Here I have a zip file but I have no idea what the name it is. I want to assign filename to a variable after unzipping the zip file in bash shell but I got some message like
Archive: name.zip inflating: ...inflating: ..
Here is my script and anyone knows whats the wrong with it?
filename=$(unzip -o *.zip)
echo $filename
If I understand you correctly: you have one ZIP file but you don't know its name. That ZIP file contains one directory at top level whose name you want to put into the variable $filename.
Try:
filename=$(unzip -Z -1 *.zip | head -n1 | sed 's/\/$//')
echo $filename
But if you are sure that the name of the top directory inside your ZIP archive is the same as the name of the archive itself without the suffix .zip, which is the default behaviour of zip, you can just try:
filename=$(basename -s .zip *.zip)
echo $filename
You just need to loop over the .zip files:
for f in *.zip; do echo "unzipping $f"; unzip -o "$f"; done;
(unzip will not return the name of the zip archive. Doing this will give you the name in $f.)
Related
I'm just learning shell scripting specifically in bash, I want to be able to use gzip to take files from a target directory and send them to a different directory. I enter directories in the command line. ext is for the extensions I want to zip and file will be the new zipped file. My script zips the files correctly, to and from the desired directories, but I get a no such file or directory error. How do I avoid this?
Current code
cd $1
for ext in $*; do
for file in `ls *.$ext`; do
gzip -c $file > $2/$file.gz
done
done
and my I/O
blackton#ltsp-amd64-charlie:~/Desktop/60256$ bash myCompress /home/blackton/Desktop/ /home/blackton/ txt
ls: cannot access *./home/blackton/Desktop/: No such file or directory
ls: cannot access *./home/blackton/: No such file or directory
gzip: alg: No such file or directory
gzip: proj.txt: No such file or directory
There are two separate things causing problems here.
In your outer loop
for ext in $*; do
done
you are looping over all the command line parameters, using each as the extension to search for - including the directory names.
Since the extension is the third parameter, you only want to run the inner loop once on $3:
for file in `ls *.$3`; do
gzip -c $file > $2/$file.gz
done
The next problem is spaces.
You do not want to run ls here - the wildcard expansion will provide the filenames directly, e.g. for file in *.$3, and it will fill $file with a whole filename at a time. The output from ls is split on each space, so you end up with two filenames alg and proj.txt, instead of one alg proj.txt.
That is not enough by itself, though. You also need to quote $file whenever you use it, so the command expands to gzip -c "alg proj.txt" instead of gzip -c alg proj.txt, which tells gzip to compress two files. In general, all variable expansions that you expect to be a filename should be quoted:
cd "$1"
for file in *."$3"; do
gzip -c "$file" > "$2/$file.gz"
done
One further problem is that if there are no files matching the extension, the wildcard will not expand and the command executed will be
gzip -c "*.txt" > "dir/*.txt.gz"
This will create a file that is literally called "*.txt.gz" in the target directory. A simple way to avoid this would be to check that the original file exists first - this will also avoid accidentally trying to gzip an oddly named directory.
cd "$1"
for file in *."$3"; do
if [ -f "$file" ]; then
gzip -c "$file" > "$2/$file.gz"
fi
done
you can try this;
#!/bin/bash
Src=$1
Des=$2
ext="txt"
for file in $Src/*; do
if [ "${file##*.}" = "${ext}" ]; then
base=$(basename $file)
mkdir -p $2 #-p ensures creation if directory does not exist
gzip -c $file > $Des/$base.gz
fi
done
The goal of the script is to check to see if a filename exists inside a folder. If the file name does NOT exist, then delete the file.
This is the script I got so far
#!/bin/bash
echo "What's the folder name?"
read folderName
$fileLocation="/home/daniel/Dropbox/Code/Python/FR/alignedImages/$folderName"
for files in "/home/daniel/Dropbox/Code/Python/FR/trainingImages/$folderName"/*
do
fileNameWithFormatFiles=${files##*$folderName/}
fileNameFiles=${fileNameWithFormat%%.png*}
for entry in "/home/daniel/Dropbox/Code/Python/FR/alignedImages/$folderName"/*
do
fileNameWithFormat=${entry##*$folderName/}
fileName=${fileNameWithFormat%%.png*}
if [ -f "/home/daniel/Dropbox/Code/Python/FR/alignedImages/$fileNameFiles.jpg" ]
then
echo "Found File"
else
echo $files
rm -f $files
fi
done
done
read
I have two folders, alignedImages and trainingImages.
