I have a number column, I need to replace the first number by 7 in oracle.
How to replace guys?
number want_number
4789654 7789654
2754678 7754678
1765689 7765689
For instance
REGEXP_REPLACE(number, '^\d', '7')
should work.
Or, a substring option with concatenation:
SQL> with test (num) as
2 (select 4789654 from dual union all
3 select 2754678 from dual union all
4 select 1765689 from dual
5 )
6 select num, '7' || substr(num, 2) wanted_num
7 from test;
NUM WANTED_NUM
---------- --------------------
4789654 7789654
2754678 7754678
1765689 7765689
SQL>
You could manipulate as numbers, rather than converting to (and presumably later back from) strings:
with your_table (original) as (
select 4789654 from dual
union all select 2754678 from dual
union all select 1765689 from dual
union all select 999 from dual
union all select 1000 from dual
union all select 1001 from dual
)
select original,
original
- trunc(original, -floor(log(10, original)))
+ 7 * power(10, floor(log(10, original))) as wanted
from your_table;
ORIGINAL WANTED
---------- ----------
4789654 7789654
2754678 7754678
1765689 7765689
999 799
1000 7000
1001 7001
The floor(log(10, original) gives you the magnitude of the number. As an example, for your first original value 4789654 that evaluates to 6. If you then do trunc(original, -floor(log(10, original))) that is trunc(4789654, -6), which zeros the six least significant digits, giving you 4000000. Subtracting that from the original value gives you 789654. Then power(10, floor(log(10, original))) gives you power(10, 6) which is 1000000, multiplying that by 7 gives you 7000000, and adding that back on gives you 7789654.
(This won't work if your original value is <= zero, but that looks unlikely?)
Related
Using PL SQL, I need to format number to VARCHAR2. I need to show decimal places if they are not zero. And decimal separator should be comma.
INPUT
OUTPUT
0.2
'0,2'
100.4
'100,4'
22
'22'
Would something like this do?
SQL> with test (input) as
2 (select 0.2 from dual union all
3 select 100.4 from dual union all
4 select 22 from dual
5 )
6 select input,
7 case when input = trunc(input) then to_char(input, '999G990')
8 else to_char(input, '999G990D0')
9 end output
10 from test;
INPUT OUTPUT
---------- ----------
,2 0,2
100,4 100,4
22 22
SQL>
this is locale independent, does not limit or round numbers
with
test(input) as (
select 0.2 from dual union all
select 100.4 from dual union all
select -12.34567 from dual union all
select 1.23e34 from dual union all
select -1.23e-34 from dual union all
select 22 from dual
)
select input
,case when input < 0 then '-' end -- sign
||case when abs(input) < 1 then '0' end -- zero
||replace(to_char(abs(input)),to_char(0,'fmd'),',') -- comma
output
from test
/
I want to select the data from a Oracle table, whereas the table columns contains the data as , [ex : key,value] separated values; so here I want to select the second split i.e, value
table column data as below :
column_data
++++++++++++++
asper,worse
tincher,good
golder
null -- null values need to eliminate while selection
www,ewe
from the above data, desired output like below:
column_data
+++++++++++++
worse
good
golder
ewe
Please help me with the query
According to data you provided, here are two options:
result1: regular expressions one (get the 2nd word if it exists; otherwise, get the 1st one)
result2: SUBSTR + INSTR combination
SQL> with test (col) as
2 (select 'asper,worse' from dual union all
3 select 'tincher,good' from dual union all
4 select 'golder' from dual union all
5 select null from dual union all
6 select 'www,ewe' from dual
7 )
8 select col,
9 nvl(regexp_substr(col, '\w+', 1, 2), regexp_substr(col, '\w+', 1,1 )) result1,
10 --
11 nvl(substr(col, instr(col, ',') + 1), col) result2
12 from test
13 where col is not null;
COL RESULT1 RESULT2
------------ -------------------- --------------------
asper,worse worse worse
tincher,good good good
golder golder golder
www,ewe ewe ewe
SQL>
With Oracle 11g I want to parse a number to strip decimals if their value is 0 and keep two decimal figure after the decimal separator ',' if the value of decimals is different from 0
Example:
1,00 -> 1
1,001 -> 1
0,203 -> 0,20
And so on.
