I have a date:
myStringDate = "27-09-2019"
that is a string, and I need to convert to time.Time in Go.
So, I do:
date, err = time.Parse("01-02-2006", myStringDate)
And I get an error:
data:<*time.ParseError>(0xc000098140)
:<time.ParseError>
Layout:"01-02-2006"
Value:"27-09-2019"
LayoutElem:"01"
ValueElem:"-09-2019"
Message:": month out of range"
Nevertheless, the layout I use to parse it seems OK.
I am parsing several files, all coming from the same sources, and the other file can be parsed without any problems
What point am I missing ?
Per the documentation, the layout parameter to Parse is the canonical date "Mon Jan 2 15:04:05 -0700 MST 2006" represented in the desired format. That means the layout you gave is MM-DD-YYYY, when your data appears to be DD-MM-YYYY. If that is the case, your layout string should be 02-01-2006.
myStringDate := "27-09-2019"
date, err := time.Parse("02-01-2006", myStringDate)
https://play.golang.org/p/qUEDtcG1v3W
Related
I know I need to use a time layout in Go (as shown here https://golang.org/src/time/format.go) but I can't find the layout for an ISO 8601 timestamp.
If it helps, I get the timestamp from the Facebook API. Here is an example timestamp: 2016-07-25T02:22:33+0000
I found this layout to work: "2006-01-02T15:04:05-0700"
The problem here is that RFC3339 requires the zone offset to be given as "+00:00" (or "Z" in case of UTC) while ISO8601 allows it to be "+0000".
From RFC3339:
[...]
time-numoffset = ("+" / "-") time-hour ":" time-minute
time-offset = "Z" / time-numoffset
[...]
full-time = partial-time time-offset
date-time = full-date "T" full-time
So instead of the time.RFC3339 layout
"2006-01-02T15:04:05Z07:00"
you have to use:
"2006-01-02T15:04:05Z0700"
RFC3339 is equivalent to ISO 8601. Specifically, it has identical format, RFC3339 just has stricter requirements (example, it requires a complete date representation with 4-digit year).
What's the difference between ISO 8601 and RFC 3339 Date Formats?
So you can use the constant time.RFC3339 as your layout.
You have that to use the some layout of your date.
data := "2022-01-24T00:00:00.000-03:00"
layout := "2006-01-02T15:04:05.000-03:00"
dataTime, err := time.Parse(layout, data)
I am attempting to change an SQL datetime variable (2016-06-09 14:29:34) into a format that looks like this (00:00_20160601). I have tried to follow a couple of SO questions that will allow me to format a Time object.
This is what I have done so far:
start_datetime = "2016-06-09 14:29:34"
t =Time.new(start_datetime)
t.strftime("%H:%M_%Y%d%m")
This results in the time being formatted to 2016-01-01 00:00:00 +0000, which is obviously not what I want. I was wondering if someone could help me format the datetime object the way I specified?
You can do this with DateTime:
require 'datetime'
DateTime.parse("2016-06-09 14:29:34").strftime("%H:%M_%Y%d%m")
#=> "14:29_20160906"
The format you're feeding in is basically ISO-8601 so it's parsed by default.
Feeding that value into Time.new is completely incorrect. The first argument there is the year, the rest have to be supplied separately. That's why you get 2016-01-01, since everything else comes out as defaults.
Time.new is converting automatically and the result of "2016-06-09 14:29:34".to_i is 2016.
It's not entirely clear why your day value changes from 09 in the input to 01 in the desired output, so I'll use the normal thing and output the same as was input:
require 'time'
start_datetime = "2016-06-09 14:29:34"
t = Time.strptime(start_datetime, '%Y-%m-%d %H:%M:%S')
t.strftime('00:00_%Y%m%d') # => "00:00_20160609"
Since the hours and minutes are being thrown away there are a couple of other ways to go about this.
Ignore the hours and minutes when parsing:
t = Time.strptime(start_datetime, '%Y-%m-%d')
Or use a Date object instead of a Time object:
require 'date'
start_datetime = "2016-06-09 14:29:34"
t = Date.strptime(start_datetime, '%Y-%m-%d')
t.strftime('00:00_%Y%m%d') # => "00:00_20160609"
Making a GET request to a private (no public documentation) API returns data in JSON format.
