I want to automate a task quarterly in a year.
Task should execute
Jan 1st
April 1st
July 1st
October 1st
etc
As I tried #Scheduled(cron = "0 0 6 1 1/3 ?") in Spring Boot application but its not working currently and mail didn't trigger quarterly.
Try this
#scheduled(cron = "0 0 6 1 */3 *")
So read the first day of each 3 month at 6:00
Try this one -
#scheduled(cron ="0 0 0 1 JAN,APR,JUL,OCT ? *")
Next execution:
Wed Jul 01 00:00:00 UTC 2020
Thu Oct 01 00:00:00 UTC 2020
Fri Jan 01 00:00:00 UTC 2021
Thu Apr 01 00:00:00 UTC 2021
Thu Jul 01 00:00:00 UTC 2021
Fri Oct 01 00:00:00 UTC 2021
Sat Jan 01 00:00:00 UTC 2022
Fri Apr 01 00:00:00 UTC 2022
Fri Jul 01 00:00:00 UTC 2022
Sat Oct 01 00:00:00 UTC 2022
Related
this is an example of my data
ip=1.2.3.4, setup_time=05:58:38.617 GMT Tue Mar 16 2021, foo=moshe, bar=haim
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Mar 16 2021, foo=moshe2, bar=haim2
i would like to be able to sort by the setup_time column in bash. I know that I can't use sort because sort allow only sort by string matching and this is not a format of YYYY-MM-DD HH:mm:ss so string sorting is not possible.
so any ideas would be greatly appreciated.
thank you
#update
ok to better understand what i'm trying to achieve i created the folowing file named 1:
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Mar 16 2021, foo=moshe, bar=haim
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Mar 17 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2021, foo=moshe2, bar=haim2
so I executed this:
cat 1 | sed 's/, /!/g' | sort -t '!' -k2,2
what i did here is replaced , with ! so i can use a delimiter in sort, the problem is that sort is doing string sorting and not timestamp kind of sorting so the output is:
ip=2.3.4.5!setup_time=05:59:30.260 GMT Tue Mar 17 2021!foo=moshe2!bar=haim2
ip=2.3.4.5!setup_time=06:50:30.260 GMT Tue Mar 18 2021!foo=moshe2!bar=haim2
ip=1.2.3.4!setup_time=06:58:38.617 GMT Tue Mar 16 2021!foo=moshe!bar=haim
Sort is able to deal with month names, thanks to the option M
No need to change , into !. Use the white space as delimiter and just issue:
LC_ALL=en sort -k7nr -k5Mr -k6nr -k2r sample
If you use this as content of the file sample:
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Apr 1 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Mar 17 2021, foo=moshe2, bar=haim2
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Mar 16 2021, foo=moshe, bar=haim
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Feb 28 2021, foo=moshe, bar=haim
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2020, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2021, foo=moshe2, bar=haim2
you will get this as output:
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Apr 1 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Mar 17 2021, foo=moshe2, bar=haim2
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Mar 16 2021, foo=moshe, bar=haim
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Feb 28 2021, foo=moshe, bar=haim
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2020, foo=moshe2, bar=haim2
Specifying -k7 means to sort on the seventh field. The r option reverses the order of sorting to descending. The M option sorts according the name of the month. The n option sorts numerically. To sort on the time, just consider the whole second field (beginning with the string setup_time=) as a fixed length string using -k2.
LC_ALL=en in the begin of the command line tells the system to use the English names of the months.
A solution involving awk:
awk '
{
year = substr($7, 1, length($7)-1)
cmd ="date --date=\""$3" "$4" "$5" "$6" "$year"\" +%s"
cmd | getline var
print var, $0
close(cmd)
}' file | sort -k 1 | cut -f 1- -d' '
The trick is that date --date="GMT Tue Mar 18 2021" will parse the date heuristically (meaning it will also work with gdate --date="GMT Tue 18 Mar 2021"), and then you can print only the seconds since epoch.
awk will output the seconds as first column, you sort by it, then you remove the first column from the result.
