Define a variable not explained - laravel

Sorry for the dumb question but can anyone please tell me how to define a variable in very simple terms? I have struggled for several months with "undefined variable" errors. Are variables stored in config? Or maybe in routes?
I have a database with a customers table. When I put this on my view home page {{$customers->name}} I get Undefined variable: customers.
Fine. So how and where do I define a variable. I would have thought it WAS defined given that the database table is literally called customers. Ugh!
My model file Customer.php
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Customer extends Model
{
protected $fillable = ['name', 'phone'];
public function address()
{
return $this->hasOne(CustomerAddress::class);
}
public function purchases()
{
return $this->hasMany(CustomerPurchase::class);
}
}

Undefined variable means the variable does not exist and the reasons for your case is, you did not pass it in the view.
Usually, to get the customers records from the database to your views, you can do it in several ways:
Query it prior to loading your view then pass it to your views:
//doing it in the controller
//create a controller: php artisan make:controller CustomerController
<?php
namespace App\Http\Controllers;
use Illuminate\Routing\Controller as BaseController;
use App\Customer; //Dont forget to import your Customer model
class CustomerController extends BaseController
{
public function index()
{
$customers = Customer::get(); //this will fetch the customer using your mdoel
return view('customer', ['customers' => $customers]); //this will pass the records to the view
}
}
//then in your routes/web.php:
Route::get('/customers', 'CustomerController#index'); //when you go to your application/customers in the browser, it will go to the controller and return the view with the records.
//OR you can skip the controllers and do it in the routes/web.php directly as what #jitesh jose mentioned.
Query straight into your view (Not really recommended, but sometimes you just need to make it work)
In your customer.blade.php
#php
$customers = \App\Customer::get();
#endphp
<ul>
#foreach($customers as $customer)
<li>{{$customer->name}}</li>
#endforeach
</ul>
My advice, try to watch a few basic Laravel videos so that you will understand the flow of the request and response.

If your model name is Customer,laravel automatically pick the table name as customers.Otherwise you have to use your desired table name in Model as follows.
protected $table = 'customers_table';
In your web.php
Route::get('/home',function () {
$customers = DB::table('customers_table')->get();
OR
$customers = Customer::get();
return view('welcome')->with('customers',$customers);
});
You can use$customers in welcome.blade.php as
#foreach($customers as $customer)
{{$customer->name}}
#endforeach

Related

Laravel Models/function, how to make a main "function"

So guy's, I've created a Laravel project.
I have a master. Layout which always contains the user data.
So I have a navbar with $user->name for example.
In every controller I needed to add the User model and also the where function.
$user = User::find(auth()->user()->id)
Maybe this example is bad, but I've also included the company in the master, so it shows in the Navbar.
Is there a way, that I don't need to repeat that process? So I don't need it always in the controller.
Thanks for reading.
In laravel you are extending each class from a main controller so its better to create a method in main class like this
child controller
class testController extends Controller
{
// as you can see its extending so go into Controller class
}
parent class, So here i have creatd a getName method here. If you want get the value through mode
<?php
namespace App\Http\Controllers;
use Illuminate\Foundation\Bus\DispatchesJobs;
use Illuminate\Routing\Controller as BaseController;
use Illuminate\Foundation\Validation\ValidatesRequests;
use Illuminate\Foundation\Auth\Access\AuthorizesRequests;
class Controller extends BaseController
{
use AuthorizesRequests, DispatchesJobs, ValidatesRequests;
private $current_user_name = 'test';
public function getName()
{
return ($this->current_user_name);
}
}
Now go back to child controller and pass this method in view
class testController extends Controller
{
public function index()
{
return view('', $data = ['name' => $this->getName()]);
}
}
Hope this cover your query. In this way you don't need to repeat your code in every controller.
You can get data in your blade template too, like user information, but if you need more complex data and you don't want to put logic in blade, you can use this method (AppServiceProvider.php):
public function boot()
{
view()->composer('your_mast_layout', function($view)
{
$data = ...
$view->with('variable_name', $data);
});
}

Overriding routeKeyName to slug not working

Here is my show method in my PostController and when I dd($slug) I get my slug from the database but when I try to search the post associated with that slug I get a 404 | Not Found. I've override my routeKeyName in my model but it seems like it'still fetching using id column since when I replace $slug with a hard coded id of 2 in this line $post = Post::findOrFail($slug); then I get the post from the database. I can't figure out what it is that I'm missing.
public function show($slug)
{
//dd($slug);
$post = Post::findOrFail($slug);
return view('single-blog', compact('post'));
}
My Model Post.php
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
class Post extends Model
{
use HasFactory;
public function getRouteKeyName()
{
return 'slug';
}
}
Even using a different database field, you're still using route model binding.
From the docs:
Laravel automatically resolves Eloquent models defined in routes or controller actions whose type-hinted variable names match a route segment name.
So your route variable and the field you pass to your controller method need to match, and you need to type hint it:
Route:
Route::get('/posts/{post}', [PostController::class, 'show']);
Controller:
public function show(Post $post) {

