I am new to bash scripting and I am trying to understand the following line:
# Verify pre-req environment
command -v kubectl > /dev/null 2>&1 || { echo "kubectl pre-req is missing."; exit 1; }
I unerstand this part: command -v kubectl > /dev/null 2>&1 so if it fails or not we redirect the output to /dev/null in which if I understand it correctly means ignore it in all cases. So in what cases the following line will be executed then?
{ echo "kubectl pre-req is missing."; exit 1; }
and how || behaves in this case?
|| is used for OR condition in bash.
For a simplified example lets look at
cmd1 || cmd2
What happens is that if cmd1 succeeds (i.e. exit code 0), then cmd2 will NOT be performed. cmd2 will only be performed if cmd1 fails.
This is one reason why returning exit codes is so important.
For more details, please look at this post: Boolean operators ( &&, -a, ||, -o ) in Bash
I unerstand this part: command -v kubectl > /dev/null 2>&1 so if it fails or not we redirect the output to /dev/null in which if I understand it correctly means ignore it in all cases.
You've misunderstood that; no part of command -v kubectl > /dev/null 2>&1 has any connection to "if it fails" vs. "not".
Rather, > and 2> redirect two different types of output; > (or 1>) redirects whatever the command writes to standard output, and 2> redirects whatever the command writes to standard error. Whether the command writes anything to standard output is independent of whether it ends up succeeding or failing; whether it writes anything to standard error is independent of whether it ends up succeeding or failing; and whether it writes anything to standard output is independent of whether it writes anything to standard error.
For example, here is a command that prints to both standard output and standard error, and then returns successfully:
( echo "this is on standard output" ; echo "this is on standard error" >&2 ; exit 0 )
and here is one that prints to both standard output and standard error, and then fails:
( echo "this is on standard output" ; echo "this is on standard error" >&2 ; exit 1 )
By contrast, || really does have to do with whether a command succeeds (exiting with zero) or fails (exiting with something other than zero).
If the kubectl command exits with a non-zero exit status, the code after the || will be executed.
$ sh -c 'exit 42' && echo "exit status zero" || echo "exit status non-zero"
exit status non-zero
$ sh -c 'exit 0' && echo "exit status zero" || echo "exit status non-zero"
exit status zero
|| is a logic or and acts based on previous command exit code (0 means true and other value is false).
In this case, it will only execute the echo part when the first command (kubectl..) exit code is not 0 (i.e: fails). The exit 1 is to make the whole command fail, otherwise the exit code would be 0 from echo command.
Related
I have a Bash shell script that invokes a number of commands.
I would like to have the shell script automatically exit with a return value of 1 if any of the commands return a non-zero value.
Is this possible without explicitly checking the result of each command?
For example,
dosomething1
if [[ $? -ne 0 ]]; then
exit 1
fi
dosomething2
if [[ $? -ne 0 ]]; then
exit 1
fi
Add this to the beginning of the script:
set -e
This will cause the shell to exit immediately if a simple command exits with a nonzero exit value. A simple command is any command not part of an if, while, or until test, or part of an && or || list.
See the bash manual on the "set" internal command for more details.
It's really annoying to have a script stubbornly continue when something fails in the middle and breaks assumptions for the rest of the script. I personally start almost all portable shell scripts with set -e.
If I'm working with bash specifically, I'll start with
set -Eeuo pipefail
This covers more error handling in a similar fashion. I consider these as sane defaults for new bash programs. Refer to the bash manual for more information on what these options do.
To add to the accepted answer:
Bear in mind that set -e sometimes is not enough, specially if you have pipes.
For example, suppose you have this script
#!/bin/bash
set -e
./configure > configure.log
make
... which works as expected: an error in configure aborts the execution.
Tomorrow you make a seemingly trivial change:
#!/bin/bash
set -e
./configure | tee configure.log
make
... and now it does not work. This is explained here, and a workaround (Bash only) is provided:
#!/bin/bash
set -e
set -o pipefail
./configure | tee configure.log
make
The if statements in your example are unnecessary. Just do it like this:
dosomething1 || exit 1
If you take Ville Laurikari's advice and use set -e then for some commands you may need to use this:
dosomething || true
The || true will make the command pipeline have a true return value even if the command fails so the the -e option will not kill the script.
