I am trying to learn MyBatis. How to do I get the auto-generated ID after I have inserted a statement using the #InsertAnnotation.
Example of my code:
#Insert("INSERT INTO user(name, mobile, password) VALUES(#{name}, #{mobile}, #{password})")
#SelectKey(statement = "SELECT LAST_INSERT_ID()", keyProperty = "id", before = false, resultType = Long.class)
Long insertUser(User user);
I want to get the generated id as the return from the insert method.
#SelectKey is for legacy drivers.
For recent drivers, you should use useGeneratedKeys.
We have an FAQ entry explaining how to do it with XML mapper.
With annotation, it would look as follows.
#Insert("INSERT INTO user(name, mobile, password) VALUES(#{name}, #{mobile}, #{password})")
#Options(useGeneratedKeys = true, keyProperty = "id")
int insertUser(User user);
Note that #Insert method returns the number of updated rows, not the generated key.
The generated key is assigned to the property of the parameter specified by keyProperty i.e. User.id in your case.
For some databases, you might need to specify keyColumn as well.
If it didn't work, please add versions of DB, driver and MyBatis to the question.
#Select("insert into security.users (name,email,password) values(#{user.name}, #{user.email}, #{user.password}) returning id")
#Result(column = "id")
this worked me. but i try a many time with #INSERT annotation not worked;
Related
I need to retrieve a list of Category from the DB on the basis of value of column called owner. Here is my Category -
#Entity
#Table(name = "categories")
class Category(#Column(name = "category_id", nullable = false)
#Id #GeneratedValue(strategyGenerationType.AUTO)
var id: Long = 0,
#Column(name = "category_owner", nullable = false)
#field:NotNull(message = "Please assign an owner")
var owner: Long?,
#Column(name = "category_name", nullable = false)
#field:NotEmpty(message = "Please assign a name")
var name: String?)
Here is my interface which defines the function findByOwner -
interface CategoryRepository: JpaRepository<Category, Long> {
fun findByOwner(categoryOwner: Long): List<Category>
}
However, when I call the method, I get no response. I have made sure that the DB has correct data and I'm providing the correct owner Id. Have even invalidated the cache etc. What could be going wrong?
EDIT:
After spring.jpa.show-sql=true -
findAll()
Hibernate: select category0_.category_id as category1_0_, category0_.category_name as category2_0_, category0_.category_owner as category3_0_ from categories category0_
findByOwner()
Hibernate: select category0_.category_id as category1_0_, category0_.category_name as category2_0_, category0_.category_owner as category3_0_ from categories category0_ where category0_.category_owner=?
EDIT 2:
Turns out that my implementation was fine all along. The bug was in my service.
Create your named method according with the name of the column.
fun findByCategoryOwner(categoryOwner: Long): List<Category>
Or use #Query
#Query("SELECT * FROM categories WHERE category_owner = ?1", nativeQuery = true)
fun findByOwner(cateogryOwner: Long): List<Category
Can you put a breakpoint in org.springframework.data.jpa.repository.query.JpaQueryExecution class and when you execute findByOwner, it will come here.
When it reaches this breakpoint, select the query.createQuery(accessor).getResultList() and evaluate to see what value is returned by hibernate for spring-data-jpa to use
This post should help you. It appears to be happeing because of the parameter name mismatch.
Use camelCase to name your variables in Entity class then jpa will auto recognise the column name
findByCategoryOwner(String categoryOwner)
If you still wish to have underscore in your column names then try this
findByCategory_Owner(String categoryOwner)
I haven't tried the second option though
At least in java you need to provide the id in the method name:
**fun findByOwner_Id(categoryOwner: Long): List<Category>**
So change it from findByOwner -> findByOwnerId.
I've an entity defined like below. If I use save() Hibernate does not create a new index for newly created entity. Updating/modifying an existing entity works well and as expected.
I'm using kotling with spring boot 2.
#Entity(name = "shipment")
#Indexed
data class Shipment(
#Id #GeneratedValue(strategy = GenerationType.IDENTITY) val id: Long = -1,
#JoinColumn(name = "user") #ManyToOne() var user: User?,
#IndexedEmbedded
#JoinColumn(name = "sender") #ManyToOne(cascade = [CascadeType.ALL]) val sender: Contact,
#IndexedEmbedded
#JoinColumn(name = "sender_information") #ManyToOne(cascade = [CascadeType.ALL]) val senderInformation: ShipmentInformation,
) {}
Save function, I'm using this same function to update my entity and index is updated if index exists.
#Transactional
fun save(user: User, shipment: Shipment): Shipment {
shipment.user = user;
return this.shipmentRepository.save(shipment)
}
application.properties
spring.jpa.properties.hibernate.search.default.directory_provider=filesystem
spring.jpa.properties.hibernate.search.default.indexBase=./lucene/
spring.jpa.open-in-view=false
If I restart the server, indexing manually works too.
