JPA entity relationship dependent on other field - spring-boot

My database has a table that represents the common fields between a bunch of other things. So lets say there's one table like Vehicle and then Vehicle has fields like VIN, color, type...
Then there are other tables like Car and Truck and when the "type" on the Vehicle is "car" we want to look at the Car table to find other properties. Maybe stuff about fuelEfficiency and numPassengers. When type is "truck" we want to know things about trucks like maybe loadCapacity or whatever.
How do you model something like this? Do you Embed the Vehicle into all of the other types? Is there a way to do like a #OneToOne between the tables conditionally on the "type" field?

You could use a MappedSuperClass or a JoinedTable strategy, if you want to follow the real ORM way of doing this. But it comes with a cost. There are other overheads, such as querying restrictions and more joins per query etc that comes with these strategies.
If you denormalize the tables, you could use a datafilter strategy (only hibernate supports I think). But now you have everything in a single class and that could be a bigger problem to deal with.
Since you are using REST, you are probably looking to cater /api/vehicles/1 (correct me pls)
For such scenarios, it is easier to perform this using a "Vehicle" table which contains the "type" in it. You can use a jackson serializer to omit all non-null components. So in the case of a car, vehicle attributes and car parameters will come in, but null values on truck, bus etc will be omitted.

Related

Should I create three models or a polymorphic type

I have a Laravel 8 application and am wondering how to solve the problem of how to solve a typical polymorphic issue. I have an Employee model. That Employee can be an ExecutiveEmployee or EntryLevelEmployee. There will be methods an ExecutiveEmployee has that an EntryLevelEmployee doesn't have and the inverse is also true.
Using Laravel 8, is it right to create a base Employee model (without a corresponding table?) and then create two models named ExecutiveEmployee and EntryLevelEmployee that inherit from Employee? This would also imply that both employee types will have two different database tables, even though there will be a lot of overlapping data.
Does it make sense to just have one Employee model and create a migration that has the employee type listed in the model? I am assuming that it's ok if an EntryLevelEmployee has some database attributes which are relevant to it that may or may not be relevant to an ExecutiveEmployee type here, or is that an incorrect assumption?
What's the correct way to model this in Laravel 8? I prefer to keep everything in one table because of how similar the models are. I do have to keep in mind that there will be data that one has that the other doesn't. There will be different accessor methods as well.
Is it possible to have everything in one employees table while utilizing multiple models? Meaning, if I create two models named ExecutiveEmployee and EntryLevelEmployee they would both query the underlying table employees?
UPDATE 1
The more I research, the more I think polymorphism is the incorrect approach here and what I might need is Single-Table Inheritance. This package seems to bring the capability to Eloquent. Would there be a good reason to not use this?
I would use polymorphic relationships in this case, because you are more flexible and have less coupling.
Using the Single Table Inheritance (STI), you can add type specific columns in the employees table and make them nullable. But think about adding/removing types in the future.
executive_employees
id - integer
executive_specific - string
entry_level_employees
id - integer
entry_level_specific - string
employees
id - integer
name - string
email - string
employable_id - integer
employable_type - string
As for the STI the same would be
employees
id - integer
name - string
email - string
type - string
executive_specific - nullable string
entry_level_specific - nullable string
So STI would be suitable when you don't have type specific columns. But you want to add specific behavior in your code. For example a User type (Admin, Author).
Even so, it's a matter of preferences.
It really depends on the state and behavior of your employee object.
Below are few points I will consider to make a decision
If your objects' states/properties are different then definitely you will create different models as your data will be stored in different tables.
If most states/properties are same and some are different, you can
consider storing all in one table/model and for the difference in
behavior create separate table like Ron Van Der Heijden has
suggested and you can consider query scope with that to make
transaction with database.
And another view will be
How many JOINs you will create if you will create different tables,
will that impact the performance and other stuffs, will it make your
code complex?
Can you make simpler relations and handle stuffs independently?
When you are making an API, will your
code make the api overworking? or you need to create too many request
for any operation?
These stuffs will decide how you will make a decision.
Update 1:
Another point I would like to add about the package you are thinking to use, consider using a parent key in table and you can define relationships in a single model.I do not think you need to use a package, you can define it yourself, I guess.
I don't understand why you don't create a simple one-to-many relation. Based on the information you provided, the polymorphic relation looks unnecessary. I think the right way is to create employee_roles table and relations. Then you can give different permissions to different employee types. There are several ways to do that. You can create a middleware to create route restrictions. You can check the role before executing a function in the controller, and run only if the employee has permission. You can use if-else in blade not to render the parts that can't be used by auth user etc.
If you have different “types” of employees, and each employee type should have different logic then yeah, that sounds like a polymorphic relationship.

