I have some JSON data which get from an API. I need only the products name from there. How can I get this? I am already trying with foreach loop but I can't. I am using laravel framework version 6.0
[
{
"id": 2,
"name": "Bijj",
"categories": [
{
"id": 10,
"name": "Rice",
"sbu": 2,
"products" : [
{
"id": 25,
"name": "Rajkumar",
"skus": [],
"short_description": "বাংলাদেশের আবহাওয়া উপযোগী হাইব্রিড ধান",
},
{
"id": 50,
"name": "Sera",
"skus": [],
"short_description": "বাংলাদেশের আবহাওয়া উপযোগী হাইব্রিড ধান",
}
]
},
{
"id": 20,
"name": "Vhutta",
"sbu": 2,
"products" : [
{
"id": 129,
"name": "Pack-139",
"skus": [],
"short_description": "মোচায় ৮৬ % দানা ও ১৪ % শাঁস",
},
{
"id": 125,
"name": "Don-12",
"skus": [],
"short_description": "সারা বৎসর চাষ উপযোগী",
}
]
}
]
}
]
I want to get only the all products name form there.
$getSbu = Helper::CreateGuzzleHttpClient('sbu');
foreach ($getSbu as $value) {
if($value->id == 2) {
foreach ($value->categories as $category) {
$products = $category->products;
}
}
}
After decode you can simply use this helper
use Illuminate\Support\Arr;
Arr::only($array, ['categories.products.name']);
or
Arr::only($array, ['categories.*.name']);
you want get only product's name ??
and if your data array then you have to change $value['id']
$product_names = [];
foreach ($getSbu as $value) {
if($value->id == 2) {
foreach ($value->categories as $category) {
foreach ($category->products as $product) {
$product_names[] = $product->name;
}
}
}
}
dd($product_names);
foreach (json_decode($getSbu) as $value) {
Foreach works in an array so first you must decode it in order to parse it as an array.
Since you use object parsing you don't have to use parameter true in your json_decode function. If you want an array instead of an object you can use:
foreach (json_decode($getSbu,true) as $value) {
but then you access your value like array fields, for example value['id']
Your code should look like:
$getSbu = Helper::CreateGuzzleHttpClient('sbu');
foreach (json_decode($getSbu) as $value) {
if($value->id == 2) {
foreach ($value->categories as $category) {
$products = $category->products;
}
}
}
Leverage aravel collections
// this is just ur data but as json string
$var = '[{"id":2,"name":"Bijj","categories":[{"id":10,"name":"Rice","sbu":2,"products":[{"id":25,"name":"Rajkumar","skus":[],"short_description":"বাংলাদেশের আবহাওয়া উপযোগী হাইব্রিড ধান"},{"id":50,"name":"Sera","skus":[],"short_description":"বাংলাদেশের আবহাওয়া উপযোগী হাইব্রিড ধান"}]},{"id":20,"name":"Vhutta","sbu":2,"products":[{"id":129,"name":"Pack-139","skus":[],"short_description":"মোচায় ৮৬ % দানা ও ১৪ % শাঁস"},{"id":125,"name":"Don-12","skus":[],"short_description":"সারা বৎসর চাষ উপযোগী"}]}]}]';
$objCollection = collect(json_decode($var, true));
$productNames = $objCollection->pluck('categories.*.products.*.name');
dd($productNames);
Related
I got like this
[
{
"NameProduct": "iphone",
"IDProduct": 1,
"ListPrice": 100000,
"ImagePath": "iphone.png"
},
[
{
"IDCollection": 5,
"NameCollection": "Phone",
"Description": "my description",
}
],
{
"NameProduct": "SamSung",
"IDProduct": 2,
"ListPrice": 379000,
"ImagePath": "samsung.png"
},
[
{
"IDCollection": 5,
"NameCollection": "Phone",
"Description": "my description",
}
],
But I want like this:
{
"IDCollection": 5,
"NameCollection": "Phone",
"ProductList": [
{
"NameProduct": "iphone",
"IDProduct": 1,
"ListPrice": 100000,
"ImagePath": "iphone.png"
},
{
"NameProduct": "SamSung",
"IDProduct": 2,
"ListPrice": 100000,
"ImagePath": "samsung.png"
},
]
}
This is my code:
public function show(int $id)
{
$product=[];
$product_collection = CollectionProduct::where('IDCollection',$id)->get();
$collection = Collection::where('IDCollection',$id)->get();
foreach ($product_collection as $items) {
$x = Product::select('NameProduct','IDProduct','ListPrice')->find($items['IDProduct']);
$x->ImagePath = ProductImage::where('IDProduct',$items['IDProduct'])->first()['Path'];
array_push($product, $x,$collection);
}
return response()->json($product);
}
and idea how do that ?
You can use Eager Loading to get the relationships of CollectionProduct. https://laravel.com/docs/9.x/eloquent-relationships#eager-loading
For help you with the code I need to see your relationships of the DB but I think this can help you:
public function show(int $id)
{
$product_collection = CollectionProduct::with('collection.product.productImage')
->where('IDCollection',$id)
->get();
return response()->json($product_collection);
}
I have data as below:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
]
I want to filter which is is_lottery == false remove the price key from this collection. The output is:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
}
]
You can do this
$json = '[
{
"id": "3",
"title": "Boruto\'s Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "3",
"title": "Misuki\'s Photo",
"is_lottery": 0,
"price": 20
}
]';
$filtered = collect(json_decode($json, true))->map(function ($array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
return $array;
});
For native PHP you can do
$data = json_decode($json, true);
foreach ($data as $index => $array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
$data[$index] = $array;
}
$json = [
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
];
$filtered = collect(json_decode($json))->map(function($value, $key) {
if (!$value['is_lottery']) {
Arr::except($value, 'price');
}
return $value;
});
you can declare new variable called $newCollection as final collection. Use foreach() to iterate your collection then delete the is_lottery from collection by using unset() then push it to $newCollection, this is example how you can delete it using foreach:
$newCollection = [];
foreach ($photos as $key => $value) {
if ($value["is_lottery"] == 0) {
unset($value["price"]);
}
array_push($newCollection,$value);
}
or you can try using forget to remove it from collection (not tested) from this ref:
How to unset (remove) a collection element after fetching it?
