I am getting exception when calling findAll method on CrudRepository in quarkus - based code.
Here is my database configuration.
quarkus.datasource.url = jdbc:postgresql://localhost:5432/postgres
quarkus.datasource.driver = org.postgresql.Driver
quarkus.datasource.username = ZZZZ
quarkus.datasource.password = XXX
Here is repository code.
import org.springframework.data.repository.CrudRepository;
public interface FruitRepository extends CrudRepository<FruitEntity, Integer> {
}
Here is client code.
import javax.inject.Inject;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
#Path("/fruitz")
public class FruitController {
#Inject
FruitRepository fruitRepository;
#GET
#Produces("application/json")
public Iterable<FruitEntity> findAll() {
return fruitRepository.findAll();
}
}
I am getting following exception.
Caused by: javax.enterprise.inject.IllegalProductException: Normal scoped producer method may not return null: io.quarkus.agroal.runtime.DataSourceProducer.createDefaultDataSource()
at io.quarkus.agroal.runtime.DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_Bean.create(DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_Bean.zig:306)
at io.quarkus.agroal.runtime.DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_Bean.create(DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_Bean.zig:244)
at io.quarkus.arc.AbstractSharedContext.createInstanceHandle(AbstractSharedContext.java:69)
at io.quarkus.arc.ComputingCache$CacheFunction.lambda$apply$0(ComputingCache.java:99)
at io.quarkus.arc.LazyValue.get(LazyValue.java:26)
at io.quarkus.arc.ComputingCache.getValue(ComputingCache.java:41)
at io.quarkus.arc.AbstractSharedContext.get(AbstractSharedContext.java:20)
at io.quarkus.agroal.runtime.DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_ClientProxy.arc$delegate(DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_ClientProxy.zig:152)
at io.quarkus.agroal.runtime.DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_ClientProxy.getConnection(DataSourceProducer_ProducerMethod_createDefaultDataSource_7c487e3ef869f878aa871e917c94f4d26d5d5c56_ClientProxy.zig:23)
You have to annotate your interface with #Named to make it available for injection. Also ensure to have quarkus-jdbc-postgresql added as a dependency.
Related
I am new in the spring/boot word and have a working JAX-WS based web-service declared in a springboot project. It is started and configured via web.xml and sun-jaxws.xml. So, no beans included there only endpoints declarations and servlet definitions and mappings.
I just now want to save the items i get in the webservice into the mysql database using spring-boot-starter-jdbc which is not working:
I can't achieve this as the repository is not injected in the webservice implementation.
Followed all steps in other question, but not achieving this!
Normally declaration of the datasource parameters in application.properties and annotating #webservice and #Repository would suffice to get the injection of the repository working in the webservice class. What am i missing ?
Here details of the steps I followed:
the webservice implementation is a package X and i created a #SpringBootApplication in order to use a mysql datasource declared in application.properties.
So i annotated the webservice as a #Component and the data access repository with #Repository and #Component
parent version: spring-boot-starter-parent : 1.5.10.RELEASE
webservice service implementation:
BServiceManager.java
package X;
....
#Component
#WebService(name = "***",***)
#BindingType("http://schemas.xmlsoap.org/wsdl/soap/http")
#XmlSeeAlso({
packagesxxx.class,
....
})
public class BServiceManager
implements xxxxx
{
....
#Autowired
private ItemRepository irepo;
....
#WebMethod(**)
#WebResult(***)
public ResponseDataInfo sendInfo( ){
....
trepo.saveitem(item)
....
}
}
ItemRepository.java
package Y.Z;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.dao.DataAccessException;
import org.springframework.stereotype.Component;
import org.springframework.stereotype.Repository;
#Component
#Repository
public class ItemRepository {
#Autowired
private JdbcTemplate jdbcTemplate ;
....
public boolean saveitem(Item item) {
....
}
}
Item.java
package Y.Z;
public class Item {
....
}
GetItemsApplication
package Y;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.ComponentScan;
//#ComponentScan(basePackages={"Y","Y.Z","X"})
#SpringBootApplication
public class GetItemsApplication {
....
public static void main(String[] args) {
SpringApplication.run(GetItemsApplication.class, args);
log.info("--Spring Boot inits done--");
}
}
application.properties
spring.data.jpa.repositories.enabled=false
spring.data.jdbc.repositories.enabled=true
# MySQL properties
spring.datasource.url=****
spring.datasource.username=****
spring.datasource.password=****
....
