So basically, these are two files I need to compare
file1.txt
1 a
2 b
3 c
44 d
file2.txt
11 a
123 a
3 b
445 d
To show the unique lines in file 1, I use 'comm -23' command after 'sort -u' these 2 files. Additionally, I would like to make '11 a' '123 a' in file 2 become subsets of '1 a' in file 1, similarly, '445 d' is a subset of ' 44 d'. These subsets are considered the same as their superset. So the desired output is
2 b
3 c
I'm a beginner and my loop is way too slow... So here is my code
comm -23 <( awk {print $1,$2}' file1.txt | sort -u ) <( awk '{print $1,$2}' file2.txt | sort -u ) >output.txt
array=($( awk -F ',' '{print $1}' file1.txt ))
for i in "${array[#]}";do
awk -v pattern="$i" 'match($0, "^" pattern)' output.txt > repeat.txt
done
comm -23 <( cat output.txt | sort -u ) <( cat repeat.txt | sort -u )
Anyone got any good ideas?
Another question: Any ways I could show the row numbers from original file at output? For example,
(row num from file 1)
2 2 b
3 3 c
With GNU awk for arrays of arrays:
$ cat tst.awk
NR==FNR {
vals[$2][$1]
next
}
$2 in vals {
for (i in vals[$2]) {
if ( index(i,$1) == 1 ) {
next
}
}
}
{ print FNR, $0 }
$ awk -f tst.awk file2 file1
2 2 b
3 3 c
Related
assume
file1.csv
Schemaname.tablename.columns
exam1
exam2
filetomatch.csv
exam1
exam2
exam4
exam5
exam6
I used
awk 'NR==FNR{a[$1];next} ($1) in a' file1.csv filetomatch.csv >> result.csv (each time one csv is produced)
result
exam 1
exam 2
to match the results.
I have n number of files to comapre to filetomatch.csv
i need out put to be as follows
file matchedcolumns
file1 exam 1
exam 2
file2 exam 4
.
.
.
filen exam 2
exam 3
and so on..
How can i concatenate result.csvs everytime with first field as file name.
also is there a way to show the null columns as well
How can i add null values using this?
Example
File1 Column1
File1 Column1
File2 null
File3 column3
and so on
>> result.csv should be doing the concatenation for you.
for example, create test files
$ for i in {1..4}; do echo $i > file$i.txt; done
$ head file?.txt
==> file1.txt <==
1
==> file2.txt <==
2
==> file3.txt <==
3
==> file4.txt <==
4
run some awk script on all files, print the filename part of output and concatenate the results
$ for f in file{1..4}.txt; do awk '{print FILENAME, $0}' "$f" >> results.csv; done
$ cat results.csv
file1.txt 1
file2.txt 2
file3.txt 3
file4.txt 4
found this two useful:
awk 'NR==FNR{a[$1];next}($1) in a{ print FILENAME, ($1) }' file1.csv filetomatch.csv
Merge the commmon values in a column
awk -F, '{ if (f == $1) { for (c=0; c <length($1) ; c++) printf " "; print FS $2 FS $3 } else { print $0 } } { f = $1 }' file.csv
I have two text files, and each file has one column with several rows:
FILE1
a
b
c
FILE2
d
e
f
I want to create a file that has the following output:
a - d
b - e
c - f
All the entries are meant to be numbers (decimals). I am completely stuck and do not know how to proceed.
Using paste seems like the obvious choice but unfortunately you can't specify a multiple character delimiter. To get around this, you can pipe the output to sed:
$ paste -d- file1 file2 | sed 's/-/ - /'
a - d
b - e
c - f
Paste joins the two files together and sed adds the spaces around the -.