The value for date looks as follows:
AanmeldDatum: "/Date(1262300400000+0100)/"
There's another variable called AangebodenSindsTekst which means OfferedSinceText and it's value is "8 augustus 2014". So the unknown Date format should get parsed into that specific value.
I'm wondering what kind of date format it is and how can I transform this to something like this 2014-08-08 with Ruby?
I've tried this:
require 'time'
t = '1262300400000+0100'
t2 = Time.parse(t)
# => ArgumentError: no time information in "1262300400000+0100"
Ruby's Time class is your friend, especially the strptime method:
require 'time'
foo = Time.strptime('1262300400000+0100', '%N') # => 2014-08-08 16:57:25 -0700
foo = Time.strptime('1262300400000+0100', '%N%z') # => 2014-08-08 08:57:25 -0700
%N tells Ruby to use nanoseconds. It's throwing away the precision after the 9th digit which is OK if you don't need the rest of the value. Nanosecond accuracy is good enough for most of us.
%z tells Ruby to find the timezone offset, which it then applies to the returned value.
While parse can often figure out how to tear apart an incoming string, it's not bullet-proof, nor is it all-knowing. For speed, I'd recommend learning and relying on strptime if your strings are consistent.
As the Tin Man pointed out in this answer, use the following instead:
Time.strptime('1262300400000+0100', '%Q%z')
it could be milliseconds since epoc, take off the last 3 zeros and plug it into a unix time stamp converter, comes out as Dec 31st 2009
TIME STAMP: 1262300400
DATE (M/D/Y # h:m:s): 12 / 31 / 09 # 11:00:00pm UTC
I have the following date string ('US/Eastern'), which I need to convert to UTC:
date_src = '2014-07-07T23:10:00+0'
First I convert it to a "valid" format so I can operate it on later processes. I use the following to have an iso version of the date:
date = DateTime.parse(date_src).iso8601
At this point date is a nice '2014-07-07T23:10:00+00:00'. The last step on my process is to translate this date to UTC. I'm using the following:
TZInfo::Timezone.get('US/Eastern').local_to_utc(date)
The problem is this is giving me 20014 as output, instead of the UTC version of the original date. If I try:
TZInfo::Timezone.get('UTC').local_to_utc(date)
I get 2014, which is the correct year but still unexpected output.
Any ideas about what I'm doing wrong, and what I could use to solve the problem?
local_to_utc actually expects a Time or a DateTime instance:
TZInfo::Timezone.get('US/Eastern').local_to_utc(DateTime.parse(date_src))
# => #<DateTime: 2014-07-08T03:10:00+00:00 ((2456847j,11400s,0n),+0s,2299161j)>
From the documentation, you can have a hint on what actually happened:
All methods in TZInfo that operate on a time can be used with either Time or DateTime instances or with nteger timestamps (i.e. as returned by Time#to_i). The type of the values returned will match the the type passed in.
What actually happens is the local_to_utc calls to_i on the input parameter, which on a string returns the parsed integer from the beginning of the string (2014 in your case since date is the string 2014-07-07T23:10:00+00:00), and adds the time difference to it - 18000 for "US/Eastern" (5 hour difference), and 0 for UTC:
date.to_i
# => 2014
TZInfo::Timezone.get('US/Eastern').local_to_utc(date) - date.to_i
# => 18000
TZInfo::Timezone.get('UTC').local_to_utc(date) - date.to_i
# => 0
So the bottom line is - kind of serendipitously you saw this weird behavior, which stems from the compilation of some surprising quirks of the APIs you used...
A=Time.now
gives following output:
2012:05:18 12:20:50 +0530
I want to form a string like "May 18 , 2012". I tried changing A to string which was not possible. How can I achieve this?
Time.now.strftime('%b %e , %Y')
More info.
You can have a look at the Time Class, and method strftime.
It formats time according to the directives in the given format string.
http://www.ruby-doc.org/core-1.9.3/Time.html#method-i-strftime
For your current problem:
Time.now.strftime("%b %d, %Y")