Is there a way for me to simplify these echos? [duplicate] - bash

This question already has answers here:
How do I iterate over a range of numbers defined by variables in Bash?
(20 answers)
Closed 3 years ago.
I am still learning how to shell script and I have been given a challenge to make it easier for me to echo "Name1" "Name2"..."Name15" and I'm not too sure where to start, I've had ideas but I don't want to look silly if I mess it up. Any help?
I haven't actually tried anything just yet it's all just been mostly thought.
#This is what I wrote to start
#!/bin/bash
echo "Name1"
echo "Name2"
echo "Name3"
echo "Name4"
echo "Name5"
echo "Name6"
echo "Name7"
echo "Name8"
echo "Name9"
echo "Name10"
echo "Name11"
echo "Name12"
echo "Name13"
echo "Name14"
echo "Name15"
My expected results are obviously just for it to output "Name1" "Name2" etc. But I'm looking for a more creative way to do it. If possible throw in a few ways to do it so I can learn. Thank you.

The easiest (possibly not the most creative) way to do this is to use printf:
printf "%s\n" name{1..15}
This relies on bash brace expansion {1..15} to have the 15 strings.

Use a for loop
for i in {1..15};do echo "Name$i";done

A few esoteric solutions, from the least to the most unreasonable :
base64 encoded string :
base64 -d <<<TmFtZTEKTmFtZTIKTmFtZTMKTmFtZTQKTmFtZTUKTmFtZTYKTmFtZTcKTmFtZTgKTmFtZTkKTmFtZTEwCk5hbWUxMQpOYW1lMTIKTmFtZTEzCk5hbWUxNApOYW1lMTUK
The weird chain is your expected result encoded in base64, an encoding generally used to represent binary data as text. base64 -d <<< weirdChain is passing the weird chain as input to the base64 tool and asking it to decode it, which displays your expected result
generate an infinite stream of "Name", truncate it, use line numbers :
yes Name | awk 'NR == 16 { exit } { printf("%s%s\n", $0, NR) }'
yes outputs an infinite stream of what it's passed as argument (or y by default, used to automatize interactive scripts asking for [y/n] confirmation). The awk command exits once it reaches the 16th line, and otherwise prints its input (provided by yes) followed by the line number. The truncature could as easily be done with head -15, and I've tried using the nl "number line" utility or grep -n to number lines, but they always added the line numbers as prefix which required an extra re-formatting step.
read random binary data and hope to stumble on all the lines you want to output :
timeout 1d strings /dev/urandom | grep -Eo "Name(1[0-5]|[1-9])" | sort -uV
strings /dev/urandom will extract ascii sequences from the binary random source /dev/urandom, grep will filter those which respect the format of a line of your expected output and sort will reorder those lines in the correct order. Since sort needs to have a received its whole input before it reorders it and /dev/urandom won't stop producing data, we use timeout 1d to stop reading from /dev/urandom after a whole day in hope it has sifted through enough random data to find your 15 lines (I'm not sure that's even remotely likely).
use an HTTP client to retrieve this page, extract the bash script you posted and execute it.
my_old_script=$(curl "https://stackoverflow.com/questions/57818680/" | grep "#This is what I wrote to start" -A 18 | tail -n+4)
eval "$my_old_script"
curl is a command line tool that can be used as an HTTP client, grep with its -A 18 parameter will select the "This is what I wrote to start" text and the 18 lines that follow, tail will remove the first 3 lines, and eval will execute your script.
While it will be much more efficient than the previous solution, it's an even less reasonable solution because high-rep users can edit your question to make this solution execute arbitrary code on your computer. Ideally you'd be using an HTML-aware parser rather than basic string manipulation to extract the code, but we're not talking about best practices here...

