How to create a complex object in ESQL - ibm-integration-bus

Question

I would like to create the following JSON object in ESQL and put it on the SET OutputRoot.JSON.Data. How do I do that?
{
"active" : [ {"name" : "test"},
{"name": "test2"}]
"inactive" : [ {"name" : "test3"}]
}

Answer 1

There is a standard procedure for IIB developers who want to output a specific format of XML/JSON:
Use a text editor to create the document that you want to output
Create a simple message flow that parses that document.
On the FileInput node (or HTTPInput, if you prefer) set the Domain to 'JSON'
Make sure that the second node is a Trace node with Pattern set to '${Root}'.
Put the example JSON through the message flow
Examine the Trace node output, paying special attention to the field type on each node
Write ESQL that produces an identical message tree under OutputRoot.JSON.Data

Answer 2

The below snippet demonstrates how to create JSON you need:
CREATE FUNCTION Main() RETURNS BOOLEAN
BEGIN
-- Create JSON domain
CREATE LASTCHILD OF OutputRoot DOMAIN 'JSON' NAME 'JSON';
-- Create root Data field
CREATE FIELD OutputRoot.JSON.Data;
DECLARE OutMsg REFERENCE TO OutputRoot.JSON.Data;
CREATE FIELD OutMsg.active IDENTITY (JSON.Array)active;
SET OutMsg.active.Item[1].name = 'test';
SET OutMsg.active.Item[2].name = 'test2';
SET OutMsg.(JSON.Array)inactive.Item[1].name = 'test3';
RETURN TRUE;
END;
Also you can read more information about work with JSON here Manipulating messages in the JSON domain and here Creating or transforming a JSON message by using a message map