word frequency from file using partial match - bash

I have a text file like this:
tom
and
jerry
went
to
america
and
england
I want to get the frequency of each word.
When I tried the following command
sort test.txt|uniq -c
I got the following output
1 america
2 and
1 england
1 jerry
1 to
1 tom
1 went
But I need partial matches too. ie, the word to present in the word tom. So my expected word count of to is 2.
Is it possible using unix commands?

$ cat tst.awk
NR==FNR {
cnt[$1] = 0
next
}
{
for (word in cnt) {
cnt[word] += gsub(word,"&")
}
}
END {
for (word in cnt) {
print word, cnt[word]
}
}
$ awk -f tst.awk file file
went 1
america 1
to 2
and 3
england 1
jerry 1
tom 1
Since you mentioned in a comment about being low on RAM, if you don't have enough RAM to store all unique words from your file in memory at once then do the above in a loop of N (10? 100? 1000?) thousand words at a time, e.g. (bash-like pseudo-code):
sort -u file > tmp
for (( i=1; i<=$(wc -l < tmp); i+=10000 )); do
awk -f tst.awk <(head -n "$i" tmp | tail -n 10000) file
done

Script :
#!/bin/bash
while IFS= read -r word; do
count=`grep -o "${word}" file | wc -l`
echo "${word} : ${count}"
done < file
Output:
tom : 1
and : 3
jerry : 1
went : 1
to : 2
america : 1
and : 3
england : 1

Perl was made for things like this, if you've got it:
$ perl -e '#lines=<>;for $x(#lines){chomp $x;print 0+grep(/$x/,#lines), " $x\n"}' text_file
1 tom
3 and
1 jerry
1 went
2 to
1 america
3 and
1 england
The <> in list context reads all the lines at once into the array.
chomp gets rid of the ending newline.
The 0+ puts grep into scalar context where it evaluates to just the count.

You can invoke grep for every unique word of your file :
while IFS= read -r pattern; do
count="$(grep -o "$pattern" test.txt | wc -l)" # can't use grep -c as it counts lines
printf '%s: %d\n' "$pattern" "$count"
done < <(sort test.txt | uniq)

Related

How can I iterate through text two lines at a time?

I have a text file that I would like to go through and list every count each time a succession of two words appear. For example my desired output would look like this:
Sample input:
I am a man
desired output:
1 I am
1 am a
1 a man
How I thought about doing this is so:
cat $1 | sed "s/ /\n/g" | read word1 &&
while read word2;
do
echo "$word1 $word2";
word1=word2;
done
This gets an infinite loop though. Any help appreciated!
Call read twice in the while condition.
while read line1; read line2; do
echo "$line1 $line2"
done <<EOF
1
a
2
b
EOF
will output
1 a
2 b
The loop exits when the second read fails, even if the first succeeds. If you will want to execute the body (even with an empty line2), move read line2 into the body of the loop.
Assumptions:
counts are accumulated across the entire file (as opposed to restarting the counts for each new line)
word pairs can span lines, eg, one\nword is the same as one word
we're only interested in 2-word pairings, ie, no need to code for a dynamic number of words (eg, 3-words, 4-words)
Sample input data:
$ cat words.dat
I am a man
I am not a man I
am a man
One awk idea:
$ awk -v RS='' ' # treat file as one loooong single record
{ for (i=1;i<NF;i++) # loop through list of fields 1 - (NF-1)
count[$(i)" "$(i+1)]++ # use field i and i+1 as array index
}
END { for (i in count) # loop through array indices
print count[i],i
}
' words.dat
This generates:
2 am a
3 a man
1 am not
3 I am
1 not a
2 man I
NOTE: no sorting requirement was stated otherwise we could pipe the result to sort, or if using GNU awk we may be able to add an appropriate PROCINFO["sorted_in"] statement
OP's original input:
$ awk -v RS='' '{for (i=1;i<NF;i++) count[$(i)" "$(i+1)]++} END {for (i in count) print count[i],i}' <<< "I am a man"
1 am a
1 a man
1 I am
Removing the assumption about dynamic word counts ...
$ awk -v wcnt=2 -v RS='' ' # <word_count> = 2; treat file as one loooong single record
NF>=wcnt { for (i=1;i<=(NF-wcnt+1);i++) { # loop through list of fields 1 - (NF-<word_count>)
pfx=key=""
for (j=0;j<wcnt;j++) { # build count[] index from <word_count> fields
key=key pfx $(j+i)
pfx=" "
}
count[key]++
}
}
END { for (i in count) # loop through array indices
print count[i],i
}
' words.dat
With -v wcnt=2:
2 am a
3 a man
1 am not
3 I am
1 not a
2 man I
With -v wcnt=3:
1 not a man
2 I am a
1 I am not
2 man I am
2 am a man
2 a man I
1 am not a
With -v wcnt=5:
1 I am a man I
1 I am not a man
1 am not a man I
1 am a man I am
1 man I am a man
1 man I am not a
1 a man I am not
1 not a man I am
1 a man I am a
With -v wcnt=3 and awk '...' <<< "I am a man":
1 I am a
1 am a man
With -v wcnt=5 and awk '...' <<< "I am a man":
# no output since less than wcnt=5 words to work with
With bash:
set -f # for slurping in the words of the file, we want word splitting
# but not glob expansion
words=( $(< "$1") )
for ((i = 1; i < ${#words[#]}; i++)); do
printf "%s %s\n" "${words[i-1]}" "${words[i]}"
done
Given #chepner's input file, this outputs
1 a
a 2
2 b
A rewrite of your code: you need a grouping construct so that all the reads are reading from the same pipeline of data.
tr -s '[:space:]' '\n' < "$1" | {
IFS= read -r word1
while IFS= read -r word2; do
echo "$word1 $word2"
word1=$word2
done
}
For counting, the simplest method is to pipe the output into | sort | uniq -c
With the words.dat file from #markp-fuso, output from both these solutions is
3 I am
3 a man
2 am a
1 am not
2 man I
1 not a
The counting can be done in bash using an associative array:
declare -A pairs
for ((i = 1; i < ${#words[#]}; i++)); do
key="${words[i-1]} ${words[i]}"
pairs[$key]=$(( pairs[$key] + 1 ))
done
for key in "${!pairs[#]}"; do
printf "%7d %s\n" "${pairs[$key]}" "$key"
done
1 not a
3 a man
1 am not
2 am a
3 I am
2 man I

