I have two tables viz
1. users
columns: id, name
2. user_access
columns: id, user_id, user_access_id
user access is a pivot table that defines the relationship between users table and users table itself. For example, a user might have access to data of some other users.
I have defined this relationship in User model.
Now I want to fetch those user ids for a user which don't exist in user_access table.
For example, a user may have access to id 1 & 2 but he doesn't have access to id 3 & 4, so I want to fetch id 3 & 4 and not 1 & 2.
To achieve this I use whereDoesntHave eloquent but it's not working for relationship on the same tables and I get the following error
Facade\Ignition\Exceptions\ViewException
Call to undefined method Illuminate\Database\Eloquent\Builder::getRelated() (View: C:\xampp\htdocs\prd_tracker\resources\views\tracker\ticket\script.blade.php)
but it does work for different tables.
Here is my code
User Model
public function userAccess()
{
return $this->belongsToMany('App\User', 'user_access', 'user_id', 'user_access_id')->using('App\USER_ACCESS');
}
Logic
use App\User;
$user_id = Auth::user()->id;
//Get All Those Users Ids Which Does Not Belong To Auth User
$exception_user_ids = User::whereDoesntHave('users', function ($query) use($user_id) {
$query->where('user_id', $user_id);
})
->pluck('id');
The error may be in the User model.
The App\User model cannot belongsToMany() of itself...App\User.
I believe you may need a UserAccess model.
Try:
User Model
public function userAccess()
{
return $this->belongsToMany('App\UserAccess', 'user_access', 'user_id', 'user_access_id')
}
or try a hasMany relationship:
User Model
public function userAccess()
{
return $this->hasMany('App\UserAccess', 'user_id', 'id');
}
https://laravel.com/docs/7.x/eloquent-relationships#many-to-many
https://laravel.com/docs/7.x/eloquent-relationships#one-to-many
Related
I need to create a relationship between user and many stores. I have created a three models
Store Model
id name email phone info
1 xyz xyz#gmail.com 9329292922 Small Store
2 abc abc#gmail.com 9494949449 Some Store
User Model
id name email
1 ewd ewd#gmail.com
2 xcv xcv#gmail.com
User_Store
user_id store_id
1 1
1 2
What does the user_store model contain relations whether it is belongstoMany or hasmany?
You can use belongsToMany relationship
In your Store model define a method
public function users() {
return $this->belongsToMany(Users::class, 'user_store', 'user_id', 'store_id');
}
In your Users model define a method
public function stores() {
return $this->belongsToMany(Stores::class, 'user_store', 'user_id', 'store_id');
}
Looks to me like you want a simple many-to-many relationship.
For this you only need two models User and Store, you only need StoreUser if you want to do something special with the pivot table otherwise it is unnecessary.
The following would be the Laravel way:
Table structure
stores
id
name
email
phone
info
users
id
name
email
store_user
user_id
store_id
Laravel excepts the pivot table to be called store_user, you can read more about it here:
To define this relationship, three database tables are needed: users,
roles, and role_user. The role_user table is derived from the
alphabetical order of the related model names, and contains the
user_id and role_id columns.
Model structure
class User extends Model
{
public function stores()
{
return $this->belongsToMany(Store::class);
}
}
class Store extends Model
{
public function users()
{
return $this->belongsToMany(User::class);
}
}
I have 2 tables: roles & users.
In users I have role_id, and I want to check if that role has a column "access_admin_area" on true. If true, I am using a middleware.
Gate::define('admin', function ($user) {
return !empty($user->roles()->where('access_admin_area', true)->first());
});
From User model:
public function roles()
{
return $this->hasOne(Role::class);
}
SQLSTATE[42703]: Undefined column: 7 ERROR: column roles.user_id does not exist↵LINE 1: select * from "roles" where "roles"."user_id" = $1 and "role..
The error describes the issue pretty nicely here - the hasOne relationship method inside your User model expects the Role table row to have a user_id column that specifies a foreign key referencing the user table id column.
