I want to get all rows that have one unique column. The problem with my code is that it works only when I select just that one column, but in the end I need to have multiple columns.
$values= Model::select('id','value_first','gender_first','value_second','gender_second')->groupBy('value_first')->get();
Here is Solution of Your Problem
$values= Model::select('id','value_first','gender_first','value_second','gender_second')->distinct('value_first')->get();
As per Laravel Documentation you can use distinct method for the same
The distinct method allows you to force the query to return distinct
results for e.g
$values= Model::select('id','value_first','gender_first','value_second','gender_second')->distinct('value_first')->get();
Reference: Laravel-> Database: Query Builder -> Selects
Related
I am working on a project where I have to fetch only distinct data from the table display in the dropdown. How can I do that? I am using '''hasura-graphql''' data-provider for it. So how can I get only distinct data from a particular column?
Thanks in advance.
I think passing a default "distinct_on" filter with the column name as value will do the job. Also, hasura recommends sorting by this column in first position.
It is typically recommended to use order_by along with distinct_on to
ensure we get predictable results (otherwise any arbitrary row with a
distinct value of the column may be returned). Note that the
distinct_on column needs to be the first column in the order_by
expression.
So i set default sort:
<ReferenceInput
reference="yourTable"
source="yourDistinctColumn"
sort={{field: "yourDistinctColumn", order: "ASC"}}//or DESC, your choice
filter={{distinct_on: "yourDistinctColumn"}}
>
<SelectInput optionText="yourDistinctColumn"/>
</ReferenceInput>
https://hasura.io/docs/1.0/graphql/manual/queries/distinct-queries.html
Is there any query to get only one item from target column? below didn't working?
App\Job::whereNotNull('deleted_at')->pluck('customer_name')->first()
I wish to get just one item name from 'customer_name'
Now Laravel 5.6 using...
When using eloquent, using first will give you a single item, the first record matching your query. You can then access the property on that item:
// This will give you an instance of App\Job (or null)
$job = App\Job::whereNotNull('deleted_at')->first();
// You can then access the customer_name property on the object
$job->customer_name;
If you only want to retrieve that single column when you run your query, you can pass an array of columns to first.
App\Job::whereNotNull('deleted_at')->first(['customer_name']);
Assuming you're using the SoftDeletes trait in your model, your query will automatically have an additional check added to all of your queries to ensure that deleted_at is null. So when you're doing ->whereNotNull('deleted_at') you're adding an additional clause to ensure records are not null as well, so you won't have any records being returned.
If you want to look only at deleted records, you can use onlyTrashed():
App\Job::onlyTrashed()->first();
There is a built-in method for this: value('field')
App\Job::whereNotNull('deleted_at')->value('customer_name');
Docs: https://laravel.com/docs/5.6/queries, look for "Retrieving A Single Row / Column From A Table"
If you meant only one field but still as rows, you can use ->select('field') instead.
And since you want only trashed items, you can use ->onlyTrashed() instead of the not null check.
Soft deleting documentation: https://laravel.com/docs/5.6/eloquent#deleting-models
Try like this:
$job = \App\Job::selectRaw('customer_name')
->whereNotNull('deleted_at')
->first();
And use it like $job->customer_name
I'm trying to create duplicate records in my result set in order for me to show row more than once in a report. Some rows need to show up in multiple groups. My answer to this is to have FetchXML return dupes and then ill just create group filters to solve my problem. If you guys have better approach to my problem let me know. Thanks.
You must use subreport for this case and pass parameters into it from main report.
I have a report that needs to be generated from two different queries.
The first query retrieves a list of information from one data source
The second query must then be called once for each of the records returned by the first query?
Each result set from the second query will then be displayed in separate report tables.
Any pointers are welcome.
It is not possible to perform a SQL join on the first and second query.
Yes this is possible lets assume you have bind your first query results to data table. you can create another table inside the parent table cell and assign your 2 data set to that table with filter of dataset 1
http://publib.boulder.ibm.com/infocenter/rmc/v7r5m0/index.jsp?topic=/org.eclipse.birt.doc/birt/birt-13-1.html
http://publib.boulder.ibm.com/infocenter/rmc/v7r5m0/index.jsp?topic=/org.eclipse.birt.doc/birt/birt-13-2.html
The functionality I require is provided by SubReports
http://www.eclipse.org/birt/phoenix/examples/reports/birt2.1/subreport/index.php
I have looked around and have not found anything similar to what I am asking.
Short of extending the CActiveRecord class is there a way to query just the primary key values (or any column's values) of a table and have an array of those values returned instead of a collection of activerecord objects?
ie
ModelName::model()->getColumnValues('column_name');
I keep having to get a list of record that match a certain condition and then run through the results to pull out the column values I need. I would like to cut out the last step and just get the values instead of the entire record.
Any ideas?
Using a CDbCommand you can execute a query and fetch the results from one column with the queryColumn method. queryColumn returns the results from the first column.
Example:
$command = Yii::app()->db->createCommand("SELECT column FROM table WHERE ...");
$result = $command->queryColumn();