Related

variable passing through awk command [duplicate]

This question already has answers here:
How do I set a variable to the output of a command in Bash?
(15 answers)
Closed 1 year ago.
here's my issue, I have a bunch of fastq.gz files and I need to determine the number of lines of it (this is not the issue), and from that number of line derive a value that determine a threshold used as a variable used down in the same loop. I browsed but cannot find how to do it. here's what I have so far:
for file in *R1.fastq*; do
var=echo $(zcat "$file" | $((`wc -l`/400000)))
for i in *Bacter*; do
awk -v var1=$var '{if($2 >= var1) print $0}' ${i} | wc -l >> bacter-filtered.txt
done
done
I get the error message: -bash: 14850508/400000: No such file or directory
any help would be greatly appreciated !
The problem is in the line
var=echo $(zcat "$file" | $((`wc -l`/400000)))
There are a bunch of shell syntax elements here combined in ways that don't connect up with each other. To keep things straight, I'd recommend splitting it into two separate operations:
lines=$(zcat "$file" | wc -l)
var=$((lines/400000))
(You may also have to do something about the output to bacter-filtered.txt -- it's just going to contain a bunch of numbers, with no identifications of which ones come from which files. Also since it always appends, if you run this twice you'll have the output from both runs stuck together. You might want to replace all those appends with a single > bacter-filtered.txt after the last done, so the whole output just gets stored directly.)
What's wrong with the original? Well, let's start with this:
zcat "$file" | $((`wc -l`/400000))
Unless I completely misunderstand, the purpose here is to extract $file (with zcat), count lines in the result (with wc -l), and divide that by 400000. But since the output of zcat isn't piped directly to wc, it's piped to a complex expression involving wc, it's somewhat ambiguous what should happen, and is actually different under different shells. In zsh, it does something completely different from that: it lets wc read from the script's stdin (generally your Terminal), divides the result from that by 400000, and then pipes the output of zcat to that ... number?
In bash, it does something closer to what you want: wc actually does read from the output of zcat, so the second part of the pipe essentially turns into:
... | $((14850508/400000))
Now, what I'd expect to happen at this point (and happens in my tests) is that it should evaluate $((14850508/400000)) into 37, giving:
... | 37
which will then try to execute 37 as a command (because it's part of a pipeline, and therefore is supposed to be a command). But for some reason it's apparently not evaluating the division and just trying to execute 14850508/400000 as a command. Which doesn't really work any better or worse than 37, so I guess it doesn't matter much.
So that's where the error is coming from, but there's actually another layer of confusion in the original line. Suppose that internal pipeline was fixed so that it properly output "37" (rather than trying to execute it). The outer structure would then be:
var=echo $(cmdthatprints37)
The $( ) basically means "run the command inside, and substitute its output into the command line here", so that would evaluate to:
var=echo 37
...which, in shell syntax, means "run the command 37 with var set to "echo" in its environment.
The solution here would be simple. The echo is messing everything up so remove it:
var=$(cmdthatprints37)
...which evaluates to:
var=37
...which is what you want. Except that, as I said above, it'd be better to split it up and do the command bits and the math separately rather than getting them mixed up.
BTW, I'd also recommend some additional double-quoting of shell variables; shellcheck.net will be happy to point out where.

Using for loop to compare two strings character by character in bash

I am writing a bash script that loops over a large file of data which i have extracted the key parts I need to use. It seems quite trivial when I was trying to do it but all I need to do is something akin to,
string1=...
string2=...
correct=0
for i in 1..29
do
if [string1[i] == string2[i]]
then
correct=correct+1
fi
done
When I tried doing something like this I get a Bad Substitution which I assume is because some of the key's look like this,
`41213343323455122411141331555 - key`
`3113314233111 22321112433111* - answer`
The spaces and occational * that are found don't need special treatment in my case, just a simple comparison of each index.
#!/bin/bash
answersCorrect=0
for i in $(nawk 'BEGIN{ for(i=1;i<=29;i++) print i}')
do
if [ "${answer:i:1}" = "${key:i:1}" ]
then
answersCorrect=$answersCorrect+1 #this line#
fi
done
I am getting no compiler errors now however I don't think i'm incrementing answersCorrect correctly. When I output it it is something like 0+1+1+1 instead of just 3 (this segment is being used inside a while loop)
Fixed Solution for that line : answersCorrect=$((answersCorrect+1))
The original problem is fixed by comments and some extra work of #Mikel.
An alternative is comparing the strings after converting the strings to lines.
diff --suppress-common-lines <(fold -w1 <<< "${string1}") <(fold -w1 <<< "${string2}") |
grep -c "^<"

