passing arguments in graphQL queries - graphql

Question

I'm just starting to learn GraphQL and I'm currently trying to create a clone of twitter. In the code below, is there a way I can pass the 81 from the id argument (e.g. user(id: 81)) automatically to the userId argument (e.g. tweets(userId: 81))?
I've copied my code below
{
user(id: 81) {
username
email
tweets(userId: 81) {
content
}
}
}
user_type.rb
module Types
class UserType < Types::BaseObject
field :username, String, null: false
field :email, String, null: false
field :bio, String, null: true
field :tweets, [Types::TweetType], null: true do
argument :user_id, ID, required: true
end
def tweets(user_id:)
Tweet.where(user_id: user_id)
end
end
end
tweet_type.rb
module Types
class TweetType < Types::BaseObject
field :id, ID, null: false
field :content, String, null: false
field :userId, ID, null: false
field :createdAt, GraphQL::Types::ISO8601DateTime, null: false
field :user, Types::UserType, null: false
end
end
query_type.rb
module Types
class QueryType < Types::BaseObject
field :tweets,
[Types::TweetType],
null: false,
description: "Returns a list of all tweets"
field :user,
Types::UserType,
null: false,
description: "Returns a list of all users" do
argument :id, ID, required: true
end
def tweets
Tweet.all
end
def user(id:)
User.find(id)
end
end
end

Answer 1

GraphQL has a first-class way to factor dynamic values out of the query, and pass them as a separate dictionary (variables). You would use syntax similar to that below, and can read more about it here.
query User($id: Int) {
user(id: $id) {
username
email
tweets(userId: $id) {
content
}
}
}