Foreach command with table [duplicate]

I have a huge tab-separated file formatted like this
X column1 column2 column3
row1 0 1 2
row2 3 4 5
row3 6 7 8
row4 9 10 11
I would like to transpose it in an efficient way using only bash commands (I could write a ten or so lines Perl script to do that, but it should be slower to execute than the native bash functions). So the output should look like
X row1 row2 row3 row4
column1 0 3 6 9
column2 1 4 7 10
column3 2 5 8 11
I thought of a solution like this
cols=`head -n 1 input | wc -w`
for (( i=1; i <= $cols; i++))
do cut -f $i input | tr $'\n' $'\t' | sed -e "s/\t$/\n/g" >> output
done
But it's slow and doesn't seem the most efficient solution. I've seen a solution for vi in this post, but it's still over-slow. Any thoughts/suggestions/brilliant ideas? :-)
awk '
{
for (i=1; i<=NF; i++) {
a[NR,i] = $i
}
}
NF>p { p = NF }
END {
for(j=1; j<=p; j++) {
str=a[1,j]
for(i=2; i<=NR; i++){
str=str" "a[i,j];
}
print str
}
}' file
output
$ more file
0 1 2
3 4 5
6 7 8
9 10 11
$ ./shell.sh
0 3 6 9
1 4 7 10
2 5 8 11
Performance against Perl solution by Jonathan on a 10000 lines file
$ head -5 file
1 0 1 2
2 3 4 5
3 6 7 8
4 9 10 11
1 0 1 2
$ wc -l < file
10000
$ time perl test.pl file >/dev/null
real 0m0.480s
user 0m0.442s
sys 0m0.026s
$ time awk -f test.awk file >/dev/null
real 0m0.382s
user 0m0.367s
sys 0m0.011s
$ time perl test.pl file >/dev/null
real 0m0.481s
user 0m0.431s
sys 0m0.022s
$ time awk -f test.awk file >/dev/null
real 0m0.390s
user 0m0.370s
sys 0m0.010s
EDIT by Ed Morton (#ghostdog74 feel free to delete if you disapprove).
Maybe this version with some more explicit variable names will help answer some of the questions below and generally clarify what the script is doing. It also uses tabs as the separator which the OP had originally asked for so it'd handle empty fields and it coincidentally pretties-up the output a bit for this particular case.
$ cat tst.awk
BEGIN { FS=OFS="\t" }
{
for (rowNr=1;rowNr<=NF;rowNr++) {
cell[rowNr,NR] = $rowNr
}
maxRows = (NF > maxRows ? NF : maxRows)
maxCols = NR
}
END {
for (rowNr=1;rowNr<=maxRows;rowNr++) {
for (colNr=1;colNr<=maxCols;colNr++) {
printf "%s%s", cell[rowNr,colNr], (colNr < maxCols ? OFS : ORS)
}
}
}
$ awk -f tst.awk file
X row1 row2 row3 row4
column1 0 3 6 9
column2 1 4 7 10
column3 2 5 8 11
The above solutions will work in any awk (except old, broken awk of course - there YMMV).
The above solutions do read the whole file into memory though - if the input files are too large for that then you can do this:
$ cat tst.awk
BEGIN { FS=OFS="\t" }
{ printf "%s%s", (FNR>1 ? OFS : ""), $ARGIND }
ENDFILE {
print ""
if (ARGIND < NF) {
ARGV[ARGC] = FILENAME
ARGC++
}
}
$ awk -f tst.awk file
X row1 row2 row3 row4
column1 0 3 6 9
column2 1 4 7 10
column3 2 5 8 11
which uses almost no memory but reads the input file once per number of fields on a line so it will be much slower than the version that reads the whole file into memory. It also assumes the number of fields is the same on each line and it uses GNU awk for ENDFILE and ARGIND but any awk can do the same with tests on FNR==1 and END.
awk
Gawk version which uses arrays of arrays:
tp(){ awk '{for(i=1;i<=NF;i++)a[i][NR]=$i}END{for(i in a)for(j in a[i])printf"%s"(j==NR?RS:FS),a[i][j]}' "${1+FS=$1}";}
Plain awk version which uses multidimensional arrays (this was about twice as slow in my benchmark):
tp(){ awk '{for(i=1;i<=NF;i++)a[i,NR]=$i}END{for(i=1;i<=NF;i++)for(j=1;j<=NR;j++)printf"%s"(j==NR?RS:FS),a[i,j]}' "${1+FS=$1}";}
macOS comes with a version of Brian Kerningham's nawk from 2007 which doesn't support arrays of arrays.
To use space as a separator without collapsing sequences of multiple spaces, use FS='[ ]'.
rs
rs is a BSD utility which also comes with macOS, but it should be available from package managers on other platforms. It is named after the reshape function in APL.
Use sequences of spaces and tabs as column separator:
rs -T
Use tab as column separator:
rs -c -C -T
Use comma as column separator:
rs -c, -C, -T
