I have few files. e.g.
file1.txt
1 2 3 4
2 3 3 4
3 2 4 2
7 2 0 0
1 2 9 9
3 0 9 0
file2.txt
3
4
2
33
NAN
NAN
file3.txt
2
4
4
NAN
NAN
NAN
I would like to print 1st column from each file in a new file with replacing NAN to "?".
The desire output file:
ofile.txt
1 3 2
2 4 4
3 2 4
7 33 ?
1 ? ?
3 ? ?
I was trying with awk '$1 {print}' file1.txt file2.txt file3.txt > ofile.txt
but it is not printing my desire output.
You may use this single awk to get this output:
awk '{s[FNR] = (s[FNR] == "" ? "" : s[FNR] "\t") ($1 == "NAN" ? "?" : $1)}
END{for (i=1; i<=length(s); i++) print s[i]}' file[123].txt
1 3 2
2 4 4
3 2 4
7 33 ?
1 ? ?
3 ? ?
To store output in a file use > ofile.txt at the end of above command.
EDIT: Since OP has control M characters in his/her Input_file so adding solution as per that now. This should remove control M characters from Input_files too.
paste <(awk '{gsub(/\r/,"");print $1}' file1) file2 file3 | awk '{gsub(/\r/,"");gsub(/NAN/,"?")} 1'
Could you please try following.
paste <(awk '{print $1}' file1) file2 file3 | awk '{gsub(/NAN/,"?")} 1'
Using multiple awk
paste <(awk '{print $1}' file1 ) <(awk '{print $1}' file2 ) <(awk '{print $1}' file3) | sed 's/NAN/\?/g'
or
paste <(awk '{print $1}' file1 ) <(awk '{print $1}' file2 ) <(awk '{print $1}' file3) |awk '{gsub("NAN", "?", $0); print}'
Related
I am trying to add values in Column B based on unique value in Column A. How can i do it using AWK (or) Any other way using bash?
Column_A | Column_B
--------------------
A | 1
A | 2
A | 1
B | 3
B | 8
C | 5
C | 8
Result:
Column_A | Column_B
--------------------
A | 6
B | 11
C | 13
Considering that your Input_file is same as shown, sorted with first field, could you please try following(will edit solution for alignment too soon).
awk '
BEGIN{
OFS=" | "
}
FNR==1 || /^-/{
print
next
}
prev!=$1 && prev{
print prev,sum
prev=sum=""
}
{
sum+=$NF
prev=$1
}
END{
if(prev && sum){
print prev,sum
}
}' Input_file
another awk
$ awk 'NR<3 {print; next}
{a[$1]+=$NF; line[$1]=$0}
END {for(k in a) {sub(/[0-9]+$/,a[k],line[k]); print line[k]}}' file
Column_A | Column_B
--------------------
A | 4
B | 11
C | 13
note that A totals to 4, not 6.
One possible solution (Assuming file is in CSV format):
Input :
$ cat csvtest.csv
A,1
A,2
A,3
B,3
B,8
C,5
C,8
$ cat csvtest.csv | awk -F "," '{arr[$1]+=$2} END {for (i in arr) {print i","arr[i]}}'
A,6
B,11
C,13
I want, the selected lines of file to be print in output file side by side separated by space. Here what I have did so far,
for file in SAC*
do
awk 'FNR==2 {print $4}' $file >>exp
awk 'FNR==3 {print $4}' $file >>exp
awk 'FNR==4 {print $4}' $file >>exp
awk 'FNR==5 {print $4}' $file >>exp
awk 'FNR==7 {print $4}' $file >>exp
awk 'FNR==8 {print $4}' $file >>exp
awk 'FNR==24 {print $0}' $file >>exp
done
My output is:
XV
AMPY
BHZ
2012-08-15T08:00:00
2013-12-31T23:59:59
I want output should be
XV AMPY BHZ 2012-08-15T08:00:00 2013-12-31T23:59:59
First the test data (only 9 rows, tho):
$ cat file
1 2 3 14
1 2 3 24
1 2 3 34
1 2 3 44
1 2 3 54
1 2 3 64
1 2 3 74
1 2 3 84
1 2 3 94
Then the awk. No need for that for loop in shell, awk can handle multiple files:
$ awk '
BEGIN {
ORS=" "
a[2];a[3];a[4];a[5];a[7];a[8] # list of records for which $4 should be outputed
}
FNR in a { print $4 } # output the $4s
FNR==9 { printf "%s\n",$0 } # replace 9 with 24
' file file # ... # the files you want to process (SAC*)
24 34 44 54 74 84 1 2 3 94
24 34 44 54 74 84 1 2 3 94
I have two files, file1.csv
3 1009
7 1012
2 1013
8 1014
and file2.csv
5 1009
3 1010
1 1013
In the shell, I want to subtract the count in the first column in the second file from that in the first file, based on the identifier in the second column. If an identifier is missing in the second column, the count is assumed to be 0.