If you have cleanup you need to do on exit, you can also use 'trap' with the pseudo-signal ERR. This works the same way as trapping INT or any other signal; bash throws ERR if any command exits with a nonzero value:
# Create the trap with
# trap COMMAND SIGNAME [SIGNAME2 SIGNAME3...]
trap "rm -f /tmp/$MYTMPFILE; exit 1" ERR INT TERM
command1
command2
command3
# Partially turn off the trap.
trap - ERR
# Now a control-C will still cause cleanup, but
# a nonzero exit code won't:
ps aux | grep blahblahblah
Or, especially if you're using "set -e", you could trap EXIT; your trap will then be executed when the script exits for any reason, including a normal end, interrupts, an exit caused by the -e option, etc.
The $? variable is rarely needed. The pseudo-idiom command; if [ $? -eq 0 ]; then X; fi should always be written as if command; then X; fi.
The cases where $? is required is when it needs to be checked against multiple values:
command
case $? in
(0) X;;
(1) Y;;
(2) Z;;
esac
or when $? needs to be reused or otherwise manipulated:
if command; then
echo "command successful" >&2
else
ret=$?
echo "command failed with exit code $ret" >&2
exit $ret
fi
Run it with -e or set -e at the top.
Also look at set -u.
On error, the below script will print a RED error message and exit.
Put this at the top of your bash script:
# BASH error handling:
# exit on command failure
set -e
# keep track of the last executed command
trap 'LAST_COMMAND=$CURRENT_COMMAND; CURRENT_COMMAND=$BASH_COMMAND' DEBUG
# on error: print the failed command
trap 'ERROR_CODE=$?; FAILED_COMMAND=$LAST_COMMAND; tput setaf 1; echo "ERROR: command \"$FAILED_COMMAND\" failed with exit code $ERROR_CODE"; put sgr0;' ERR INT TERM
An expression like
dosomething1 && dosomething2 && dosomething3
will stop processing when one of the commands returns with a non-zero value. For example, the following command will never print "done":
cat nosuchfile && echo "done"
echo $?
1
#!/bin/bash -e
should suffice.
I am just throwing in another one for reference since there was an additional question to Mark Edgars input and here is an additional example and touches on the topic overall:
[[ `cmd` ]] && echo success_else_silence
Which is the same as cmd || exit errcode as someone showed.
For example, I want to make sure a partition is unmounted if mounted:
[[ `mount | grep /dev/sda1` ]] && umount /dev/sda1
I have a Bash shell script that invokes a number of commands.
I would like to have the shell script automatically exit with a return value of 1 if any of the commands return a non-zero value.
Is this possible without explicitly checking the result of each command?
For example,
dosomething1
if [[ $? -ne 0 ]]; then
exit 1
fi
dosomething2
if [[ $? -ne 0 ]]; then
exit 1
fi
Add this to the beginning of the script:
set -e
This will cause the shell to exit immediately if a simple command exits with a nonzero exit value. A simple command is any command not part of an if, while, or until test, or part of an && or || list.
See the bash manual on the "set" internal command for more details.
It's really annoying to have a script stubbornly continue when something fails in the middle and breaks assumptions for the rest of the script. I personally start almost all portable shell scripts with set -e.
If I'm working with bash specifically, I'll start with
set -Eeuo pipefail
This covers more error handling in a similar fashion. I consider these as sane defaults for new bash programs. Refer to the bash manual for more information on what these options do.
To add to the accepted answer:
Bear in mind that set -e sometimes is not enough, specially if you have pipes.
For example, suppose you have this script
#!/bin/bash
set -e
./configure > configure.log
make
... which works as expected: an error in configure aborts the execution.
Tomorrow you make a seemingly trivial change:
#!/bin/bash
set -e
./configure | tee configure.log
make
... and now it does not work. This is explained here, and a workaround (Bash only) is provided:
#!/bin/bash
set -e
set -o pipefail
./configure | tee configure.log
make
The if statements in your example are unnecessary. Just do it like this:
dosomething1 || exit 1
If you take Ville Laurikari's advice and use set -e then for some commands you may need to use this:
dosomething || true
The || true will make the command pipeline have a true return value even if the command fails so the the -e option will not kill the script.