If your desired output is the result of the subtraction, then you could use awk:
paste file1 file2 | awk '{ print $1 - $2 }'
given:
$ cat /tmp/a.txt
1
2
3
$ cat /tmp/b.txt
4
5
6
awk is a good bet to process the two files and do arithmetic:
$ awk 'FNR==NR { a[FNR""] = $0; next } { print a[FN""]+$1 }' /tmp/a.txt /tmp/b.txt
5
7
9
Or, if you want the strings rather than arithmetic:
$ awk 'FNR==NR { a[FNR""] = $0; next } { print a[FNR""] " - "$0 }' /tmp/a.txt /tmp/b.txt
1 - 4
2 - 5
3 - 6
Another solution using while and file descriptors :
while read -r line1 <&3 && read -r line2 <&4
do
#printf '%s - %s\n' "$line1" "$line2"
printf '%s\n' $(($line1 - $line2))
done 3<f1.txt 4<f2.txt
Say, I have two files and want to find out how many equal lines they have. For example, file1 is
1
3
2
4
5
0
10
and file2 contains
3
10
5
64
15
In this case the answer should be 3 (common lines are '3', '10' and '5').
This, of course, is done quite simply with python, for example, but I got curious about doing it from bash (with some standard utils or extra things like awk or whatever). This is what I came up with:
cat file1 file2 | sort | uniq -c | awk '{if ($1 > 1) {$1=""; print $0}}' | wc -l
It does seem too complicated for the task, so I'm wondering is there a simpler or more elegant way to achieve the same result.
P.S. Outputting the percentage of common part to the number of lines in each file would also be nice, though is not necessary.
UPD: Files do not have duplicate lines
To find lines in common with your 2 files, using awk :
awk 'a[$0]++' file1 file2
Will output 3 10 15
Now, just pipe this to wc to get the number of common lines :
awk 'a[$0]++' file1 file2 | wc -l
Will output 3.
Explanation:
Here, a works like a dictionary with default value of 0. When you write a[$0]++, you will add 1 to a[$0], but this instruction returns the previous value of a[$0] (see difference between a++ and ++a). So you will have 0 ( = false) the first time you encounter a certain string and 1 ( or more, still = true) the next times.
By default, awk 'condition' file is a syntax for outputting all the lines where condition is true.
Be also aware that the a[] array will expand every time you encounter a new key. At the end of your script, the size of the array will be the number of unique values you have throughout all your input files (in OP's example, it would be 9).
Note: this solution counts duplicates, i.e if you have:
file1 | file2
1 | 3
2 | 3
3 | 3
awk 'a[$0]++' file1 file2 will output 3 3 3 and awk 'a[$0]++' file1 file2 | wc -l will output 3
If this is a behaviour you don't want, you can use the following code to filter out duplicates :
awk '++a[$0] == 2' file1 file2 | wc -l
with your input example, this works too. but if the files are huge, I prefer the awk solutions by others:
grep -cFwf file2 file1
with your input files, the above line outputs
3
Here's one without awk that instead uses comm:
comm -12 <(sort file1.txt) <(sort file2.txt) | wc -l
comm compares two sorted files. The arguments 1,2 suppresses unique lines found in both files.
The output is the lines they have in common, on separate lines. wc -l counts the number of lines.
Output without wc -l:
10
3
5
And when counting (obviously):
3
You can also use comm command. Remember that you will have to first sort the files that you need to compare:
[gc#slave ~]$ sort a > sorted_1
[gc#slave ~]$ sort b > sorted_2
[gc#slave ~]$ comm -1 -2 sorted_1 sorted_2
10
3
5
From man pages for comm command:
comm - compare two sorted files line by line
Options:
-1 suppress column 1 (lines unique to FILE1)
-2 suppress column 2 (lines unique to FILE2)
-3 suppress column 3 (lines that appear in both files)
You can do all with awk:
awk '{ a[$0] += 1} END { c = 0; for ( i in a ) { if ( a[i] > 1 ) c++; } print c}' file1 file2
To get the percentage, something like this works:
awk '{ a[$0] += 1; if (NR == FNR) { b = FILENAME; n = NR} } END { c = 0; for ( i in a ) { if ( a[i] > 1 ) c++; } print b, c/n; print FILENAME, c/FNR;}' file1 file2
and outputs
file1 0.428571
file2 0.6
In your solution, you can get rid of one cat:
sort file1 file2| uniq -c | awk '{if ($1 > 1) {$1=""; print $0}}' | wc -l
How about keeping it nice and simple...
