How to sort DDL by name of the object - sorting

Question

I want to sort the generated DDL of a database by name of the object. For example, I have the following DDL:
CREATE TABLE MyTable3 (
col1 integer,
col2 varchar(10)
);
CREATE TABLE MyTable1 (
col1 integer
);
CREATE TABLE MyTable2 (
col1 integer,
col2 varchar(10),
time timestamp
time2 timestamp
);
And I want the following output:
CREATE TABLE MyTable1 (
col1 integer
);
CREATE TABLE MyTable2 (
col1 integer,
col2 varchar(10),
time timestamp
);
CREATE TABLE MyTable3 (
col1 integer,
col2 varchar(10)
);
I have tried with awk, but I do not know to specify multiple lines: awk -F; '{print $NB}'
I found that msort could be the solution, but this package is not longer maintained.
As you can see, each element can have different quantity of lines, and I want to sort them by the first line which contains the name of the object.
What other options do I have to sort a document by multiple lines and a specific terminator (semi-colon).

Answer 1

Can you please try below gawk solution. The solution however assumes the tablename is in the same line as CREATE TABLE.
awk '
BEGIN {
}
{
if($0 ~ /CREATE TABLE/) {
found = match($0, /CREATE TABLE (.*) \(/, ary);
if(found != 0)
{
tablename=ary[1];
}
oneDDL=$0;
}
else if($0 ~ /;/) {
oneDDL=oneDDL"\n"$0;
arr[tablename]=oneDDL;
}
else {
oneDDL=oneDDL"\n"$0;
}
}
END {
asort(arr);
for(i in arr) {
print arr[i];
print "\n";
}
}' Input_File
Put tablename in an array arr as index with value as the text of DDL oneDDL.
Sort the array.
Then print the contents of the array.