ActiveMQ how to resend/retry DLQ messages programmatically - jms

I would like to create a simple code snippet that fetches all messages from the DLQ and re-sends them to the original destination (AKA resend/retry)
It can be done easily by the ActiveMQ UI (but for a single message at a time).

There is no direct JMS API for re-sending a message from a DLQ to its original queue. In fact, the JMS API doesn't even discuss dead-letter queues. It's merely a convention used by most brokers to deal with messages that can't be consumed.
You'd need to create an actual JMS consumer to receive the message from the DLQ and then create a JMS producer to send the message back to its original queue.
It's important that you use Session.TRANSACTED mode to avoid potential message loss or duplication.
If you use Session.AUTO_ACKNOWLEDGE and there is a problem between the time the message is consumed and sent (e.g the application crashes, hardware failure, etc.) then the message could be lost due to the fact that it was already acknowledged before it was sent successfully.
If you use Session.CLIENT_ACKNOWLEDGE and there is a problem between the time the message is sent and acknowledged then the message could ultimately be duplicated due to the fact that it was already sent before it was acknowledged successfully.
Both operations should be part of the JMS transaction so that the work is atomic.
Lastly, I recommend you either invoke commit() on the transacted session for each message sent or after a small batch of messages (e.g. 10). Given that you have no idea how many messages are in the DLQ it would be unwise to process every message in a single transaction. Generally you want the transaction to be as small as possible in order to minimize the window during which an error might occur and the transaction's work will need to be performed again. Also, the larger the transaction is the more heap memory will be required on the broker to keep track of the work in the transaction. Keep in mind that you can invoke commit() on the same session as many times as you want. You don't need to create a new session for each transaction.

Retrying all messages on the DLQ is already implemented in activemq as an mbean.
You can trigger the retry method with jmxterm/jolokia
e.g
Replaying all messages on queue ActiveMQ.DLQ with jolokia
curl -XGET --user admin:admin --header "Origin: http://localhost" http://localhost:8161/api/jolokia/exec/org.apache.activemq:brokerName=localhost,destinationName=ActiveMQ.DLQ,destinationType=Queue,type=Broker/retryMessages
NOTE: You can only use this method on a queue that is marked as a DLQ. It will not work for regular queues.
Also the DLQ queue can have its 'DLQ' flag set to false if the server is restarted. It is automatically set to true when a new message is sent to the DLQ

After Justin's reply I've manually implemented the retry mechanism like so:
public void retryAllDlqMessages() throws JMSException {
logger.warn("retryAllDlqMessages starting");
logger.warn("Creating a connection to {}", activemqUrl);
ActiveMQConnectionFactory connectionFactory = new ActiveMQConnectionFactory("test", "test", activemqUrl);
HashMap<String, MessageProducer> messageProducersMap = new HashMap<>();
MessageConsumer consumer = null;
try (ActiveMQConnection connection = (ActiveMQConnection) connectionFactory.createConnection();
ActiveMQSession session = (ActiveMQSession) connection.createSession(true, Session.SESSION_TRANSACTED)) {
String dlqName = getDlqName();
logger.warn("Creating a session to {}", dlqName);
ActiveMQQueue queue = (ActiveMQQueue) session.createQueue(dlqName);
logger.warn("Starting JMS Connection");
connection.start();
logger.warn("Creating a DLQ consumer");
consumer = session.createConsumer(queue);
logger.warn("Consumer start receiving");
Message message = consumer.receive(CONSUMER_RECEIVE_TIME_IN_MS);
int retriedMessages = 0;
while (message != null) {
try {
retryMessage(messageProducersMap, session, message);
retriedMessages++;
} catch (Exception e) {
logger.error("Error calling retryMessage for message = {}", message);
logger.error("Rolling back the JMS transaction...");
session.rollback();
return;
}
message = consumer.receive(CONSUMER_RECEIVE_TIME_IN_MS);
}
logger.warn("Consumer finished retrying {} messages", retriedMessages);
logger.warn("Commiting JMS Transactions of retry");
session.commit();
} finally {
if (!messageProducersMap.isEmpty()) {
logger.warn("Closing {} messageProducers in messageProducersMap", messageProducersMap.size());
for (MessageProducer producer : messageProducersMap.values()) {
producer.close();
}
}
if (consumer != null) {
logger.warn("Closing DLQ Consumer");
consumer.close();
}
}
}
private void retryMessage(HashMap<String, MessageProducer> messageProducersMap, ActiveMQSession session, Message message) {
ActiveMQObjectMessage qm = (ActiveMQObjectMessage) message;
String originalDestinationName = qm.getOriginalDestination().getQualifiedName();
logger.warn("Retry message with JmsID={} to original destination {}", qm.getJMSMessageID(), originalDestinationName);
try {
if (!messageProducersMap.containsKey(originalDestinationName)) {
logger.warn("Creating a new producer for original destination: {}", originalDestinationName);
messageProducersMap.put(originalDestinationName, session.createProducer(qm.getOriginalDestination()));
}
logger.info("Producing message to original destination");
messageProducersMap.get(originalDestinationName).send(qm);
logger.info("Message sent");
} catch (Exception e) {
logger.error("Message retry failed with exception", e);
}
}

