Cannot insert date into the Oracle databe in Spring Boot via Thymeleaf - spring-boot

Question

I have a typo in my CRUD process. I couldn't handle with inserting date type into the my database named for Oracle 11g.
When I try to insert data, there is an error appeared on the console.
Field error in object 'employee' on field 'registerDate': rejected value [2019-09-11]; codes [typeMismatch.employee.registerDate,typeMismatch.registerDate,typeMismatch.java.util.Date,typeMismatch]; arguments [org.springframework.context.support.DefaultMessageSourceResolvable: codes [employee.registerDate,registerDate]; arguments []; default message [registerDate]]; default message [Failed to convert property value of type 'java.lang.String' to required type 'java.util.Date' for property 'registerDate'; nested exception is org.springframework.core.convert.ConversionFailedException: Failed to convert from type [java.lang.String] to type [#javax.validation.constraints.NotNull #javax.persistence.Temporal #javax.persistence.Column java.util.Date] for value '2019-09-11'; nested exception is java.lang.IllegalArgumentException]
How can I fix it?
Employee Forum
<form action="#" th:action="#{/employees/save}"
th:object="${employee}" method="POST">
...
<input type="date" name="date" th:field="*{registerDate}"
class="form-control mb-4 col-4" placeholder="Register Date">
</form>
Employee Object
#NotNull(message="is required")
#Temporal(TemporalType.DATE)
#Column(name="REGISTER_DATE")
private Date registerDate;
Controller Class
#PostMapping("/save")
public String saveEmployee(#ModelAttribute("employee") Employee theEmployee,#RequestParam("date") String date) throws IOException, ParseException {
// Date
SimpleDateFormat dateformat = new SimpleDateFormat("dd/MM/yyyy");
Date registerDate = dateformat.parse(String.valueOf(date));
System.out.println("/save | registerDate : " + registerDate);
theEmployee.setRegisterDate(registerDate);
// save the employee
employeeService.save(theEmployee);
}

Answer 1

Maybe you need to format the date for Oracle, for example:
#DateTimeFormat(pattern = "hh:mm aa")
#Column(name = "date_start")
private Date dateStart;