Bash split stdin by null and pipe to pipeline

I have a stream that is null delimited, with an unknown number of sections. For each delimited section I want to pipe it into another pipeline until the last section has been read, and then terminate.
In practice, each section is very large (~1GB), so I would like to do this without reading each section into memory.
For example, imagine I have the stream created by:
for I in {3..5}; do seq $I; echo -ne '\0';
done
I'll get a steam that looks like:
1
2
3
^#1
2
3
4
^#1
2
3
4
5
^#
When piped through cat -v.
I would like to pipe each section through paste -sd+ | bc, so I get a stream that looks like:
6
10
15
This is simply an example. In actuality the stream is much larger and the pipeline is more complicated, so solutions that don't rely on streams are not feasible.
I've tried something like:
set -eo pipefail
while head -zn1 | head -c-1 | ifne -n false | paste -sd+ | bc; do :; done
but I only get
6
10
If I leave off bc I get
1+2+3
1+2+3+4
1+2+3+4+5
which is basically correct. This leads me to believe that the issue is potentially related to buffering and the way each process is actually interacting with the pipes between them.
Is there some way to fix the way that these commands exchange streams so that I can get the desired output? Or, alternatively, is there a way to accomplish this with other means?
In principle this is related to this question, and I could certainly write a program that reads stdin into a buffer, looks for the null character, and pipes the output to a spawned subprocess, as the accepted answer does for that question. Given the general support of streams and null delimiters in bash, I'm hoping to do something that's a little more "native". In particular, if I want to go this route, I'll have to escape the pipeline (paste -sd+ | bc) in a string instead of just letting the same shell interpret it. There's nothing too inherently bad about this, but it's a little ugly and will require a bunch of somewhat error prone escaping.
Edit
As was pointed out in an answer, head makes no guarantees about how much it buffers. Unless it only buffers single byte at a time, which would be impractical, this will never work. Thus, it seems like the only solution would be to read it into memory, or write a specific program.
The issue with your original code is that head doesn't guarantee that it won't read more than it outputs. Thus, it can consume more than one (NUL-delimited) chunk of input, even if it's emitting only one chunk of output.
read, by contrast, guarantees that it won't consume more than you ask it for.
set -o pipefail
while IFS= read -r -d '' line; do
bc <<<"${line//$'\n'/+}"
done < <(build_a_stream)
If you want native logic, there's nothing more native than just writing the whole thing in shell.
Calling external tools -- including bc, cut, paste, or others -- involves a fork() penalty. If you're only processing small amounts of data per invocation, the efficiency of the tools is overwhelmed by the cost of starting them.
while read -r -d '' -a numbers; do # read up to the next NUL into an array
sum=0 # initialize an accumulator
for number in "${numbers[#]}"; do # iterate over that array
(( sum += number )) # ...using an arithmetic context for our math
done
printf '%s\n' "$sum"
done < <(build_a_stream)
For all of the above, I tested with the following build_a_stream implementation:
build_a_stream() {
local i j IFS=$'\n'
local -a numbers
for ((i=3; i<=5; i++)); do
numbers=( )
for ((j=0; j<=i; j++)); do
numbers+=( "$j" )
done
printf '%s\0' "${numbers[*]}"
done
}
As discussed, the only real solution seemed to be writing a program to do this specifically. I wrote one in rust called xstream-util. After installing it with cargo install xstream-util, you can pipe the input into
xstream -0 -- bash -c 'paste -sd+ | bc'
to get the desired output
6
10
15
It doesn't avoid having to run the program in bash, so it still needs escaping if the pipeline is complicated. Also, it currently only supports single byte delimiters.