Biggest advantage of this solution is that it will work for other types of date formats (within reason of course).
Note1: for this to work you need GNU date (on Mac OS gdate, for example)
Note2: instead of awk you could use also bash with while/read (as in Read a file line by line assigning the value to a variable), but awk is rather standard, so not sure if it is a big difference for you.
If you have a sort with month name support -- use that. Pierre's solution is elegant!
If you don't, convert the date to ISO 8601 (which sorts lexicographically) and use a Schwartzian transform or a Decorate / Sort / Undecorate pattern.
The easiest, since the date you have is non standard, is use Perl to decorate, sort to sort on the first field, then cut to undecorate (remove the added field):
perl -lnE '
BEGIN{
%m2n = qw(Jan 01 Feb 02 Mar 03 Apr 04 May 05 Jun 06
Jul 07 Aug 08 Sep 09 Oct 10 Nov 11 Dec 12
);}
m/setup_time=([\d:]+).*?(\w\w\w) (\d\d?) (\d\d\d\d),/;
$mon=$m2n{$2};
say "$4$mon$3$1\t$_"' YourFile | sort -t $'\t' -r -k1,1 | cut -d $'\t' -f2-
Using pierre's data, prints:
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Apr 1 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2021, foo=moshe2, bar=haim2
ip=2.3.4.5, setup_time=05:59:30.260 GMT Tue Mar 17 2021, foo=moshe2, bar=haim2
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Mar 16 2021, foo=moshe, bar=haim
ip=1.2.3.4, setup_time=06:58:38.617 GMT Tue Feb 28 2021, foo=moshe, bar=haim
ip=2.3.4.5, setup_time=06:50:30.260 GMT Tue Mar 18 2020, foo=moshe2, bar=haim2
I wanted to construct a spring cron expression that executes At 23:00:00pm, on first Sunday, every 2 months starting in January, so far I have this
0 0 23 ? 1/2 SUN but this one executes At 23:00:00pm, every Sunday, every 2 months starting in January. how can I make it execute only the first Sunday every two months?
0 0 23 ? 1/2 SUN next excution dates are as follows
Sun Mar 07 23:00:00 UTC 2021
Sun Mar 14 23:00:00 UTC 2021
Sun Mar 21 23:00:00 UTC 2021
Sun Mar 28 23:00:00 UTC 2021
Sun May 02 23:00:00 UTC 2021
Sun May 09 23:00:00 UTC 2021
Sun May 16 23:00:00 UTC 2021
Sun May 23 23:00:00 UTC 2021
Sun May 30 23:00:00 UTC 2021
Sun Jul 04 23:00:00 UTC 2021
but what I wanted was
Sun Mar 07 23:00:00 UTC 2021
Sun May 02 23:00:00 UTC 2021
Sun Jul 04 23:00:00 UTC 2021
how can I improve my expression to get the above result?
0 0 23 1-7 1/2 SUN
The only part you are missing, is day number in the range 1-7.
Code to verify the schedule:
var sundays = CronExpression.parse("0 0 23 1-7 1/2 SUN");
var nextDate = LocalDateTime.now();
var dateFormatter = DateTimeFormatter.ofPattern("EEE, MMM d, yyyy 'at' hh:mm:ss a");
for (var i = 0; i < 10; i++) {
nextDate = sundays.next(nextDate);
System.out.println(nextDate.format(dateFormatter));
}
Will run at:
Sun, Mar 7, 2021 at 11:00:00 pm
Sun, May 2, 2021 at 11:00:00 pm
Sun, Jul 4, 2021 at 11:00:00 pm
Sun, Sep 5, 2021 at 11:00:00 pm
Sun, Nov 7, 2021 at 11:00:00 pm
...
