want to use $typeid here
return $query;
}
I am not sure whether you can pass your variable in eloquent relationship methods by using with method or not. But you can add a where clause in controller.
Main_category::with(['categories' => function($query) use($typeid) {
$query->where('category_type.type_id', $typeid);
}])->get();
Or you can create a query scope for model too.
in Model
public function scopeWithCategories($query, $typeid) {
return $query->with(['categories' => function($query) use($typeid) {
$query->where('category_type.type_id', $typeid);
}]);
}
and finally in Controller
Main_category::withCategories($typeid)->get();
I'm trying to build an app in Laravel 5.3, I want to add additional column data in the pivot table. Following is my code:
My Users model:
public function relations()
{
return $this->belongsToMany('App\Plan')->withPivot('child');
}
My Plan model:
public function relations()
{
return $this->belongsToMany('App\User')->withPivot('child');
}
In my controller I'm fetching the user data from Auth::user(); and for plans and child element I'm getting through request. I want to store this to my pivot table. Following is the code which I tried in my controller:
$user = \Auth::user();
$plan_id = $request->plan_id;
$childid = $request->child_id;
$plan = App\Plan::find($plan_id);
$user->relations()->attach($plan, ['child' => $childid]);
Help me out in this.
You should use attach() like this:
$user->relations()->attach($plan_id, ['child' => $childid]);
Try the save method as:
$user->relations()->save($plan, ['child' => $childid]);
Docs
Both save and attach work. Just that attach will return null while save will return $user object when I try with tinker
Laravel's Eloquent update() function returns a boolean, and not the updated entry. I'm using:
return User::find($id)->update( Input::all() )
And this returns only a boolean. Is there a way I can get the actual row, without running another query?
I think that's the behaviour that you want:
$user = User::find($id)->fill(Input::all());
return ($user->update())?$user:false;
I hope it works fine for you.
Another approach can is to use the laravel tap helper function.
Here is an example to use it for updating and getting the updated model:
$user = User::first();
$updated = tap($user)->update([
"username" => "newUserName123"
]);
tap($user) allows us to chain any method from that model. While at the end, it will return the $user model instead of what update method returned.