Windows can access file, DOS file copy gets Access Denied - windows

I'm trying to set up a set of folders on a Windows NT server 2008 (yes, I know, old) where a user doesn't have access to see the list of files within the folder, but can read a file if they know the full file path.
So I've set up the following AD permissions:
Permissions on the containing folder ("This folder only"):
Traverse folder / execute file
Read attributes
Read extended attributes
Read permissions
Permissions on the files ("Files only"):
Traverse folder / execute file
List folder / read data
Read attributes
Read extended attributes
Read permissions
... and from windows, everything looks great! I can't see inside the folder, but if I know the full path to a file within, I can type it into an address bar and open the file.
But when I run in Command Prompt:
COPY "FullPathToSameFileAsBefore.txt" "C:\someLocalSpot.txt"
... I get:
Access is denied.
0 file(s) copied.
Any ideas? Is there some special access Command Prompt needs to perform the copy that windows doesn't in order to read the file? Any alternatives that will work instead? I can set any of the permissions that are needed, with the caveat that the user cannot see the list of files within the directory.
EDIT with additional info:
So I tried to perform a copy with VBScript using a FileSystemObject. Same error. But using VBScript to read the file with an ADODB binary stream does work.
So it seems to boil down to "You can read this file, but you can't perform a copy." Which seems weird, since if you can read the file, you can certainly copy it (read it, then write the contents someplace else.)

Related

Stata can't open file saved in local cloud storage folder on Mac

I am using Stata on a Mac. I updated the OS to Monterey today. If I try to open a .dta file---that is saved on my local computer in a folder that syncs to OneDrive---from code in the Do File Editor/Command prompt (where I refer to the file using its full file path), it doesn't open. The error is r(601) - File ... cannot be found.
But if I click on it in Finder, it opens in Stata just fine. After I have done this, I can then open this file in Stata by running the exact same Stata code that didn't work before. Somehow it seems like Stata can't see the file/folder initially, but then it can. I am not sure if this has to do with the OneDrive file/folder permissions or something else.
If, in Stata, I change the directory to the correct directory using cd and then load the file (without referring to the path), it works. However, I would like to be able to refer to the file using the entire file path and not have to change the directory each time.
Interestingly, if I change the directory to the correct directory using Change working directory in the File drop down and then try to load the file using the file path, it also works. But if I do not do the drop down and write out the cd using code, and try accessing the file using the path it doesn't work!
Somehow Stata has to initially "see"/"access" the correct folder (in a very particular way) before being able to access it with the file path. Very strange. (Just to be clear, if I do not change the directory to the correct directory and then try to load the file using its file path, it doesn't work.)
I also tried creating a file using texdoc init... (in a folder that already exists, but that has not been used by Stata before) and get this error:
could not create directory .....
mkdir(): 693 could not create directory
texdoc_mkdir(): - function returned error
texdoc_init(): - function returned error
<istmt>: - function returned error
I do not get this error if I instead use another folder in the same directory that I have previously used.
I think that the error I am encountering is the same or similar to this one (with no acceptable answer): https://answers.microsoft.com/en-us/msoffice/forum/all/onedrive-folder-doesnt-exist/e6b97d47-3f6a-4863-bf68-d3a02832f2bb

Windows - Writing to file with `.txt` or `.zip` says Access denied

I'm trying to write data to a text file in Windows programatically (either through cmd directly or from a scripting language like Lua), but if I try to open any file with the following conditions, an error occurs, saying permission denied.
the file name ends with .txt or .zip
I try to create the file inside some subfolders of my user folder, e.g. %USERPROFILE%\Documents\**\file.txt or %USERPROFILE%\Pictures\**\file.zip.
this is done programatically (works fine using any GUI).
This happens only on Windows, and even if I run cmd with admin rights.
C:\Users\Username\Pictures>echo aaaa > a.txt
Access denied.
C:\Users\Username\Documents>echo aaaa > a.txt
Access denied.
EDIT: I noticed this was specific to subfolders of %USERPROFILE%, and not related to Lua, which the original text of this question was about. So I rewrote the question to reflect the problem properly.
I still can't find any pattern of which folders are affected by this, currently only Pictures and Documents.

Creating a directory that is read only

I need to know if it is possible to create a read only directory from windows command line.
I know it is possible to use chmod and make files read only. But what I need is to create a folder and then immediately set it as read only upon creation. Trying to create new files inside this directory should then throw an error.
This can be done manually by modifying folder permissions using the gui. But, I need to do it from cmd for some tests.
I tried
attrib +r dirPath
But this only works for files and not for the whole directory.
Any help is appreciated.
EDIT:
A background to me problem. I need to test the behavior of a software that writes some text files. I want to test a use-case when I ask the software to write to a read only directory. I want to see I handle the exceptions correctly and inform users appropriately.

