I'm new to GO and trying to build functions with the aws-sdk I have something like this
input := &rds.CreateDBClusterSnapshotInput{
// removed for brevity
}
result, err := svc.CreateDBClusterSnapshot(input)
if err != nil {
// removed for brevity
}
input = &rds.ModifyDBClusterSnapshotAttributeInput{
// removed for brevity
}
When I try to build, I get this error
cannot use &rds.ModifyDBClusterSnapshotAttributeInput literal (type *rds.ModifyDBClusterSnapshotAttributeInput) as type *rds.CreateDBClusterSnapshotInput in assignment
What's wrong with my assignment?
As #Sergio Tulentsev pointed out, you are assigning ModifyDBClusterSnapshotAttributeInput type to the variable input, that is a CreateDBClusterSnapshotInput type.
There would be a few solutions to handle this problem, but the easiest way would be to make a method for each type struct that returns a compatible type for input like this;
func (createInput CreateDBClusterSnapshotInput) ReturnInput() {
return createInput.input // assuming that there are a input type your create
}
If you don't want to make a method with the same functionality for each struct, you can create a base type, make your two structs extend the type, and build a method for the base type.
Related
ERROR: type CustomStruct is not an expression.
type CustomStruct struct {
}
func getTypeName(t interface{}) string {
rt := reflect.TypeOf(t).Elem()
return rt.Name()
}
getTypeName(CustomStruct)
How can I pass struct type to function without type instance?
This will work
getTypeName((*CustomStruct)(nil))
But I wonder if there is more simple version..
You can't. You can only pass a value, and CustomStruct is not a value but a type. Using a type identifier is a compile-time error.
Usually when a "type" is to be passed, you pass a reflect.Type value which describes the type. This is what you "create" inside your getTypeName(), but then the getTypeName() will have little left to do:
func getTypeName(t reflect.Type) string {
return t.Name()
}
// Calling it:
getTypeName(reflect.TypeOf(CustomStruct{}))
(Also don't forget that this returns an empty string for anonymous types such as []int.)
Another way is to pass a "typed" nil pointer value as you did, but again, you can just as well use a typed nil value to create the reflect.Type too, without creating a value of the type in question, like this:
t := reflect.TypeOf((*CustomStruct)(nil)).Elem()
fmt.Println(t.Name()) // Prints CustomStruct
Lets resurrect this!
The generics proposal for Go got approved, and that's coming, eventually. When this question was first asked, this probably made more sense as a question, but for anyone looking to implement a generics pattern now, I think I've got an alright API for it.
For now, you can't interact with abstract types, but you can interact with methods on the abstract type, and reflect allows you to examine function signatures. For a method, the 0th is the receiver.
type Example struct {int}
type Generic struct{reflect.Type}
func (p Example) Type() {}
func Reflect(generic interface{}) Generic {
real := reflect.TypeOf(generic)
if real.Kind() != reflect.Func || real.NumIn() < 1 {
panic("reflect.Type.In(n) panics if not a func and if n out of bounds")
}
return Generic{real.In(0)}
}
func (g Generic) Make() interface{} {
return reflect.Zero(g.Type).Interface()
}
func main() {
tOfp := Reflect(Example.Type)
fmt.Printf("Name of the type: %v\n", tOfp.Name())
fmt.Printf("Real (initial)value: %v\n", tOfp.Make())
}
Some quick notes:
The structure of "Example" doesn't matter, rather only that it has a method with a non-pointer receiver.
The definition of a type called "Generic" as a struct is to accomplish what I believed OP's actual intent to be.
The above definition of "Generic" is a struct instead of an interface so that it can have its own method set. Defining "Generic" as an interface, and using a methodset specific to each operand-type used with it would make tons of sense.
If you weren't aware, actual generics are coming in Go 1.18. My example above has no linter or compile protection, and will panic at runtime if used incorrectly. It does work, and will let you reason over abstract types while you wait for a native implementation.
Happy Coding!
From Go version 1.18 a new feature Generics has been introduced. In most of the case instead of passing types to function, we can use generics. Then we will also get compile time error instead of runtime error and it's more efficient than reflect also.