If you have cleanup you need to do on exit, you can also use 'trap' with the pseudo-signal ERR. This works the same way as trapping INT or any other signal; bash throws ERR if any command exits with a nonzero value:
# Create the trap with
# trap COMMAND SIGNAME [SIGNAME2 SIGNAME3...]
trap "rm -f /tmp/$MYTMPFILE; exit 1" ERR INT TERM
command1
command2
command3
# Partially turn off the trap.
trap - ERR
# Now a control-C will still cause cleanup, but
# a nonzero exit code won't:
ps aux | grep blahblahblah
Or, especially if you're using "set -e", you could trap EXIT; your trap will then be executed when the script exits for any reason, including a normal end, interrupts, an exit caused by the -e option, etc.
The $? variable is rarely needed. The pseudo-idiom command; if [ $? -eq 0 ]; then X; fi should always be written as if command; then X; fi.
The cases where $? is required is when it needs to be checked against multiple values:
command
case $? in
(0) X;;
(1) Y;;
(2) Z;;
esac
or when $? needs to be reused or otherwise manipulated:
if command; then
echo "command successful" >&2
else
ret=$?
echo "command failed with exit code $ret" >&2
exit $ret
fi
Run it with -e or set -e at the top.
Also look at set -u.
On error, the below script will print a RED error message and exit.
Put this at the top of your bash script:
# BASH error handling:
# exit on command failure
set -e
# keep track of the last executed command
trap 'LAST_COMMAND=$CURRENT_COMMAND; CURRENT_COMMAND=$BASH_COMMAND' DEBUG
# on error: print the failed command
trap 'ERROR_CODE=$?; FAILED_COMMAND=$LAST_COMMAND; tput setaf 1; echo "ERROR: command \"$FAILED_COMMAND\" failed with exit code $ERROR_CODE"; put sgr0;' ERR INT TERM
An expression like
dosomething1 && dosomething2 && dosomething3
will stop processing when one of the commands returns with a non-zero value. For example, the following command will never print "done":
cat nosuchfile && echo "done"
echo $?
1
#!/bin/bash -e
should suffice.
I am just throwing in another one for reference since there was an additional question to Mark Edgars input and here is an additional example and touches on the topic overall:
[[ `cmd` ]] && echo success_else_silence
Which is the same as cmd || exit errcode as someone showed.
For example, I want to make sure a partition is unmounted if mounted:
[[ `mount | grep /dev/sda1` ]] && umount /dev/sda1
I currently have a script that does something like
./a | ./b | ./c
I want to modify it so that if any of a, b, or c exit with an error code I print an error message and stop instead of piping bad output forward.
What would be the simplest/cleanest way to do so?
In bash you can use set -e and set -o pipefail at the beginning of your file. A subsequent command ./a | ./b | ./c will fail when any of the three scripts fails. The return code will be the return code of the first failed script.
Note that pipefail isn't available in standard sh.
You can also check the ${PIPESTATUS[]} array after the full execution, e.g. if you run:
./a | ./b | ./c
Then ${PIPESTATUS} will be an array of error codes from each command in the pipe, so if the middle command failed, echo ${PIPESTATUS[#]} would contain something like:
0 1 0
and something like this run after the command:
test ${PIPESTATUS[0]} -eq 0 -a ${PIPESTATUS[1]} -eq 0 -a ${PIPESTATUS[2]} -eq 0
will allow you to check that all commands in the pipe succeeded.
If you really don't want the second command to proceed until the first is known to be successful, then you probably need to use temporary files. The simple version of that is:
tmp=${TMPDIR:-/tmp}/mine.$$
if ./a > $tmp.1
then
if ./b <$tmp.1 >$tmp.2
then
if ./c <$tmp.2
then : OK
else echo "./c failed" 1>&2
fi
else echo "./b failed" 1>&2
fi
else echo "./a failed" 1>&2
fi
rm -f $tmp.[12]
The '1>&2' redirection can also be abbreviated '>&2'; however, an old version of the MKS shell mishandled the error redirection without the preceding '1' so I've used that unambiguous notation for reliability for ages.