How to architect a project which has more number of dynamic pages in laravel

I have a project which has a large number of dynamic pages. Approximately 30+ pages. The content of each page is different. what I did is created 30 tables and 30 routes as well. And on the admin side, there are 30+ modules to edit the contents. Is it the right way to do this?. In database table, different columns has to be kept.
// Route definition...
Route::get('/page1', [Page1Controller::class, 'show']);
Route::get('/page2', [Page2Controller::class, 'show']);
Route::get('/page3', [Page3Controller::class, 'show']);
// Controller method definition...
public function index() {
return view('page1');
}
// Route definition...
// All other routes above this slug catch all. otherwise it will try and hit this controller all the time and fail.
Route::get('/{slug}', [PageController::class, 'show']);
// Controller method definition...
public function show($slug)
{
$contents = PageContents::where('slug', $slug)->firstOrFail();
if ($contents) {
return view('page')->with('contents', $contents);
}
return view('404');
}
This way you have a table with all the contents you need. e.g. title, body copy so on. but if each layout is different you could also return a different view. e.g.
public function show($slug)
{
$contents = PageContents::where('slug', $slug)->firstOrFail();
if ($contents) {
return view('page-'.$slug)->with('contents', $contents);
}
return view('404');
}
You can create only one controller and add a parameter in the route(web.php):
web.php
//---Route Definition
Route::get('page/{page_number}', [PageController::class, 'show'])->name('page.show');
PageController.php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Crypt;
class PageController extends Controller {
//---Show
public function show($page_number) {
return view('show.show', compact('page_number'));
}//---End of Function show
}
If you want to retrieve your data from a database just one table is enough, just create a page table and give a field by the name of page_number and retrieve your specific page data by the given field.
For example:
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Crypt;
class PageController extends Controller {
//---Show
public function show($page_number) {
$page = PageContent::where('page_number', $page_number)->first();
return view('show.show', compact('page'));
}//---End of Function show
}
**
Your Link to routes
<a href="{{ route('page.show', ['page_number' => 1])) }}" class="" title="Show">
Show
</a>

Laravel(500- Internal server error): Unable to get data from model to controller

I have been trying to list a dropdown in the index page with data from database. I created a model and made some changes in controller to display it in my view page but making any change in the controller gives a blank page with 500 Internal server error in the console. Please help me out to sort this problem.
Table name: walker_type
Routes:
Route::get('/', 'WebController#index');
Model: ProviderType.php :
<?php
class ProviderType extends Eloquent {
protected $table = 'walker_type';
}
Controller: WebController.php
public function index() {
$walkerTypeList = ProviderType::all();
return view('website.index')->with(['walkerTypeList' => $walkerTypeList]);
}
View:index.php
#foreach ($walkerTypeList as $car)
<option data-icon="glyphicon-road" value="{{ $car->name }}"> {{ $car->name }} </option>
#endforeach
Had u declare your model below your namespace?
eg. use App\WalkerType;
also you forgot to declare a namespace to your Model.
it should have namespace App;
or if you have a folder for your model to make it more conventional.
you should have a namespace on each of your model.
eg. App\Model
and then use that in every controllers by declarin in between your namespace and class
eg.
namespace App\Controllers;
use App\Model\WalkerType;
class SomeController extends Controller{
protected $data; //this is a class variable that can call anywhere to your class by calling it this way $this->data
public function some_method(){
$this->data['variable_a'] = "some_value"; //this can call in you view later by $variable_a
$this->data['sum'] = 1+4; //result can be display in your view by calling the variable $sum
return view('someview',$this->data);
}
}
I hope this can help you for your project efficiently, cause we had experienced that we forgot to include some of the data that has been processed on the controller and needed to display in your view file but forgot to include.

How can i get result from model in laravel 5

Good day, i'm trying to get the result from my model that called with Mainmodel through my controller, my controller is MainController.
Here is my controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use app\Mainmodel;
class MainController extends Controller
{
function index(){
echo "Kok, direct akses sih?";
}
function get_menu(){
$menu = app\Mainmodel::request_menu();
dd($menu);
}
}
Here is my model
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Mainmodel extends Model
{
function request_menu(){
$menu = DB::table('menu')
->orderBy('[order]', 'desc')
->get();
return $menu;
}
}
my routes
Route::get('menu','MainController#get_menu');
with my script above i get this
FatalErrorException in MainController.php line 17: Class
'App\Http\Controllers\app\Mainmodel' not found
how can i fix this ? thanks in advance.
Note: I'm bit confuse with laravel. I'm using codeigniter before. And i have a simple question. In laravel for request to database should i use model ? or can i just use my controller for my request to database.
sorry for my bad english.
I would imagine it's because your using app rather than App for the namespace.
Try changing:
app\Mainmodel
To:
App\Mainmodel
Alternatively, you can add a use statement to the top of the class and then just reference the class i.e.:
use App\Mainmodel;
Then you can just do something like:
Mainmodel::request_menu();
The way you're currently using you models is not the way Eloquent should be used. As I mentioned in my comment you should create a model for each table in your database (or at least for the majority of use cases).
To do this run:
php artisan make:model Menu
Then in the newly created Menu model add:
protected $table = 'menu';
This is because Laravel's default naming convention is singular for the class name and plural for the table name. Since your table name is menu and not menus you just need to tell Laravel to use a different table name.
Then your controller would look something like:
<?php
namespace App\Http\Controllers;
use App\Menu;
class MainController extends Controller
{
public function index()
{
echo "Kok, direct akses sih?";
}
public function get_menu()
{
$menu = Menu::orderBy('order', 'desc')->get();
dd($menu);
}
}
Hope this helps!
You can solve it by different solution. The solution is you don't have to call request_menu(); you can get it in your controller.
MainController
use use Illuminate\Support\Facades\DB;
public function get_menu(){
$menu = DB::table('menu')
->orderBy('Your_Field_Name', 'DESC')
->get();
dd($menu);
}

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