How to update minor version number in bash? - bash

Question

Currently, I want to update the minor version in a text file using a bash command. This is the format I am dealing with: MAJOR.Minor.BugFix. I am able to increment the BugFix version number but have been unable to increment just the minor version.
I.e
01.01.00-> 01.02.00
01.99.00-> 02.00.00
This is the code snippet I found online and was trying to tweak to update the minor instead of the bug fix
echo 01.00.1 | awk -F. -v OFS=. 'NF==1{print ++$NF}; NF>1{if(length($NF+1)>length($NF))$(NF-1)++; $NF=sprintf("%0*d", length($NF), ($NF+1)%(10^length($NF))); print}'

Answer 1

As -F takes a regular expression -F. will match any character. Do something like -F"[.]" to make it match periods and you can just split fields without any of the length() stuff.
larsks idea of splitting into multiple lines is a good one:
echo $a | awk -F'[.]' '{
major=$1;
minor=$2;
patch=$3;
minor += 1;
major += minor / 100;
minor = minor % 100;
printf( "%02d.%02d.%02d\n", major, minor, patch );
}'

Answer 2

You don't need AWK for this, just read with IFS=. will do.
Though in Bash, leading zeroes indicate octal so you'll need to guard against them.
IFS=. read -r major minor bugfix <<< "$1"
# Specify base 10 in case of leading zeroes (octal)
((major=10#$major, minor=10#$minor, bugfix=10#$bugfix))
if [[ $minor -eq 99 ]]; then
((major++, minor=0))
else
((minor++))
fi
printf '%02d.%02d.%02d\n' "$major" "$minor" "$bugfix"
Test run:
$ ./test.sh 01.01.00
01.02.00
$ ./test.sh 01.99.09
02.00.09
$ ./test.sh 1.1.1
01.02.01

Answer 3

Quick answer:
version=01.02.00
newversion="$(printf "%06d" "$(expr "$(echo $version | sed 's/\.//g')" + 100)")"
echo "${newversion:0:2}.${newversion:2:2}.${newversion:4:2}"
Full explanation:
version=01.02.00
# get the number without decimals
rawnumber="$(echo $version | sed 's/\.//g')"
# add 100 to number (to increment minor version)
sum="$(expr "$rawnumber" + 100)"
# make number 6 digits
newnumber="$(printf "%06d" "$sum")"
# add decimals back to number
newversion="${newnumber:0:2}.${newnumber:2:2}.${newnumber:4:2}"
echo "$newversion"

Answer 4

awk provides a simple and efficient way to handle updating the minor-version (and increment the major-version if the minor version is 99 and setting the minor-version zero), e.g.
awk -F'.' '{
if ($2 == 99) {
$1++
$2=0
}
else
$2++
printf "%02d.%02d.%02d\n", $1, $2 ,$3
}' minorver
Above the leading-zeros are are ignored when considered as a number and then it is just a simple comparison of the minor-version to determine whether to increment the major-version and zero the minor-version or simply increment the minor-version. The printf is used to provide the formatted output:
Example Use/Output
With your data in the file minorver, you can do:
$ awk -F'.' '{
> if ($2 == 99) {
> $1++
> $2=0
> }
> else
> $2++
> printf "%02d.%02d.%02d\n", $1, $2 ,$3
> }' minorver
01.02.00
02.00.00
Let me know if you have further questions.