Laravel Ajax Failed loading Post - ajax

i am trying to update data but i am getting error, failed loading post.
AJAX code:
jQuery(document).ready(function($) {
$('#update-data').on('click',function(){
alert("run");
// e.preventDefault(e);
$.ajax({
type: "POST",
url: "teachers/" + $('#update-data').attr("value"),
dataType: 'json',
headers: { 'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content') },
data : $(this).serialize(),
beforeSend: function() {
},
success: function (data) {
alert("updated");
},
});
});
});
view:
when i try all text field in div i get error failed loading post,
<div id="update-form">
//all text fields
<button type="button"name="id" value="{{#$teacher->id}}" id="update-data" >UPDATE</button>
</div>
but when i put everything in form my data is being updated correctly, but in this case ajax code is totally ignored and only last record is updating.
<form action="#if(isset($teacher)) {{route('teachers.update', $teacher->id)}} #else {{route('teachers.store')}}
#endif" method="post" id="update-form" autocomplete="off" enctype="multipart/form-data" >
<button type="submit" name="id" value="{{#$teacher->id}}" id="update-data" > UPDATE</button>
</form>
Console Error:
app.js:10216 POST http://todolist.local/teachers/729 405 (Method Not Allowed)
app.js:10216 XHR failed loading: POST "http://todolist.local/teachers/729".
javascript?v=1567677915:4 XHR finished loading: GET "http://todolist.local/_debugbar/open?op=get&id=X15228e3cd6c2213f70bded7c0a69583b".
Update Controller:
public function update(TeacherRequest $request, $id)
{
$teacher = Teacher::find($id);
if($teacher->save()){
return response()->json([
'status' => 'success',
'msg' => 'esecond has been updated'
]);
}
}
web.php:
Route::get('/', 'TeachersController#index')->name('home');
Route::resource('teachers', 'TeachersController');

Update your ajax request as below:
jQuery(document).ready(function($) {
$('#update-form').on('submit', function(e) {
e.preventDefault();
$.ajax({
type: "PUT",
/*Your logic*/
});
});
});
View
<form action="#if(isset($teacher)) {{route('teachers.update', $teacher->id)}} #else {{route('teachers.store')}} #endif" method="post" id="update-form" autocomplete="off" enctype="multipart/form-data" >
{{method_field('PUT')}}
{{ csrf_field() }}
<button type="submit" name="id" value="{{#$teacher->id}}" id="update-data" > UPDATE</button>
</form>
Try this..
ajax post caused the webpage to reload before I could get a result, therefore.

Related

why laravel ajax returns json view page

i am using ajax to store the info but when i store or not store it returns a json page and i don't want it to return a json i want to add the item without relead the page and using calidation also
please help
here is my code
my route
Route::resource('products',App\Http\Controllers\ProductController::class);
my form
<form method="POST" id="productform">
#csrf
#method('POST')
<ul id="showerrors">
</ul>
<div class="form-group">
<label for="">name</label>
<input type="text" name="name" class="form-control">
</div>
<button type="button" class="btn btn-secondary" data-bs-dismiss="modal">Close</button>
<button type="submit" class="btn btn-primary">Save changes</button>
</form>
and my ajax code
<script>
$(document).ready(function(){
$('#productform').submit(function(e){
e.preventDefault();
var data = {
'name' : $("input[name='name']").val(),
'_token' : $("input[name='token']").val(),
}
// console.log(data);
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax({
url:"/products",
type : "POST",
data:data,
dataType:'json',
success:function(response){
console.log(response.status);
if(response.status == 400){
$('#showerrors').empty();
$('#showerrors').addClass('alert alert-danger');
$.each(response.errors,function(key,value){
$('#showerrors').append('<li>'+value+'</li>')
});
}
else{
$("#successmessage").empty();
$("#successmessage").addClass('alert alert-success');
$("#successmessage").text(response.message);
$('#exampleModal').modal('toggle'); //or $('#IDModal').modal('hide');
conssole.log(response.message);
return false;
}
},
});
});
});
Try this solution
add id to input field
<input type="text" name="name" class="form-control" id="name">
changes in script
$(document).ready(function(){
$('#productform').submit(function(e){
e.preventDefault();
var name = $('#name').val();
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax({
url:"/products",
type : "POST",
data:{
name: name
},
dataType:'json',
success:function(response){
console.log(response.status);
if(response.status == 400){
$('#showerrors').empty();
$('#showerrors').addClass('alert alert-danger');
$.each(response.errors,function(key,value){
$('#showerrors').append('<li>'+value+'</li>')
});
}
else{
$("#successmessage").empty();
$("#successmessage").addClass('alert alert-success');
$("#successmessage").text(response.message);
$('#exampleModal').modal('toggle'); //or $('#IDModal').modal('hide');
conssole.log(response.message);
return false;
}
},
});
});
});
in your controller store function
suppose your model name is Product
public function store(Request $request)
{
...
$product = Product::create($request->only('name));
return response()->json([
'status' => 200,
'message' => 'Product created successfully.'
]);
}