Example Code
func HttpGet[T](url, body) T {
var resp T
return T
}
resp := HttpGet[ResponseType]("dummy.example", nil)
I am trying to understand the code that is used at my company. I am new to go lang, and I have already gone through the tutorial on their official website. However, I am having a hard time wrapping my head around empty interfaces, i.e. interface{}. From various sources online, I figured out that the empty interface can hold any type. But, I am having a hard time figuring out the codebase, especially some of the functions. I will not be posting the entire thing here, but just the minimal functions in which it has been used. Please bear with me!
Function (I am trying to understand):
func (this *RequestHandler) CreateAppHandler(rw http.ResponseWriter, r *http.Request) *foo.ResponseError {
var data *views.Data = &views.Data{Attributes: &domain.Application{}}
var request *views.Request = &views.Request{Data: data}
if err := json.NewDecoder(r.Body).Decode(request); err != nil {
logrus.Error(err)
return foo.NewResponsePropogateError(foo.STATUS_400, err)
}
requestApp := request.Data.Attributes.(*domain.Application)
requestApp.CreatedBy = user
Setting some context, RequestHandler is a struct defined in the same package as this code. domain and views are seperate packages. Application is a struct in the package domain. The following two structs are part of the package views:
type Data struct {
Id string `json:"id"`
Type string `json:"type"`
Attributes interface{} `json:"attributes"`
}
type Request struct {
Data *Data `json:"data"`
}
The following are part of the package json:
func NewDecoder(r io.Reader) *Decoder {
return &Decoder{r: r}
}
func (dec *Decoder) Decode(v interface{}) error {
if dec.err != nil {
return dec.err
}
if err := dec.tokenPrepareForDecode(); err != nil {
return err
}
if !dec.tokenValueAllowed() {
return &SyntaxError{msg: "not at beginning of value"}
}
// Read whole value into buffer.
n, err := dec.readValue()
if err != nil {
return err
}
dec.d.init(dec.buf[dec.scanp : dec.scanp+n])
dec.scanp += n
// Don't save err from unmarshal into dec.err:
// the connection is still usable since we read a complete JSON
// object from it before the error happened.
err = dec.d.unmarshal(v)
// fixup token streaming state
dec.tokenValueEnd()
return err
}
type Decoder struct {
r io.Reader
buf []byte
d decodeState
scanp int // start of unread data in buf
scan scanner
err error
tokenState int
tokenStack []int
}
Now, I understood that, in the struct Data in package views, Application is being set as a type for the empty interface. After that, a pointer to Request in the same package is created which points to the variable data.
I have the following doubts:
What exactly does this keyword mean in Go? What is the purpose of writing this * RequestHandler?
Initialization of a structure in Go can be done while assigning it to a variable by specifying the values of all it's members. However, here, for the struct Data, only the empty interface value is assigned and the values for the other two fields are not assigned?
What is the advantage of assigning the Application struct to an empty interface? Does it mean I can use the struct members using the interface variable directly?
Can someone help me figure out the meaning of this statement? json.NewDecoder(r.Body).Decode(request)?
While I know this is too much, but I am having a hard time figuring out the meaning of interfaces in Go. Please help!
this is not a keyword in go; any variable name can be used there. That is called the receiver. A function declared in that way must be called like thing.func(params), where "thing" is an expression of the type of the receiver. Within the function, the receiver is set to the value of thing.
A struct literal does not have to contain values for all the fields (or any of them). Any fields not explicitly set will have the zero value for their types.
As you said, an empty interface can take on a value of any type. To use a value of type interface{}, you would use type assertion or a type switch to determine the type of the value, or you could use reflection to use the value without having to have code for the specific type.
What specifically about that statement do you not understand? json is the name of a package in which the function NewDecoder is declared. That function is called, and then the Decode function (which is implemented by the type of the return value of NewDecoder) is called on that return value.
You may want to take a look at Effective Go and/or The Go Programming Language Specification for more information.
For example, I have an interface{} named a, and I also have an reflect.Type called elemType. Now, I want to type assert a to elemType, but a.(elemType) can't be compiled successfully. How to fix it?