#Transactional
override fun onApplicationEvent(event: ApplicationReadyEvent) {
val fullTextEntityManager: FullTextEntityManager = Search.getFullTextEntityManager(entityManager)
fullTextEntityManager.createIndexer().purgeAllOnStart(true)
fullTextEntityManager.createIndexer().optimizeAfterPurge(true)
fullTextEntityManager.createIndexer().batchSizeToLoadObjects(15)
fullTextEntityManager.createIndexer().cacheMode(CacheMode.IGNORE)
fullTextEntityManager.createIndexer().threadsToLoadObjects(2)
fullTextEntityManager.createIndexer().typesToIndexInParallel(2)
fullTextEntityManager.createIndexer().startAndWait()
return
}
I tried to force to use JPA transaction manager but It did not help me.
#Bean(name = arrayOf("transactionManager"))
#Primary
fun transactionManager(#Autowired entityManagerFactory: EntityManagerFactory): org.springframework.orm.jpa.JpaTransactionManager {
return JpaTransactionManager(entityManagerFactory)
}
Update
I think I found why I don't get the results of newly inserted entities.
My search query has a condition on "pid" field which is declared:
#Field(index = Index.YES, analyze = Analyze.NO, store = Store.NO)
#SortableField
#Column(name = "id", updatable = false, insertable = false)
#JsonIgnore
#NumericField val pid: Long,
and query:
query.must(queryBuilder.keyword().onField("customer.pid").matching(user.customer.id.toString()).createQuery())
pid is not stored and so newly inserted values are not visible. Can this be the cause?
BTW: How can I query/search by nested indexed document id? In my case it is customer.id which is DocumentId. I've tried to change the query like below but don't get any result, should I create a new field to query?
query.must(queryBuilder.keyword().onField("customer.id").matching(user.customer.id.toString()).createQuery())
Update 2
I found a solution and now getting the newly inserted datas too. There was an error with definition of "pid" field and I've defined my Fields as below and it works as expected.
#Fields(
Field(name = "pid", index = Index.YES, analyze = Analyze.YES, store = Store.NO)
)
#SortableField(forField = "pid")
#Id #GeneratedValue(strategy = GenerationType.IDENTITY) val id: Long?,
Can we search and sort by id in an easy way or is it the best practice? I know that we should use native JPA functions to get results by id but in my case I need to search by an embedded id to restrict search results. (depends on role of user) so therefore it is not an option for me.
And I don't understand why manual indexing works...
BTW: How can I query/search by nested indexed document id? In my case it is customer.id which is DocumentId. I've tried to change the query like below but don't get any result, should I create a new field to query?
Normally you don't need to create a separate field if all you want is to perform an exact match.
Can we search and sort by id in an easy way
Searching, yes, at least in Hibernate Search 5.
Sorting, no: you need a dedicated field.
or is it the best practice?
The best practice is to declare a field alongside your #DocumentId if you need anything more complex than an exact match on the ID.
I know that we should use native JPA functions to get results by id
I'm not sure I understand what you mean by "native JPA functions".
but in my case I need to search by an embedded id to restrict search results. (depends on role of user)
Yes, this should work. That is, it should work if the id is properly populated.
And I don't understand why manual indexing works...
Neither do I, but I suppose the explanation lies in the "error in the definition of "pid" field". Maybe the ID wasn't populated properly in some cases, leading to the entity being considered as deleted by Hibernate Search?
If you need me to give you a definitive answer, the best way to get it would be to create a reproducer. You can use this as a template: https://github.com/hibernate/hibernate-test-case-templates/tree/master/search
This looks odd:
#Id #GeneratedValue(strategy = GenerationType.IDENTITY) val id: Long = -1,
I'd expect a nullable long, initialized to null (or whatever is the Kotlin equivalent).
I'm not sure this is the problem, but I imagine it could be, as a non-null ID is generally only expected from an already persisted entity.
Other than that, I think you're on the right track: if mass indexing works but not automatic indexing, it may have something to do with your changes not being executed in database transactions.
I am fairly new to spring ,I am looking to check if a certain email id exists in database or not , using Spring Jdbc Template ,I looked here but could'nt find the proper answer .I am looking something like ,SELECT count(*) from table where email=?
Any help will be appreciated.
You can do something as below if you are using jdbctemplate and new version of spring
private boolean isEmailIdExists(String email) {
String sql = "SELECT count(*) FROM table WHERE email = ?";
int count = jdbcTemplate.queryForObject(sql, new Object[] { email }, Integer.class);
return count > 0;
}
queryForObject method of jdbcTemplate accepts the sql query as the first parameter, second argument is an array of objects for the sql query place holders and the third argument is the expected return value from the sql query.