Related

Virtual Destinations Active and client id wildcard

I have been reading the documentation for virtual destinations here: http://activemq.apache.org/virtual-destinations.html
But I hit a bit of a snag, when I send to a topic it does not seem to follow the client id name as described on the document
My setup on the active mq is:
<destinationInterceptors>
<virtualDestinationInterceptor>
<virtualDestinations>
<virtualTopic name="Destination.>" prefix="Target.*." selectorAware="false" />
</virtualDestinations>
</virtualDestinationInterceptor>
</destinationInterceptors>
The code above describes that when I send to a Destination.Status topic with a ClientId of CustomerA.
It should send only to Target.CustomerA.Destination.Status if understand correctly, but what's happening is it's sending to Target.CustomerA.Destination.Status and Target.CustomerB.Destination.Status so basically fanning out messages to queues and ignoring the client id.
I did not see any further documentation about how to configure it, i was wondering if anyone else encountered this ?
Am I missing something here ?
Below is my producer if it's helpful.
public static class HelloWorldProducer implements Runnable {
public void run() {
try {
// Create a ConnectionFactory
ActiveMQConnectionFactory connectionFactory = new ActiveMQConnectionFactory("tcp://localhost:61617");
// Create a Connection
Connection connection = connectionFactory.createConnection();
connection.setClientID("CustomerA");
connection.start();
// Create a Session
Session session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE);
// Create the destination (Topic or Queue)
Destination destination = session.createTopic("Destination.Status");
// Create a MessageProducer from the Session to the Topic or Queue
MessageProducer producer = session.createProducer(destination);
producer.setDeliveryMode(DeliveryMode.NON_PERSISTENT);
// Create a messages
String text = "Hello world! From: " + Thread.currentThread().getName() + " : " + this.hashCode();
TextMessage message = session.createTextMessage(text);
// Tell the producer to send the message
System.out.println("Sent message: "+ message.hashCode() + " : " + Thread.currentThread().getName());
producer.send(message);
// Clean up
session.close();
connection.close();
}
catch (Exception e) {
System.out.println("Caught: " + e);
e.printStackTrace();
}
}
}
Any inputs will be beneficial.
The sender in this scenario has no real effect on the routing at the broker whether or not you've set a ClientID as it is just sending to a named Topic, in this case "Destination.Status". The configuration on the broker controls the routing and in your case you've configured "Destination.>" so any Queue consumer that comes along and subscribes to a Queue that matches the configuration you've set. So in your case I'd guess you have one consumer subscribing to Queue (Target.CustomerA.Destination.Status) and one to Queue (Target.CustomerB.Destination.Status) which then causes any message sent to the Topic to be fanned out to both.
If you want competing consumers then you'd need to subscribe both to Target.CustomerA.Destination.Status and then the broker would round-robin dispatch the sent message to either of the active subscribers.

WebFlux/Reactive Spring RabbitmMq Message is acknowledged even the save failed

I've started working recently with spring webflux and Rabbitmq along with cassandra reactive repository. What I've noticed is that the message is acknowledged even saving in cassandra didn't succued for some element. I propagete exception thrown during saving but even though the message is take down from queue. I'm wondering what I should do to let Rabbitmq know that this message should be consider as failed (I want to reject message to send it to dead letter queue )
#RabbitListener(queues = Constants.SOME_QUEUE, returnExceptions = "true")
public void receiveMessage(final List<ItemList> itemList) {
log.info("Received message from queue: {}", Constants.SOME_QUEUE);
itemService.saveAll(itemList)
.subscribe(
item-> log.info("Saving item with {}", item.getId()),
error -> {
log.error("Error during saving item", error);
throw new AmqpRejectAndDontRequeueException(error.getMessage());
},
() -> log.info(Constants.SOME_QUEUE+
" queue - {} items saved", itemList.size())
);
}
Reactive is non-blocking; the message will be acked as soon as the listener thread returns to the container. You need to somehow block the listener thread (e.g. with a Future<?>) and wake it up when the cassandra operation completes, exiting normally if successful, or throwing an exception on failure so the message will be redelivered.
I solved my problem by sending explicitly acknowledge/reject message to rabbitmq. It caused that I was forced to wrote a little more code but now at least it works and I have full controll what's happening.

