Replace a character within a shell script - bash

I have a script:
$cat ifile.sh
extension="name.f"
parameter_list="abc,xyz,stuv,ptq,rhu"
echo newfiles are $parameter_list
I would like to execute the ifile.sh and output should replace the comma , with extension i.e. _name.f. So my desire output will be
$sh ifile.sh
newfiles are abc_name.f xyz_name.f stuv_name.f ptq_name.f rhu_name.f
So I need to modify the echo newfiles are $parameter_list. I am trying with the follwoing
$cat ifile.sh
extension="name.f"
parameter_list="abc,xyz,stuv,ptq,rhu"
echo newfiles are sed -i 's/,/$extension/g' $parameter_list

Use a parameter expansion.
echo "newfiles are ${parameter_list//,/_$extension }_$extension"

Related

How to process text in shell script and assign to varibles?

sample.text file .
var1=https://www.process.com
var2=https://www.hp.com
var3=http://www.google.com
:
:
varz=https://www.sample.com
i am sending this sample txt as input to one script.
that script should split the lines and assign the variables to diff parameters
like
$varn= $var1,....$varn
$value=https://www.sample.com ( all the variables value)
i am trying with below script not working .
#!/bin/bash
for $1 in ( cat sample.txt );
do
echo $1 #var1=https://www.process.com
sed 's/=/\n/g' $1 | awk 'NR%2==0'
done
main aim is to assign all urls to one variable and vars to one variable and process the file
If sample.text already contains your variable assignments for you, e.g.
var1=https://www.process.com
var2=https://www.hp.com
var3=http://www.google.com
and you want access to var1, var2, ... varn, then you are making things difficult on yourself by trying to read and parse sample.text instead of simply sourcing it with '.' or source.
For example, given sample.text containing:
$ cat sample.text
var1=https://www.process.com
var2=https://www.hp.com
var3=http://www.google.com
varz=https://www.sample.com
You need only source the file to access the variable, e.g.
#!/bin/bash
. sample.text || {
printf "error sourcing sample.text\n"
exit 1
}
printf "%s\n" $var{1..3} $varz
Example Use/Output
$ bash source_sample.sh
https://www.process.com
https://www.hp.com
http://www.google.com
https://www.sample.com
Look things over and let me know if you have further questions.

How do I replace text using a variable in a shell script

I have a variable with a bunch of data.
text = "ABCDEFGHIJK"
file = garbage.txt //iiuhdsfiuhdsihf]sdiuhdfoidsoijsf
What I would like to do is replace the ] charachter in file with text. I've tried using sed but I keep getting odd errors.
output should be:
//iiuhdsfiuhdsihfABCDEFGHIJKsdiuhdfoidsoijsf
Just need to escape the ] character with a \ in regex:
text="ABCDEFGHIJK"
sed "s/\(.*\)\]\(.*\)/\1$text\2/" file > file.changed
or, for in-place editing:
sed -i "s/\(.*\)\]\(.*\)/\1$text\2/" file
Test:
sed "s/\(.*\)\]\(.*\)/\1$text\2/" <<< "iiuhdsfiuhdsihf]sdiuhdfoidsoijsf"
# output => iiuhdsfiuhdsihfABCDEFGHIJKsdiuhdfoidsoijsf
There is always the bash way that should work in your osx:
filevar=$(cat file)
echo "${filevar/]/$text}" #to replace first occurence
OR
echo "${filevar//]/$text}" #to replace all occurences
In my bash i don't even have to escape ].
By the way, the simple sed does not work?
$ a="AA"
$ echo "garbage.txt //iiuhdsfiuhdsihf]sdiuhdfoidsoijsf" |sed "s/]/$a/g"
garbage.txt //iiuhdsfiuhdsihfAAsdiuhdfoidsoijsf

