Laravel blade file can't view - laravel-5.8

I created CustomerController in Http, later, I fixed-route get customers, but getting an error in a single action Controller.
I tried to show off CustomerController view for displaying customers logged in page
Here is my error message:
Use of undefined constant view - assumed 'view' (this will throw an Error in a future version of PHP)

Looks like you're trying to access the old ways to render blade file look at this :-
return View::make('customers.index', $customersList);
To use view() method
return view('admin.pages.customers.index',compact('someVaiable'));
OR
// You can define constant for your controller get methods
private $layout;
public function __construct()
{
$this->layout = 'admin.pages.customers.';
}
public function index(){
return view($this->layout.'index');
}
Take a look a this for Single Action Controllers example
https://laravel.com/docs/5.8/controllers#single-action-controllers

The first argument of the view method in the controller should be the name of the view.
Routes/web.php
Route::get('/', 'CustomerController');
app/Http/Controllers/CustomerController.php
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
class CustomerController extends Controller
{
public function __invoke(Request $request)
{
return view('customers');
}
}
resources/views/customers.blade.php
<h1>Customers</h1>

Related

Laravel Models/function, how to make a main "function"

So guy's, I've created a Laravel project.
I have a master. Layout which always contains the user data.
So I have a navbar with $user->name for example.
In every controller I needed to add the User model and also the where function.
$user = User::find(auth()->user()->id)
Maybe this example is bad, but I've also included the company in the master, so it shows in the Navbar.
Is there a way, that I don't need to repeat that process? So I don't need it always in the controller.
Thanks for reading.
In laravel you are extending each class from a main controller so its better to create a method in main class like this
child controller
class testController extends Controller
{
// as you can see its extending so go into Controller class
}
parent class, So here i have creatd a getName method here. If you want get the value through mode
<?php
namespace App\Http\Controllers;
use Illuminate\Foundation\Bus\DispatchesJobs;
use Illuminate\Routing\Controller as BaseController;
use Illuminate\Foundation\Validation\ValidatesRequests;
use Illuminate\Foundation\Auth\Access\AuthorizesRequests;
class Controller extends BaseController
{
use AuthorizesRequests, DispatchesJobs, ValidatesRequests;
private $current_user_name = 'test';
public function getName()
{
return ($this->current_user_name);
}
}
Now go back to child controller and pass this method in view
class testController extends Controller
{
public function index()
{
return view('', $data = ['name' => $this->getName()]);
}
}
Hope this cover your query. In this way you don't need to repeat your code in every controller.
You can get data in your blade template too, like user information, but if you need more complex data and you don't want to put logic in blade, you can use this method (AppServiceProvider.php):
public function boot()
{
view()->composer('your_mast_layout', function($view)
{
$data = ...
$view->with('variable_name', $data);
});
}

How to architect a project which has more number of dynamic pages in laravel

I have a project which has a large number of dynamic pages. Approximately 30+ pages. The content of each page is different. what I did is created 30 tables and 30 routes as well. And on the admin side, there are 30+ modules to edit the contents. Is it the right way to do this?. In database table, different columns has to be kept.
// Route definition...
Route::get('/page1', [Page1Controller::class, 'show']);
Route::get('/page2', [Page2Controller::class, 'show']);
Route::get('/page3', [Page3Controller::class, 'show']);
// Controller method definition...
public function index() {
return view('page1');
}
// Route definition...
// All other routes above this slug catch all. otherwise it will try and hit this controller all the time and fail.
Route::get('/{slug}', [PageController::class, 'show']);
// Controller method definition...
public function show($slug)
{
$contents = PageContents::where('slug', $slug)->firstOrFail();
if ($contents) {
return view('page')->with('contents', $contents);
}
return view('404');
}
This way you have a table with all the contents you need. e.g. title, body copy so on. but if each layout is different you could also return a different view. e.g.
public function show($slug)
{
$contents = PageContents::where('slug', $slug)->firstOrFail();
if ($contents) {
return view('page-'.$slug)->with('contents', $contents);
}
return view('404');
}
You can create only one controller and add a parameter in the route(web.php):
web.php
//---Route Definition
Route::get('page/{page_number}', [PageController::class, 'show'])->name('page.show');
PageController.php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Crypt;
class PageController extends Controller {
//---Show
public function show($page_number) {
return view('show.show', compact('page_number'));
}//---End of Function show
}
If you want to retrieve your data from a database just one table is enough, just create a page table and give a field by the name of page_number and retrieve your specific page data by the given field.
For example:
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Crypt;
class PageController extends Controller {
//---Show
public function show($page_number) {
$page = PageContent::where('page_number', $page_number)->first();
return view('show.show', compact('page'));
}//---End of Function show
}
**
Your Link to routes
<a href="{{ route('page.show', ['page_number' => 1])) }}" class="" title="Show">
Show
</a>

index view isn't showing

hi I have created a new default index view but it not loading its content and showing the blank page,,, my file structure https://ibb.co/wW337xS
index blade:
#extends('layouts.frontLayout.front_design')
#section('content')
<!--html here-->
#endsection
controller:
<?php
namespace App\Http\Controllers;
use App\Index;
use Illuminate\Http\Request;
class IndexController extends Controller
{
public function index()
{
return view('index');
}
route:
Route::resource('/','IndexController');
Its problem is occured, becouse you send user to the view with name of 'index', it means that there is a blade page in the view folder of your resource, but as i see in your structure, the index.blade.php is in this address: layouts.index. then you can refactor your controller:
public function index()
{
return view('layouts.index');
}
wrong
Route::resource('/','IndexController');
right
Route::get('/', 'IndexController#index');