Saving SQL files into specific folders in Oracle

I am using Oracle 11g. When I open a new SQL file writing the command
ed filename.sql
A new file is created in my bin folder with the name as filename but, I want them to be in separate folders for my convenience. I am developing 3 application(well for my practice only). I want them to store in different folders for each project. I tried all of the following none of them worked please tell me how can I save the files into specific folders.
ed erp/logindetails.sql
ed 'erp/logindetails.sql'
ed "erp/logindetails.sql"
ed 'erp\logindetails.sql'
ed erp\logindetails.sql
These commands except where I used "" worked and opened the default text editor with the name afiedt.buf which I am getting when I enter only edit. No files are created with any of the above command.
You're giving EDIT a relative path to the file; since your current working directory seems to be the bin directory that the SQL*Plus directory is in (is this Windows, and are you running a shortcut that sets the working directory, maybe?) it will try to create a file like %ORACLE_HOME%\bin\erp\logindetails.sql, and you're unlikely to have created an erp directory there. Giving the full path to the directory will work:
edit c:\users\dibya\projects\erp\logindetails.sql
for example.
As noted in the documentation, EDIT will search for existing files, but that involves setting an environment variable - which you'd have to change as you move between the projects. You might find it easier to edit the files in the OS and just run them from SQL*Plus.
You might also be able to use separate shortcuts to launch SQL*Plus for each project, each setting the 'start in' directory to a project-specific location - then just edit logindetails.sql would be looking in the right place by default. Or, from a command prompt cd into the relevant project-specific directory and launch SQL*Plus from there, which is effectively what a shortcut would do.

Executing binary files with a shebang

I created a simple program that takes the path of a directory as an input, creates an archive of that directory (converting it into a single file), adds a shebang to that file (so that the contents of the file can be easily extracted), and writes the file to the base directory of the specified path.
The problem is that the file does not extract itself when I double click on it. Instead the operating system (I'm using Ubuntu 11.10) tries to open it with gedit. This obviously shows the shebang, random gibberish, and the contents of the archived files.
I made the file executable, first by using chmod +x; and when it still didn't work I tried chmod 777. However it still refuses to execute the file with the shebang when I double click on it. Perhaps this is because it's not a pure text file.
Interestingly when I try to execute the file directly from command line it reads the shebang and extracts the contents of the archive properly. So there's nothing wrong with my file format. I don't know much about what operating systems do when you double click on a file but I would sure like to understand.
It surely makes no sense to add a shebang to a file if you still need to manually execute it from the command line. One advantage could be that you don't need to specify the program to open it with but I believe that's hardly an advantage. Any help will be greatly appreciated.
Update 1:
The program that creates the archive is called opm. It can be installed via the node package manager using the following command:
npm install opm
After that you simply use opm to pack and unpack directories for you. For example if I have a directory called test in my home directory then I can open a terminal and execute the following command to pack it:
opm test
This will create an archive of the directory called test.pack in the home directory. The .pack file has the shebang #!/usr/bin/opm. Opening a file with the extension .pack with opm tells it that it's an archive and opm unpacks it in the same directory.
Note: Change the name of the test.pack file if you do not want it to overwrite your existing test directory.
I added the shebang to the .pack file so that it would extract itself when I opened it. However that doesn't seem to work. Nevertheless if I run one of the following command then it works:
./test.pack
You may check my source code and make any modifications to the program as you may wish to.
Update 2:
Alright I created the following .desktop file for opm and stored it in the $HOME/.local/share/applications/ directory:
[Desktop Entry]
Type=Application
Version=1.0
Encoding=UTF-8
Name=OPM
GenericName=Object Packer and Minifier
NoDisplay=true
Comment=JavaScript Package Manager
TryExec=opm
Exec=opm %f
Terminal=false
MimeType=application/opm
Now I was able to associate .pack files with opm by right clicking on a .pack file, going to the Properties window, the Open With tab, and setting opm.desktop as the default application. Now I am able to unpack a .pack file by simply opening it.
However I would like to know how to associate .pack files with the mime type application/opm. Currently the .pack files are associated with application/x-java-pack200. How do I do so? Is it better if I use a different extension (e.g. .opm)? By associating the packed archives with the mime type application/opm will the OS open them with opm by default without having to explicitly set a default application from Properties > Open With?
If there's already a MIME-type associated with .pack then you'll want to use a different extension (.opm) to associate with your MIME-type (application/opm). The way you automatically associate a program that opens files of a specific MIME-type is with xdg-mime .
Alternatively,
Edit ~/.local/share/applications/mimeapps.list and put your MIME/application combo under [Default Applications] like so:
[Default Applications]
application/opm=opm.desktop;
Place your opm.desktop file in ~/.local/share/applications/ folder. (You've already done this)

Resources