Refresh the likes counter without reloading the Ajax page

It was necessary to write a method for salting posts in php and decorate the whole thing with ajax so that the page would not reload. The method was written, likes are put, but for the changes to be visible, you need to reload the page. I suspect I made a mistake in the area of success
This is part of the post, you need to update the button with id = "likebtn {{$ post-> id}}"
html form
<form action="{{route('likePost', ['id' => Auth::user()->id, 'postId' => $post->id])}}" method="POST" id="likepostform{{$post->id}}">
#csrf #method('PATCH')
<button data-id="{{$post->id}}" id="likebtn{{$post->id}}" type="submit" class="likebtn button-delete-post-2">
<img src="{{asset('img/footer/like.png')}}" class="img-fluid" width="25"><small class="text-muted mr-4">{{$post->likepost}}</small>
</button>
<input type="hidden" value="{{Auth::user()->id}}" id="user_id">
</form>
Ajax
<script type="text/javascript">
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$(document).ready(function () {
$("body").on("click",".likebtn",function(e){
e.preventDefault();
var id = $(this).data('id');
var token = $("meta[name='csrf-token']").attr("content");
var user_id = $("#user_id").val();
$.ajax({
url: "id"+user_id+"/"+id+"/like",
type: 'PATCH',
data: {_token: token, id: id, user_id: user_id},
success: function (data){
$("#likebtn"+id).html($(data).find("#likebtn"+id).html());
},
error: function() {
alert('error');
}
});
});
});
</script>

WordPress AJAX 400 Bad request while submitting form

I am poor in AJAX and trying to submit the form and insert the record to the custom table since a couple of days but not getting it to work.
I am getting 400 Bad request error on console. Please have a look at the code.
In fact, I have tried multiple ways to submit data but none of them
works.
HTML
<form class="addtocartform" id="gsAddToCart" method="POST">
<label class="gs-label" for="options">Options</label>
<select class="gs-select-box" id="product_option" name="product_option">
<option value="0">Somnath</option>
<option value="1">Dwarka</option>
<option value="2">Rameshwaram</option>
</select>
<label class="gs-label" for="qty">Qty.</label>
<input class="gs-number" id="qty" min="1" name="qty" step="1" type="number" value="1">
<button class="gs-button order-button add-to-cart-button">
<i class="fa fa-cart-plus"></i>
<span class="gs-button-label">Add to Cart</span>
</button>
<input id="product" name="product" type="hidden" value="160"/>
<input id="group_id" name="group_id" type="hidden" value="194"/>
</input>
</form>
WordPress Hooks - Enqueue scripts
function gs_enqueue_ajax_scripts()
{
wp_register_script('gs-ajax', GROUP_SHOP_ROOT . 'public/js/add-to-cart-ajax.js', ['jquery'], 1.0, TRUE);
wp_localize_script('gs-ajax', 'ajax_vars', [
'ajax_url' => admin_url('admin-ajax.php'),
'nonce' => wp_create_nonce('gs_nonce'),
]);
wp_enqueue_script('gs-ajax');
}
add_action('wp_enqueue_scripts', 'gs_enqueue_ajax_scripts');
WordPress Hooks - Process and Insert Data
function gs_add_to_cart_ajax()
{
check_ajax_referer('gs_nonce', $_POST[ 'nonce' ], FALSE);
// validating stuffs ..
$cart = new Group_Shop_Cart();
$cart->add_to_cart($_POST[ 'group_id' ], $_POST[ 'product' ], $_POST[ 'qty' ], $_POST[ 'product_option' ]);
wp_die();
}
add_action('wp_ajax_gs_add_to_cart_ajax', 'gs_add_to_cart_ajax');
add_action('wp_ajax_nopriv_gs_add_to_cart_ajax', 'gs_add_to_cart_ajax');
Javascript
(function ($) {
$(document).on("click", ".add-to-cart-button", function () {
let data = JSON.stringify({
action: 'gs_add_to_cart_ajax',
group_id: $('#group_id').val(),
product: $('#product').val(),
qty: $('#qty').val(),
product_option: $('#product_option').val(),
});
$('form.addtocartform').on('submit', function (e) {
e.preventDefault();
$.ajax({
method: 'POST',
dataType: 'json',
nonce: ajax_vars.nonce,
url: ajax_vars.ajax_url,
data: data,
success: function (response) {
alert("Success");
}
});
});
});
})(jQuery);
I have no idea what is wrong in this code that not submitting.
Modified Code
$.ajax({
method: 'POST',
dataType: 'json',
nonce: ajax_vars.nonce,
url: ajax_vars.ajax_url,
data: {
action: 'gs_add_to_cart_ajax',
group_id: $('#group_id').val(),
product: $('#product').val(),
qty: $('#qty').val(),
product_option: $('#product_option').val(),
},
success: function (response) {
alert("Success");
}
});

