Let's say I want http://localhost/#/ to redirect to http://localhost/#/home, how would I do that?
One way to do it is by setting a default on the viewport:
<au-viewport default="home"></au-viewport>
Related
I cant find a way to navigate to a new page when inertia-link is clicked when using a dynamic route in laravel.
route:
This two is not added together in the code. I tried both way to tested so i put both here
Route::get('/{clothesCategory}', 'ClothesController#getCalsas'); // this doesnt work
Route::get('/NotDynamic, 'ClothesController#getCalsas'); // this work
Html:
<inertia-link href="/NotDynamic">Not Working</inertia-link> //this only works with NotDynamic route
Working // this works with both routes
Why is this happening I dont understand the reason behind it? also how can I get the inertia-link to work with the Dynamic route?
You can simply follow this example:
<inertia-link :href="'/' + data.slug">Go To</inertia-link>
use the ":" (colon symbol) before "href". Then you can insert dynamic value into the link.
Found how to do this using :headers
<inertia-link href="/endpoint" :headers="{ clothesCategory: endpoint}">end point</inertia-link>
Currently my users must get the visit form given by Route::get then fill it in to get back a result view given by Route::post. I need to create a shareable link such as /account/search/vrm/{vrm} where {vrm} is the VRM that is usually filled in on the form page. This VRM then needs to redirected to Route::post as post data. This needs to be done by my controller. How can I do this in my controller?
Routes:
// Shows form view
Route::get('/account/search', 'User\AccountController#getSearch')->name('account.search');
// Shows result view
Route::post('/account/search', 'User\AccountController#runSearch');
// Redirect to /account/search as POST
Route::get('/account/search/vrm/{vrm}', function($vrm) { ???????? });
POSTs cannot be redirected.
Your best bet is to have them land on a page that contains a form with <input type="hidden"> fields and some JavaScript that immediately re-submits it to the desired destination.
You can redirect to a controller action or call the controller directly, see the answer here:
In summary, setting the request method in the controller, or calling a controller's action.
Ps: I don't want to repeat the same thing.
For those who comes later:
If you are using blade templating engine for the views, you can add '#csrf' blade directive after the form starting tag to prevent this. This is done by laravel to prevent cross site reference attacks. By adding this directive, you can get around this.
return redirect()->route('YOUR_ROUTE',['PARAM'=>'VARIABLE'])
Is it possible to change the complete theme inside an action of an ActionController?
Well theoratically yes as Loadlayout is called in controller.
You use remove blocks if needed refer Programatically remove block from layout and also by using create blocks you can add blocks..
Yes, probably before layout gets rendered.
But better to make it over session + redirect and default
$mageRunCode with store code.
Mage::run($mageRunCode, $mageRunType);
at the end of index.php
I have controller PlayerController and actions inside: View, Info, List.
So on urls "/Player/View" i get result with default Layout.
I want to get result with different Layout on request "/External/View".
How can i achieve this?
Although you can override the layout from the controller as has been suggested in another answer, in my opinion this means the controllers are getting just too involved in determining what the UI will be. Best to leave this purely to the Views to decide.
The closest to what you're asking is to do this in your current "~/Views/_ViewStart.cshtml":
#{
if(Context.Request.Path.StartsWith("/External", StringComparison.OrdinalIgnoreCase))
Layout = "~/Views/_ExternalLayout.cshtml";
else
Layout = "~/Views/_Layout.cshtml";
}
Where "~/Views/_ExternalLayout.cshtml" is your alternative layout.
Might want to check the leading "/" is correct on there, I can't remember if it is.
If you put this in the existing _ViewStart, then any view that is being rendering in response to a url starting with "/External" will use this new layout, otherwise the 'normal' one will be used.
Another approach is to use the routing table to add a route value that can be used here to make a layout decision; but I've gone for this approach to keep it simple.
You can specify which layout should be used when returning a view inside your 'ExternalController' controller action.
return View("View", "~/Views/Shared/_AnotherLayout.cshtml")
So, i have my .htaccess, my controllers, everything is going fine. I added localization, so now i have Portuguese(Default), English and Italian.
I am using the _lang files in the appplication/languages directory, i am using session->userdata('lang') and everything works fine.
My controllers are named with portuguese words, after the top menu. What i'm looking for is:
to rewrite my url, changing the name of the controller, depending on the session->userdata('lang').
Is this even possible? how?
Thank you
So i am trying, as InFog suggested, in the routes file:
if ($this->session->userdata('lang') == 'english') {
$route['novidades/([a-z]+)'] = 'news/$1';
}
but i just get a blank screen when i open the application.
And i've tried it without the if clause, and nothing happens, when i go to
http://localhost/myapp/novidades
the url stays the same
You can solve this using CodeIgniter Routes. You can do it editing the file 'system/application/config/routes.php:
$route['news/([a-z]+)'] = 'noticias/$1';
This way an URL like '/news/run-fools' will be remaped to 'noticias/run-fools'. Now you can have just one controller =)
Good Luck
Override CI_Router to translate the name in the fetch_class() method to change controllers. Override fetch_method() to change methods.