How can I convert YYYYMM (stored as a number in oracle database) to MMM-YYYY
For e.g.
For 202001 - I want to convert into "Jan-2020".
Please help.
You can use TO_CHAR and TO_DATE as the following:
SQL> WITH YOUR_DATE ( DT ) AS ( -- your data
2 SELECT 202001 FROM DUAL
3 )
4 -- your query
5 SELECT TO_CHAR(TO_DATE(DT,'YYYYMM'), 'Mon-YYYY') AS RESULT FROM YOUR_DATE;
RESULT
--------
Jan-2020
SQL>
Cheers!!
Related
I've inherited some data from an external source which is a timestamp. This was put into warehouse by someone as a varchar2. I need to convert this to a legitimate timestamp but am unsure how. This is how the string looks. "2021-04-23T11:02:17.00Z".
Would appreciate some help.
PS Ideally, I'd also like to know how to trunc this to a more traditional date format of DD-MMM-YYYY e.g. 21-Jan-2021 or even DD-MM-YYYY is fine.
Use to_timestamp_tz() to get the corresponding timstamp with time zone, convert it to the timezone you want it in (for example sessiontimezone) with AT TIME ZONE and cast() that to a timestamp.
SELECT cast(to_timestamp_tz('2021-04-23T11:02:17.00Z', 'YYYY-MM-DD"T"HH24:MI:SS.FF2:TZR') AT TIME ZONE sessiontimezone AS timestamp)
FROM dual;
db<>fiddle
Shouldn't be too difficult. Extract the "date" part, apply TO_DATE function to it (with appropriate format mask) and - that's all. It means that you should "stop" at the date_value in the following query. The last, final_result is a string again, just formatted as you wanted.
SQL> with test (col) as
2 (select '2021-04-23T11:02:17.00Z' from dual)
3 select substr(col, 1, 10) string,
4 --
5 to_date(substr(col, 1, 10), 'yyyy-mm-dd') date_value,
6 --
7 to_char(to_date(substr(col, 1, 10), 'yyyy-mm-dd'), 'dd-mm-yyyy') final_result
8 from test;
STRING DATE_VALUE FINAL_RESU
---------- ---------- ----------
2021-04-23 2021-04-23 23-04-2021
SQL>
In order to avoid that "operation", you might even create a view. For example:
This is a table you currently have:
SQL> create table test as
2 (select 1 id, 'Littlefoot' name, '2021-04-23T11:02:17.00Z' col from dual);
Table created.
Create a view, re-using code I posted above:
SQL> create or replace view v_test as
2 select id, name,
3 to_date(substr(col, 1, 10), 'yyyy-mm-dd') col
4 from test;
View created.
Select from it:
SQL> select * from v_test;
ID NAME COL
---------- ---------- ----------
1 Littlefoot 2021-04-23
Want another format? No problem:
SQL> alter session set nls_date_format = 'dd-mon-yyyy';
Session altered.
SQL> select * from v_test;
ID NAME COL
---------- ---------- -----------
1 Littlefoot 23-apr-2021
SQL>
Or, apply TO_CHAR to view's col column (also demonstrated in code I posted first; see the final_result).
You can use the TO_TIMESTAMP function to do this.
Try:
TO_TIMESTAMP('2021-04-23T11:02:17.00Z', 'YYYY-MM-DDTHH:MI:SS')
You can read more about this function in their Documentation
I have a table with TIMESTAMP datatype and I need to compare month value to select all table values. Example the created is the field and wanted to get all the rows which is created between November & December of any year. Tried with below query and it don't work.
select * from table_name where TO_CHAR(created_time, 'mon') in ('nov','dec')
Use EXTRACT:
SELECT *
FROM table_name
WHERE EXTRACT( MONTH from created_time ) IN ( 11, 12 )
Or, you can use TO_CHAR( created_time, 'MM' ) to get the numeric month value (and not worry about language settings as you would have to with the MON format model):
SELECT *
FROM table_name
WHERE TO_CHAR( created_time, 'MM' ) IN ( '11', '12' )
db<>fiddle
Well, there are several ways to achieve this.
