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I want to write a script on Bash that does:
I have a file, that consists of string like this:
2002-02-15 00:01:19 217.21.43.21 RES company_name
2002-02-15 00:01:19 217.21.43.21 RES company_name
2002-02-15 00:01:19 217.21.43.21 DEL company_name
2002-02-13 00:01:19 217.21.43.21 RES company_name
I need to calculate the number of requests with parameter RES for each day.
Output of script should be:
2002-02-15 2
2002-02-13 1
This should be enough:
awk '/RES/ { N[$1] += 1; }; END { for (day in N) { print day, N[day] } }' your_input
It creates an associative array N whose indices are the days of the first field, and whose values are incremented by one for every line matching RES.
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how can I use for loop to delete maximum and minimum values from a dictionary. for instance if you have a dictionary grades = {sam: [23,43,55]}, peter: [66,55,44], sarah: [99,55,77]}. how can I remove only the maximum and minimum values?
im new to coding and cannot figure it out. Language is python
Hi you can try something like this:
# Create dictionary
dic = {'sam': [23,43,55], 'peter': [66,55,44], 'sarah': [99,55,77]}
# Use for loop to iterate
for key, value in dic.items():
# Find maximum value and it's index
max_value = max(value)
max_index = value.index(max_value)
# Delete maximum value
del dic[key][max_index]
# Find minimum value and it's index
min_value = min(value)
min_index = value.index(min_value)
# Delete miniumum value
del dic[key][min_index]
# Print output
print(dic)
Let me know if you don't understand anything. Cheers
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Im aiming for a regex formula to return chunks of a string based on a character, if this string contains L1 then its going to be only one chunk, if L2 is found it would return 2 chunks, L3 = 3 chunks.
Example
Lets assume we have this string
"L2N1N1"
and we would like to get 2 string
"L2N1" and "L2N1N1"
Another example
"L3N1N1N2"
to return 3 strings
"L3N1" "L3N1N1" "L3N1N1N2"
Im using Ruby
"L3N1N1N2".sub(/L(\d)(?:N\d)+/) do |m|
$1.to_i.times.map { |i| m[0..3+2*i] }.join(' ')
end
#⇒ "L3N1 L3N1N1 L3N1N1N2"
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I need a regular expression that only matches three digit numbers in the following array. I need the result to be a new array.
Input:
my_array = [111,45456,456,74897,787,45466,789,6587,784,234,456,4658,4587,235,456]
Desired output:
new_array = [111,456,787,789,784,234,456,235,456]
Why regular expression on numbers? You can select all numbers less than 1000 and greater than 99.
my_array.select { |n| n<1000 && n>99 }
Just the regexp would look like this: /^\d{3}$/. But if you'd like an expression that would return an array of values that match that expression this would do it: my_array.select{ |num| num.to_s.match(/^\d{3}$/) }.
Take a look at RegExr to learn more about Regular Expressions.
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I use the excellent faker gem to generate random words for my models. Eg. product.name = Faker::Lorem.word
Sometimes I need to generate a sentence, and I want the length of the sentence to
vary each time.
How to achieve this with ruby?
How about:
result = rand(max_size).times.map { produce_word }
Since you have not provided enough information, this is my approach, [*1..100].sample will return a random number between 1 and 100, so looping that times the string which is returned bya method named get_word will get stored in the array word_array
word_array = []
[*1..100].sample.times do
word_array << get_word
end
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I'm creating a quick search rails app feature. Any help with how to structure the following matching specifications would be appreciated.
Basically, when a user enters a name to search, they should get results based on the following matching criteria.
accept match on first 3 chars (e.g. Jon for Jones)
reject match on less than 3 chars (e.g. Jo for Jones)
accept exact match for 2 char author name (e.g. Li for Li)
reject exact match on 1 char author name
reject mismatch on chars beyond 3 (e.g. reject Jonis for Jones)
Can this be done with a regular expression?
matchto = 'Jones'.downcase
input = 'Jon'.downcase
matchto.start_with?(input) && 1 < input.length &&
( input.length == matchto.length || 2 < input.length )