Bash while read input issue - bash

Question

An possible way to use while read is:
while read server application date; do ..
So now i could print only the applications, i understand that. So here comes my question:
with my example i know exactly how many "arrays" there are but how would i do it if i dont know how many "arrays" exist per line?
Example file:
Server : ID1 ; ID2 ; ID3
Server : ID1
Server : ID1 ; ID2
Server : ID1 ; ID2 ; ID3 ; ID4
It doesnt have to be with read but how could i read them so i could for example
echo "$Server $ID3"
p.s sorry for the bad english
so what i am doing so far is this:
#!/bin/bash
file=$1
csv=$2
echo Server : Applikation : AO : BV : SO > endlist.txt
while read server aid; do
grep $aid $csv | while IFS=";" read id aid2 name alia status typ beschreibung gesch gesch2 finanzierung internet service servicemodell AO BV SO it betrieb hersteller; do
if [[ $aid == $aid2 ]]
then
echo $server : $name : $AO : $BV : $SO >> endlist.txt
fi
done
done < $file
the Problem is that the first while read is for now only SERVER and AID but i want to edit this file so more than one AID is possible

Answer 1

It doesnt have to be with read but how could i read them so i could for example
echo "$Server $ID3"
First split the input on :, then read the array on ;. Use bash arrays and read -a to save input to an array.
# split the input on `:` and spaces
while IFS=' :' read -r server temp_ids; do
# split the ids on `;` and spaces into an array
IFS=' ;' read -r -a id <<<"$temp_ids"
# check if there are at least 3 elements
if ((${#id[#]} >= 3)); then
# array numbering starts from 0
echo "$server ${id[2]}"
else
echo There is no 3rd element...
fi
done <<EOF
Server : ID1 ; ID2 ; ID3
Server : ID1
Server : ID1 ; ID2
Server : ID1 ; ID2 ; ID3 ; ID4
EOF
will output:
Server ID3
There is no 3rd element...
There is no 3rd element...
Server ID3