I have searchDetails array in my search. I have done all other search and get data on filter, Problem is that when i search with stone_min, stone_max I get data if there is only one searchDetails array, if there is two data it is return null. How can i do this ? I want search with stone_min, stone_max for particular product_id.
what i try :
Example for data to search :
{
"limit": 1000,
"offset":0,
"user_id": "",
"min_price": "",
"max_price": "",
"searchDetails": [
{
"product_id": "1",
"attributeId": [],
"is_exclude": "no",
"stone_min": "5",
"stone_max": "15"
},
{
"product_id": "2",
"attributeId": [],
"is_exclude": "no",
"stone_min": "100",
"stone_max": "500"
}
]
}
My query for getting all data
$searchablePost = Post::with(['product','postattribute.attribute.category','user.userDetails'])
->whereIn('product_id', $userApprovalProductIDs)
->where('status', 'Active')
->whereIn('demand_or_supply', $demand_or_supply);
Search for min-max stone :
if (count($searchDetails) > 0) {
$j = 0;
foreach ($searchDetails as $value) {
if (strtolower(trim($value['is_exclude'])) == "no") {
$searchablePost = $searchablePost->where(function ($query) use ($value) {
if ($value['stone_min'] && $value['stone_max']) {
if (isset($j) && $j == 0){
$query->where('stone_min', '>=', $value['stone_min'])->where('stone_max', '<=', $value['stone_max'])->where("product_id", (int)$value['product_id']);
} else {
$query->where('stone_min', '>=', $value['stone_min'])->where('stone_max', '<=', $value['stone_max'])->where("product_id", (int)$value['product_id']);
}
}
});
}
}
}
$searchedPost = $searchablePost->offset($offset)->limit($limit)->orderBy('id','desc')->get();
If you want to search between stone_min and stone_max for particualar product then do:
$request = json_decode($request->searchDetails, true);
$stoneMinMax = collect($request)->pluck('stone_min', 'stone_max');
Product::where(function($q) use($productId) ($stoneMinMax){
$q->where('product_id', $productId)
->whereBetween('stone_column', $stoneMinMax->toArray());
})->get();
I'm using laravel-fractal to transform my data and here is a response
how can I delete data;
I made a search and I realized I need to use a Serializer;
But I just want to remove data for all includes(relations)
{
"data": [
{
"id": 1,
"name": "test name",
"status": null,
"tags": [
"first",
"second"
],
"created_at": "1396/9/3",
"contacts": {
"data": [
{
"value": "test#test.com",
"type": "email",
"icon": "fa fa-email"
}
]
}
},
{
"id": 2,
"name": "name test 2",
"status": null,
"tags": [],
"created_at": "1396/9/3",
"contact": {
"data": []
}
}
]
I found my answer at GitHub. The following answer is copied from thephpleague/fractal on GitHub:
You can write your own serializer for that.
class YourDataSerializer extends ArraySerializer
{
public function collection($resourceKey, array $data)
{
if ($resourceKey) {
return [$resourceKey => $data];
}
return $data;
}
public function item($resourceKey, array $data)
{
if ($resourceKey) {
return [$resourceKey => $data];
}
return $data;
}
}
Register your serializer with manager
$manager = new Manager();
$manager->setSerializer(new YourDataSerializer());
and when you want to have data or anything else you can pass in resourceKey to your Item or Collection as a third param.
$resource = new Collection($folders, new AccountFolderTransformer(), 'data');
use array serializer:
Fractal::create()
->item($item, new MyTransformer())
->serializeWith(new ArraySerializer())
When I execute this in my Controller
$data = User::with('teams')->find(2);
return response(['data' => $data]);
I get this as result
{
"id": 2,
"country_id": 1,
"first_name": "John",
"last_name": "Doe",
"created_at": "-0001-11-30 00:00:00",
"updated_at": "2015-02-02 23:08:21",
"full_name": "John Doe",
"teams": [
{
"id": 1,
"name": "Helpdesk medewerker",
"description": ""
},
{
"id": 2,
"name": "Retentie",
"description": ""
}
]
}
Im not interested in the full teams data, but only interested in the teamNames of the user.
I've done this by adding this
$data->each(function($user) {
$user->team_names = $user->teams->lists('name');
unset($user->teams);
});
I was wondering if this is the correct way of modifying the Eloquent result.
You can use an attribute accessor for that. Add this to your model:
protected $hidden = ['teams']; // hide teams relation in JSON output
protected $appends = ['team_names']; // add custom attribute to JSON output
public function getTeamNamesAttribute(){
return $this->teams->lists('name');
}
To change hidden and appends dynamically you can use the setter methods:
$data = User::with('teams')->find(2);
$data->setHidden(['teams']);
Filter out the columns you want in your first build.
$data = User::with(['teams' => function($query){
return $query->select('name');
}])->find(2);
Will output:
{
...
"teams": [
{
"name": "Helpdesk medewerker"
},
{
"name": "Retentie"
}
]
}
You can also use the lists method.
$data = User::with(['teams' => function($query){
return $query->lists('name');
}])->find(2);
Will output:
{
...
"teams": ["Helpdesk medewerker", "Retentie"]
}