In this case we only have one place holder and hence I gave the second argument as new Object[] { email } and the result we are expecting is a count which is a Integer and hence I gave it as Integer.class
I kind of got this answer from https://www.mkyong.com/spring/jdbctemplate-queryforint-is-deprecated/
You can go through it if you are interested.
private boolean isEmailIdExists(String email) {
return jdbcTemplate.queryForObject("SELECT EXISTS(SELECT FROM table WHERE email = ?)", Boolean.class, email);
}
http://www.postgresqltutorial.com/postgresql-exists/
I am trying to access database FK using named SQL query with Hibernate, the idea is to query a customer table which contains name, and companyId,etc. CompanyId is the FK for a commpany table. The query I wrote is as follows:
#NamedNativeQuery(name="getcustomer", query="Select CUSTOMER.* from CUSTOMER,COMPANY where CUSTOMER_FIRST_NAME = (?1) and CUSTOMER_LAST_NAME= (?2) and CUSTOMER_COMPANY_ID_FK = (?3) ",resultClass=Customer.class)
The issue I am currently having as follow:
Exception in thread "main" org.hibernate.QueryParameterException:
Position beyond number of declared ordinal parameters. Remember that
ordinal parameters are 1-based! Position: 2 at
org.hibernate.engine.query.spi.ParameterMetadata.getOrdinalParameterDescriptor(ParameterMetadata.java:89)
at
org.hibernate.engine.query.spi.ParameterMetadata.getOrdinalParameterExpectedType(ParameterMetadata.java:109)
at
org.hibernate.internal.AbstractQueryImpl.determineType(AbstractQueryImpl.java:507)
at
org.hibernate.internal.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:479)
at
com.comresource.scrapmetalapp.DAOImpl.CustomerDAOImpl.searchCustomer(CustomerDAOImpl.java:61)
at
com.comresource.scrapmetalapp.ServiceImpl.CustomerServiceImpl.searchCustomer(CustomerServiceImpl.java:39)
at com.comresource.scrapmetalapp.Config.Run.main(Run.java:57)
My DAO implementation is like this:
#Override
public Customer searchCustomer(String fName, String lName, Integer company) {
Session session = sessionFactory.openSession();
return (Customer) session.getNamedQuery("getcustomer").setParameter(1, fName)
.setParameter(2, lName)
.setParameter(3, company)
.uniqueResult();
}
What is the issue here?
For this, I would need to see how you are associating the mapping in your model class, but the query should go like this.
public Customer getMeThatCustomer(String param1, String param2, int foreignkey){
session = getCurrentSession();
org.hibernate.Query query = session.createQuery("From Customer as c where c.name=:param1 and c.lastname=:param2 and c.company.companyid=:foreignkey");
//Note the last parameter, where I have mentioned c.company, in place of
company, there should be the foregin key association and then the primary key in java class.
query.setParameter("param1",param1);
query.setP...er("param2",param2);
quer.....("companyid",companyid);
return (Customer) query.uniqueResult();
}
So, try it out, let me know if there is any problem
I have a user repository in the application which works nicely for cases like this one:
#Query(" FROM UserEntity ue WHERE ue.site.id = :site_id
and ue.name = :username")
User findByUsername(#Param("site_id") String siteId,
#Param("username") String userName);
There is now a new option in one of the user fields, which should prevent the user to appear anywhere in the application. So instead of modifying the whole application, I've decided to modify just the queries in repositories with hardcoded clause like this:
#Query(" FROM UserEntity ue WHERE ue.site.id = :site_id
and ue.name = :username and ue.state != 'Disabled'")
User findByUsername(#Param("site_id") String siteId,
#Param("username") String userName);
(The changed part is and ue.state != 'Disabled')
The problem is, that such query doesn't return anything no matter what the value of state is.
I've also tried ue.state not like 'Disabled', but with the same result.
I've seen a lot of examples of using #Query, but didn't find any with hardcoded clauses. Is that even possible?
Yes you can pass the hardcoded values without changing the method signature.
JPA repository
#Query(" FROM Users ue WHERE ue.userLogin = :userLogin and ue.userName != 'admin'")
public Users cehckeme(#Param("userLogin") String userLogin);
Test Code
ApplicationContext ctx = new ClassPathXmlApplicationContext(
"spring_model.xml");
usersRepository = (UsersRepository) ctx.getBean("usersRepository");
System.out.println(usersRepository.cehckeme("pthakre").getUserLogin());
Genrated query
Hibernate:
select
*
from
( select
users0_.USER_ID as USER1_2_,
users0_.USER_LOGIN as USER2_2_,
users0_.USER_NAME as USER3_2_,
users0_.USER_PASSWORD as USER4_2_
from
MED_USERS users0_
where
users0_.USER_LOGIN=?
and users0_.USER_NAME<>'admin' )
where
rownum <= ?