-c changes the input column separator and -C changes the output column separator. A lone -c or -C sets the separator to tab. -T transposes rows and columns.
Do not use -t instead of -T, because it automatically selects the number of output columns so that the output lines fill the width of the display (which is 80 characters by default but which can be changed with -w).
When an output column separator is specified using -C, an extra column separator character is added to the end of each row, but you can remove it with sed:
$ seq 4|paste -d, - -|rs -c, -C, -T
1,3,
2,4,
$ seq 4|paste -d, - -|rs -c, -C, -T|sed s/.\$//
1,3
2,4
rs -T determines the number of columns based on the number of columns on the first row, so it produces the wrong result when the first line ends with one or more empty columns:
$ rs -c, -C, -T<<<$'1,\n3,4'
1,3,4,
R
The t function transposes a matrix or dataframe:
Rscript -e 'write.table(t(read.table("stdin",sep=",",quote="",comment.char="")),sep=",",quote=F,col.names=F,row.names=F)'
If you replace Rscript -e with R -e, then it echoes the code that is being run to STDOUT, and it also results in the error ignoring SIGPIPE signal if the R command is followed by a command like head -n1 which exits before it has read the whole STDIN.
quote="" can be removed if the input doesn't contain double quotes or single quotes, and comment.char="" can be removed if the input doesn't contain lines that start with a hash character.
For a big input file, fread and fwrite from data.table are faster than read.table and write.table:
$ seq 1e6|awk 'ORS=NR%1e3?FS:RS'>a
$ time Rscript --no-init-file -e 'write.table(t(read.table("a")),quote=F,col.names=F,row.names=F)'>/dev/null
real 0m1.061s
user 0m0.983s
sys 0m0.074s
$ time Rscript --no-init-file -e 'write.table(t(data.table::fread("a")),quote=F,col.names=F,row.names=F)'>/dev/null
real 0m0.599s
user 0m0.535s
sys 0m0.048s
$ time Rscript --no-init-file -e 'data.table::fwrite(t(data.table::fread("a")),sep=" ",col.names=F)'>t/b
x being coerced from class: matrix to data.table
real 0m0.375s
user 0m0.296s
sys 0m0.073s
jq
tp(){ jq -R .|jq --arg x "${1-$'\t'}" -sr 'map(./$x)|transpose|map(join($x))[]';}
jq -R . prints each input line as a JSON string literal, -s (--slurp) creates an array for the input lines after parsing each line as JSON, and -r (--raw-output) outputs the contents of strings instead of JSON string literals. The / operator is overloaded to split strings.
Ruby
ruby -e'STDIN.map{|x|x.chomp.split(",",-1)}.transpose.each{|x|puts x*","}'
The -1 argument to split disables discarding empty fields at the end:
$ ruby -e'p"a,,".split(",")'
["a"]
$ ruby -e'p"a,,".split(",",-1)'
["a", "", ""]
Function form:
$ tp(){ ruby -e's=ARGV[0];STDIN.map{|x|x.chomp.split(s==" "?/ /:s,-1)}.transpose.each{|x|puts x*s}' -- "${1-$'\t'}";}
$ seq 4|paste -d, - -|tp ,
1,3
2,4
The function above uses s==" "?/ /:s because when the argument to the split function is a single space, it enables awk-like special behavior where strings are split based on contiguous runs of spaces and tabs:
$ ruby -e'p" a \tb ".split(" ",-1)'
["a", "b", ""]
$ ruby -e'p" a \tb ".split(/ /,-1)'
["", "a", "", "\tb", ""]
A Python solution:
python -c "import sys; print('\n'.join(' '.join(c) for c in zip(*(l.split() for l in sys.stdin.readlines() if l.strip()))))" < input > output
The above is based on the following:
import sys
for c in zip(*(l.split() for l in sys.stdin.readlines() if l.strip())):
print(' '.join(c))
This code does assume that every line has the same number of columns (no padding is performed).
Have a look at GNU datamash which can be used like datamash transpose.
A future version will also support cross tabulation (pivot tables)
Here is how you would do it with space separated columns:
datamash transpose -t ' ' < file > transposed_file
the transpose project on sourceforge is a coreutil-like C program for exactly that.
gcc transpose.c -o transpose
./transpose -t input > output #works with stdin, too.
Pure BASH, no additional process. A nice exercise:
declare -a array=( ) # we build a 1-D-array