Laravel ajax return 404

I'm trying to send data to back-end and i'm getting 404 error with this explanation in network tab:
"message": "",
"exception": "Symfony\\Component\\HttpKernel\\Exception\\NotFoundHttpException",
Route
Route::middleware('verified')->group(function () {
Route::post('/snaptoken/{id}', 'Admin\PayController#token')->name('securepaymentnow');
});
Controller
public function token(Request $request, $id)
{
//Find project
$project = Project::findOrFail($id);
//rest of data
}
Blade
//form and button
<form id="payment-form" method="POST" action="{{route('securepaymentnow', $project->id)}}">
#csrf
<input type="hidden" name="result_type" id="result-type" value="">
<input type="hidden" name="result_data" id="result-data" value="">
</form>
<button class="btn-sm bg-success pay-button" data-id="{{$project->id}}" type="submit"><i class="fas fa-fas fa-shield-alt"></i> Secure Payment</button>
//javascript
$('.pay-button').click(function (event) {
$.ajaxSetup({
headers: { 'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content') }
});
event.preventDefault();
// $(this).attr("disabled", "disabled");
var prdfoId = $(this).data('id');
$.ajax({
url: '{{url("/securepaymentnow")}}/'+encodeURI(prdfoId),
type: "POST",
cache: false,
success: function(data) {
var resultType = document.getElementById('result-type');
var resultData = document.getElementById('result-data');
}
});
});
Any idea?
.........................................................................................................................
if you are using url() function, you should use the {{ url('/snaptoken') }}.
But if you want to use the "name" from the "securepaymentnow", use route() function with this example {{ route('securepaymentnow', $theId) }}.
Both should works.
Refer Laravel NamedRoute for details.

ajax alert is not working using codeigniter

I am newer to ajax. I want to add two fields using ajax and codeigniter.. When i click the submit button the two fields are added but the alert message is not showing also the page is not refreshing. Can any one solve my issue.. Thanks in advance..
This is my Form
<form action="" id="suggestionsform" method="post">
<div class="form-group">
<label for="suggname">Name</label>
<input type="text" class="form-control" name="suggname" id="suggname" placeholder="Enter Your Name" required="required">
</div>
<div class="form-group">
<label for="suggmessage">Suggestion</label>
<textarea class="form-control" rows="4" name="suggmessage" id="suggmessage"
placeholder="Enter Your Suggestions"></textarea>
</div>
<button type="submit" class="btn btn-default" id="suggestions">Submit</button>
</form>
This is my ajax codeing
<script>
// Ajax post
$(document).ready(function() {
$("#suggestions").click(function(event) {
event.preventDefault();
var name = $("#suggname").val();
var suggestion = $("#suggmessage").val();
$.ajax({
type: "POST",
url: "<?php echo site_url('Helen/addSuggestion')?>",
dataType: 'json',
data: {name: name, suggestion: suggestion},
success: function(data) {
if (data=='true')
{
alert("Thank you for your Suggestion");
}
}
});
});
});
</script>
Controller Coding
public function addSuggestion()
{
$data=array(
'name' => $this->input->post('name'),
'messages' => $this->input->post('suggestion'),
'date' => now()
);
$data=$this->Helen_model->setSuggestion($data);
echo json_encode($data);
}
Model Coding
public function setSuggestion($data){
$this->db->insert('messages', $data);
return $this->db->insert_id();
}
You can achieve like this..
Model
Return true status if insert successful.
public function setSuggestion($data){
$res = $this->db->insert('messages', $data);
if($res){
$result = array('status'=>true,'message'=>'successful');
}
else
{
$result = array('status'=>false,'message'=>'failed');
}
return $result;
}
JS
Check status in success function
<script>
// Ajax post
$(document).ready(function() {
$("#suggestions").click(function(event) {
event.preventDefault();
var name = $("#suggname").val();
var suggestion = $("#suggmessage").val();
$.ajax({
type: "POST",
url: "<?php echo site_url('Helen/addSuggestion')?>",
dataType: 'json',
data: {name: name, suggestion: suggestion},
success: function(response) {
data = eval(response);//or data = JSON.parse(response)
if (data.status ===true)
{
alert("Thank you for your Suggestion");
}
}
});
});
});
</script>
Try to use echo '{"status": "success"}; on your controller response.
That i see on your script you are shown database response.

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