This is all that's needed:
cat file1 file2 | sort -n | uniq -d | wc -l
3
man sort:
-n, --numeric-sort -- compare according to string numerical value
man uniq:
-d, --repeated -- only print duplicate lines
man wc:
-l, --lines -- print the newline counts
Hope this helps.
EDIT - one fewer process (credit martin):
sort file1 file2 | uniq -d | wc -l
One way using awk:
awk 'NR==FNR{a[$0]; next}$0 in a{n++}END{print n}' file1 file2
Output:
3
The first answer by Aserre using awk is good but may have the undesirable effect of counting duplicates - even if the duplicates exist in only ONE of the files, which is not quite what the OP asked for.
I believe this edit will return only the unique lines that exist in BOTH files.
awk 'NR==FNR{a[$0]=1;next}a[$0]==1{a[$0]++;print $0}' file1 file2
If duplicates are desired, but only if they exist in both files, I believe this next version will work, but will only report duplicates in the second file that exist in the first file. (If the duplicates exist in the first file, only the those that also exist in file2 will be reported, so file order matters).
awk 'NR==FNR{a[$0]=1;next}a[$0]' file1 file2
Btw, I tried using grep, but it was painfully slow on files with a few thousand lines each. Awk is very fast!
UPDATE 1 : new version ensures intra-file duplicates are excluded from count, so only cross-file duplicates would show up in the final stats :
mawk '
BEGIN { _*= FS = "^$"
} FNR == NF { split("",___)
} ___[$_]++<NF { __[$_]++
} END { split("",___)
for (_ in __) {
___[__[_]]++ } printf(RS)
for (_ in ___) {
printf(" %\04715.f %s\n",_,___[_]) }
printf(RS) }' \
<( jot - 1 999 3 | mawk '1;1;1;1;1' | shuf ) \
<( jot - 2 1024 7 | mawk '1;1;1;1;1' | shuf ) \
<( jot - 7 1295 17 | mawk '1;1;1;1;1' | shuf )
3 3
2 67
1 413
===========================================
this is probably waaay overkill, but i wrote something similar to this to supplement uniq -c :
measuring the frequency of frequencies
it's like uniq -c | uniq -c without wasting time sorting. The summation and % parts are trivial from here, with 47 over-lapping lines in this example. It avoids spending any time performing per row processing, since the current setup only shows the summarized stats.
If you need to actual duplicated rows, they're also available right there serving as the hash key for the 1st array.
gcat <( jot - 1 999 3 ) <( jot - 2 1024 7 ) |
mawk '
BEGIN { _*= FS = "^$"
} { __[$_]++
} END { printf(RS)
for (_ in __) { ___[__[_]]++ }
for (_ in ___) {
printf(" %\04715.f %s\n",
_,___[_]) } printf(RS) }'
2 47
1 386
add another file, and the results reflect the changes (I added <( jot - 5 1295 5 ) ):
3 9
2 115
1 482
Hi all I have this data files
File1
1 The hero
2 Chainsaw and the gang
3 .........
4 .........
where the first field is the id and the second field is the product name
File 2
The hero 12
The hero 2
Chainsaw and the gang 2
.......................
From these two files I want to have a third file
File 3
The hero 12 1
The hero 2 1
Chainsaw and the gang 2 2
.......................
As you can see I am just adding the indices reading from file 1
I used this method
awk -F '\t' 'NR == FNR{a[$2]=$1; next}; {print $0, a[$1]}' File1 File2 > File 3
where I am creating this associated array using File 1 and doing just lookup using product names from file 2
However my files are huge, I have like 20 million product names and this process is taking a lot of time. Any suggestions, how I can speed it up?
You can use this awk:
awk 'FNR==NR{p=$1; $1=""; sub(/^ +/, ""); a[$0]=p;next} {q=$NF; $NF=""; sub(/ +$/, "")}
($0 in a) {print $0, q, a[$0]}' f1 f2
The hero 12 1
The hero 2 1
Chainsaw and the gang 2 2
The script you posted won't produce the output you want from the input files you posted so let's fix that first:
$ cat file1
1 The hero
2 Chainsaw and the gang
$ cat file2
The hero 12
The hero 2
Chainsaw and the gang 2
$ awk -F'\t' 'NR==FNR{map[$2]=$1;next} {key=$0; sub(/[[:space:]]+[^[:space:]]+$/,"",key); print $0, map[key]}' file1 file2
The hero 12 1
The hero 2 1
Chainsaw and the gang 2 2
Now, is that really too slow or were you doing some pre or post-processing and that was the real speed issue?