read -a line < "$1" # read the headline
COLS=${#line[#]} # save number of columns
index=0
while read -a line ; do
for (( COUNTER=0; COUNTER<${#line[#]}; COUNTER++ )); do
array[$index]=${line[$COUNTER]}
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
for (( COUNTER = ROW; COUNTER < ${#array[#]}; COUNTER += COLS )); do
printf "%s\t" ${array[$COUNTER]}
done
printf "\n"
done
GNU datamash is perfectly suited for this problem with only one line of code and potentially arbitrarily large filesize!
datamash -W transpose infile > outfile
There is a purpose built utility for this,
GNU datamash utility
apt install datamash
datamash transpose < yourfile
Taken from this site, https://www.gnu.org/software/datamash/ and http://www.thelinuxrain.com/articles/transposing-rows-and-columns-3-methods
Here is a moderately solid Perl script to do the job. There are many structural analogies with #ghostdog74's awk solution.
#!/bin/perl -w
#
# SO 1729824
use strict;
my(%data); # main storage
my($maxcol) = 0;
my($rownum) = 0;
while (<>)
{
my(#row) = split /\s+/;
my($colnum) = 0;
foreach my $val (#row)
{
$data{$rownum}{$colnum++} = $val;
}
$rownum++;
$maxcol = $colnum if $colnum > $maxcol;
}
my $maxrow = $rownum;
for (my $col = 0; $col < $maxcol; $col++)
{
for (my $row = 0; $row < $maxrow; $row++)
{
printf "%s%s", ($row == 0) ? "" : "\t",
defined $data{$row}{$col} ? $data{$row}{$col} : "";
}
print "\n";
}
With the sample data size, the performance difference between perl and awk was negligible (1 millisecond out of 7 total). With a larger data set (100x100 matrix, entries 6-8 characters each), perl slightly outperformed awk - 0.026s vs 0.042s. Neither is likely to be a problem.
Representative timings for Perl 5.10.1 (32-bit) vs awk (version 20040207 when given '-V') vs gawk 3.1.7 (32-bit) on MacOS X 10.5.8 on a file containing 10,000 lines with 5 columns per line:
Osiris JL: time gawk -f tr.awk xxx > /dev/null
real 0m0.367s
user 0m0.279s
sys 0m0.085s
Osiris JL: time perl -f transpose.pl xxx > /dev/null
real 0m0.138s
user 0m0.128s
sys 0m0.008s
Osiris JL: time awk -f tr.awk xxx > /dev/null
real 0m1.891s
user 0m0.924s
sys 0m0.961s
Osiris-2 JL:
Note that gawk is vastly faster than awk on this machine, but still slower than perl. Clearly, your mileage will vary.
Assuming all your rows have the same number of fields, this awk program solves the problem:
{for (f=1;f<=NF;f++) col[f] = col[f]":"$f} END {for (f=1;f<=NF;f++) print col[f]}
In words, as you loop over the rows, for every field f grow a ':'-separated string col[f] containing the elements of that field. After you are done with all the rows, print each one of those strings in a separate line. You can then substitute ':' for the separator you want (say, a space) by piping the output through tr ':' ' '.
Example:
$ echo "1 2 3\n4 5 6"
1 2 3
4 5 6
$ echo "1 2 3\n4 5 6" | awk '{for (f=1;f<=NF;f++) col[f] = col[f]":"$f} END {for (f=1;f<=NF;f++) print col[f]}' | tr ':' ' '
1 4
2 5
3 6
If you have sc installed, you can do:
psc -r < inputfile | sc -W% - > outputfile
I normally use this little awk snippet for this requirement:
awk '{for (i=1; i<=NF; i++) a[i,NR]=$i
max=(max<NF?NF:max)}
END {for (i=1; i<=max; i++)
{for (j=1; j<=NR; j++)
printf "%s%s", a[i,j], (j==NR?RS:FS)
}
}' file
This just loads all the data into a bidimensional array a[line,column] and then prints it back as a[column,line], so that it transposes the given input.
This needs to keep track of the maximum amount of columns the initial file has, so that it is used as the number of rows to print back.
A hackish perl solution can be like this. It's nice because it doesn't load all the file in memory, prints intermediate temp files, and then uses the all-wonderful paste
#!/usr/bin/perl
use warnings;
use strict;
my $counter;
open INPUT, "<$ARGV[0]" or die ("Unable to open input file!");
while (my $line = <INPUT>) {
chomp $line;
my #array = split ("\t",$line);
open OUTPUT, ">temp$." or die ("unable to open output file!");
print OUTPUT join ("\n",#array);
close OUTPUT;
$counter=$.;
}
close INPUT;