The result would be
-2 1009
-3 1010
7 1012
1 1013
8 1014
The files are huge (several GB). The second columns are sorted.
How would I do this efficiently in the shell?
Assuming that both files are sorted on second column:
$ join -j2 -a1 -a2 -oauto -e0 file1 file2 | awk '{print $2 - $3, $1}'
-2 1009
-3 1010
7 1012
1 1013
8 1014
join will join sorted files.
-j2 will join one second column.
-a1 will print records from file1 even it there is no corresponding row in file2.
-a2 Same as -a1 but applied for file2.
-oauto is in this case the same as -o1.2,1.1,2.1 which will print the joined column, and then the remaining columns from file1 and file2.
-e0 will insert 0 instead of an empty column. This works with -a1 and -a2.
The output from join is three columns like:
1009 3 5
1010 0 3
1012 7 0
1013 2 1
1014 8 0
Which is piped to awk, to subtract column three from column 2, and then reformatting.
$ awk 'NR==FNR { a[$2]=$1; next }
{ a[$2]-=$1 }
END { for(i in a) print a[i],i }' file1 file2
7 1012
1 1013
8 1014
-2 1009
-3 1010
It reads the first file in memory so you should have enough memory available. If you don't have the memory, I would maybe sort -k2 the files first, then sort -m (merge) them and continue with that output:
$ sort -m -k2 -k3 <(sed 's/$/ 1/' file1|sort -k2) <(sed 's/$/ 2/' file2|sort -k2) # | awk ...
3 1009 1
5 1009 2 # previous $2 = current $2 -> subtract
3 1010 2 # previous $2 =/= current and current $3=2 print -$3
7 1012 1
2 1013 1 # previous $2 =/= current and current $3=1 print prev $2
1 1013 2
8 1014 1
(I'm out of time for now, maybe I'll finish it later)
EDIT by Ed Morton
Hope you don't mind me adding what I was working on rather than posting my own extremely similar answer, feel free to modify or delete it:
$ cat tst.awk
{ split(prev,p) }
$2 == p[2] {
print p[1] - $1, p[2]
prev = ""
next
}
p[2] != "" {
print (p[3] == 1 ? p[1] : 0-p[1]), p[2]
}
{ prev = $0 }
END {
split(prev,p)
print (p[3] == 1 ? p[1] : 0-p[1]), p[2]
}
$ sort -m -k2 <(sed 's/$/ 1/' file1) <(sed 's/$/ 2/' file2) | awk -f tst.awk
-2 1009
-3 1010
7 1012
1 1013
8 1014
Since the files are sorted¹, you can merge them line-by-line with the join utility in coreutils:
$ join -j2 -o auto -e 0 -a 1 -a 2 41144043-a 41144043-b
1009 3 5
1010 0 3
1012 7 0
1013 2 1
1014 8 0
All those options are required:
-j2 says to join based on the second column of each file
-o auto says to make every row have the same format, beginning with the join key
-e 0 says that missing values should be substituted with zero
-a 1 and -a 2 include rows that are absent from one file or another
the filenames (I've used names based on the question number here)
Now we have a stream of output in that format, we can do the subtraction on each line. I used this GNU sed command to transform the above output into a dc program:
sed -re 's/.*/c&-n[ ]np/e'
This takes the three values on each line and rearranges them into a dc command for the subtraction, then executes it. For example, the first line becomes (with spaces added for clarity)
c 1009 3 5 -n [ ]n p
which subtracts 5 from 3, prints it, then prints a space, then prints 1009 and a newline, giving
-2 1009
as required.
We can then pipe all these lines into dc, giving us the output file that we want:
$ join -o auto -j2 -e 0 -a 1 -a 2 41144043-a 41144043-b \
> | sed -e 's/.*/c& -n[ ]np/' \
> | dc
-2 1009
-3 1010
7 1012
1 1013
8 1014
¹ The sorting needs to be consistent with LC_COLLATE locale setting. That's unlikely to be an issue if the fields are always numeric.
TL;DR
The full command is:
join -o auto -j2 -e 0 -a 1 -a 2 "$file1" "$file2" | sed -e 's/.*/c& -n[ ]np/' | dc
It works a line at a time, and starts only the three processes you see, so should be reasonably efficient in both memory and CPU.
