Laravel - Using Stream with the new Http client - laravel

Question

I'm migrating my old system to the new version of Laravel, and I'm having problems with one of my requests...
Basically on this request I receive any file and simply forward it to the user. Here is the old version using Guzzle:
use Symfony\Component\HttpFoundation\StreamedResponse;
public function getMedia($media)
{
try {
$response = $this->client->get('media/' . $media, [
'stream' => true
]
);
$contentType = $response->getHeader('Content-Type');
$body = $response->getBody();
$stream = new StreamedResponse(function () use ($body) {
while (!$body->eof()) {
echo $body->read(1024);
}
});
$stream->headers->set('Content-Type', $contentType);
return $stream;
} catch (ClientException $e) {
return response()->json([
'errors' => json_decode($e->getResponse()->getBody()->getContents())->errors,
'message' => 'Unfortunately we could not find the requested file'
], 404);
}
}
And the new code that I tried to write, without success:
use Symfony\Component\HttpFoundation\StreamedResponse;
public function getMedia($media)
{
$response = Http::withOptions([
'stream' => true
])->get("media/{$media}");
$contentType = $response->header('Content-Type');
$body = $response->body();
$stream = new StreamedResponse(function () use ($body) {
while (!$body->eof()) {
echo $body->read(1024);
}
});
$stream->headers->set('Content-Type', $contentType);
return $stream;
}
Does anyone have any idea how to solve this? I don't know what to do anymore...

Answer 1

I know, 2 years late, but i'm doing something similar, you should access to the response via the psr
instead of:
$body = $response->body(); // This try to return an string
Use this:
$body = $response->toPsrResponse()->getBody(); // the guzzle response
Then you can use your normal code
I hope someone can find this useful,