What is wrong with the shell script for curl post command - bash

Question

i need help in understanding what is wrong with the below shell script,all its doing is executing a curl script using shell scripting and searching for a string domain_id in the output of curl command ,once it finds the search all it does it simply displays valid url
Here is the full code for shell script below
#!/bin/sh
# Black Box Tester!
url=”https://api.platform.abc.com/auth/oauth/token“
content=”$(curl --location --request POST “$url” --header 'Content-Type:
application/x-www-form-urlencoded' --header 'Authorization: Basic
V0pSWURISA==' --data-raw 'grant_type=password&username=event-
player1#abc.com&password=********' | grep domain_id”
if [ ! -z $content ] && [ $content -eq domain_id ]
then
echo “valid url”
else
echo “invalid url”
fi
Below is the error i get in console after i try executing the script
WS-126691A:loginimagedocker carolyn$ ./login.sh
./login.sh: line 4: unexpected EOF while looking for matching `)'
./login.sh: line 11: syntax error: unexpected end of file

Answer 1

You are trying to pass parameter in multiple line without mentioning end of line.
use \ to pass multi line argument
#!/bin/sh
# Black Box Tester!
url=”http://api.platform.abc.com/auth/oauth/token“
content=”$(curl --location --request POST “$url” --header 'Content-Type: \
application/x-www-form-urlencoded' --header 'Authorization: Basic \
V0pSWURISA==' --data-raw 'grant_type=password&username=event- \
player1#abc.com&password=********' | grep domain_id” )
if [ ! -z $content ] && [ $content -eq domain_id ]
then
echo “valid url”
else
echo “invalid url”
fi