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
logging.level.org.springframework.jdbc.core.JdbcTemplate=debug
NB: even having datasource bean is not helping :
File: DataSourceConfig.java
package Y.Z;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Qualifier;
import org.springframework.boot.autoconfigure.jdbc.DataSourceBuilder;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.jdbc.core.JdbcTemplate;
//#EnableJdbcRepositories for Spring
#Configuration
public class MDataSourceConfig {
#Bean
public DataSource dataSource() {
DataSourceBuilder dataSourceBuilder = DataSourceBuilder.create();
return dataSourceBuilder.build();
}
#Bean
public JdbcTemplate getJdbcTemplate() {
return new JdbcTemplate(dataSource());
}
}
Your Webservice doesn't seem to get created by Spring.
Therefore Spring has no control over its dependencies, so you have to get the dependency programmatically.
There are many ways to do this.
Easy but not very elegant and uses global variables which might cause problems, especially with tests: https://stackoverflow.com/a/18486178/66686
More elegant but requires weaving Spring autowiring using #Configurable
I have created the basic application using Spring boot using JPA. I have added #AutoWired annotation for RatingRepo in RatingResource, but haven't added #Component annotation to RatingRepo
package com.example.demo;
import java.util.Arrays;
import java.util.List;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
import com.example.demo.RatingsRateService.model.Rating;
import com.example.demo.RatingsRateService.model.UserRating;
#RestController
#RequestMapping("ratingsdata")
public class RatingResource {
#Autowired
RatingRepo repo;
/*
* #RequestMapping("/{movieId}") public Rating
* getRating(#PathVariable("movieId") String movieId) { return new
* Rating(movieId,7); }
*/
#RequestMapping("users/{userid}")
public UserRating getRating(#PathVariable("userid") int userid) {
List<Rating> ratings =repo.findByUserId(userid);
/*
* List<Rating> ratings = Arrays.asList(new Rating("1",4), new Rating("2",3),
* new Rating("3",2));
*/
System.out.println(ratings);
UserRating userRating = new UserRating();
userRating.setUserRating(ratings);
return userRating;
}
}
package com.example.demo;
import java.util.List;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Query;
import com.example.demo.RatingsRateService.model.Rating;
//to update the data in database , created the interd=face and will implement
//class,primary key
public interface RatingRepo extends JpaRepository<Rating, Integer>{
#Query(" from Rating where userid = ?1")
List<Rating> findByUserId( int userid);
}
. Still, it is working fine. Can you someone please explain why it is so? Or it is not needed to add #Component annotation for the repo?
first of there is #Repository annotation required not #Component
and #Repository also auto configure due to below:
Probably you are using spring boot
Spring Data repositories usually extend from the Repository or CrudRepository interfaces. If you are using auto-configuration, repositories will be searched from the package containing your main configuration class (the one annotated with #EnableAutoConfiguration or #SpringBootApplication) down.
ref: https://docs.spring.io/spring-boot/docs/current/reference/html/boot-features-sql.html#boot-features-spring-data-jpa-repositories
I have the below code.
Note that I have an interface MySuperCoolEntityRepositoryContract.
And I have a "concrete interface" MySuperCoolEntityJpaRepository that implements my above MySuperCoolEntityRepositoryContract interface and JpaRepository.
All of that works fine with #ComponentScan.
I am changing my code to "java config", aka a centralized location where I can code up my DI definitions. (Also known as CompositionRoot in some circles).
The issue is when I try to "code up" the concrete for the interface. (Skip down to later in this question.
package com.me.domain.jpaentities;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Transient;
import java.io.Serializable;
import java.math.BigDecimal;
import java.time.LocalDateTime;
import java.util.Collection;
import java.util.LinkedHashSet;
import java.util.Objects;
import java.util.Set;
#Entity(name = "MySuperCoolEntityTableName")
public class MySuperCoolEntity implements Serializable {
#Id
#Column(name = "CoolSurrogateKeyColumn")
private String coolSurrogateKey;
#Column(name = "CoolMagicValueColumn")
private String coolMagicValue;
public String getCoolSurrogateKey() {
return this.coolSurrogateKey;
}
public void setCoolSurrogateKey(String coolSurrogateKey) {
this.coolSurrogateKey = coolSurrogateKey;
}
public String getCoolMagicValue() {
return this.coolMagicValue;
}
public void setCoolMagicValue(String coolMagicValue) {
this.coolMagicValue = coolMagicValue;
}
}
===============
package com.me.dal.repositories.interfaces;
import com.me.domain.jpaentities.MySuperCoolEntity;
import java.util.Collection;
public interface MySuperCoolEntityRepositoryContract {
Collection<MySuperCoolEntity> findByCoolMagicValue(String coolMagicValue);
}
=========================
package com.me.dal.repositories;
import com.me.dal.repositories.interfaces.MySuperCoolEntityRepositoryContract;
import com.me.domain.jpaentities.MySuperCoolEntity;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.stereotype.Repository;
import java.util.Collection;
#Repository
public interface MySuperCoolEntityJpaRepository extends MySuperCoolEntityRepositoryContract, JpaRepository<MySuperCoolEntity,String> {
Collection<MySuperCoolEntity> findByCoolMagicValue(String coolMagicValue);
}
Now this issue.
