Upload multiple image files using 2 input file in Laravel - laravel

Question

I want to upload multiple images using 2 input file fields in Laravel and put that 2 files to DB with different attributes (imagepath1, imagepath2). If I try that code there both input & upload the same file like imagekitchen2 (there both change but imagepath1 become imagepath2 and imagepath2 still imagepath2).
Controller
public function store(Request $request)
{
$kitchens = new Kitchen();
$kitchens->title = $request->input('title-kitchen');
$kitchens->description = $request->input('description-kitchen');
if ($request->hasfile('imagekitchen1')) {
$file = $request->file('imagekitchen1');
$extension = $file->getClientOriginalExtension();
$filename = time().'.'.$extension;
$file->move('uploads/product/kitchen/', $filename);
$kitchens->imagepath1 = $filename;
} else {
$kitchens->imagepath1 = '';
}
$kitchens->save();
if ($request->hasfile('imagekitchen2')) {
$file = $request->file('imagekitchen2');
$extension = $file->getClientOriginalExtension();
$filename = time().'.'.$extension;
$file->move('uploads/product/kitchen/', $filename);
$kitchens->imagepath2 = $filename;
} else {
$kitchens->imagepath2 = '';
}
$kitchens->save();
}
View
<div class="card-body">
<div class="row">
<div class="col-md-6">
<form action="{{ route('addimagekitchen') }}" enctype="multipart/form-data" method="POST">
{{ csrf_field() }}
<div class="form-group">
<label>Title</label>
<label>
<input type="text" name="title-kitchen" class="form-control">
</label>
</div>
<div class="input-group">
<div class="custom-file">
<label for="image" style="display: block">Main image</label> <br/>
<input type="file" name="imagekitchen1" style="margin-left: 20px">
</div>
</div>
<div class="input-group">
<div class="custom-file">
<label for="image" style="display: block">Second image</label> <br/>
<input type="file" name="imagekitchen2" style="margin-left: 20px">
</div>
</div>
<div class="input-group">
<div class="custom-file">
<label for="image" style="display: block">Third image</label> <br/>
<input type="file" name="imagekitchen[]" style="margin-left: 20px">
</div>
</div>
<div class="form-group">
<label>Description</label>
<textarea class="form-control" name="description-kitchen" id="description-kitchen"
rows="3"></textarea>
</div>
<button type="submit" class="btn btn-success"> Insert</button>
Cancel
</form>
</div>
</div>
</div>

Answer 1

I'm not completely sure what you mean, but probably you should change:
$kitchens->save();
if($request->hasfile('imagekitchen2')){
into
$kitchens->save();
$kitchens = new Kitchen();
if($request->hasfile('imagekitchen2')){
this way, you will create 2 records, otherwise you used same object and updated it after creation. Depending on your needs you might also want to add:
$kitchens->title = $request->input('title-kitchen');
$kitchens->description = $request->input('description-kitchen');
before:
if($request->hasfile('imagekitchen2')){
in case you want to save same title and description for both records.
Of course I'm not sure if you want to create records if there are no files - at the moment both will be saved in case no file uploaded.