Assuming this is a csv with blank separation, if this is a "," use argument -F ','
awk 'FNR==NR {Inits[$2]=$1; ids[$2]++; next}
{Discounts[$2]=$1; ids[$2]++}
END { for (id in ids) print Inits[ id] - Discounts[ id] " " id}
' file1.csv file2.csv
for memory issue (could be in 1 serie of pipe but prefer to use a temporary file)
awk 'FNR==NR{print;next}{print -1 * $1 " " $2}' file1 file2 \
| sort -k2 \
> file.tmp
awk 'Last != $2 {
if (NR != 1) print Result " "Last
Last = $2; Result = $1
}
Last == $2 { Result+= $1; next}
END { print Result " " $2}
' file.tmp
rm file.tmp
Using Shell Script (Bash), I am trying to sum the columns for all the different variables of a list. Suppose I have the following input of a Test.tsv file
Win Lost
Anna 1 1
Charlotte 3 1
Lauren 5 5
Lauren 6 3
Charlotte 3 2
Charlotte 4 5
Charlotte 2 5
Anna 6 4
Charlotte 2 3
Lauren 3 6
Anna 1 2
Anna 6 2
Lauren 2 1
Lauren 5 5
Lauren 6 6
Charlotte 1 3
Anna 1 4
And I want to sum up how much each of the participants have won and lost. So I want to get this as a result:
Sum Win Sum Lost
Anna 57 58
Charlotte 56 57
Lauren 53 56
What I would usually do is take the sum per person and per column and repeat that process over and over. See below how I would do it for the example mentioned:
cat Test.tsv | grep -Pi '\bAnna\b' | cut -f2 -d$'\t' |paste -sd+ | bc > Output.tsv
cat Test.tsv | grep -Pi '\bCharlotte\b' | cut -f2 -d$'\t' |paste -sd+ | bc >> Output.tsv
cat Test.tsv | grep -Pi '\bLauren\b' | cut -f2 -d$'\t' |paste -sd+ | bc >> Output.tsv
cat Test.tsv | grep -Pi '\bAnna\b' | cut -f3 -d$'\t' |paste -sd+ | bc > Output.tsv
cat Test.tsv | grep -Pi '\bCharlotte\b' | cut -f3 -d$'\t' |paste -sd+ | bc >> Output.tsv
cat Test.tsv | grep -Pi '\bLauren\b' | cut -f3 -d$'\t' |paste -sd+ | bc >> Output.tsv
However I would need to repeat this line for every participant. This becomes a pain when you have to many variables you want to sum it up for.
What would be the way to write this script?
Thanks!
This is pretty straightforward with awk. Using GNU awk:
awk -F '\t' 'BEGIN { OFS = FS } NR > 1 { won[$1] += $2; lost[$1] += $3 } END { PROCINFO["sorted_in"] = "#ind_str_asc"; print "", "Sum Win", "Sum Lost"; for(p in won) print p, won[p], lost[p] }' filename
-F '\t' makes awk split lines at tabs, then:
BEGIN { OFS = FS } # the output should be separated the same way as the input
NR > 1 { # From the second line forward (skip header)
won[$1] += $2 # tally up totals
lost[$1] += $3
}
END { # When done, print the lot.
# GNU-specific: Sorted traversal or player names
PROCINFO["sorted_in"] = "#ind_str_asc"
print "", "Sum Win", "Sum Lost"
for(p in won) print p, won[p], lost[p]
}
I have two text files each with 3 fields. I need to get the lines with the same value on the third field. The 3rd field value is unique in each file. Example:
file1:
1 John 300
2 Eli 200
3 Chris 100
4 Ann 600
file2:
6 Kevin 250
7 Nancy 300
8 John 100
output:
1 John 300
7 Nancy 300
3 Chris 100
8 John 100
When I use the following command:
cat file1 file2 | sort -k 3 | uniq -c -f 2
I get only one row from an input file with the duplicate value. I need both!
this one-liner gives you that output:
awk 'NR==FNR{a[$3]=$0;next}$3 in a{print a[$3];print}' file1 file2
My solution is
join -1 3 -2 3 <(sort -k3 file1) <(sort -k3 file2) | awk '{print $2, $3, $1; print $4, $5, $1}'
or
join -1 3 -2 3 <(sort -k3 file1) <(sort -k3 file2) -o "1.1 1.2 0 2.1 2.2 0" | xargs -n3