Print the entire row which has difference in value while compare the columns - bash

Question

I want to print the entire row whose value dont match
EG :
Symbol Qty Symbol Qty Symbol qty
a 10 a 10 a 11
b 11 b 11 b 11
c 12 c 12 f 13
f 12 f 12 g 13
OUTPUT :
a 10 a 10 a 11
c 12 c 12 (empty Space)
f 12 f 12 f 13
empty space {ES} g 13
awk 'FNR==NR{a[$0];next}!($0 in a ) ' output1.csv output2.csv >> finn1.csv
awk 'FNR==NR{a[$0];next}!($0 in a ) ' finn1.csv output4.csv >> finn.csv
but this prints all in one column that is missing
Like a 11, but I require the whole line

Answer 1

Assuming that you only want to test for mismatched Qty fields, try this:
#!/bin/bash
declare input_file="/path/to/input_file"
declare -i header_flag=0 a b c
while read line; do
[ ${header_flag} -eq 0 ] && header_flag=1 && continue # Ignore first line.
[ ${#line} -eq 0 ] && continue # Ignore blank lines.
read x a x b x c x <<< ${line} # Reuse ${x} because it is not used.
[ ${a} -ne ${b} -o ${a} -ne ${c} -o ${b} -ne ${c} ] && echo ${line}
done < ${input_file}

Answer 2

The awk one-liner
awk '!($1 == $3 && $2 == $4 && $3 == $5 && $4 == $6)' file
will output
Symbol Qty Symbol Qty Symbol qty
a 10 a 10 a 11
c 12 c 12 f 12
f 12 f 12 g 13
You're going about this the wrong way: you can't mash up all the files into one and then try to find which ones have different/missing values. You need to process the individual files
$ cat file1
Symbol Qty
a 10
b 11
c 12
f 12
$ cat file2
Symbol Qty
a 10
b 11
c 12
f 12
$ cat file3
Symbol qty
a 11
b 11
f 13
g 13
Then
assuming you have GNU awk
gawk '
FNR > 1 { qty[$1][FILENAME] = $1 " " $2 }
END {
OFS = "\t"
for (sym in qty) {
missing = !((ARGV[1] in qty[sym]) && (ARGV[2] in qty[sym]) && (ARGV[3] in qty[sym]))
unequal = !(qty[sym][ARGV[1]] == qty[sym][ARGV[2]] && qty[sym][ARGV[1]] == qty[sym][ARGV[3]])
if (missing || unequal) {
print qty[sym][ARGV[1]], qty[sym][ARGV[2]], qty[sym][ARGV[3]]
}
}
}
' file{1,2,3}
outputs
a 10 a 10 a 11
c 12 c 12
f 12 f 12 f 13
g 13