MDB onMessage() holds the connection in case of redelivering message

I need to redeliver a message if it can't be processed, for example because of some external endpoint failure. So I'm using following MDB configuration (it worth to mention that I'm using openMQ (Glassfish 4.1)):
#MessageDriven(mappedName = "MyQueue", name = "MyQueue", activationConfig = {
#ActivationConfigProperty(propertyName = "destinationType", propertyValue = "javax.jms.Queue"),
#ActivationConfigProperty(propertyName = "endpointExceptionRedeliveryAttempts", propertyValue = "10"),
#ActivationConfigProperty(propertyName = "endpointExceptionRedeliveryInterval", propertyValue = "30000")})
Here's onMessage() method:
#Override
#TransactionAttribute(TransactionAttributeType.REQUIRED)
public void onMessage (Message message)
{
try
{
//some processing here
}
catch (JMSException jmsException)
{
logger.log (Level.SEVERE, "Exception processing notification message", jmsException);
}
catch (BackingStoreException e)
{
// because of throwing RuntimeException, the message is going to be redelivered according to mdb configuration params(interval and attempts count)
throw new RuntimeException ();
}
}
In order to redeliver a message it's also possible to rollback a transaction, however openMQ lacks the property for redelivery interval, so it doesn't suites me:
https://github.com/javaee/openmq/issues/220
https://github.com/javaee/openmq/issues/23
https://github.com/javaee/openmq/issues/134
All in all, redelivery works fine, besides one moment: if message is going to be redelivered, mdb doesn't release the connection and holds it for endpointExceptionRedeliveryInterval * endpointExceptionRedeliveryAttempts, in my case 5 minutes. So, cause the default values for maxPoolSize is 32, 32 "bad" messages are enough to block the mdb.
Is there are way to release the connection in case of message redelivering?
This is the expected behavior as per JMS specification and I do not think that there could be some way to release the connection object while some sort of message processing is under progress. Read JMS specs here and below is relevant except from "4.3.5 Closing a Connection":
If one or more of the connection’s session’s message listeners is
processing a message at the point connection close is invoked, all the
facilities of the connection and it’s sessions must remain available
to those listeners until they return control to the JMS provider.
When connection close is invoked it should not return until message
processing has been orderly shut down. This means that all message
listeners that may have been running have returned and that all
pending receives have returned.
I am not sure why you want to use such high numbers for retry mechanism, 10 attempts are too big to go for, maximum I have seen till now is 3 times, I think you can try to adjust your retry mechanism numbers, or may be having another connection which is dedicated to re-delivery.

Receive method in JMS waiting for messages

I want a method to browse all messages from a messsage queue and can send it to another queue using jmstemplate with using Websphere queues(NOT MQ). I have tried using receive and it is able to retrieve all the messages from the queue but it is still waiting for another message. And the messages are being lost. It must be in a transaction
The Code I have Tried:
**String message = (String) jmsTemplate.receiveAndConvert();
System.out.print(message);
while ((message = (String) jmsTemplate.receiveAndConvert()) != null) {
messages.add(message);
}
return messages;
}**
The JMStemplate should be used for only synchronous read or sending message. For asychronous read use one of the listener implementation. Read here

