Pass a path to the "." source in a makefile - bash

Question

In a directory I have a config file with my db variables.
This file (db/database.ini) looks like this:
[PostgreSQL]
host=localhost
database=...
user=postgres
password=...
I have another file (db/create_stmts.sql) where I have all my raw create table statements, and i am trying to experiment the use of a Makefile to have a command like this:
make create-db from_file=db/create_stmts.sql
In order not to repeat myself, I thought of tailing the variables of db/database.ini to a file which I would then source, creating shell variables to pass to psql in the make file.
Here's my plan:
make-db:
# from_file: path to .sql file with all create statements to create the database where to insert
# how to run: make create-db from_file={insert path to sql file}
file_path=$(PWD)/file.sh
tail -n4 db/database.ini > file.sh && . $(file_path)
# -U: --user
# -d: --database
# -q: --quiet
# -f: --file
psql -U $(user) -d $(database) -q -f $(from_file) && rm file.sh
Which I run by: make create-db from_file=db/create_stmts.sql
Which gives me this message - from which i kindof understand that the sourcing just did not work.
#from_file: path to .sql file with all create statements to create the database where to insert
# how to run: make create-db from_file={insert path to sql file}
file_path=/home/gabriele/Desktop/TIUK/companies-house/file.sh
tail -n4 db/database.ini > file.sh && .
# -U: --user
# -d: --database
# -q: --quiet
# -f: --file
psql -U -d -q -f db/schema_tables.sql && rm file.sh
psql: FATAL: Peer authentication failed for user "-d"
Makefile:3: recipe for target 'create-db' failed
make: *** [create-db] Error 2
Any help?

Answer 1

Another solution, perhaps simpler to understand:
make-db:
file_path=$$PWD/file.sh; \
tail -n4 db/database.ini > file.sh && . $$file_path; \
psql -U $$user -d $$database -q -f $$from_file && rm file.sh
Note using ; and \ to convince make to run all commands in a single shell, and using $$ to escape the $ and use shell variable references.

Answer 2

The error is in the text, namely
psql -U -d -q -f db/schema_tables.sql && rm file.sh
This happens because the variables $(user) and $(database) aren't set. Every line within a target is executed in a sub shell. There is now way to use source like you would in a regular script.
You could create a file named database.mk in which you define these variables and use include database.mk at the top of your makefile to include them:
Makefile
CONFILE ?= database
include $(CONFILE).mk
test:
#echo $(user)
#echo $(database)
database.mk
user := user
database := data
If you want to parse the ini file you could do that as such
CONFILE := db/database.ini
make-db: _setup_con
echo $(user) $(database)
# your target
_setup_con:
$(eval user=$(shell grep "user=" $(CONFILE) | grep -Eo "[^=]*$$"))
$(eval database=$(shell grep "database=" $(CONFILE) | grep -Eo "[^=]*$$"))
# and so forward

Answer 3

I would make it more Make-way by using feature of automatic Makefile generation. Given that a configuration file is a simple properties file, its syntax is easily parseable by Make, it's sufficient to just get the lines with variables, i.e.:
include database.mk
database.mk: db/database.ini
grep -E '^\w+=\w+$$' $< > $#
.PHONY: create-db
create-db: $(from_file)
psql -U $(user) -d $(database) -q -f $<
Some additional notes:
create-db should be made .PHONY to avoid situation when nothing is done due to somebody creating (accidentally or not) a file named create-db,
by making create-db depending on from_file one can get a clean and readable error from make that a file does not exist instead of possibly cryptic error later.