This leaks files if you interrupt something. Bomb-proof (more or less) shell programming uses:
tmp=${TMPDIR:-/tmp}/mine.$$
trap 'rm -f $tmp.[12]; exit 1' 0 1 2 3 13 15
...if statement as before...
rm -f $tmp.[12]
trap 0 1 2 3 13 15
The first trap line says 'run the commands 'rm -f $tmp.[12]; exit 1' when any of the signals 1 SIGHUP, 2 SIGINT, 3 SIGQUIT, 13 SIGPIPE, or 15 SIGTERM occur, or 0 (when the shell exits for any reason).
If you're writing a shell script, the final trap only needs to remove the trap on 0, which is the shell exit trap (you can leave the other signals in place since the process is about to terminate anyway).
In the original pipeline, it is feasible for 'c' to be reading data from 'b' before 'a' has finished - this is usually desirable (it gives multiple cores work to do, for example). If 'b' is a 'sort' phase, then this won't apply - 'b' has to see all its input before it can generate any of its output.
If you want to detect which command(s) fail, you can use:
(./a || echo "./a exited with $?" 1>&2) |
(./b || echo "./b exited with $?" 1>&2) |
(./c || echo "./c exited with $?" 1>&2)
This is simple and symmetric - it is trivial to extend to a 4-part or N-part pipeline.
Simple experimentation with 'set -e' didn't help.
Unfortunately, the answer by Johnathan requires temporary files and the answers by Michel and Imron requires bash (even though this question is tagged shell). As pointed out by others already, it is not possible to abort the pipe before later processes are started. All processes are started at once and will thus all run before any errors can be communicated. But the title of the question was also asking about error codes. These can be retrieved and investigated after the pipe finished to figure out whether any of the involved processes failed.
Here is a solution that catches all errors in the pipe and not only errors of the last component. So this is like bash's pipefail, just more powerful in the sense that you can retrieve all the error codes.
res=$( (./a 2>&1 || echo "1st failed with $?" >&2) |
(./b 2>&1 || echo "2nd failed with $?" >&2) |
(./c 2>&1 || echo "3rd failed with $?" >&2) > /dev/null 2>&1)
if [ -n "$res" ]; then
echo pipe failed
fi
To detect whether anything failed, an echo command prints on standard error in case any command fails. Then the combined standard error output is saved in $res and investigated later. This is also why standard error of all processes is redirected to standard output. You can also send that output to /dev/null or leave it as yet another indicator that something went wrong. You can replace the last redirect to /dev/null with a file if yo uneed to store the output of the last command anywhere.
To play more with this construct and to convince yourself that this really does what it should, I replaced ./a, ./b and ./c by subshells which execute echo, cat and exit. You can use this to check that this construct really forwards all the output from one process to another and that the error codes get recorded correctly.
res=$( (sh -c "echo 1st out; exit 0" 2>&1 || echo "1st failed with $?" >&2) |
(sh -c "cat; echo 2nd out; exit 0" 2>&1 || echo "2nd failed with $?" >&2) |
(sh -c "echo start; cat; echo end; exit 0" 2>&1 || echo "3rd failed with $?" >&2) > /dev/null 2>&1)
if [ -n "$res" ]; then
echo pipe failed
fi
This answer is in the spirit of the accepted answer, but using shell variables instead of temporary files.
if TMP_A="$(./a)"
then
if TMP_B="$(echo "TMP_A" | ./b)"
then
if TMP_C="$(echo "TMP_B" | ./c)"
then
echo "$TMP_C"
else
echo "./c failed"
fi
else
echo "./b failed"
fi
else
echo "./a failed"
fi
This question already has answers here:
Aborting a shell script if any command returns a non-zero value
(10 answers)
Closed 1 year ago.
I am a noob in shell-scripting. I want to print a message and exit my script if a command fails. I've tried:
my_command && (echo 'my_command failed; exit)
but it does not work. It keeps executing the instructions following this line in the script. I'm using Ubuntu and bash.
Try:
my_command || { echo 'my_command failed' ; exit 1; }
Four changes:
Change && to ||
Use { } in place of ( )
Introduce ; after exit and
spaces after { and before }
Since you want to print the message and exit only when the command fails ( exits with non-zero value) you need a || not an &&.
cmd1 && cmd2
will run cmd2 when cmd1 succeeds(exit value 0). Where as
cmd1 || cmd2
will run cmd2 when cmd1 fails(exit value non-zero).
Using ( ) makes the command inside them run in a sub-shell and calling a exit from there causes you to exit the sub-shell and not your original shell, hence execution continues in your original shell.