package com.me.myapplication.configuration;
import com.me.dal.repositories.MySuperCoolEntityJpaRepository;
import com.me.dal.repositories.interfaces.MySuperCoolEntityRepositoryContract;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
#Configuration
public class MyCompositionRoot {
#Bean
public MySuperCoolEntityRepositoryContract getAMySuperCoolEntityRepositoryContract()
{
return new MySuperCoolEntityJpaRepository(); /* << issue is here, this is an abstract class, aka, an interface with some methods defined */
}
}
Using the super cool JpaRepository "concrete interface" aka "really an abstract class but called an interface" aka "Interface Default Methods" ( see https://dzone.com/articles/interface-default-methods-java ) ........
The exact error is:
MySuperCoolEntityJpaRepository is abstract; cannot be instantiated
I do understand the error. MySuperCoolEntityJpaRepository is abstract. I get that.
But with this super cool "just extend JpaRepository and get all kinds of default functionality".....
How do I register a concrete JpaRepository with Spring DI (specifically with "code it up" java config ?
............
I tried making it a "class".
public class MySuperCoolEntityJpaRepository extends MySuperCoolEntityRepositoryContract, JpaRepository<MySuperCoolEntity,String>
but that wants me to define all those built in methods like "findAll",etc, etc.
Spring boot magically provides implementation for the methods defined in your interface. The #EnableJpaRepositories scans all packages below the package for interfaces extending JpaRepository and creates a Spring bean for it that is backed by an implementation of SimpleJpaRepository (spring data provides default imlpementations of CRUD repository through this class).
Your interface MySuperCoolEntityJpaRepository extends the interface MySuperCoolEntityRepositoryContract , but you only extend the JpaRepository on the interface MySuperCoolEntityJpaRepository which means spring will only provide the default implementations for methods in the interface MySuperCoolEntityJpaRepository . So try it like :
public interface MySuperCoolEntityRepositoryContract extends JpaRepository<MySuperCoolEntity,String>{
Collection<MySuperCoolEntity> findByCoolMagicValue(String coolMagicValue);
}
then extend this in your repository like :
#Repository
public interface MySuperCoolEntityJpaRepository extends MySuperCoolEntityRepositoryContract {
Collection<MySuperCoolEntity> findByCoolMagicValue(String coolMagicValue);
}
Related Post : how annotation #Repository in java spring work?
I figured out a workaround. I don't really like it, but I guess it works.
I also added MySuperCoolEntityBalServiceContract (you can get the idea from just the below), so you know why/how I need to have the getAMySuperCoolEntityRepositoryContract method in my CompositionRoot class below.
I'll leave this (not marked) as the answer in case someone else has a better way, or sees issue(s) with the below. I don't like the EntitiyManager work around, but it got things moving.