1.Using the nlsparam of to_char function
The 'nlsparam' argument specifies the language in which month and day names and abbreviations are returned.
Example
SQL> create table t ( c1 timestamp ) ;
Table created.
SQL> alter session set nls_timestamp_format = 'dd.mm.yyyy hh24:mi:ss.rr' ;
Session altered.
SQL> insert into t values ( systimestamp - 30 ) ;
1 row created.
SQL> insert into t values ( systimestamp ) ;
1 row created.
SQL> select * from t ;
C1
---------------------------------------------------------------------------
30.07.2020 09:29:35.20
29.08.2020 09:29:42.20
SQL> select value from nls_database_parameters where parameter='NLS_LANGUAGE' ;
VALUE
--------------------------------------------------------------------------------
AMERICAN
SQL> select c1 , to_char(c1, 'mon' , 'NLS_DATE_LANGUAGE = american') as mon from t ;
C1
---------------------------------------------------------------------------
MON
------------
30.07.2020 09:29:35
jul
29.08.2020 09:29:42
aug
2.However, to avoid depending in the language, you can use extract and compare the number of the month which is the same in any language. In this case you need to convert the timestamp to a date, but before you need to set the nls_timestamp_format to the specific format.
SQL> alter session set nls_timestamp_format = 'dd.mm.yyyy hh24:mi:ss';
Session altered.
SQL> select c1 , extract(month from to_date(c1,'dd.mm.yyyy hh24:mi:ss')) from t ;
C1
---------------------------------------------------------------------------
EXTRACT(MONTHFROMTO_DATE(C1,'DD.MM.YYYYHH24:MI:SS'))
----------------------------------------------------
30.07.2020 09:29:35
7
29.08.2020 09:29:42
8
I have a table with one column giving me dates in the form 24-JUL-17 and another column a string telling me the hour in the form hh:mm:ss.several_decimals but they are in 24 hours and not AM/PM, could someone point me on how I can add a column in oracle that combines them both into a timestamp?
CAST the date to a timestamp data type and use TO_DSINTERVAL to convert the time column to a DAY TO SECOND INTERVAL and then add one to the other:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE table_name (
date_column DATE,
time_column VARCHAR2(15)
);
INSERT INTO table_name ( date_column, time_column )
VALUES ( DATE '2017-06-24', '12:34:56.789012' );
Query 1:
SELECT CAST( date_column AS TIMESTAMP )
+ TO_DSINTERVAL( '+0 ' || time_column ) AS datetime
FROM table_name
Results:
| DATETIME |
|----------------------------|
| 2017-06-24 12:34:56.789012 |
Here is an example with a fabricated table.
WITH test_data AS (
SELECT
SYSDATE date_val,
'14:23:15.123' AS time_val
FROM
dual
) SELECT
to_timestamp(TO_CHAR(date_val,'MM/DD/YYYY')
|| ' '
|| time_val,'MM/DD/YYYY HH24:MI:SS.FF3')
FROM
test_data
Just concatenate both input strings with || and convert it with TO_TIMESTAMP. The format is a bit tricky, took me a while to get it right.
CREATE TABLE mytable (mydate VARCHAR2(9), mytime VARCHAR2(20), mytimestamp TIMESTAMP);
INSERT INTO mytable (mydate, mytime) VALUES ('24-JUL-17', '22:56:47.1915010');
Test it
SELECT TO_TIMESTAMP(mydate||mytime, 'DD-MON-YYHH24:MI:SS.FF9') FROM mytable;
2017-07-24 22:56:47,191501000
Or, in a table:
UPDATE mytable
SET mytimestamp = TO_TIMESTAMP(mydate||mytime, 'DD-MON-YYHH24:MI:SS.FF9');
I want to migrate a table which contains some columns with dates. The issue is my dates are often in dd/mm/yyyyy HH24:MM:YYYY format. But sometimes it appears that the format is only dd/mm/yyyy, or blank.