Replace an unknown string within a line using Bash

I want to be able to modify db001 with a string I pass into the command via CLI. At any given time db001 could be a different value so I can't just look for that value.
./myscript modify_db <new value>
myfile.txt
./myscript modify_db mynewdbname002
Before: database_node=db001.mydomain.local
After: database_node=mynewdbname002.mydomain.local
./myscript modify_db db003
Before: database_node=mynewdbname002.mydomain.local
After: database_node=db003.mydomain.local
You can use this sed command inside your script:
sed "s/^\(database_node=\)[^.]*/\1$1/" file
Example:
s='database_node=db001.mydomain.local'
repl() {
sed "s/^\(database_node=\)[^.]*/\1$1/" <<< "$s";
}
and call it as:
repl mynewdbname002
database_node=mynewdbname002.mydomain.local
repl db003
database_node=db003.mydomain.local
You could have a script like, just like below taking an input argument having the replacement value,
#!/bin/bash
perl -lpe "s/database_node=(\w+)/database_node=$1/g" file
and just do
./script.sh newdbname
Use the -i flag for in-place replacement and -i.bak for in-place replacement with a backup of your original file
perl -lpe -i.bak "s/database_node=(\w+)/database_node=$1/g" file
(or) with a simple bash function
function replaceFile() {
perl -lpe -i.bak "s/database_node=(\w+)/database_node=$1/g" file
}
I would avoid trying to produce the new state from the previous state and rather just use a template :
function modify_db() {
echo "database_node=$1.mydomain.local"
}
I use echo here for illustration but you should obviously do whatever you want to do with the "database_node=$1.mydomain.local".
Supposing it should modify the only line starting with database_node from a file db_conf after having printed the old value :
function modify_db() {
echo "Before: $(grep '^database_node=' db_conf)"
sed -i "s/^database_node=.*\.mydomain\.local/database_node=$1.mydomain.local/" db_conf
echo "After: $(grep '^database_node=' db_conf)"
}

How to add single quotes to each string in a variable?

I am passing variable $$PSTCMT to a script as an argument:
test.sh $$PSTCMT
in the script the value is show as below:
PSTCMT1=$1
echo PSTCMT1
the output is:
abc,def,fgh
I want to replace above as below
PSTCMT ='abc','def','fgh'
echo $PSTCMT will give below output as
'abc','def','fgh'
If you are in BASH then you can do:
pstcmt1='abc,def,fgh'
pstcmt="'${pstcmt1//,/\',\'}'"
echo "$pstcmt"
'abc','def','fgh'
Without BASH you can use sed:
pstcmt="'$(sed "s/,/','/g" <<< "$pstcmt1")'"

replace first line of files by another made by changing path from unix to windows

I am trying to do a bash script that:
loop over some files : OK
check if the first line matches this pattern (#!f:\test\python.exe) : OK
create a new path by changing the unix style to windows style : KO
Precisely,
From: \c\tata\development\tools\virtualenvs\test2\Scripts\python.exe
I want to get: c:\tata\development\tools\virtualenvs\test2\Scripts\python.exe
insert the new line by appending #! and the new path : KO
Follow is my script but I'm really stuck!
for f in $WORKON_HOME/$env_name/$VIRTUALENVWRAPPER_ENV_BIN_DIR/*.py
do
echo "----"
echo file=$f >&2
FIRSTLINE=`head -n 1 $f`
echo firstline=$FIRSTLINE >&2
unix_path=$WORKON_HOME/$env_name/$VIRTUALENVWRAPPER_ENV_BIN_DIR/python.exe
new_path=`echo $unix_path | awk '{gsub("/","\\\")}1'`
echo new_path=$new_path >&2
# I need to change the new_path by removing the first \ and adding : after the first letter => \c -> c:
new_line="#!"$new_path
echo new_line=$new_line >&2
case "$FIRSTLINE" in
\#!*python.exe* )
# Rewrite first line
sed -i '1s,.*,'"$new_line"',' $f
esac
done
Output:
file=/c/tata/development/tools/virtualenvs/test2/Scripts/pip-script.py
firstline=#!f:\test\python.exe
new_path=\c\tata\development\tools\virtualenvs\test2\Scripts\python.exe
new_line=#!\c\tata\development\tools\virtualenvs\test2\Scripts\python.exe
Line that is written in the file: (some weird characters are written I do not know why...)
#!tatadevelopment oolsirtualenvs est2Scriptspython.exe
Line I am expecting:
#!c:\tata\development\tools\virtualenvs\test2\Scripts\python.exe
sed is interpreting the backslashes and characters following them as escapes, so you're getting, e.g. tab. You need to escape the backslashes.
sed -i "1s,.*,${new_line//\\/\\\\}," "$f"

Resources