Sorry for my confusing expression. My meaning is that I get a type from a function, and I want to type assert an interface{} to this type, but this type is stored in a reflect.Type variable.
What I want to do is similar to the code below:
var a interface{}
//do something
func getType() reflect.Type {
var ret reflect.Type
//do something
return ret
}
targetType := getType()
result := a.(targetType)
Consider a standard type assertion in Go:
v := a.(typeName)
Here the compiler can determine the type of the variable v at compile time, and make use of that knowledge when compiling any further statements involving the variable.
With your example of using a refltect.Type variable in the assertion, it would be impossible to determine the type of v, so the code could not be compiled.
If you need to check that a particular interface variable is of a particular type at runtime, you can still do that with the reflect package. For example:
// if elemType is a normal type
if reflect.ValueOf(a).Type() == elemType {
fmt.Println("type matches")
}
// if elemType is an interface, can check if the value implements it
if reflect.ValueOf(a).Type().Implements(elemType) {
fmt.Println("value implements interface")
}
But you will need a concrete type to return back to standard variables. If you've only got a small selection of possible types, perhaps using a type switch might do what you want.
I am trying to create a function that takes a []byte and an interface{} (standing for the struct) and returns an interface{} as the struct type passed into the func.
Something like this:
package main
import (
"encoding/json"
)
func UnmarshalFromJSONArray(sms []byte,tt string) (interface{}) {
var ts = new(tt)
err := json.Unmarshal(sms,&ts)
if(err != nil) {
fmt.Println(err)
}
return sms
}
So that method would run something like this:
// let's say a struct has the following definition:
type MyStructType struct {
Id int
Name string
Desc string
}
// we can some how get its fully qualified class name (this may require reflection?) or pass it into the UnMarshal method direction some how.
mst := "package.MyStructType",
// and then assume a byte array ba that has JSON format for
ba := []byte(`{"Id":"3","Name":"Jack","Desc":"the man"}`)
stct := UnmarshalFromJSONArray(ba,mst)
MyStructureType out := stct
// leaving "stct" being the unmarshalled byte array which can be used like any other struct of type "MyStructureType"
The key being that I never need to know what the fields of MyStructureType are before unmarshalling. All I need are the name of the struct and some way to instance one and then populate it with JSON byte array data that matches its fields. Hopefully that is possible (it is trivial in java using reflection). So I want to basically unmarshal an anonymous struct type by it's name without needing to know what fields it has.
Any suggestions?
The short answer is that this is impossible. There is no string to type translator in Go. You can make a map of strings to reflect.Type's, but you would need to know the possible options ahead of time or you need to provide the caller with a way to register types (perhaps in init).
Assuming you have found a way to resolve the string to its reflect.Type, you can simply call reflect.New(typ).Interface() to get the pointer you need to pass to json.Unmarshal().
The best answer is to avoid trying this all together. Writing idiomatic Java in Go isn't really possible. If I knew more about your problem, I could give you a more idiomatic Go solution.
If I have a function that looks like this
func ThisIsMyComplexFunc() (ComplexStruct, error)
where ComplexStruct is a big struct that usually contain loads of values.
What if the function stumbles on an error right in the beginning, before I even started building my struct, ideally I would like to only return the error, e.g.
return nil, err
but it wont let me do it, it forces me to create a dummy complex struct and return that together with the error, even though I never want to use the struct.
Is there a way around this?
If your function is declared to return two values, then you will need to return two values.
One option that might simplify your code is to use named return values:
func ThisIsMyComplexFunc() (s ComplexStruct, err error) {
...
}
Now you can just assign to s and/or err and then use a bare return statement. You will still be returning a ComplexStruct value, but you don't need to initialise it manually (it will default to a zero value).
You can return a pointer to the struct:
func ThisIsMyComplexFunc() (*ComplexStruct, error) {
...
if somethingIsWrong {
return nil, err
}
...
return &theStructIBuilt, nil
}
In general, it'll be cheaper to pass big structs by pointer anyway, because it's easier to copy a pointer than the whole struct.