file.txt
...
<LOCAL_PATH_TO_REPO>/src/java/example.java
...
^A longer file but this pretty much explains what I am trying to do.
script.sh
dir=$(pwd)
# replace <LOCAL_PATH_TO_REPO> with dir
I tried using the sed command but it did not work for some reason. Any ideas on how to do this?
Your error means you have backslashes in the variable text.
The simplest solution is to change the delimiter to the one that does not occur in the variable text.
If there are no commas use a comma:
sed -i "s,LOCAL_PATH_TO_REPO,$PWD," file.yml
The -i flag introduces changes into the input file (works for GNU sed).
Related
I want to remove the first two characters of a column in a text file.
I am using the below but this is also truncating the headers.
sed -i 's/^..//' file1.txt
Below is my file:
FileName,Age
./Acct_Bal_Tgt.txt,7229
./IDQ_HB1.txt,5367
./IDQ_HB_LOGC.txt,5367
./IDQ_HB.txt,5367
./IGC_IDQ.txt,5448
./JobSchedule.txt,3851
I want the ./ to be removed from each line in the file name.
Transferring comments to an answer, as requested.
Modify your script to:
sed -e '2,$s/^..//' file1.txt
The 2,$ prefix limits the change to lines 2 to the end of the file, leaving line 1 unchanged.
An alternative is to remove . and / as the first two characters on a line:
sed -e 's%^[.]/%%' file1.txt
I tend to use -e to specify that the script option follows; it isn't necessary unless you split the script over several arguments (so it isn't necessary here where there's just one argument for the script). You could use \. instead of [.]; I'm allergic to backslashes (as you would be if you ever spent time working out whether you needed 8 or 16 consecutive backslashes to get the right result in a troff document).
Advice: Don't use the -i option until you've got your script working correctly. It overwrites your file with the incorrect output just as happily as it will with the correct output. Consequently, if you're asking about how to write a sed script on SO, it isn't safe to be using the -i option. Also note that the -i option is non-standard and behaves differently with different versions of sed (when it is supported at all). Specifically, on macOS, the BSD sed requires a suffix specified; if you don't want a backup, you have to use two arguments: -i ''.
Use this Perl one-liner:
perl -pe 's{^[.]/}{}' file1.txt > output.txt
The Perl one-liner uses these command line flags:
-e : Tells Perl to look for code in-line, instead of in a file.
-p : Loop over the input one line at a time, assigning it to $_ by default. Add print $_ after each loop iteration.
s{^[.]/}{} : Replace a literal dot ([.]) followed by a slash ('/'), found at the beginning of the line (^), with nothing (delete them). This does not modify the header since it does not match the regex.
If you prefer to modify the file in-place, you can use this:
perl -i.bak -pe 's{^[.]/}{}' file1.txt
This creates the backup file file1.txt.bak.
SEE ALSO:
perldoc perlrun: how to execute the Perl interpreter: command line switches
perldoc perlrequick: Perl regular expressions quick start
So I have a bunch of files that I want to edit at once using sed but the problem is that I need to edit a line and change the text to a file name stored in variable filename. Every time I tried, it changes the text to the literal "filename" and I don't know how to fix it.
The command I've used is:
sed -i 's/$x/'$filename'/g' *.html
From your description and the command used I assume that you try to replace a variable text stored in
X="text2replace"
with a filename stored in
FILENAME="filename"
According this, a command like
sed -i "s/${X}/${FILENAME}/g" *.html
should do the job. It will replace all occurrences of text2replace in all HTML files found with the string filename.
You may have also a look into
When do we need curly braces around shell variables
When to wrap quotes around a shell variable
This might work for you (GNU parallel and sed):
parallel --header : sed -i 's#{x}#{filename}#' {file} ::: file *.html ::: x pattern ::: filename name
I have the line of text within a text file. The line looks something like this:
xxxx,xxxxx,xxxxxx,xxxxx,xxxx,NL-1111 xx,xxxx,xxx
The NL- is an identifier for the country so this could be anything. I would like to remove the NL- part from the line so it looks like this:
xxxx,xxxxx,xxxxxx,xxxxx,xxxx,1111 xx,xxxx,xxx
And write the file afterwards.
Thanks in advance.
Another solution close to sed's ones, but with perl:
perl -i -pe "s/(?<=,)[a-zA-Z]{2}-//g" file.txt
It uses look behind expression, so that you don't need to repeat the comma in the replacement part.
something like this using sed
sed -i 's/,[A-Z][A-Z]-\([0-9]\+,\)/,\1/i' file.txt
,[A-Z][A-Z]-\([0-9]\+,\)search for comma letter, letter, -, digit(s), comma
,\1keep only the commas and the digits.
iignore case on the letters
thankyou to #chris for proof-reading.