I've obtained something like that in a very unelegant way
select replace(trim(to_char (trunc ('0,2345',2),'9999999990.99')), '.', ',')
from dual
Do you know more elegant way? The output should be a char (not number).
Not sure it's much more elegant, but assuming your replace is to deal with different locales, this might work for you:
with t as (
select 1.00 as n from dual
union all select 1.001 from dual
union all select 0.203 from dual
union all select 0.2345 from dual
union all select 112.999 from dual
)
select n, regexp_replace(to_char(trunc(n, 2), '9999999990D00',
'NLS_NUMERIC_CHARACTERS='',.'''), '[,.]00$', null) as new_n
from t;
N NEW_N
---------- --------------
1 1
1.001 1
0.203 0,20
0.2345 0,23
112.999 112,99
The nls_param argument to to_char let's you dictate whether it used a comma or a period as the decimal separator. If you can set that at session level then the query looks a bit simpler. The regexp_replace strips ,00 (or .00, which come to think of it is overkill) from the end of th string.
As ThinkJet noted the regexp_replace is a bit excessive, and since the decimal seperator is defined in the column clase (and the format has no group separators anyway) it can be done with a plan replace:
with t as (
select 1.00 as n from dual
union all select 1.001 from dual
union all select 0.203 from dual
union all select 0.2345 from dual
union all select 112.999 from dual
union all select 13.08 from dual
)
select n, replace(trim(
to_char(trunc(n, 2), '9999999990D00', 'NLS_NUMERIC_CHARACTERS='',.''')),
',00', null) as new_n
from t;
N NEW_N
---------- --------------
1 1
1.001 1
0.203 0,20
0.2345 0,23
112.999 112,99
13.08 13,08
Still not sure this can be described as 'elegant' though.
To achieve correct results you must deal with numbers, not strings:
with t as (
select 1.00 as n from dual
union all select 1.001 from dual
union all select 0.203 from dual
union all select 0.2345 from dual
union all select 112.999 from dual
union all select 112.105 from dual
union all select 0 from dual
union all select -12.307 from dual
)
select
n,
decode( trunc(n,2) - trunc(n) ,
0, to_char(trunc(n), 'TM9', 'NLS_NUMERIC_CHARACTERS = '', '''),
to_char(trunc(n,2),'9999999990D00', 'NLS_NUMERIC_CHARACTERS = '', ''')
)
string_val
from t
SQLFiddle
P.S. Updated to get incorrect truncation instead of round, as in OP request.
Another variant
SELECT n,
to_char( trunc( n, 2 ),
case when mod( trunc( n, 2 ), 1 ) = 0
then '9990'
else '9990D00'
end, 'NLS_NUMERIC_CHARACTERS='',.''' ) val
from t
;
SQLFiddle demo
Data in the file_name field of the generation table should be an assigned number, then _01, _02, or _03, etc. and then .pdf (example 82617_01.pdf).
Somewhere, the program is putting a state name and sometimes a date/time stamp, between the assigned number and the 01, 02, etc. (82617_ALABAMA_01.pdf or 19998_MAINE_07-31-2010_11-05-59_AM.pdf or 5485325_OREGON_01.pdf for example).
We would like to develop a SQL statement to find the bad file names and fix them. In theory it seems rather simple to find file names that include a varchar2 data type and remove it, but putting the statement together is beyond me.
Any help or suggestions appreciated.
Something like:
UPDATE GENERATION
SET FILE_NAME (?)
WHERE FILE_NAME (?...LIKE '%STRING%');?
