I am using Akka in Play Controller and performing ask() to a actor by name publish , and internal publish actor performs ask to multiple actors and passes reference of sender. The controller actor needs to wait for response from multiple actors and create a list of response.
Please find the code below. but this code is only waiting for 1 response and latter terminating. Please suggest
// Performs ask to publish actor
Source<Object,NotUsed> inAsk = Source.fromFuture(ask(publishActor,service.getOfferVerifyRequest(request).getPayloadData(),1000));
final Sink<String, CompletionStage<String>> sink = Sink.head();
final Flow<Object, String, NotUsed> f3 = Flow.of(Object.class).map(elem -> {
log.info("Data in Graph is " +elem.toString());
return elem.toString();
});
RunnableGraph<CompletionStage<String>> result = RunnableGraph.fromGraph(
GraphDSL.create(
sink , (builder , out) ->{
final Outlet<Object> source = builder.add(inAsk).out();
builder
.from(source)
.via(builder.add(f3))
.to(out); // to() expects a SinkShape
return ClosedShape.getInstance();
}
));
ActorMaterializer mat = ActorMaterializer.create(aSystem);
CompletionStage<String> fin = result.run(mat);
fin.toCompletableFuture().thenApply(a->{
log.info("Data is "+a);
return true;
});
log.info("COMPLETED CONTROLLER ");
If you have several responses ask won't cut it, that is only for a single request-response where the response ends up in a Future/CompletionStage.
There are a few different strategies to wait for all answers:
One is to create an intermediate actor whose only job is to collect all answers and then when all partial responses has arrived respond to the original requestor, that way you could use ask to get a single aggregate response back.
Another option would be to use Source.actorRef to get an ActorRef that you could use as sender together with tell (and skip using ask). Inside the stream you would then take elements until some criteria is met (time has passed or elements have been seen). You may have to add an operator to mimic the ask response timeout to make sure the stream fails if the actor never responds.
There are some other issues with the code shared, one is creating a materializer on each request, these have a lifecycle and will fill up your heap over time, you should rather get a materializer injected from play.
With the given logic there is no need whatsoever to use the GraphDSL, that is only needed for complex streams with multiple inputs and outputs or cycles. You should be able to compose operators using the Flow API alone (see for example https://doc.akka.io/docs/akka/current/stream/stream-flows-and-basics.html#defining-and-running-streams )
Related
How can I guarantee linearizability of requests in Reactor Netty?
Theory:
Given:
Request A wants to write x=2, y=0
Request B wants to read x, y and write x=x+2, y=y+1
Request C wants to read x and write y=x
All Requests are processed asynchronously and return to the client immediately with status ACCEPTED.
Example:
Send requests A, B, C in order.
Example Log Output: (request, thread name, x, y)
Request A, nioEventLoopGroup-2-0, x=2, y=0
Request C, nioEventLoopGroup-2-2, x=2, y=2
Request B, nioEventLoopGroup-2-1, x=4, y=3
Business logic requires all reads after A to see x=2 and y=0.
And request B to see x=2, y=0 and set y=1.
And request C to see x=4 and set y=4.
In short: The business logic makes every next write operation dependent on the previous write operation to be completed. Otherwise the operations are not reversible.
Example Code
Document:
#Document
#Data
#NoArgsConstructor
#AllArgsConstructor
public class Event {
#Id
private String id;
private int data;
public Event withNewId() {
setId(UUID.randomUUID().toString());
return this;
}
}
Repo:
public interface EventRepository extends ReactiveMongoRepository<Event, String> {}
Controller:
#RestController
#RequestMapping(value = "/api/event")
#RequiredArgsConstructor
public class EventHandler {
private final EventRepository repo;
#PostMapping
public Mono<String> create(Event event) {
return Mono.just(event.withNewId().getId())
.doOnNext(id ->
// do query based on some logic depending on event data
Mono.just(someQuery)
.flatMap(query ->
repo.find(query)
.map(e -> event.setData(event.getData() + e.getData())))
.switchIfEmpty(Mono.just(event))
.flatMap(e -> repo.save(e))
.subscribeOn(Schedulers.single())
.subscribe());
}
}
It does not work, but with subscribeOn I try to guarantee linearizability. Meaning that concurrent requests A and B will always write their payload to the DB in the order in which they are received by the server. Therefore if another concurrent request C is a compound of first read than write, it will read changes from the DB that reflect those of request B, not A, and write its own changes based of B.