Achieving Laravel Eloquent Model Inheritance

I currently do have a vehicles table that holds "Cars".
Now I want to allow the system to have Bikes, Cars and Trucks.
They have some fields in common (manufacturer_id, mileage, ... ) but they also have specific fields (Bike: cylinder_capacity, seats; Car: doors, ...)
I have tried using all columns in vehicles table and then use the models to handle the differences, But i had problems setting the fillable fields for the child models...
Then I read about polymorphic relations and it seems the right way to go.
So, my questions are: Which approach is the best? What is the best way to implement it?
Thanks!
Create additional tables:
vehicles_types to store types, like cars, bikes etc.
vehicles_attributes to store specific type attributes related via vehicle_type_id with fields vehicle_type_id, name, value.
I extend other models occasionally, and it works as expected. The migrations need to be set up separately, but the class logic (attributes and methods) will work in the normal OOP way. If you're familiar with this, just do what you're doing!

How to obtain a generic search/find method with spring data?

All I need is to provide all my repositories with a generic search/find method.
Something like this:
public interface BaseRepository<T, ID extends Serializable>
extends PagingAndSortingRepository<T, ID> {
Iterable<T> search(SearchParameters sp);
}
where the SearchParameters object represents a set of values for each property, and probably a condition to apply on them.
Jpa Criteria is probably the way to go, but I'm really having a hard time finding something that fits my needs.
I used one approach which goes in the same direction but i would rather say its a dynamic approach instead of generic. Its now working pretty well and we are able to generate all desired filters automatically by just giving the search entity. I also thought the criteria api is the way to go but after a while it just got too messy with all the side effects and i turned around creating the query string with parameters myself.
I created an entityscanner which takes all domain entities and generates filterdefinition objects for each desired filter. This scanner takes an entity and follows properties up to a certain level (to keep the amount of filters at bay). I cannot give you the code here since that belongs to a customer but the approach i can provide.
What i needed in the filterdefinition is this: entitytype, propertypath, propertytype, valuesexpression in case we render options (think masterdata), joins needed (to avoid joining several times the same tables), open/closed bracket. This is the definition of a filter.
Then you need a value object holding the current configuration of a user: Inputvalue, operator (>=), brackets, filter link (and/or) .
With this we can render a completly dynamic filter engine with some small limitations. I.e i did not implement parent searches of the same entity yet.
You might start simple an generate a sub query for each filter. Like: where id in (select ....) and/or id in (select ...) This works ok if the amount of entities is not too high but you will feel the performance penalty of several subqueries if the amount of rows in the domain entity table is high.
Then you dive in and find a way to separate the joins needed for a property path and in the querycreator you fiddle out the way of joining entities only again if neccessary.
As said. Start simple. Take first level properties of simple types like string and create your query engine. Enhance it by following specific entity joins and after you can go crazy and introduce expressions fetching options for a select rendering or use the conversion service for input parameters and so on.

How to Program a Spring with Hibernate web app?