# paste files together
my $execute = "paste ";
foreach (1..$counter) {
$execute.="temp$counter ";
}
$execute.="> $ARGV[1]";
system $execute;
The only improvement I can see to your own example is using awk which will reduce the number of processes that are run and the amount of data that is piped between them:
/bin/rm output 2> /dev/null
cols=`head -n 1 input | wc -w`
for (( i=1; i <= $cols; i++))
do
awk '{printf ("%s%s", tab, $'$i'); tab="\t"} END {print ""}' input
done >> output
Some *nix standard util one-liners, no temp files needed. NB: the OP wanted an efficient fix, (i.e. faster), and the top answers are usually faster than this answer. These one-liners are for those who like *nix software tools, for whatever reasons. In rare cases, (e.g. scarce IO & memory), these snippets can actually be faster than some of the top answers.
Call the input file foo.
If we know foo has four columns:
for f in 1 2 3 4 ; do cut -d ' ' -f $f foo | xargs echo ; done
If we don't know how many columns foo has:
n=$(head -n 1 foo | wc -w)
for f in $(seq 1 $n) ; do cut -d ' ' -f $f foo | xargs echo ; done
xargs has a size limit and therefore would make incomplete work with a long file. What size limit is system dependent, e.g.:
{ timeout '.01' xargs --show-limits ; } 2>&1 | grep Max
Maximum length of command we could actually use: 2088944
tr & echo:
for f in 1 2 3 4; do cut -d ' ' -f $f foo | tr '\n\ ' ' ; echo; done
...or if the # of columns are unknown:
n=$(head -n 1 foo | wc -w)
for f in $(seq 1 $n); do
cut -d ' ' -f $f foo | tr '\n' ' ' ; echo
done
Using set, which like xargs, has similar command line size based limitations:
for f in 1 2 3 4 ; do set - $(cut -d ' ' -f $f foo) ; echo $# ; done
I used fgm's solution (thanks fgm!), but needed to eliminate the tab characters at the end of each row, so modified the script thus:
#!/bin/bash
declare -a array=( ) # we build a 1-D-array
read -a line < "$1" # read the headline
COLS=${#line[#]} # save number of columns
index=0
while read -a line; do
for (( COUNTER=0; COUNTER<${#line[#]}; COUNTER++ )); do
array[$index]=${line[$COUNTER]}
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
for (( COUNTER = ROW; COUNTER < ${#array[#]}; COUNTER += COLS )); do
printf "%s" ${array[$COUNTER]}
if [ $COUNTER -lt $(( ${#array[#]} - $COLS )) ]
then
printf "\t"
fi
done
printf "\n"
done
I was just looking for similar bash tranpose but with support for padding. Here is the script I wrote based on fgm's solution, that seem to work. If it can be of help...
#!/bin/bash
declare -a array=( ) # we build a 1-D-array
declare -a ncols=( ) # we build a 1-D-array containing number of elements of each row
SEPARATOR="\t";
PADDING="";
MAXROWS=0;
index=0
indexCol=0
while read -a line; do
ncols[$indexCol]=${#line[#]};
((indexCol++))
if [ ${#line[#]} -gt ${MAXROWS} ]
then
MAXROWS=${#line[#]}
fi
for (( COUNTER=0; COUNTER<${#line[#]}; COUNTER++ )); do
array[$index]=${line[$COUNTER]}
((index++))
done
done < "$1"
for (( ROW = 0; ROW < MAXROWS; ROW++ )); do
COUNTER=$ROW;
for (( indexCol=0; indexCol < ${#ncols[#]}; indexCol++ )); do
if [ $ROW -ge ${ncols[indexCol]} ]
then
printf $PADDING
else
printf "%s" ${array[$COUNTER]}
fi
if [ $((indexCol+1)) -lt ${#ncols[#]} ]
then
printf $SEPARATOR
fi
COUNTER=$(( COUNTER + ncols[indexCol] ))
done
printf "\n"
done
I was looking for a solution to transpose any kind of matrix (nxn or mxn) with any kind of data (numbers or data) and got the following solution:
Row2Trans=number1
Col2Trans=number2
for ((i=1; $i <= Line2Trans; i++));do
for ((j=1; $j <=Col2Trans ; j++));do
awk -v var1="$i" -v var2="$j" 'BEGIN { FS = "," } ; NR==var1 {print $((var2)) }' $ARCHIVO >> Column_$i
done
done
paste -d',' `ls -mv Column_* | sed 's/,//g'` >> $ARCHIVO
If you only want to grab a single (comma delimited) line $N out of a file and turn it into a column:
head -$N file | tail -1 | tr ',' '\n'
Not very elegant, but this "single-line" command solves the problem quickly:
cols=4; for((i=1;i<=$cols;i++)); do \
awk '{print $'$i'}' input | tr '\n' ' '; echo; \
done