package com.me.myapplication.configuration;
import com.me.apicore.managers.MySuperCoolEntityBalService;
import com.me.apicore.managers.interfaces.MySuperCoolEntityBalServiceContract;
import com.me.dal.repositories.interfaces.MySuperCoolEntityRepositoryContract;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.data.jpa.repository.support.JpaRepositoryFactory;
import org.springframework.data.repository.core.support.RepositoryFactorySupport;
import javax.inject.Inject;
import javax.persistence.EntityManager;
#Configuration
public class MyCompositionRoot {
#Inject
private EntityManager entManager; /* part of the work around trick */
#Bean
public MySuperCoolEntityBalServiceContract getAMySuperCoolEntityBalServiceContract() {
return new MySuperCoolEntityBalService(this.getAMySuperCoolEntityRepositoryContract());
}
#Bean
public MySuperCoolEntityRepositoryContract getAMySuperCoolEntityRepositoryContract() {
//return new MySuperCoolEntityJpaRepository(); /* does not work. :( */
RepositoryFactorySupport factory = new JpaRepositoryFactory(entManager);
MySuperCoolEntityRepositoryContract repository = factory.getRepository(MySuperCoolEntityRepositoryContract.class);
return repository;
}
}
And I tweaked this (note the addition of the RepositoryDefinition annotation)
package com.me.dal.repositories.interfaces;
import com.me.domain.jpaentities.MySuperCoolEntity;
import org.springframework.data.repository.RepositoryDefinition;
import java.util.Collection;
#RepositoryDefinition(domainClass = MySuperCoolEntity.class, idClass = String.class)
public interface MySuperCoolEntityRepositoryContract {
Collection<MySuperCoolEntity> findByCoolMagicValue(String coolMagicValue);
}
i am writing a junit test that have to invoke some method from some autowired dependency which has to interact with Cassandra, but i am getting this exception:
[ERROR] Tests run: 1, Failures: 0, Errors: 1, Skipped: 0, Time elapsed: 0.21 s <<< FAILURE! - in unicon.mattheews.admin.service.repository.test.AdminUserRepositoryTests
[ERROR] testFindByUsername(unicon.mattheews.admin.service.repository.test.AdminUserRepositoryTests) Time elapsed: 0.001 s <<< ERROR!
org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'unicon.mattheews.admin.service.repository.test.AdminUserRepositoryTests': Unsatisfied dependency expressed through field 'repository'; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type 'unicon.matthews.admin.service.repository.AdminUserRepository' available: expected at least 1 bean which qualifies as autowire candidate. Dependency annotations: {#org.springframework.beans.factory.annotation.Autowired(required=true)}
Caused by: org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type 'unicon.matthews.admin.service.repository.AdminUserRepository' available: expected at least 1 bean which qualifies as autowire candidate. Dependency annotations: {#org.springframework.beans.factory.annotation.Autowired(required=true)}
This is the junit test:
import static org.hamcrest.Matchers.hasItems;
import static org.hamcrest.Matchers.is;
import static org.junit.Assert.assertEquals;
import static org.junit.Assert.assertNotNull;
import static org.junit.Assert.assertThat;
import java.util.HashMap;
import java.util.Map;
import java.util.Optional;
import java.util.stream.Collectors;
import java.util.stream.Stream;
import org.junit.Before;
import org.junit.ClassRule;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.data.util.Version;
import org.springframework.test.context.junit4.SpringRunner;
import example.springdata.cassandra.util.CassandraKeyspace;
import unicon.matthews.admin.AdminUser;
import unicon.matthews.admin.service.repository.AdminUserRepository;
#RunWith(SpringRunner.class)
#SpringBootTest(classes = CassandraConfiguration.class)
public class AdminUserRepositoryTests {
#ClassRule public final static CassandraKeyspace CASSANDRA_KEYSPACE = CassandraKeyspace.onLocalhost().atLeast(Version.parse("3.0"));
#Autowired AdminUserRepository repository;
#Before
public void setUp() throws Exception {
repository.deleteAll();
}
#Test
public void testFindByUsername() {
try {
final String userName = "aironman";
AdminUser.Builder myBuilderAdmin = AdminUser.Builder.class.newInstance();
myBuilderAdmin.withId("id");
myBuilderAdmin.withEmailAddress("some#domain.com");
myBuilderAdmin.withOrgId("orgId");
myBuilderAdmin.withPassword("some-password");
myBuilderAdmin.withSuperAdmin(Boolean.TRUE);
myBuilderAdmin.withTenantId("tenantId");
myBuilderAdmin.withUserName(userName);
//que viene aqui exactamente?
Map<String, String> someMetadata = new HashMap<String, String>();
someMetadata.put("some-key","some-value");
myBuilderAdmin.withMetadata(someMetadata);
AdminUser myAdminUser = myBuilderAdmin.build();
repository.save(myAdminUser);
Optional<AdminUser> loadedUserName = repository.findByUsername(userName);
assertNotNull(loadedUserName);
// assertThat(repository.findOne(homer.id).isPresent(), is(true));
assertEquals("something went wrong!",userName,loadedUserName.get().getUsername());
} catch (InstantiationException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
}
System.out.println("Done testFindByUsername!");
}
}
AdminUserRepository looks like:
import java.util.Optional;
import org.springframework.data.cassandra.repository.Query;
import org.springframework.data.repository.CrudRepository;
import org.springframework.stereotype.Repository;
import unicon.matthews.admin.AdminUser;
#Repository
public interface AdminUserRepository extends CrudRepository<AdminUser, String> {
#Query("select * from AdminUser where username = ?0")
Optional<AdminUser> findByUsername(final String userName);
}
CassandraConfiguration looks like:
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.annotation.Configuration;
import org.springframework.data.cassandra.config.SchemaAction;
import org.springframework.data.cassandra.config.java.AbstractCassandraConfiguration;
import org.springframework.data.cassandra.repository.config.EnableCassandraRepositories;
#Configuration
#EnableAutoConfiguration
class CassandraConfiguration {
#Configuration
#EnableCassandraRepositories
static class CassandraConfig extends AbstractCassandraConfiguration {
#Override
public String getKeyspaceName() {
return "example";
}
#Override
public SchemaAction getSchemaAction() {
return SchemaAction.RECREATE;
}
}
}
I understand that spring is trying to instantiate this AdminUserRepository class which is created using CrudRepository from spring-data project. It is supposed that if i mark this interface with #Repository, spring will instantiate the class within the spring context in order that another bean will be capable to autowire it within it, so, why spring is not able to instantiate the dependency?