You can find the problem rows like this:
select *
from Files
where length(FILE_NAME) - length(replace(FILE_NAME, '_', '')) > 1
You can fix them like this:
update Files
set FILE_NAME = SUBSTR(FILE_NAME, 1, instr(FILE_NAME, '_') -1) ||
SUBSTR(FILE_NAME, instr(FILE_NAME, '_', 1, 2))
where length(FILE_NAME) - length(replace(FILE_NAME, '_', '')) > 1
SQL Fiddle Example
You can also use Regexp_replace function:
SQL> with t1(col) as(
2 select '82617_mm_01.pdf' from dual union all
3 select '456546_khkjh_89kjh_67_01.pdf' from dual union all
4 select '19998_MAINE_07-31-2010_11-05-59_AM.pdf' from dual union all
5 select '5485325_OREGON_01.pdf' from dual
6 )
7 select col
8 , regexp_replace(col, '^([0-9]+)_(.*)_(\d{2}\.pdf)$', '\1_\3') res
9 from t1;
COL RES
-------------------------------------- -----------------------------------------
82617_mm_01.pdf 82617_01.pdf
456546_khkjh_89kjh_67_01.pdf 456546_01.pdf
19998_MAINE_07-31-2010_11-05-59_AM.pdf 19998_MAINE_07-31-2010_11-05-59_AM.pdf
5485325_OREGON_01.pdf 5485325_01.pdf
To display good or bad data regexp_like function will come in handy:
SQL> with t1(col) as(
2 select '826170_01.pdf' from dual union all
3 select '456546_01.pdf' from dual union all
4 select '19998_MAINE_07-31-2010_11-05-59_AM.pdf' from dual union all
5 select '5485325_OREGON_01.pdf' from dual
6 )
7 select col bad_data
8 from t1
9 where not regexp_like(col, '^[0-9]+_\d{2}\.pdf$');
BAD_DATA
--------------------------------------
19998_MAINE_07-31-2010_11-05-59_AM.pdf
5485325_OREGON_01.pdf
SQL> with t1(col) as(
2 select '826170_01.pdf' from dual union all
3 select '456546_01.pdf' from dual union all
4 select '19998_MAINE_07-31-2010_11-05-59_AM.pdf' from dual union all
5 select '5485325_OREGON_01.pdf' from dual
6 )
7 select col good_data
8 from t1
9 where regexp_like(col, '^[0-9]+_\d{2}\.pdf$');
GOOD_DATA
--------------------------------------
826170_01.pdf
456546_01.pdf
To that end your update statement might look like this:
update your_table
set col = regexp_replace(col, '^([0-9]+)_(.*)_(\d{2}\.pdf)$', '\1_\3');
--where clause if needed
I am using this code to round down the decimal value to the next multiple of 25.
ie if value is 33.60 it should round to 33.50
create or replace
PROCEDURE "TEST1" (PQUERY IN VARCHAR2) as
prNspValue number(14,2) :='';
p_percentage_Value number(4,2) :='';
begin
prNspValue:=33.60;
dbms_output.put_line(prNspValue);
p_percentage_Value:=substr(prNspValue,instr(prNspValue,'.')+1,length(prNspValue));
dbms_output.put_line(p_percentage_value);
p_percentage_Value:=p_percentage_Value-mod(p_percentage_Value,25);
dbms_output.put_line(p_percentage_value);
if(p_percentage_Value!=0)then
prNspValue:=substr(prNspValue,1,instr(prNspValue,'.'))+p_percentage_Value/100;
else
prNspValue:=substr(prNspValue,1,instr(prNspValue,'.'));
end if;
dbms_output.put_line(prNspValue);
end;
but the problem is when the value is 33.60 it is taken as 33.6. so it is rounding it to 33.0.
How can i correct this code?
you can use the round function directly FLOOR(your_number*4)/4:
SQL> WITH my_data AS (
2 SELECT 33.00 num FROM dual
3 UNION ALL SELECT 33.10 FROM dual
4 UNION ALL SELECT 33.20 FROM dual
5 UNION ALL SELECT 33.30 FROM dual
6 UNION ALL SELECT 33.40 FROM dual
7 UNION ALL SELECT 33.50 FROM dual
8 UNION ALL SELECT 33.60 FROM dual
9 UNION ALL SELECT 33.70 FROM dual
10 UNION ALL SELECT 33.80 FROM dual
11 UNION ALL SELECT 33.90 FROM dual
12 ) SELECT num,
13 floor (num * 4) / 4 rounded
14 FROM my_data;
NUM ROUNDED
---------- ----------
33 33
33,1 33
33,2 33
33,3 33,25
33,4 33,25
33,5 33,5
33,6 33,5
33,7 33,5
33,8 33,75
33,9 33,75
10 rows selected