Here cols is the number of columns, where you can replace 4 by head -n 1 input | wc -w.
Another awk solution and limited input with the size of memory you have.
awk '{ for (i=1; i<=NF; i++) RtoC[i]= (RtoC[i]? RtoC[i] FS $i: $i) }
END{ for (i in RtoC) print RtoC[i] }' infile
This joins each same filed number positon into together and in END prints the result that would be first row in first column, second row in second column, etc.
Will output:
X row1 row2 row3 row4
column1 0 3 6 9
column2 1 4 7 10
column3 2 5 8 11
#!/bin/bash
aline="$(head -n 1 file.txt)"
set -- $aline
colNum=$#
#set -x
while read line; do
set -- $line
for i in $(seq $colNum); do
eval col$i="\"\$col$i \$$i\""
done
done < file.txt
for i in $(seq $colNum); do
eval echo \${col$i}
done
another version with set eval
Here is a Bash one-liner that is based on simply converting each line to a column and paste-ing them together:
echo '' > tmp1; \
cat m.txt | while read l ; \
do paste tmp1 <(echo $l | tr -s ' ' \\n) > tmp2; \
cp tmp2 tmp1; \
done; \
cat tmp1
m.txt:
0 1 2
4 5 6
7 8 9
10 11 12
creates tmp1 file so it's not empty.
reads each line and transforms it into a column using tr
pastes the new column to the tmp1 file
copies result back into tmp1.
PS: I really wanted to use io-descriptors but couldn't get them to work.
Another bash variant
$ cat file
XXXX col1 col2 col3
row1 0 1 2
row2 3 4 5
row3 6 7 8
row4 9 10 11
Script
#!/bin/bash
I=0
while read line; do
i=0
for item in $line; { printf -v A$I[$i] $item; ((i++)); }
((I++))
done < file
indexes=$(seq 0 $i)
for i in $indexes; {
J=0
while ((J<I)); do
arr="A$J[$i]"
printf "${!arr}\t"
((J++))
done
echo
}
Output
$ ./test
XXXX row1 row2 row3 row4
col1 0 3 6 9
col2 1 4 7 10
col3 2 5 8 11
I'm a little late to the game but how about this:
cat table.tsv | python -c "import pandas as pd, sys; pd.read_csv(sys.stdin, sep='\t').T.to_csv(sys.stdout, sep='\t')"
or zcat if it's gzipped.
This is assuming you have pandas installed in your version of python
Here's a Haskell solution. When compiled with -O2, it runs slightly faster than ghostdog's awk and slightly slower than Stephan's thinly wrapped c python on my machine for repeated "Hello world" input lines. Unfortunately GHC's support for passing command line code is non-existent as far as I can tell, so you will have to write it to a file yourself. It will truncate the rows to the length of the shortest row.
transpose :: [[a]] -> [[a]]
transpose = foldr (zipWith (:)) (repeat [])
main :: IO ()
main = interact $ unlines . map unwords . transpose . map words . lines
An awk solution that store the whole array in memory
awk '$0!~/^$/{ i++;
split($0,arr,FS);
for (j in arr) {
out[i,j]=arr[j];
if (maxr<j){ maxr=j} # max number of output rows.
}
}
END {
maxc=i # max number of output columns.
for (j=1; j<=maxr; j++) {
for (i=1; i<=maxc; i++) {
printf( "%s:", out[i,j])
}
printf( "%s\n","" )
}
}' infile
But we may "walk" the file as many times as output rows are needed:
#!/bin/bash
maxf="$(awk '{if (mf<NF); mf=NF}; END{print mf}' infile)"
rowcount=maxf
for (( i=1; i<=rowcount; i++ )); do
awk -v i="$i" -F " " '{printf("%s\t ", $i)}' infile
echo
done
Which (for a low count of output rows is faster than the previous code).
A oneliner using R...
cat file | Rscript -e "d <- read.table(file('stdin'), sep=' ', row.names=1, header=T); write.table(t(d), file=stdout(), quote=F, col.names=NA) "
I've used below two scripts to do similar operations before. The first is in awk which is a lot faster than the second which is in "pure" bash. You might be able to adapt it to your own application.
awk '
{
for (i = 1; i <= NF; i++) {
s[i] = s[i]?s[i] FS $i:$i
}
}
END {
for (i in s) {
print s[i]
}
}' file.txt
declare -a arr
while IFS= read -r line
do
i=0
for word in $line
do
[[ ${arr[$i]} ]] && arr[$i]="${arr[$i]} $word" || arr[$i]=$word
((i++))
done
done < file.txt
for ((i=0; i < ${#arr[#]}; i++))
do
echo ${arr[i]}
done
Simple 4 line answer, keep it readable.
col="$(head -1 file.txt | wc -w)"
for i in $(seq 1 $col); do
awk '{ print $'$i' }' file.txt | paste -s -d "\t"
done