Is there a way in Reactor Netty to schedule executors with an unbound FIFO queue, so that I can process the requests asynchronously but in order?
I don't think that this is specific to Netty or Reactor in particular, but to a more broad topic - how to handle out-of-order message delivery and more-than-once message delivery. A few questions:
Does the client always sends the same number of requests in the same order? There's always a chance that, due to networking issues the requests may arrive out of order, or one or more may be lost.
Does the client make retries? What happens if the same request reaches the server twice?
If the order matters, why doesn't the client wait for the result of the nth-1 request, before issuing nth request? In other words, why there are many concurrent requests?
I'd try to redesign the operation in such a way that there's a single request executing the operations on the backend in the required order and using concurrency here if necessary to speed-up the process.
If it's not possible, for example, you don't control the client, or more generally the order in which the events (requests) arrive, you have to implement ordering on application-level logic using per-message semantics to do the ordering. You can, for example store or buffer the messages, waiting for all to arrive, and when they do, only then trigger the business logic using the data from the messages in the correct order. This requires some kind of a key (identity) which can attribute messages to the same entity, and a sorting-key, that you know how to sort the messages in the correct order.
EDIT:
After getting the answers, you can definitely implement it "the Reactor way".
Sinks.Many<Event> sink = Sinks.many() // you creat a 'sink' where the events will go
.multicast() // broads all messages to all subscribes of the stream
.directBestEffort(); // additional semantics - publishing will fail if no subscribers - doesn't really matter here
Flux<Event> eventFlux = sink.asFlux(); // the 'view' of the sink as a flux you can subscribe to
public void run() {
subscribeAndProcess();
sink.tryEmitNext(new Event("A", "A", "A"));
sink.tryEmitNext(new Event("A", "C", "C"));
sink.tryEmitNext(new Event("A", "B", "B"));
sink.tryEmitNext(new Event("B", "A", "A"));
sink.tryEmitNext(new Event("B", "C", "C"));
sink.tryEmitNext(new Event("B", "B", "B"));
}
void subscribeAndProcess() {
eventFlux.groupBy(Event::key)
.flatMap(
groupedEvents -> groupedEvents.distinct(Event::type) // distinct to avoid duplicates
.buffer(3) // there are three event types, so we buffer and wait for all to arrive
.flatMap(events -> // once all the events are there we can do the processing the way we need
Mono.just(events.stream()
.sorted(Comparator.comparing(Event::type))
.map(e -> e.key + e.value)
.reduce(String::concat)
.orElse(""))
)
)
.subscribe(System.out::println);
}
// prints values concatenated in order per key:
// - AAABAC
// - BABBBC
See Gist: https://gist.github.com/tarczynskitomek/d9442ea679e3eed64e5a8470217ad96a
There are a few caveats:
If all of the expected events for the given key don't arrive you waste memory buffering - unless you set a timeout
How will you ensure that all the events for a given key go to the same application instance?
How will you recover from failures encountered mid-processing?
Having all this in mind, I would go with a persistent storage - say saving the incoming events in the database, and doing the processing in background - for this you don't need to use Reactor. Most of the time a simple Servlets based Spring app will be far easier to maintain and develop, especially if you have no previous experience with Functional Reactive Programming.
Looking at the provided code I would not try to handle it on Reactor Netty level.
At first, several comments regarding controller implementation because it has multiple issues that violate reactive principles. I would recommend to spend some time learning reactive API but here are some hints
In reactive nothing happens until you subscribe. At the same time calling subscribe explicitly is an anti-pattern and should be avoided until you are creating framework similar to WebFlux.
parallel scheduler should be used to run non-blocking logic until you have some blocking code.
doOn... are so-called side-effect operators and should not be used for constructing reactive flows.
#PostMapping
public Mono<String> create(Event event) {
// do query based on some logic depending on event data
return repo.find(query)
.map(e -> event.setData(event.getData() + e.getData()))
.switchIfEmpty(Mono.just(event))
.flatMap(e -> repo.save(e));
}
Now, processing requests in the predefined sequence could be tricky because of network failures, possible retries, etc. What if you never get Request B or Request C? Should you still persist Request A?
As #ttarczynski mentioned in his comment the best option is to redesign API and send single request.
In case it's not an option you would need to introduce some state to "postpone" request processing and then, depending on consistency semantic, process them as a "batch" when the last request is received or just defer Request C until you get Request A & B.
