Find the durations and their maximum between the dataset in an interval in shell script - shell

Question

This is related to my older question Find the durations and their maximum between the dataset in shell script
I have a dataset as:
ifile.txt
2
3
2
3
2
20
2
0
2
0
0
2
1
2
5
6
7
0
3
0
3
4
5
I would like to find out different duration and their maximum between the 0 values in 6 values interval.
My desire output is:
ofile.txt
6 20
1 2
1 2
1 2
5 7
1 3
3 5
Where
6 is the number of counts until next 0 within 6 values (i.e. 2,3,2,3,2,20) and 20 is the maximum value among them;
1 is the number of counts until next 0 within next 6 values (i.e. 2,0,2,0,0,2) and 2 is the maxmimum;
Next 1 and 2 are withing same 6 values;
5 is the number of counts until next 0 within next 6 values (i.e. 1,2,5,6,7,0) and 7 is the maximum among them;
And so on
As per the answer in my previous question, I was trying with this:
awk '(NR%6)==0
$0!=0{
count++
max=max>$0?max:$0
}
$0==0{
if(count){
print count,max
}
count=max=""
}
END{
if(count){
print count,max
}
}
' ifile.txt

Answer 1

A format command added to the EDIT2 solution given by RavinderSingh13 which will print exact desire output:
awk '
$0!=0{
count++
max=max>$0?max:$0
found=""
}
$0==0{
print count,max
count=max=0
next
}
FNR%6==0{
print count,max
count=max=0
found=1
}
END{
if(!found){
print count,max
}
}
' Input_file | awk '!/^ /' | awk '$1 != 0'
Output will be as follows.
6 20
1 2
1 2
1 2
5 7
1 3
3 5
EDIT2: Adding another solution which will print values in every 6 elements along with zeros coming in between.
awk '
$0!=0{
count++
max=max>$0?max:$0
found=""
}
$0==0{
print count,max
count=max=0
next
}
FNR%6==0{
print count,max
count=max=0
found=1
}
END{
if(!found){
print count,max
}
}
' Input_file
Output will be as follows.
6 20
1 2
1 2
0 0
1 2
5 7
1 3
3 5
EDIT: As per OP's comment OP doesn't want to reset of count of non-zeros when a zero value comes in that case try following.
awk '
$0!=0{
count++
max=max>$0?max:$0
found=""
}
FNR%6==0{
print count,max
count=max=0
found=1
}
END{
if(!found){
print count,max
}
}
' Input_file
Output will be as follows.
6 20
3 2
5 7
.......
Could you please try following(written and tested with posted samples only).
awk '
$0!=0{
count++
max=max>$0?max:$0
found=""
}
$0==0{
count=FNR%6==0?count:0
found=""
}
FNR%6==0{
print count,max
count=max=0
found=1
}
END{
if(!found){
print count,max
}
}
' Input_file