Line differences with element location in shell script

Input:
file1.txt
abc 1 2 3 4
file2.txt
abc 1 2 5 6
Expected output:
differences is
3
5
at location 3
I am able to track the differences using:
comm -3 file1.txt file2.txt | uniq -c | awk '{print $4}' | uniq
But not able to track the element location.
Could you guys please suggest the shell script to track the element location?
With perl, and Path::Class from CPAN for convenience
perl -MPath::Class -MList::Util=first -e '
#f1 = split " ", file(shift)->slurp;
#f2 = split " ", file(shift)->slurp;
$idx = first {$f1[$_] ne $f2[$_]} 0..$#f1;
printf "difference is\n%s\n%s\nat index %d\n", $f1[$idx], $f2[$idx], $idx;
' file{1,2}.txt
difference is
3
5
at index 3

Using sed commands on an output to find an average

My goal is to compute the average ping times of a website over the first 10 counts, average over the second 10 counts and average over the last 10 counts and print them in one go using bash scripting.
So far, I have come up with the following script:
ping -c 30 google.com > pings.txt
sed 's/\=/= /g' pings.txt > formatted_op.txt
sed -n '2, 11p' formatted_op.txt > 1.txt
sed -n '12, 22p' formatted_op.txt > 2.txt
sed -n '22, 32p' formatted_op.txt > 3.txt
awk '{print $10}' 1.txt | awk '{ sum += $1 } END {print sum/10}' > 1_avg.txt
awk '{print $10}' 2.txt | awk '{ sum += $1 } END {print sum/10}' > 2_avg.txt
awk '{print $10}' 3.txt | awk '{ sum += $1 } END {print sum/10}' > 3_avg.txt
cat 1_avg.txt 2_avg.txt 3_avg.txt > final_avg.txt
cat final_avg.txt
rm 1.txt 2.txt 3.txt 1_avg.txt 2_avg.txt 3_avg.txt formatted_op.txt pings.txt
However, I want to be able to do this without creating any temporary files. How do I do so?
I have also tried doing it using pipes as follows:
ping -c 30 google.com | sed 's/\=/= /g' | sed -n '2, 11p' | awk '{print $10}'| awk '{ sum += $1 } END {print sum/10}'
but this only computes the average of the first 10 pings and using ping 3 times would give different results each time.
This can all be done with awk pretty easily. Assuming your ping output looks like this:
64 bytes from yyz08s09-in-f110.1e100.net (172.217.1.110): icmp_seq=27 ttl=59 time=0.636 ms
64 bytes from yyz08s09-in-f110.1e100.net (172.217.1.110): icmp_seq=28 ttl=59 time=0.638 ms
64 bytes from yyz08s09-in-f110.1e100.net (172.217.1.110): icmp_seq=29 ttl=59 time=0.658 ms
64 bytes from yyz08s09-in-f110.1e100.net (172.217.1.110): icmp_seq=30 ttl=59 time=0.666 ms
This will do the trick:
ping -c 30 google.com | \
awk '
{
split($8,a,"=");
if(NR > 1 && NR < 12) {
round1+=a[2]
} else if (NR < 22) {
round2+=a[2]
} else if (NR < 32) {
round3+=a[2]
}
}
END {
print round1/10" "round2/10" "round3/10
}
'
We use the NR variable to check which line of output is being processed and then increment the appropriate variable. (The value is gotten by splitting the time field on the equals sign.)
You don't have to make it that complicated. Do something like
for i in {1..10}
do
ping -c 30 google.com | tail -n1 |
awk -v count="$i" -v FS="/" '{print "Count", count,"average : ",$5}'
done
Sample Output
Count 1 average : 78.484
Count 2 average : 74.473
Count 3 average : 76.971
Count 4 average : 78.789
Count 5 average : 103.609
Count 6 average : 105.754
Count 7 average : 98.969
Count 8 average : 99.009
Count 9 average : 86.186
Count 10 average : 86.521
A pure Bash solution is not possible, because Bash has no support for floating point arithmetic. You need at least bc.
In order to calculate an average it is not necessary to collect and store all values. You can calculate the average incrementally. See here or here for the mathematics or read Volume 2 of Donald Knuth's "The Art of Computer Programming". The formula as a Bash function might look like this:
avg ()
{
local a=$1 # average of the values already seen in the past
local x=$2 # new sample
local n=$3 # sequence number
bc -l <<<"$a + ($x - $a) / $n"
}
A single ping time can be collected by the following function.
pingtime ()
{
ping -c1 ${host:-localhost} |
sed -n 's/.*time=\(.*\) .*/\1/p'
}
With the above functions the calculation of n average values with m samples for each average can be done with two for loops.
n=3
m=10
for i in $(seq $n); do
a=
for j in $(seq $m); do
t=$(pingtime)
if [ -z "$a" ]; then
a=$t
else
a=$(avg $a $t $j)
fi
done
LC_NUMERIC=C printf '%2g\n' $a
done
In the outer loop the average a is first cleared. In the inner loop the ping time is measured. If the average is empty it is initialized with the first sample. Otherwise the average is calculated. And the result is reported in the outer loop.
bc and printf behave differently depending on the localization. If necessary a specific behavior can be forced by setting LC_NUMERIC.
If you wish you can add a sleep 1 in front of the ping, to measure only one sample per second.
You can also try my solution
#!/bin/bash
pings=10
for i in {1..10};
do
ping -c ${pings} google.pl | grep -o 'time=.*' | sed 's/time=\(.*\) ms/\1/g' | awk -v iteration="$i" -v pings="$pings" '{sum+=$1+$2+$3} END {print "Iteration " iteration " Average time " sum/pings}'
done