I'm using WebFlux to pull data from two different REST endpoints, and trying to correlate some data from one stream with the other. I have Flux instances called events and egvs and for each event, I want to find the EGV with the nearest timestamp.
final Flux<Tuple2<Double,Object>> data = events
.map(e -> Tuples.of(e.getValue(),
egvs.map(egv -> Tuples.of(egv.getValue(),
Math.abs(Duration.between(e.getDisplayTime(),
egv.getDisplayTime()).toSeconds())))
.sort(Comparator.comparingLong(Tuple2::getT2))
.take(1)
.map(v -> v.getT1())));
When I send data to my Thymeleaf template, the first element of the tuple renders as a number, as I'd expect, but the second element renders as a FluxMapFuseable. It appears that the egvs.map(...) portion of the pipeline isn't executing. How do I get that part of the pipeline to execute?
UPDATE
Thanks, #Toerktumlare - your answer helped me figure out that my approach was wrong. On each iteration through the map operation, the event needs the context of the entire set of EGVs to find the one it matches with. So the working code looks like this:
final Flux<Tuple2<Double, Double>> data =
Flux.zip(events, egvs.collectList().repeat())
.map(t -> Tuples.of(
// Grab the event
t.getT1().getValue(),
// Find the EGV (from the full set of EGVs) with the closest timestamp
t.getT2().stream()
.map(egv -> Tuples.of(
egv.getValue(),
Math.abs(Duration.between(
t.getT1().getDisplayTime(),
egv.getDisplayTime()).toSeconds())))
// Sort the stream of (value, time difference) tuples and
// take the smallest time difference.
.sorted(Comparator.comparingLong(Tuple2::getT2))
.map(Tuple2::getT1)
.findFirst()
.orElse(0.)));
what i think you are doing is that you are breaking the reactive chain.
During the assembly phase reactor will call each operator backwards until it finds a producer that can start producing items and i think you are breaking that chain here:
egvs.map(egv -> Tuples.of( ..., ... )
you see egvs returns something that you need to take care of and chain on to the return of events.map
I'll give you an example:
// This works because we always return from flatMap
// we keep the chain intact
Mono.just("foobar").flatMap(f -> {
return Mono.just(f)
}.subscribe(s -> {
System.out.println(s)
});
on the other hand, this behaves differently:
Mono.just("foobar").flatMap(f -> {
Mono.just("foo").doOnSuccess(s -> { System.out.println("this will never print"); });
return Mono.just(f);
});
Because in this example you can see that we ignore to take care of the return from the inner Mono thus breaking the chain.
You havn't really disclosed what evg actually is so i wont be able to give you a full answer but you should most likely do something like this:
final Flux<Tuple2<Double,Object>> data = events
// chain on egv here instead
// and then return your full tuple object instead
.map(e -> egvs.map(egv -> Tuples.of(e.getValue(), Tuples.of(egv.getValue(), Math.abs(Duration.between(e.getDisplayTime(), egv.getDisplayTime()).toSeconds())))
.sort(Comparator.comparingLong(Tuple2::getT2))
.take(1)
.map(v -> v.getT1())));
I don't have compiler to check against atm. but i believe that is your problem at least. its a bit tricky to read your code.
def socket = karate.webSocket(demoBaseUrlgame)
def body = {"_id":"p194","pid":1960939,"at":'#(gsauthtoken2)',"f1":'#(gametableid)',"f2":"023e86a7-d579-33a4-ac4f-9803beecaef1","f3":"webh5","f4":false,"f5":"","f6":"","f7":"","f8":"Windows","f9":"10","f10":"Chrome","f11":"96.0.4664.110","f12":false,"f13":"","f14":"","f15":false}
print "Body:", body
socket.send( '#(body)')
def loginuser2 = socket.listen(1000)
print loginuser2
In this one, i am sending one CM request but getting multiple SM, but only first one is getting fetched with or without the handler.
Is there a way where we can fetch multiple sm for one cm?
If you want to "gather" multiple messages, you need to write a "handler" function with logic to "stop" when you have enough messages.
This is covered in the example, please read the docs: https://github.com/karatelabs/karate#websocket
I'm showing the line in the example which you should study carefully below:
* def handler = function(msg){ return msg.startsWith('hello') }
So you can do anything, for example wait until some particular message, wait until some elapsed time, or wait until some count of messages. How you write that logic is up to you and your messages.
I have the method below, where I am calling several ReactiveMongoRepositories in order to receive and process certain documents. Since I am kind of new to Webflux, I am learning as I go.