I am Working on web application where i have 90 fields for a Person class which are divided in to family details,education details, personal details etc....
I want separate form for each, like for family details has-father name, mother name siblings etc... fields and so on for other
I want separate table for each detail with common reference id for all tables
My question is how many bean classes should i write? Is it with one bean class can i map from multiple forms to multiple tables?
class PersonRegister{
private Long iD;
private String emailID;
private String password;
.
.
}//for register.......
once logged in i need to maintain his/her details
Either
class person{
}
or
class PersonFamilyDetails{}
class PersonEducationDetails{}
etc
which way software developing standards specify to create?
Don't go overboard, I believe in your case single but very wide (i.e. with a lot of columns) table would be most efficient and simplest from maintenance perspective. Only thing to keep in mind is too query only for a necessary subset of columns/fields when loading lots of rows. Otherwise you'll be fetching kilobytes of unnecessary data, not needed for particular use case.
Unfortunately Hibernate doesn't have direct support for that, when designing a mapping for Person, you'll end up with huge class and even worse - Hibernate will always fetch all simple columns (and many-to-one relationships). You can however overcome this problem either by creating several views in the database containing only subset of columns or by having several Java classes mapping to the same table but only to subset of columns.
Splitting your database model into several tables is beneficial only if your schema is not normalized. E.g. when storing siblings first name and last name you may wish to have a separate Sibling table and next time some other family member is entered, you can reuse the same row. This makes database smaller and might be faster when searching by sibling.
Your question comes down to database normalization, as described in-depth by Boyce and Codd, see
http://en.wikipedia.org/wiki/Database_normalization.
The main advantage of database normalization is avoiding modification anomalies. In your case, if you got one table with for each person e.g. father-firstname and father-lastname, and you have multiple people with the same father, this data will be duplicated, and when you discover a typo in the father-lastname, you could modify it for one sibling, and not for the next.
In this simplified case, database design best practices would call for a first normalization into a separate table with father-id, father-firstname and father-lastname, and your person table having a one-to-many relation to it.
For one-to-one relations, e.g. person->personeducationdetails, there's some debate. In the original definition of 1st Normal Form, every optional field would be normalized by putting it's own table. This was later weakened by introducing 'null' in relational databases, see http://en.wikipedia.org/wiki/First_normal_form#cite_note-CoddRule-12. But still, if a whole set of columns could be null at the same time, you put them in a separate table with a one-to-one relation.
E.g. if you don't know a person's educationdetails, all of its related fields are null, so you better split them off in a separate table, and simply not have a personeducationdetails record for that person.

Doctrine ORM: How to define a 1-n realtionship with a n-n connecting table

So, this is a bit complicated: I have two tables, say cats and dogs.
They are in a many-to-many relationship (could be called friendships or whatever), so that Doctrine automatically creates a table cats_dogs for me with the appropriate fields. (that is rowid, cat_id, dog_id per default.)
Now, imagine I have a third table, award, where I want to award one of these friendships. Here I therefore need a field that references one row in cats_dogs. However, since this table does not really exist between my models, (Doctrine handles it for me) what would be the most elegant solution for this?
In the end, I want in my award model two fields, a cat and a dog, who need to be in a friendship.
I am using the annotation driver.
What stops you from manually creating the m:n table instead of having doctrine do it for you?
The Doctrine aims is to map objects from an E/R schema and to make easier the access to object connections. Therefore I believe that the table cats_dogs automatically provided by Doctrine is necessary as it is. It is concise and hits its purposes, i.e. it provides a list of all dogs of a cat or, vice versa, all the cats of a dog.
Thus, I can conclude that it is preferable to create a third entity (besides Cat and Dog) named Award which provides a one-to-one relationship with Cat and another one-to-one relationship with Dog. Making it consistent with the cats_dogs table is only up to you, and is not a Doctrine task by default. E.g., you can use some cascade persist option.
I believe that this is the most effective solution with Doctrine.
As a final remark, consider that each table should map a specific relationship between one or more entities, and in fact the table cats_dogs represents the friendship relationships, while the table Award will represent the awarded relationship relationship between two friends.

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