Write a script that prints from a dir k strokes sorted by date

I have a directory "Main Dir" and I want to write a script, which will get 2 parameters: sorted_by_date , that will find in the directory the id-worker directory (it does exist) and in it, from a file called "sent.txt", it will print results-num (an integer) strokes sorted by date.
I'm a begginer in bash (have knowledge and skills mainly in C), and I stil didn't saw how to write scripts, but I've tried to do something from a little commands I learned and from a little search in the internet.
Can somebody help a newbie like me in my first script-writing ?
I'll paste here my first try:
#!/bin/bash
id_worker = "$1"
results_num = "$2"
sort -k3 -t "./Main Dir/id_worker/sent.text"
head -n+3 $results_num
I'm going to go out on a limb here, and assume your sort command is producing the information you want from the id_worker sent.txt file and that you are talking about the number of lines you want when you say strokes. Given the extended discussion in the comments, that is about the only thing I see that makes sense.
With that in mind, you were not that far off in your first attempt. What you needed to do to fix the sort command was to dereference your id_worker with $ to get the value you passed. In bash you assign variables as id_worker="something", but to get the value back, you must precede the variable with a $, just as you see with your id_worker="$1". NOTE: there are NO spaces allowed on either side of the '=' sign in bash. Putting that together, it looks like you intended:
sort -k3 -t "./Main Dir/$id_worker/sent.text"
Where you are beginning in the directory above Main Dir running your script because you have given a relative path "./Main Dir/stuff".
Now if you want to limit the number of lines to the first results_num lines of the sorted output, then you can use head, but you need to remove the "+" sign (which is only relevant with the tail command). To use it with the sorted output, you mustpipe the results of sort to head using the '|' pipe character. For example:
sort -k3 -t "./Main Dir/$id_worker/sent.text" | head -n $results_num
Putting all of the pieces that I think you intended, and including a short check to make sure both id_worker and results_num are given on the command line, you would end up with something like:
#!/bin/bash
## verify both arguments given
[ -z $1 -o -z $2 ] && {
printf "error: insufficient input. usage: %s worker num\n" "${0##*/}"
exit 1
}
id_worker="$1"
results_num="$2"
## pipe the results of sort to head to print first $results_num lines
sort -k3 -t "./Main Dir/$id_worker/sent.text" | head -n $results_num
Note: if you are having trouble with your script, run it with:
bash -x scriptname id_worker results_num
to enable line-by-line debugging output from bash. Let me know if I have not understood what you were saying or if the results are not what you intended. There are several ways of approaching this problem, but I do need to clearly understand what you want to go further. Good luck.

Shell Script : If a string is present in a file

I am a newbie to shell scriptng and I want to check if 3 strings("hello","who","when " etc) are present in a file.
I find many ways when I google out awk,cat ,grep etc ,What can be the best way and how Can I do it.
I just need to know if the strings are present or not .
Your question is a little incomplete:
do you want to find strings or words? So when the word Othello appears, does that count as hello?
in your question there is whitespace behind the when. Is that intentional?
do you want to know whether all three words are in the file, or is one of the words enough?
The general solution is to use grep or egrep to search for text in a file. The exact command line depends on the answers to the above questions.
to search for words (Othello doesn't count as hello) you need to pass the -w option to grep.
I'm assuming thhat the whitespace was a mistake.
When you need all the words, you can do egrep -wo 'hello|who|when' | sort -u. The egrep command finds all instances of the given words, and prints them out one per line. At that point, you will have many duplicates. Therefore the sort -u command sorts them and only keeps the unique lines (that's what the -u means). In a complete program, I would do it as follows:
filename="story.txt"
words=$(egrep -wo 'hello|who|when' "$filename" | sort -u)
n=$(echo "$words" | wc -l)
if [ $n = 3 ]; then
echo "found all words in the file"
else
echo "didn't find all words, only \""$words"\"."
fi
There's a lot more that I could tell you about this little piece of code, and why I wrote it exactly like that, but for a beginner, it's already enough to understand.
But just in case that you need a simple solution and the file is small anyway, so performance is not critical, you can do this:
filename="story.txt"
if egrep -wl 'hello' "$filename" 1>/dev/null; then
if egrep -wl 'when' "$filename" 1>/dev/null; then
if egrep -wl 'who' "$filename" 1>/dev/null; then
echo "found all three words"
fi
fi
fi
[Update:]
This second code snippet also checks whether the given file contains all three words. Each of the if clauses checks for one of the words. The option -l (lowercase ell) to egrep makes it potentially faster, but you probably don't need that option at all.
Normally egrep prints all lines that match the given expressions (your three words in this case). Since we don't need that output, we redirect it using the arrow operator > to a special file called /dev/null. Whatever you write into that file is discarded.
The if statement takes another command as its argument, and if that command returns successfully, the then branch is taken. The nice thing about the egrep command is that it returns successfully iff the given search expression is contained in the file, so these two things perfectly fit together.
For further reading you should try the reference documentation from the Open Group website: http://www.google.com/search?q=opengroup+grep

Resources