I guess that's why I'm getting ORA-01830 when I'm trying to migrate the datas.
I tried
CASE
WHEN TO_DATE(MYDATE,'DD/MM/YYYY')
then TO_DATE(MYDATE,'DD/MM/YYYY 00:00:00')
END AS MYDATE
But I'm not sure if it is possible to test the date format (and ofcourse it's not working).
Thank you
TO_DATE cannot test date format, but you can do it. If Lalit's answer would not be enough, try something like
select
case when my_date like '__/__/__' then to_date(my_date, 'dd/mm/yy')
when my_date like '__-__-__' then to_date(my_date, 'dd-mm-yy')
...
end
So you have the data type issue. DATE is stored as string literal. As you have mentioned that the date model has the DD/MM/YYYY part same, just that the time portion is either missing for some rows or the entire value is NULL.
For example, let's say your table have the values like -
SQL> WITH dates AS(
2 SELECT 1 num, '29/12/2014 16:38:57' dt FROM dual UNION ALL
3 SELECT 2, '29/12/2014' FROM dual UNION ALL
4 SELECT 3, NULL FROM dual
5 )
6 SELECT num, dt
7 FROM dates
8 /
NUM DT
---------- -------------------
1 29/12/2014 16:38:57
2 29/12/2014
3
SQL>
TO_DATE with proper format model should do the trick.
Let's stick to a format model first.
SQL> alter session set nls_date_format='dd/mm/yyyy hh24:mi:ss';
Session altered.
Now, let's use TO_DATE to explicitly convert the string literal to date.
SQL> WITH dates AS(
2 SELECT 1 num, '29/12/2014 16:38:57' dt FROM dual UNION ALL
3 SELECT 2, '29/12/2014' FROM dual UNION ALL
4 SELECT 3, NULL FROM dual
5 )
6 SELECT num, to_date(dt, 'dd/mm/yyyy hh24:mi:ss') dt
7 FROM dates
8 /
NUM DT
---------- -------------------
1 29/12/2014 16:38:57
2 29/12/2014 00:00:00
3
SQL>
in my select query i have the following
substr(to_date(NEXT_ARRIVAL_DATE, 'yyyy-mm-dd'), 0, 10)
Which yields:
08-JUN-11
What i need is it to yield:
2011-06-08
EDIT:
The data was coming in wrong. sorry. The below workds fine
to_char(to_date(NEXT_ARRIVAL_DATE, 'mm/dd/yyyy'), 'YYYY-MM-DD') || ' 00:000:00'
Your DATE_NEXT_ARRIVAL column obviously has a date datatype.
SQL> create table t23 (next_arrival_date date)
2 /
Table created.
SQL> insert into t23 values (sysdate+7)
2 /
1 row created.
SQL> select to_date(next_arrival_date, 'YYYY-MM-DD')
2 from t23
3 /
TO_DATE(N
---------
11-JUN-08
SQL>
If you want to display the date in a different format you need to use TO_CHAR() i.e. convert it to a string:
SQL> select to_char(next_arrival_date, 'YYYY-MM-DD')
2 from t23
3 /
TO_CHAR(NE
----------
2011-06-08
SQL>
If you have to do this for a whole bunch of dates, you might want to change the session settings instead....
SQL> alter session set nls_date_format='YYYY-MM-DD'
2 /
Session altered.
SQL> select sysdate, next_arrival_date
2 from t23
3 /
SYSDATE NEXT_ARRIV
---------- ----------
2011-06-01 2011-06-08
SQL>
in Oracle you can convert a DATE column to string with
to_char(NEXT_ARRIVAL_DATE, 'yyyy-mm-dd')
but it looks like the value of NEXT_ARRIVAL_DATE is a string in the required format.
so you can just do select NEXT_ARRIVAL_DATE from ...