To my feeling the code below doesn't feel very efficient, as I am opening multiple streams at the same time. This non-blocking way of writing code makes it complicated somehow to get a value from a stream and re-use that value in the cascaded flatmaps down the line.
In the example below I have to call the userRepository twice, since I want the user at the beginning and than later as well. Is there a possibility to do this more efficiently with Webflux?
public Mono<Guideline> addGuideline(Guideline guideline, String keycloakUserId) {
Mono<Guideline> guidelineMono = userRepository.findByKeycloakUserId(keycloakUserId)
.flatMap(user -> {
return teamRepository.findUserInTeams(user.get_id());
}).zipWith(instructionRepository.findById(guideline.getInstructionId()))
.zipWith(userRepository.findByKeycloakUserId(keycloakUserId))
.flatMap(objects -> {
User user = objects.getT2();
Instruction instruction = objects.getT1().getT2();
Team team = objects.getT1().getT1();
if (instruction.getTeamId().equals(team.get_id())) {
guideline.setAddedByUser(user.get_id());
guideline.setTeamId(team.get_id());
guideline.setDateAdded(new Date());
guideline.setGuidelineStatus(GuidelineStatus.ACTIVE);
guideline.setGuidelineSteps(Arrays.asList());
return guidelineRepository.save(guideline);
} else {
return Mono.error(new InstructionDoesntBelongOrExistException("Unable to add, since this Instruction does not belong to you or doesn't exist anymore!"));
}
});
return guidelineMono;
}
i'll post my earlier comment as an answer. If anyone feels like writing the correct code for it then go ahead.
i don't have access to an IDE current so cant write an example but you could start by fetching the instruction from the database.
Keep that Mono<Instruction> then you fetch your User and flatMap the User and fetch the Team from the database. Then you flatMap the team and build a Mono<Tuple> consisting of Mono<Tuple<User, Team>>.
After that you take your 2 Monos and use zipWith with a Combinator function and build a Mono<Tuple<User, Team, Instruction>> that you can flatMap over.
So basically fetch 1 item, then fetch 2 items, then Combinate into 3 items. You can create Tuples using the Tuples.of(...) function.
Background
I'm trying to observe one Int stream (actually I'm not, but to make the argument easier) and do something with it while combining that stream to multiple other streams, say a String stream and a Double stream like the following:
// RxSwift
let intStream = BehaviorSubject<Int>(value: 0) // subscribe to this later on
let sharedStream = intStream.share()
let mappedStream = sharedStream.map { ... }.share()
let combinedStream1 = Observable.combineLatest(sharedStream, stringStream).map { ... }
let combinedStream2 = Observable.combineLatest(sharedStream, doubleStream).map { ... }
The above code is just to demonstrate what I'm trying to do. The code above is part of view model code (the VM part of MVVM), and only the first map (for mappedStream) runs, while the others are not called.
Question
What is wrong with the above approach, and how do I achieve what I'm trying to do?
Also, is there a better way to achieve the same effect?
Updates
I confirmed that setting the replay count to 1 makes things work. But why?
The code above all goes in the initialization phase of the view model, and the subscription happens afterwards.
Okay, I have an answer but it's a bit complex... One problem is that you are using a Subject in the view model, but I'll ignore that for now. The real problem comes from the fact that you are using hot observables inappropriately (share() make a stream hot) and so events are getting dropped.
It might help if you put a bunch of .debug()s on this code so you can follow along. But here's the essence...
When you subscribe to mappedStream, it subscribes to the share which in turn subscribes to the sharedStream, which subscribes to the intStream. The intStream then emits the 0, and that 0 goes down the chain and shows up in the observer.
Then you subscribe to the combinedStream1, which subscribes to the sharedStream's share(). Since this share has already been subscribed to, the subscriptions stop there, and since the share has already output it's next event, the combinedStream1 doesn't get the .next(0) event.
Same for the combinedStream2.
Get rid of all the share()s and everything will work:
let intStream = BehaviorSubject<Int>(value: 0) // subscribe to this later on
let mappedStream = intStream.map { $0 }
let combinedStream1 = Observable.combineLatest(intStream, stringStream).map { $0 }
let combinedStream2 = Observable.combineLatest(intStream, doubleStream).map { $0 }
This way, each subscriber of intStream gets the 0 value.
The only time you want to share is if you need to share side effects. There aren’t any side effects in this code, so there’s no need to share.