All of the images in alignedImages will be inside trainingImages, but not the otherway around. So, I'm trying to make it so that if trainingImages does not contain a file with the same name as the file in alignedImages, then I want it to delete the file in trainingImages.
Also, the pictures are not the same, so I can't just compare md5's or hashes or whatever. Just the file names would be the same, except they are .jpg instead of .png
fileLocation="/home/daniel/Dropbox/Code/Python/FR/alignedImages/$folderName"
echo "What's the folder name?"
read folderName
rsync --delete --ignore-existing $fileLocation $folderName
rsync command is what you are looking for and when given the --delete option it will delete from destination dir any file that doesn't exist in source dir and --ignore-existing will cause rsync skip copying files from source if a file with same name already exist in destination dir.
The side effect of this is that it would copy any file in source dir but not in destination. You say all files in source are in destination so I guess that's ok
there is a better way! files, not for loops!
#!/bin/bash
echo "What's the folder name?"
read folderName
cd "/home/daniel/Dropbox/Code/Python/FR/alignedImages/$folderName"
find . -type f -name "*.png" | sed 's/\.png//' > /tmp/align.list
cd "/home/daniel/Dropbox/Code/Python/FR/trainingImages/$folderName"
find . -type f -name "*.jpg" | sed 's/\.jpg//' > /tmp/train.list
here's how to find files in both lists:
fgrep -f /tmp/align.list /tmp/train.list | sed 's/.*/&.jpg/' > /tmp/train_and_align.list
fgrep -v finds non-matches instead of matches: find files in train but not align:
fgrep -v -f /tmp/align.list /tmp/train.list | sed 's/.*/&.jpg/' > /tmp/train_not_align.list
test delete of all files in train_not_align.list:
cd "/home/daniel/Dropbox/Code/Python/FR/trainingImages/$folderName"
cat /tmp/train_not_align.list | tr '\n' '\0' | xargs -0 echo rm -f
(if this produces good output, remove the echo statement to actually delete those files.)
Files
events-number1.10a.pdf
Result
events-number1.10a.docx.pdf
Ideal
events-number1.10a.pdf
events-number1.10a.docx.pdf
A simple rename command will do the job.
rename 's/(?=\.pdf$)/.docx/' *.pdf
You can try this simple bash script
#!/bin/bash
for file in *.pdf
do
new_file=$(echo "$file" | sed -r 's/(.*)(\.pdf)/\1.docx\2/')
mv $file $new_file
done
Output:
events-number1.index10a.docx.pdf
events-number1.index10b.docx.pdf
events-number1.index10c.docx.pdf
events-number2.index10a.docx.pdf
events-number2.index10b.docx.pdf
events-number2.index10c.docx.pdf
If you want copy the file using cp command instead of mv command
cp $file $new_file
So your existing files won't change.
Explanation :
Passing all the log file to for loop ,then split the file name to your expected result for using sed command and stored in one variable . Then mv the old file to new file that mean your expected file .
I have a folder that after an rsync will have a zip in it. I want to unzip it to its own folder(if the zip is L155.zip, to unzip its content to L155 folder). The problem is that I dont know it's name beforehand(although i know it will be "letter-number-number-number"), so I have to unzip an uknown file to its unknown folder and this to be done automatically.
The command “unzip *”(or unzip *.zip) works in terminal, but not in a script.
These are the commands that have worked through terminal one by one, but dont work in a script.
#!/bin/bash
unzip * #also tried .zip and /path/to/file/* when script is on different folder
i=$(ls | head -1)
y=${i:0:4}
mkdir $y
unzip * -d $y
First I unzip the file, then I read the name of the first extracted file through ls and save it in a variable.I take the first 4 chars and make a directory with it and then again unzip the files to that specific folder.