I think the simplest solution here is reading it from the file into a shell variable, then writing it back immediately and using the pattern substitution variation of parameter expansion:
line="$(<file)"; echo "${line/[a-zA-Z][a-zA-Z]-}" >|file;
I would warn you against solutions that use sed-in-place functionality. I've found that sed behavior differs on different platforms with respect to the -i option. On Mac you have to give an empty argument ('') to the -i option, while on Cygwin you must not have an empty argument following the -i. To get platform compatibility you'd have to test what platform you're on.
sed might do the trick: remove the string ",NL-", "BE-" etc from anywhere in the file:
sed -i 's/,[A-Z][A-Z]-/,/' file.txt
I have a huge .txt file that I want all spaces, line-breaks, indentations etc removed. It should literally be one long string.
I tried
sed -i 's/\ //g' test.txt
but nothing happens
sed -n "s/[[:blank:]]//g;H
$ {x;s/\n//g;p;}"
The H than $ are needed if you want to include New line due to fact that sed treat by default line by line (so no new line inside a line). The -n and p are needed to avoid double display with use of H
Seems to work ok for me:
[~/Desktop]
==> cat test.txt
the quick brown fox
[~/Desktop]
==> sed -i "s/\ //g" test.txt
[~/Desktop]
==> cat test.txt
thequickbrownfox
Sometimes using " " directly is hard and especially when you use double quotes (which involves that bash will interpret the string before passing it to sed).
sed -i -e 's/\s//g' file.txt
... should work (it works for me). "\s" means all whitespace characters, and with single quotes '', for bash not to interpret it before you passing it to sed.
While you use cygwin I think your OS is windows, then you don't need to use bash to implement your goal. Just open your txt file with the text editor, and replace the while space with nothing, then all of the whit space in you txt file will be removed.
This method can meet almost all kinds of removal. And also can apply in excel or word and so on.
Good luck!
I have a flat file that contains something like this:
11|30646|654387|020751520
11|23861|876521|018277154
11|30645|765418|016658304
Using shell script, I would like to append a string to certain lines in this file, if those lines contain a specific string.
For example, in the above file, for lines containing 23861, I would like to append a string "Processed" at the end, so that the file becomes:
11|30646|654387|020751520
11|23861|876521|018277154|Processed
11|30645|765418|016658304
I could use sed to append the string to all lines in the file, but how do I do it for specific lines ?
I'd do it this way
sed '/\|23861\|/{s/$/|Something/;}' file
This is similar to Marcelo's answer but doesn't require extended expressions and is, I think, a little cleaner.
First, match lines having 23861 between pipes
/\|23861\|/
Then, on those lines, replace the end-of-line with the string |Something
{s/$/|Something/;}
If you want to do more than one of these you could simply list them
sed '/\|23861\|/{s/$/|Something/;};/\|30645\|/{s/$/|SomethingElse/;}' file
Use the following awk-script:
$ awk '/23861/ { $0=$0 "|Processed" } {print}' input
11|30646|654387|020751520
11|23861|876521|018277154|Processed
11|30645|765418|016658304
or, using sed:
$ sed 's/\(.*23861.*$\)/\1|Processed/' input
11|30646|654387|020751520
11|23861|876521|018277154|Processed
11|30645|765418|016658304
Use the substitution command:
sed -i~ -E 's/(\|23861\|.*)/\1|Processed/' flat.file
(Note: the -i~ performs the substitution in-place. Just leave it out if you don't want to modify the original file.)
You can use the shell
while read -r line
do
case "$line" in
*23681*) line="$line|Processed";;
esac
echo "$line"
done < file > tempo && mv tempo file
sed is just a stream version of ed, which has a similar command set but was designed to edit files in place (allegedly interactively, but you wouldn't want to use it that way unless all you had was one of these). Something like
field_2_value=23861
appended_text='|processed'
line_match_regex="^[^|]*|$field_2_value|"
ed "$file" <<EOF
g/$line_match_regex/s/$/$appended_text/
wq
EOF
should get you there.
Note that the $ in .../s/$/... is not expanded by the shell, as are $line_match_regex and $appended_text, because there's no such thing as $/ - instead it's passed through as-is to ed, which interprets it as text to substitute ($ being regex-speak for "end of line").
The syntax to do the same job in sed, should you ever want to do this to a stream rather than a file in place, is very similar except that you don't need the leading g before the regex address:
sed -e "/$line_match_regex/s/$/$appended_text/" "$input_file" >"$output_file"
You need to be sure that the values you put in field_2_value and appended_text never contain slashes, because ed's g and s commands use those for delimiters.
If they might do, and you're using bash or some other shell that allows ${name//search/replace} parameter expansion syntax, you could fix them up on the fly by substituting \/ for every / during expansion of those variables. Because bash also uses / as a substitution delimiter and also uses \ as a character escape, this ends up looking horrible:
appended_text='|n/a'
ed "$file" <<EOF
g/${line_match_regex//\//\\/}/s/$/${appended_text//\//\\/}/
wq
EOF
but it does work. Nnote that both ed and sed require a trailing / after the replacement text in s/search/replace/ while bash's ${name//search/replace} syntax doesn't.