AdminUserRepository interface is located within src/main/java and AdminUserRepositoryTests is located within src/test/java.
this is my actual pom.xml, please help.
Marking a Spring data repository with #Repository actually doesn't do anything. If you wan't to enable a CrudRepository you need to annotate your configuration with #EnableJpaRepositories. However, since you are using Cassandra I think it's more likely you want to be using a CassandraRepository ?
public interface AdminUserRepository extends CassandraRepository<AdminUser, String> {
#Query("select * from AdminUser where username = ?0")
Optional<AdminUser> findByUsername(final String userName);
}
Having some trouble injecting a dependency in one of my JUnit test classes.
I believe the TestApplication is not package scanning or is not being loaded.
Code below:
package com.mitto.repositories;
import static org.junit.Assert.*;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.TestExecutionListeners;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import org.springframework.test.context.support.DependencyInjectionTestExecutionListener;
import org.springframework.test.context.transaction.TransactionalTestExecutionListener;
import com.github.springtestdbunit.DbUnitTestExecutionListener;
import com.github.springtestdbunit.annotation.DatabaseSetup;
import com.mitto.MittoApplicationTests;
import com.mitto.domain.User;
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration( classes= { MittoApplicationTests.class } )
#TestExecutionListeners({DependencyInjectionTestExecutionListener.class,
TransactionalTestExecutionListener.class,
DbUnitTestExecutionListener.class})
#DatabaseSetup("UserRepositoryTest.xml")
public class UserRepositoryTest {
#Autowired
UserRepository repository;
private static final long FACEBOOK_ID = 1234567;
#Test
public void getUserById() {
User user = repository.findOne(1L);
assertNotNull(user);
assertEquals( user.getFacebookId(), FACEBOOK_ID );
}
}
MittoApplicationTests.java
package com.mitto;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
#RunWith(SpringRunner.class)
#SpringBootTest
public class MittoApplicationTests {
#Test
public void contextLoads() {
}
}
UserRepository.java
package com.mitto.repositories;
import org.springframework.data.repository.PagingAndSortingRepository;
import org.springframework.stereotype.Repository;
import com.mitto.domain.User;
#Repository
public interface UserRepository extends PagingAndSortingRepository<User, Long>{
User findByFacebookId( long facebookId );
User findByAuthToken( String token );
}
I can't see anything wrong with this.
Sometimes, a working example is better than fixes.
Here is a working example:
First, in your configuration class
#SpringBootApplication
#ComponentScan(value = "com.mitto")
#EnableJpaRepositories(value = "com.mitto")
#EntityScan(basePackages = {"com.mitto.domain"}, basePackageClasses = {Jsr310JpaConverters.class})
public class MittoApplicationTests {
}
Second, in your test class
#RunWith(SpringJUnit4ClassRunner.class)
#SpringBootTest(classes = MittoApplicationTests.class) // replace the #ContextConfiguration with #SpringBootTest
// rest of of your annotations ...
public class UserRepositoryTest {
#Autowired
UserRepository repository;
// your test cases
}
A Spring Boot application is just a Spring ApplicationContext, so nothing very special has to be done to test it beyond what you would normally do with a vanilla Spring context. One thing to watch out for though is that the external properties, logging and other features of Spring Boot are only installed in the context by default if you use SpringApplication to create it.
Spring Boot provides a #SpringBootTest annotation which can be used as an alternative to the standard spring-test #ContextConfiguration annotation when you need Spring Boot features. The annotation works by creating the ApplicationContext used in your tests via SpringApplication.
Please read the documentation for more details:
SpringBootTest annotation
boot-features-testing