The whole procedure after first unzip is done, is because the files inside .zip, all start with a name that the zip already has, so if L155.ZIP is the zip, the files inside with be L155***.txt.
The zip file is at /path/to/file/NAME.zip.
When I run the script I get errors like the following:
unzip: cannot find or open /path/to/file/*.ZIP
unzip: cannot find or open /path/to/file//*.ZIP.zip
unzip: cannot find or open /path/to/file//*.ZIP.ZIP. No zipfiles found.
mkdir: cannot create directory 'data': File exists data
unzip: cannot find or open data, data.zip or data.ZIP.
Original answer
Supposing that foo.zip contains a folder foo, you could simply run
#!/bin/bash
unzip \*.zip \*
And then run it as bash auto-unzip.sh.
If you want to have these files extracted into a different folder, then I would modify the above as
#!/bin/bash
cp *.zip /home/user
cd /home/user
unzip \*.zip \*
rm *.zip
This, of course, you would run from the folder where all the zip files are stored.
Another answer
Another "simple" fix is to get dtrx (also available in the Ubuntu repos, possibly for other distros). This will extract each of your *.zip files into its own folder. So if you want the data in a different folder, I'd follow the second example and change it thusly:
#!/bin/bash
cp *.zip /home/user
cd /home/user
dtrx *.zip
rm *.zip
I would try the following.
for i in *.[Zz][Ii][Pp]; do
DIRECTORY=$(basename "$i" .zip)
DIRECTORY=$(basename "$DIRECTORY" .ZIP)
unzip "$i" -d "$DIRECTORY"
done
As noted, the basename program removes the indicated suffix .zip from the filename provided.
I have edited it to be case-insensitive. Both .zip and .ZIP will be recognized.
for zfile in $(find . -maxdepth 1 -type f -name "*.zip")
do
fn=$(echo ${zfile:2:4}) # this will give you the filename without .zip extension
mkdir -p "$fn"
unzip "$zfile" -d "$fn"
done
If the folder has only file file with the extension .zip, you can extract the name without an extension with the basename tool:
BASE=$(basename *.zip .zip)
This will produce an error message if there is more than one file matching *.zip.
Just to be clear about the issue here, the assumption is that the zip file does not contain a folder structure. If it did, there would be no problem; you could simply extract it into the subfolders with unzip. The following is only needed if your zipfile contains loose files, and you want to extract them into a subfolder.
With that caveat, the following should work:
#!/bin/bash
DIR=${1:-.}
BASE=$(basename "$DIR/"*.zip .zip 2>/dev/null) ||
{ echo More than one zipfile >> /dev/stderr; exit 1; }
if [[ $BASE = "*" ]]; then
echo No zipfile found >> /dev/stderr
exit 1
fi
mkdir -p "$DIR/$BASE" ||
{ echo Could not create $DIR/$BASE >> /dev/stderr; exit 1; }
unzip "$DIR/$BASE.zip" -d "$DIR/$BASE"
Put it in a file (anywhere), call it something like unzipper.sh, and chmod a+x it. Then you can call it like this:
/path/to/unzipper.sh /path/to/data_directory
simple one liner I use all the time
$ for file in `ls *.zip`; do unzip $file -d `echo $file | cut -d . -f 1`; done
How could I read the content of a parent folder and if sub-folders are found, then make a tar.gz files of those subfolders found. However, I know that subfolders will have the following filename format: name-1.2.3 What I want is to create a tar.gz file that looks like: name-1.2.3-20100928.tar.gz Any help will be appreciated.
#!/bin/sh
DATE=`/bin/date +%y%m%e`
cd /path/to/your/folder
for folder in *; do
if [ -d $folder ]; then
tar -cvzf $folder-$DATE.tar.gz $folder
fi
done
Better immunize your scripts against spaces in names:
#!/bin/bash
# Yes nested quoting is allowed with $(...) syntax, no matter whether syntax coloration does
DATE="$(/bin/date "+%y%m%e")"
cd /path/to/your/folder
for folder in * ; do
if test -d "$folder" ; then
tar cvzf "$folder-$DATE.tar.gz" "$folder"
fi
done