This question already has answers here:
How to slice an array in Bash
(4 answers)
Using ${1:1} in bash
(2 answers)
Bash: all of array except last element
(1 answer)
Closed 3 years ago.
May you please explain what does this mean:
#:1:$#-1
can you provide an exact explanation?
That's a parameter expansion that returns all the positional parameters but the last one.
It's based on ${parameter:offset:length}, where using # as parameter makes it work on positional parameters. The length $#-1 is the number of positional parameters ($#) minus one.
Here's a showcase : https://ideone.com/HKcaNj
Related
This question already has answers here:
how to split long lines for fmt.sprintf
(5 answers)
Best practice for long string literals in Go
(5 answers)
indentation style for multi-line string literals
(3 answers)
How do you write multiline strings in Go?
(11 answers)
How to format a multiline string literal [closed]
(2 answers)
Closed 6 months ago.
I had a variable payload, it is too long here just a part.
payload := strings.NewReader("json=%7B%22rent_content_layout%22%3A%22Original%22%2C%22start_verylargetext_enabled%22%3Afalse%2C%22auto_large_mode")
is any way to make the one line var data to multi line or make it human readable using golang, for bash or shell we use \n, is any trick to line break it using golang
Simply do the string concatenation with the + operator and break the string into small parts.
payload := strings.NewReader(
"json=%7B%22" +
"rent_content_layout%22%3A%22" +
"Original%22%2C%22" +
"start_verylargetext_enabled%22%3A" +
"false%2C%22auto_large_mode")
This question already has answers here:
What does the XML syntax with a colon mean?
(1 answer)
How does XPath deal with XML namespaces?
(2 answers)
Closed 2 years ago.
I found the selector "//svg:path" in inkscape source code, but can't find any reference about single colon in XPath. I found for double colon but not useful for this case.
It is in line 117 on this file
This question already has answers here:
How to get a variable value if variable name is stored as string?
(10 answers)
Bash - variable variables [duplicate]
(4 answers)
Dynamic variable names in Bash
(19 answers)
Closed 3 years ago.
I have "INSTALLMODE=BASIC" key value pair defined in my config file. And, I am splitting these key value pairs and assigning them as below.
INSTALLMODE=BASIC
key=INSTALLMODE
x=`echo $key`
Now, I want to get value of $x as BASIC. How could I do that.
Thank you.
This question already has answers here:
Why does String#gsub double content?
(3 answers)
Closed 5 years ago.
I have this code:
"1'2".gsub("'","\\'")
Instead of "1\'2", I get: "122". Why?
You need to use this:
puts "1'2".gsub("'","\\\\'")
It is because "\\'" means the context following the match, which is "2".
This question already has answers here:
ruby operator "=~" [duplicate]
(3 answers)
Closed 9 years ago.
I was wondering if anyone could explain what the =~ operator does in Ruby. I have seen it a few times but am unable to find a proper explanation of it.
It is used to match Regexes against strings:
http://www.ruby-doc.org/core-2.0.0/Regexp.html#method-i-3D-7E
It returns either a Integer value of the first occurrence in the string or if the expression doesn't match the String it returns nil.