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Hel lo I have a df file such as
col1;col2;col3;col4
A;B;C;D
E;F;G;H
I;J;K;L
and I would like to grep I and only display the col1 and col2
and get
I;J then
because from now I only know how to do :
grep 'I' df.csv
I;J;K;L
Try this:
grep 'I' df.csv | cut -d';' -f1-2
The cut command will treat each input line as a list of fields separated by ; (-d';'), and will select only the first two fields (-f1-2) for output.
Sample session:
$ cat df.csv
col1;col2;col3;col4
A;B;C;D
E;F;G;H
I;J;K;L
$ grep 'I' df.csv | cut -d';' -f1-2
I;J
$
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What is the way to know the IP address of a website such as Www.google.com by bash script?
ping -c1 www.google.com | grep PING | cut -d"(" -f2 | cut -d ")" -f1
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I am trying to concatenate the output of three cut functions with - in a shell script in a single line. I tried as below, but wont work. How do I do this ?
echo "$(cut -d',' -f2 FILE.csv)-$(cut -d',' -f1 FILE.csv)-$(cut -d',' -f3 FILE.csv)"
Using awk to change the delimiter:
awk -F, '{ print $2, $1, $3 }' OFS='-' FILE.csv
Or with csvkit commands (Especially useful if your file has more complex CSV with things like commas in quoted fields or multi-line fields that a naive split on comma can't handle correctly):
csvcut --columns 2,1,3 FILE.csv | csvformat -D'-'
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I have list
dasfdsaf
afddt4fd
asdw5h6ufdh
sfds2dsddf2nu
dsfnjufsd443ajisdfaij
sdfjid654sij
asfdnu7sdfui
sdfmii
I want to move all lines containing numbers in it to new file.
If your grep has the -P option:
grep -P '\d' old_file > new_file
grep -vP '\d' old_file > temp
mv temp old_file
If -P isn't supported, use [0-9] instead of \d to match digits:
grep '[0-9]' old_file > new_file
grep -v '[0-9]' old_file > temp
mv temp old_file
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Exactly what the title says: what is the bash command for printing out the longest word in a text file that appears at least 10 times.
Try this Denis:
tr -s " " "\n" < file | while read -r l; do echo "${#l} $l"; done | sort -n | awk '$1 >= 10 ' | awk '{print $2}' | tail -n1
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I have this list of inputs :
imalex
thislara
heiscarl
how to get :
alex
lara
carl
grep
Use grep to take the last four chars:
grep -o '.\{4\}$' file
The -o option makes sure only matched parts are printed.
sed
Using sed we can achieve a similar result:
sed 's/.*\(.\{4\}\)$/\1/' a
Here we capture the last four digits and replace each line with those last four digits. They are captured in a group \( \) and inserted \1.
read & tail
We can also grab the last five chars (including the newline) of each line using tail and a -c option. We do that for each line using read.
while read line; do
tail -c 5 <<< $line
done < file
2 answers using substring arithmetic
bash:
while read word; do
echo "${word:${#word}-4}"
done <<<"$list"
awk
echo "$list" | awk '{print substr($NF, length($NF)-4+1)}'