JMS synchronous Request/Reply using temporary queue timed out reading

I'm currently having a problem with jms synchronous request/reply approach, this is what happens:
1.) ProgramA create a jms message, a temporary queue and set it as a replyTo.
2.) ProgramB has a listener to the message created from ProgramA, process the message and reply to it. But ProgramB needs to communicate to a 3rd party web service that sometimes takes more than 10seconds to reply, and that is the problem I set the consumer to listen for 5000 (5s) and of course it will timeout afterwards. So the message is not received.
My observation:
1.) Even though ProgramA is done reading (no reply yet, at that instant I try to delete the temporary queue). It's not able to and ProgramB was still able to write to the reply queue, but nobody's going to read that message (too late).
When I try to change 5s to 20s listen time the problem was solved, but is it the right approach?
Also is it possible for the ProgramB to not try to write to the queue when ProgramA has stop reading?
Partial codes:
Destination replyQueue = send(jmsUtil, actionDTO);
SalesOrderResponseDTO responseDTO = readReply(jmsUtil, replyQueue, actionDTO);
public Destination send(JmsSessionUtil jmsUtil, SalesOrderActionDTO soDTO) {
try {
utx.begin();
jmsUtil.send(soDTO, null, 0L, 1, Long.parseLong(configBean.getProperty("jms.payrequest.timetolive")), true);
utx.commit();
return jmsUtil.getReplyQueue();
} catch (Exception e) {
try {
utx.rollback();
} catch (Exception e1) {
}
}
return null;
}
public SalesOrderResponseDTO readReply(JmsSessionUtil jmsUtil, Destination replyQueue, SalesOrderActionDTO actionDTO) {
SalesOrderResponseDTO responseDTO = null;
try {
utx.begin();
responseDTO = (SalesOrderResponseDTO) jmsUtil.read(replyQueue);
if (responseDTO != null) {
// fires the response event
SalesOrderResponsePayload eventPayload = new SalesOrderResponsePayload();
eventPayload.setResponseDTO(responseDTO);
responseEvent.fire(eventPayload);
} else { // timeout
((TemporaryQueue) replyQueue).delete();
jmsUtil.dispose();
}
utx.commit();
return responseDTO;
} catch (Exception e) {
try {
utx.rollback();
} catch (Exception e1) {
}
}
return responseDTO;
}
public String send(MessageDTO messageDTO,
JMSQueueEnum resultNotificationQueue, Long parentProcessId,
int JMSPriority, long timeToLive, boolean hasReply)
throws JMSException, InvalidDTOException, NamingException {
try {
// Process optional parameters
messageDTO.setResultNotificationQueue(resultNotificationQueue);
messageDTO.setParentProcessId(parentProcessId);
// Wrap MessageDTO in a JMS ObjectMessage
ObjectMessage msg = MessageDTOHelper.serialize(session, messageDTO);
msg.setJMSType(messageDTO.getClass().getSimpleName());
msg.setStringProperty("DTOType", messageDTO.getClass()
.getSimpleName());
requestProducer = session.createProducer(queue);
if (hasReply) {
replyQueue = session.createTemporaryQueue();
replyConsumer = session.createConsumer(replyQueue);
msg.setJMSReplyTo(replyQueue);
}
if (JMSPriority > -1) {
requestProducer.send(msg, DeliveryMode.PERSISTENT, JMSPriority,
timeToLive);
} else {
// Send the JMS message
requestProducer.send(msg);
}
return msg.getJMSMessageID();
} catch (Exception e) {
}
return null;
}
public MessageDTO read(Destination replyQueue) throws JMSException,
NamingException {
if (replyQueue instanceof Queue) {
Message msg = replyConsumer.receive(20000);
if (msg == null) {
return null;
}
MessageDTO messageDTO = MessageDTOHelper
.deserialize((ObjectMessage) msg);
return messageDTO;
} else {
}
return null;
}
Actual question here is whether you need synchronous or asynchronous communication.
I would always prefer asynchronous, and it seems from your question that there is no need for synchronous communication neither in your case. However, if there is some reason for synchronous then you are stuck with temporary queues - you'll have to specify timeout interval and you'll face problems expressed in your question. If Program A can wait, raise the timeout interval although that's far from optimal. As far as I know, there is no possibility for Program B to check if A still listens.
In case of asynchronous communication, you have (at least) two JMS options:
Using different message queues - Program A sends the message on Queue1 and finishes, but listens (e.g. through Message Driven Bean) on Queue2 where Program B puts its response when it's done. Small drawback is usage of one extra pair of producer and consumer.
Using same message queue - Program A and Program B both send and receive messages on Queue1, but with different message selector (see description here). Basically, message selectors will filter messages for specific listener and thus enable using same queue for bidirectional communication.
See also:
JMS Synchronous Message Consumption
You could have A add a header to its message with the current timestamp + 5 secs. When B receives the response from the 3rd party, if the current time is greater than the header, it should drop the result and not send. You could use the time-to-live jms message property for this, although that is not its express purpose.

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