The obvious speed up is if your "file2" is sorted then you can delete the corresponding map[] value whenever the key changes so your map[] gets smaller every time you use it. e.g. something like this (untested):
$ awk -F'\t' '
NR==FNR {map[$2]=$1; next}
{ key=$0; sub(/[[:space:]]+[^[:space:]]+$/,"",key); print $0, map[key] }
key != prev { delete map[prev] }
{ prev = key }
' file1 file2
Alternative approach when populating map[] uses too much time/memory and file2 is sorted:
$ awk '
{ key=$0
sub(/[[:space:]]+[^[:space:]]+$/,"",key)
if (key != prev) {
cmd = "awk -F\"\t\" -v key=\"" key "\" \047$2 == key{print $1;exit}\047 file1"
cmd | getline val
close(cmd)
}
print $0, val
prev = key
}' file2
From comments you're having scaling problems with your lookups. The general fix for that is to merge sorted sequences:
join -t $'\t' -1 2 -2 1 -o 1.2,2.2,1.1 \
<( sort -t $'\t' -k2 file1) \
<( sort -t $'\t' -sk1,1 file2)
I gather Windows can't do process substitution, so you have to use temporary files:
sort -t $'\t' -k2 file1 >idlookup.bykey
sort -t $'\t' -sk1,1 file2 >values.bykey
join -t $'\t' -1 2 -2 1 -o 1.2,2.2,1.1 idlookup.bykey values.bykey
If you need to preserve the value lookup sequence use nl to put line numbers on the front and sort on those at the end.
If your issue is performance then try this perl script:
#!/usr/bin/perl -l
use strict;
use warnings;
my %h;
open my $fh1 , "<", "file1.txt";
open my $fh2 , "<", "file2.txt";
open my $fh3 , ">", "file3.txt";
while (<$fh1>) {
my ($v, $k) = /(\d+)\s+(.*)/;
$h{$k} = $v;
}
while (<$fh2>) {
my ($k, $v) = /(.*)\s+(\d+)$/;
print $fh3 "$k $v $h{$k}" if exists $h{$k};
}
Save the above script in say script.pl and run it as perl script.pl. Make sure the file1.txt and file2.txt are in the same directory as the script.
Given input file
z
b
a
f
g
a
b
...
I want to output the number of occurrences of each string, for example:
z 1
b 2
a 2
f 1
g 1
How can this be done in a bash script?
You can sort the input and pass to uniq -c:
$ sort input_file | uniq -c
2 a
2 b
1 f
1 g
1 z
If you want the numbers on the right, use awk to switch them:
$ sort input_file | uniq -c | awk '{print $2, $1}'
a 2
b 2
f 1
g 1
z 1
Alternatively, do the whole thing in awk:
$ awk '
{
++count[$1]
}
END {
for (word in count) {
print word, count[word]
}
}
' input_file
f 1
g 1
z 1
a 2
b 2
cat text | sort | uniq -c
should do the job
Try:
awk '{ freq[$1]++; } END{ for( c in freq ) { print c, freq[c] } }' test.txt
Where test.txt would be your input file.
Here's a bash-only version (requires bash version 4), using an associative array.
#! /bin/bash
declare -A count
while read val ; do
count[$val]=$(( ${count[$val]} + 1 ))
done < your_intput_file # change this as needed
for key in ${!count[#]} ; do
echo $key ${count[$key]}
done
This might work for you:
cat -n file |
sort -k2,2 |
uniq -cf1 |
sort -k2,2n |
sed 's/^ *\([^ ]*\).*\t\(.*\)/\2 \1/'
This output the number of occurrences of each string in the order in which they appear.
You can use sort filename | uniq -c.
Have a look at the Wikipedia page on uniq.