How to alter functionality of login controller in Laravel to pass a variable

I'm trying to set up my Laravel installation so that upon login it will populate the home page with information from my database. How can I compact a variable to send it to the home page?
I've tried declaring a variable like this in the login controller:
$post = Post::all();
But when i do that i get the following error:
syntax error, unexpected '$post' (T_VARIABLE), expecting function
(T_FUNCTION) or const (T_CONST)
Also how can i compact a variable to send to the home page? The only code that directs the user to the home page is this line: protected $redirectTo = '/home';
and I can't compact a variable in that line because compact requires parentheses like this: return view('/home', compact('post'));
What I'm trying to accomplish is to get the home page to display the users posts.
namespace App\Http\Controllers;
use App\Models\Post;
class HomeController extends Controller
{
public function index()
{
$posts = Post::all();
return view('home', compact('posts'));
}
}
Explanation
To accomplish your goal, you don't have to change the $redirectTo property of the LoginController. Because it's the URL that needs to redirect, it needs to stay the same because still, you need to redirect to the home page.
All you have to do is alter HomeController which Laravel has already defined for you. The index() method is the one that's taking care of how to show the home page. So as the answer says alter that function.
As after successful login you are redirected to home page, try to display the posts in HomeController#index and you do not need to make any modification to your login controller.
In your HomeController just import the Post model and return the posts to index.blade.php and display there, your HomeController will look like
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Post; // path to your Post model
class HomeController extends Controller
{
/**
* Create a new controller instance.
*
* #return void
*/
public function __construct()
{
$this->middleware('auth');
}
/**
* Show the application dashboard.
*
* #return \Illuminate\Http\Response
*/
public function index()
{
$posts = Post::all();
return view('home', compact('posts'));
}
}
and in your index.blade.php, you can loop through your posts.

How to pass data to all views in Laravel 5.6?

I have two controllers. StudentController and TeacherController. I have a variable $chat which I want to pass in all the views of StudentController and TeacherController. The $chat will contain different data for both these controllers.
I searched and found ways, but I am getting empty data. I am doing it like this.
<?php
namespace App\Http\Controllers;
use View;
class StudentController extends Controller {
public function __construct()
{
$this->middleware('auth')->except(['home']);
$this->middleware('access')->except(['home']);
$chats = studentChat();
View::share('chats', $chats);
}
So, here I am printing and it is returning an empty array, but when I use the same in a function the array contains data. What is wrong here? Can anyone please help?
What I tried:
public function boot()
{
View::composer('*', function ($view) {
$chats = Cache::remember('chats', 60, function () {
if(Auth::user()->user_type() == config('constant.student'))
{
return studentChat();
}
else
{
return teacherChat();
}
});
$view->with('chats', $chats);
});
}
If you use View::share your share data to ALL your view, if you need to add data to few different views you may do this:
Create blade file(chat.blade.php for your case), and put your variables:
<? $chats = studentChat(); ?>
Include this file to the begining of your views where your need this 'global' varables:
//begin of your blade file
#include('chat')
//some code
{{ $chat->channel }}
Sharing Data With All Views
Occasionally, you may need to share a piece of data with all views that are rendered by your application. You may do so using the view facade's share method. Typically, you should place calls to share within a service provider's boot method. You are free to add them to the AppServiceProvider or generate a separate service provider to house them:
<?php
namespace App\Providers;
use Illuminate\Support\Facades\View;
class AppServiceProvider extends ServiceProvider
{
public function boot()
{
$chats = studentChat();
View::share('chats', $chats);
}
public function register()
{
//
}
}
So, what I did was in the AppServiceProvider class, in the boot function I added this.
View::composer('*', function ($view) {
if(!\Auth::check())
{
return;
}
$userType = \Auth::user()->user_type ;
if($userType == config('constant.student'))
{
$chats = studentChat();
}
else if($userType == config('constant.teacher'))
{
$chats = teacherChat();
}
$view->with('chats', $chats);
});
You can pass data to the view Like.
return View::make('demo')->with('posts', $posts);
For more details visit article : Introduction to Routing in Laravel
write your query in boot method in appServiceProvider like,
View::composer('*', function ($view) {
$share_query = Cache::remember('share_query', 60,function () {
return App\User::all();
});
$view->with('share_query', $share_query);
});
Your final solution is ok, but not the cleanest possible.
Here is what i would do.
Define a class with a single function that contains your logic and return $chats, that way you will encapsulate your logic properly and keep your service provider boot method clean.
Then you have 2 options:
Inject your class in the boot() method of the service provider you use, then call its function and uses View::share. Should looks like :
public function boot(ChatResolver $chatResolver)
{
$chats = $chatResolver->getChats();
View::share(compact('chats));
}
If you only use $chats variable in a signe view or partial (like a part of layout), you can also inject the class you defined directly in the view.
Here is a link to Laravel doc regarding that.
In some cases it might be the easiest solution.

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