To overcome this use { }
The last two changes are required by bash.
The other answers have covered the direct question well, but you may also be interested in using set -e. With that, any command that fails (outside of specific contexts like if tests) will cause the script to abort. For certain scripts, it's very useful.
If you want that behavior for all commands in your script, just add
set -e
set -o pipefail
at the beginning of the script. This pair of options tell the bash interpreter to exit whenever a command returns with a non-zero exit code. (For more details about why pipefail is needed, see http://petereisentraut.blogspot.com/2010/11/pipefail.html)
This does not allow you to print an exit message, though.
Note also, each command's exit status is stored in the shell variable $?, which you can check immediately after running the command. A non-zero status indicates failure:
my_command
if [ $? -eq 0 ]
then
echo "it worked"
else
echo "it failed"
fi
I've hacked up the following idiom:
echo "Generating from IDL..."
idlj -fclient -td java/src echo.idl
if [ $? -ne 0 ]; then { echo "Failed, aborting." ; exit 1; } fi
echo "Compiling classes..."
javac *java
if [ $? -ne 0 ]; then { echo "Failed, aborting." ; exit 1; } fi
echo "Done."
Precede each command with an informative echo, and follow each command with that same
if [ $? -ne 0 ];... line. (Of course, you can edit that error message if you want to.)
Provided my_command is canonically designed, ie returns 0 when succeeds, then && is exactly the opposite of what you want. You want ||.
Also note that ( does not seem right to me in bash, but I cannot try from where I am. Tell me.
my_command || {
echo 'my_command failed' ;
exit 1;
}
You can also use, if you want to preserve exit error status, and have a readable file with one command per line:
my_command1 || exit
my_command2 || exit
This, however will not print any additional error message. But in some cases, the error will be printed by the failed command anyway.
The trap shell builtin allows catching signals, and other useful conditions, including failed command execution (i.e., a non-zero return status). So if you don't want to explicitly test return status of every single command you can say trap "your shell code" ERR and the shell code will be executed any time a command returns a non-zero status. For example:
trap "echo script failed; exit 1" ERR
Note that as with other cases of catching failed commands, pipelines need special treatment; the above won't catch false | true.
Using exit directly may be tricky as the script may be sourced from other places (e.g. from terminal). I prefer instead using subshell with set -e (plus errors should go into cerr, not cout) :
set -e
ERRCODE=0
my_command || ERRCODE=$?
test $ERRCODE == 0 ||
(>&2 echo "My command failed ($ERRCODE)"; exit $ERRCODE)
I have a bash script having the following command
rm ${thefile}
In order to ensure the command is execute successfully, I use $? variable to check on the status, but this variable doesn't show the exact error? To do this, I redirect the standard error output to a log file using following command:
rm ${file} >> ${LOG_FILE} 2>&1
With this command I can't use $? variable to check status on the rm command because the command behind the rm command is executed successfully, thus $? variable is kind of useless here.
May I know is there a solution that could combine both features where I'm able to check on the status of rm command and at mean time I'm allow to redirect the output?
With this command I can't use $? variable to check status on the rm command because the command behind the rm command is executed successfully, thus $? variable is kind of useless here.
That is simply not true. All of the redirections are part of a single command, and $? contains its exit status.
What you may be thinking of is cases where you have multiple commands arranged in a pipeline:
command-1 | command-2
When you do that, $? is set to the exit status of the last command in the pipeline (in this case command-2), and you need to use the PIPESTATUS array to get the exit status of other commands. (In this example ${PIPESTATUS[0]} is the exit status of command-1 and ${PIPESTATUS[1]} is equivalent to $?.)
What you probably need is the shell option pipefail in bash (from man bash):
The return status of a pipeline is the exit status of the last command, unless
the pipefail option is enabled. If pipefail is enabled, the pipeline's return
status is the value of the last (rightmost) command to exit with a non-zero sta‐
tus, or zero if all commands exit successfully. If the reserved word ! precedes
a pipeline, the exit status of that pipeline is the logical negation of the exit
status as described above. The shell waits for all commands in the pipeline to
terminate before returning a value.
> shopt -s -o pipefail
> true | false
> echo $?
1
> false | true
> echo $?
1
true | true
echo $?
0