If I was you, I'd rather use hasMany relationhip between your User and Role model in this use case, since I expect your users and roles should have a many-to-many relationship
check out the many-to-many relationship eloquent and database structure in the laravel documentation https://laravel.com/docs/7.x/eloquent-relationships#many-to-many
Did you checked like this way:
public function roles()
{
return $this->hasOne('App\Role', 'id' , 'role_id');
}
You should change hasOne to belongsTo
then you can a simpler way to save yourselve from many where clauses in your controlleer is by creating another relationship with eg name as rolewithadminaccess
public function roles()
{
return $this->belongsTo(Role::class);
}
public function rolewithadminaccess()
{
return $this->roles()->where('access_admin_area', true)->limit(1);
}
then you can do this in your controller
return $user->rolewithadminaccess;
I have a relationship between two models, User and Follower.
User hasMany Follower, and Follower belongsTo User.
In my followers table in the database I have two columns, follower_id and following_id. Both these columns refer to the id column in the users table.
My follower and users table
followers
id
follower_id
following_id
users
id
name
username
User Model
public function followers(){
return $this->hasMany('App\Follower', 'follower_id');
}
public function followings(){
return $this->hasMany('App\Follower', 'following_id');
}
Follower Model
public function user(){
return $this->belongsTo('App\User');
}
In a test controller I am doing this:
$followed = Follower::find(2);
From here, I would like to select one of the columns, follower_id or following_id, and access the user that this particular row belongs to by using $followed->user->name. How would I go about that? Since I need to select a column before accessing, I am a little bit confused.
What can I do to access the data I need?
Your table should be :
followers
id
follower_id
following_id
user_id
users
id
name
username
In your Follower model :
public function user()
{
return $this->hasMany(Follower::class, 'user_id');
}
In your User model :
public function follower()
{
return $this->belongsTo(User::class, 'user_id');
}
Then you can query like this :
$follower = Follower::with('user')->findorFail(2);
$user_name = $follower->user->name;
I want to build query like this in laravel 5.3
SELECT p.post_text, p.bbcode_uid, u.username, t.forum_id, t.topic_title, t.topic_time, t.topic_id, t.topic_poster
FROM phpbb_topics t, phpbb_posts p, phpbb_users u
WHERE t.forum_id = 9
AND p.post_id = t.topic_first_post_id
AND u.user_id = t.topic_poster
ORDER BY t.topic_time
DESC LIMIT 10
Consider for example there are two tables one is users and the other is posts
while creating migration add user_id foreign key to your posts table as
$table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
create User and Post model, and in your User model define relationship to Post as
public function post(){
return $this->hasMany(Post::class);
}
and in your Post model define a relationship to User model as
public function user(){
return $this->belongsTo(User::class);
}
now you can get the user from Post model
$post = Post::findOrFail(1);
return $post->user;
I have an issue i can't resolve myself with the documentation.
I want to create a very simple conversation system between two users.
I have 3 models and tables:
User
id , name
Conversation
id
Message
id , user_id , conversation_id , content
So a message belongsTo an user and a conversation but then i want the conversation to belongstomany users.
And i dont know how to make this with the tables. If i create a user_id fields in the conversation table i can't have multiple users...
This is definitely in the documentation
Anyways. You're looking for a many to many relationship. For that you need a pivot table (or junction table) that contains the id of a user and the id of a conversation.
Following Laravel convention this table would be called conversation_user and would have the columns id (primary key), conversation_id and user_id
If you have that you can define the relations like this:
User
public function conversations(){
return $this->belongsToMany('Conversation');
}
Conversation
public function users(){
return $this->belongsToMany('User');
}
Querying the relation
$user = User::find(1);
$conversations = $user->conversations;
As documented here for inserting models into a many to many relation you should use attach()
$conversation = new Conversation;
$conversation->users()->attach($idUser1);
$conversation->users()->attach($idUser2);
// or just pass an array of ids
$conversation->users()->attach(array($idUser1, $idUser2));
I would first of all have the three folowig tables:
User
id , name
Conversation_user
user_id , message_id
Message
id , content
Than let's take care of the relationships.
In your User model:
public function conversations()
{
return $this->belongsToMany(Message::class,'conversation_user','user_id','message_id');
}
In your Message model:
public function users()
{
return $this->belongsToMany(User::class,'conversation_user','message_id','user_id');
}
Now you will be able to call the relationship like so:
$user = Auth::user();
$user->conversations();