Reorder lines of file by given sequence

I have a document A which contains n lines. I also have a sequence of n integers all of which are unique and <n. My goal is to create a document B which has the same contents as A, but with reordered lines, based on the given sequence.
Example:
A:
Foo
Bar
Bat
sequence: 2,0,1 (meaning: First line 2, then line 0, then line 1)
Output (B):
Bat
Foo
Bar
Thanks in advance for the help
Another solution:
You can create a sequence file by doing (assuming sequence is comma delimited):
echo $sequence | sed s/,/\\n/g > seq.txt
Then, just do:
paste seq.txt A.txt | sort tmp2.txt | sed "s/^[0-9]*\s//"
Here's a bash function. The order can be delimited by anything.
Usage: schwartzianTransform "A.txt" 2 0 1
function schwartzianTransform {
local file="$1"
shift
local sequence="$#"
echo -n "$sequence" | sed 's/[^[:digit:]][^[:digit:]]*/\
/g' | paste -d ' ' - "$file" | sort -n | sed 's/^[[:digit:]]* //'
}
Read the file into an array and then use the power of indexing :
echo "Enter the input file name"
read ip
index=0
while read line ; do
NAME[$index]="$line"
index=$(($index+1))
done < $ip
echo "Enter the file having order"
read od
while read line ; do
echo "${NAME[$line]}";
done < $od
[aman#aman sh]$ cat test
Foo
Bar
Bat
[aman#aman sh]$ cat od
2
0
1
[aman#aman sh]$ ./order.sh
Enter the input file name
test
Enter the file having order
od
Bat
Foo
Bar
an awk oneliner could do the job:
awk -vs="$s" '{d[NR-1]=$0}END{split(s,a,",");for(i=1;i<=length(a);i++)print d[a[i]]}' file
$s is your sequence.
take a look this example:
kent$ seq 10 >file #get a 10 lines file
kent$ s=$(seq 0 9 |shuf|tr '\n' ','|sed 's/,$//') # get a random sequence by shuf
kent$ echo $s #check the sequence in var $s
7,9,1,0,5,4,3,8,6,2
kent$ awk -vs="$s" '{d[NR-1]=$0}END{split(s,a,",");for(i=1;i<=length(a);i++)print d[a[i]]}' file
8
10
2
1
6
5
4
9
7
3
One way(not an efficient one though for big files):
$ seq="2 0 1"
$ for i in $seq
> do
> awk -v l="$i" 'NR==l+1' file
> done
Bat
Foo
Bar
If your file is a big one, you can use this one:
$ seq='2,0,1'
$ x=$(echo $seq | awk '{printf "%dp;", $0+1;print $0+1> "tn.txt"}' RS=,)
$ sed -n "$x" file | awk 'NR==FNR{a[++i]=$0;next}{print a[$0]}' - tn.txt
The 2nd line prepares a sed command print instruction, which is then used in the 3rd line with the sed command. This prints only the line numbers present in the sequence, but not in the order of the sequence. The awk command is used to order the sed result depending on the sequence.

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