oracle - path passing by multiple nodes structure - oracle

Question

I have the following oracle 12c tables structure:
table1:
path_id node_1 node1_port node_2 node2_port
------------------------------------------------------------------------
1 France France_port1 Italy Italy_port1
1 Italy Italy_port1 France France_port1
1 Italy Italy_port2 Belgium Belgium_port1
1 Belgium Belgium_port1 Italy Italy_port2
1 Belgium Belgium_port2 Sweden Sweden_port1
1 Sweden Sweden_port1 Belgium Belgium_port2
2 Belgium Belgium_port1 Germany Germany_port1
2 Germany Germany_port1 Belgium Belgium_port1
table2:
path_id start_node start_node_port end_node end_node_port
----------------------------------------------------------------
1 France France_port1 Sweden Sweden_port1
2 Belgium Belgium_port1 Germany Germany_port1
where path id has multiple nodes and node_1_port and node_2_port represent the hops of this path.
so for example path_id = 1 start from France and end in Sweden (as per table2), passing by Italy and Belgium(as per table1), while path_id = 2 start from Belgium and end in Germany.
can you give me some hints how to proceed as I'm still new to oracle.
EDIT:
I edited the post to make it a little more realistic.
In addition, node_1 and node_2 can be random names. the order of the hops will be got from the connection of node_1 and node_2 : France is connected to Italy , then Italy connected to Belgium , then Belgium connected to Sweden , then the order of the path is : France-->Italy-->Belgium-->Sweden , knowing that the port connecting Italy to France is different than the port connecting Italy to Belgium , and both ports must be included in the final table. It's a bit complicated , I'm not able to get it right.
this is the needed output:
path_id node_name node_port order
---------------------------------------------------
1 France France_port1 1
1 Italy Italy_port1 2
1 Italy Italy_port2 3
1 Belgium Belgium_port1 4
1 Belgium Belgium_port2 5
1 Sweden Sweden_port1 6
2 Belgium Belgium_port1 1
2 Germany Germany_port1 2
This is what I reached so far , knowing that I was forced to use loops as I couldn't think of any other way.
Is there a way to get the result using a query without loops as I have around 1M records in table1.
create table table_final (path_id integer,node_name varchar2(50),node_port varchar2(50),order_rec integer);
declare
id integer :=1;
start_node varchar2(50);
end_node varchar2(50);
start_node_port varchar2(50);
end_node_port varchar2(50);
cnt integer:=1;
cnt_or integer:=1;
cnt1 integer:=0;
TYPE nodes_arr IS TABLE OF VARCHAR2(50) INDEX BY BINARY_INTEGER;
nodes nodes_arr;
TYPE nodes_ports_arr IS TABLE OF VARCHAR2(50) INDEX BY BINARY_INTEGER;
ports nodes_ports_arr;
id_cnt integer;
BEGIN
select max(path_id) into id_cnt from table2;
while id <= id_cnt
LOOP
select start_node,end_node,start_node_port,end_node_port into nodes(1),end_node,ports(1),end_node_port
from table2 where path_id = id;
start_node:=nodes(1);
start_node_port:=ports(1);
insert into table_final
select id,nodes(1),ports(1),cnt from dual;
commit;
while start_node!=end_node
LOOP
cnt:=cnt+1;
cnt_or:=cnt_or+1;
if cnt =2
THEN
select node_2,node2_port into nodes(cnt),ports(cnt)
from table1 where path_id=id and node_1=nodes(cnt-1) and node_2!=node_1;
ELSE
select node_2,node2_port into nodes(cnt),ports(cnt)
from table1 where path_id=id and node_1=nodes(cnt-1) and node_2!=node_1 and node_2!=nodes(cnt-2) ;
END IF;
insert into table_final
select id,nodes(cnt),ports(cnt),cnt_or from dual;
select NVL(count(*),0) into cnt1 from table1 where path_id=id and node_1=nodes(cnt) and node1_port !=ports(cnt);
if cnt1=1
THEN
cnt_or:=cnt_or+1;
insert into table_final
select id,node_1,node1_port,cnt_or
from table1 where path_id=id and node_1=nodes(cnt) and node1_port !=ports(cnt);
END IF;
start_node:=nodes(cnt);
start_node_port:=ports(cnt);
commit;
END LOOP;
cnt:=1;
cnt_or:=1;
id:=id+1;
END LOOP;
END;

Answer 1

I am not able to see any usage of table2 here. You can simply remove duplicates from table1 itself as following:
Select t.*,
row_number()
over (partition by path_id order by to_number(replace(node_name, 'node', ''))) as order_
From
(Select distinct path_id,
Node_name,
Node_name_1_para
From table1) t
Order by path_id, order_;
-- Update --
As per the comments, you should try this query:
Select t1.path_id,
T1.node_name
T.node_name_1_para,
Row_number() over (partition by t1.path_id order by null) as order_
From
Table1 t1 join table2 t2
On (t1.path_id = t2.path_id
And t1.node_1 between t2.start_node and t2.end_node);
Cheers!!