I have a list of files with the substring YYYYMMDDHH in them (example: 2016112200 means 2016 November 22th at 00 hours). These files are: temp_2016102200.data, temp_2016102212.data, temp_2016102300.data, temp_2016102312.data, ..., temp_20170301.data. And I also have other family of files substituting temp by wind.
For each string YYYYMMDDHH I want to create a tar with the temp and its correspondent wind file. I don't want this process to stop if one or both files are missing.
My idea was to loop from 12 hours to 12 hours, but I am having some problems because to specify the date I did: b=$(date -d '2016111400' +'%Y%m%d%H') but bash informs me that that is not a valid date...
Thanks.
It's not bash telling you the date format is wrong: date is telling you. Not everything you type is a bash command.
As Kamil comments, you have to split it up so that date can parse it. The YYYY-mm-dd HH:MM:SS format is parsable. Using bash parameter expansion to extract the relevant substrings:
$ d=2016111400
$ date -d "${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00"
Mon Nov 14 00:00:00 EST 2016
Now, when you want to add 12 hours, you have to be careful to do it in the right place in the datetime string: if you add a + character after the time, it will be parsed as a timezone offset, so put the relative part either first or between the date and the time.
$ date -d "+12 hours ${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00"
Mon Nov 14 12:00:00 EST 2016
As a loop, you could do:
d=2016111400
for ((i=1; i<=10; i++)); do
# print this datetime
date -d "${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00"
# add 12 hours
d=$( date -d "+12 hours ${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00" "+%Y%m%d%H" )
done
outputs:
Mon Nov 14 00:00:00 EST 2016
Mon Nov 14 12:00:00 EST 2016
Tue Nov 15 00:00:00 EST 2016
Tue Nov 15 12:00:00 EST 2016
Wed Nov 16 00:00:00 EST 2016
Wed Nov 16 12:00:00 EST 2016
Thu Nov 17 00:00:00 EST 2016
Thu Nov 17 12:00:00 EST 2016
Fri Nov 18 00:00:00 EST 2016
Fri Nov 18 12:00:00 EST 2016
OK, a "nicer" way to loop
start=2019043000
end=2019050300
plus12hours() {
local d=$1
date -d "+12 hours ${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00" "+%Y%m%d%H"
}
for (( d = start; d <= end; d = $(plus12hours "$d") )); do
printf "%d\t%s\n" "$d" "$(date -d "${d:0:4}-${d:4:2}-${d:6:2} ${d:8:2}:00:00")"
done
2019043000 Tue Apr 30 00:00:00 EDT 2019
2019043012 Tue Apr 30 12:00:00 EDT 2019
2019050100 Wed May 1 00:00:00 EDT 2019
2019050112 Wed May 1 12:00:00 EDT 2019
2019050200 Thu May 2 00:00:00 EDT 2019
2019050212 Thu May 2 12:00:00 EDT 2019
2019050300 Fri May 3 00:00:00 EDT 2019
I need to parse all a file into a better format to produce an outcome with columns delimited by a comma, thinking of being able to export the content in CSV file.
This is an example of my input;
. D 0 Mon Dec 10 11:07:46 2018
.. D 0 Mon Feb 19 11:38:06 2018
RJ9-5 D 0 Fri Nov 30 10:34:24 2018
WorkingOnClass D 0 Wed Feb 28 09:37:52 2018
ML-Test001 D 0 Fri Dec 7 16:38:56 2018
TestML4Testing D 0 Wed Aug 22 08:58:42 2018
ML-NewDataSE SetCases1.xlsx A 1415577 Wed Aug 29 14:00:16 2018
DR0001-Dum01 D 0 Thu Aug 16 08:24:25 2018
DR0002-Dum02 D 0 Thu Aug 16 09:04:50 2018
Readme File for Documentation And Data Description.docx A 16136 Wed Aug 29 14:00:24 2018
ML Database Prototype D 0 Thu Dec 6 15:11:11 2018
OneNote D 0 Mon Dec 3 09:39:20 2018
Data A 0 Mon Dec 10 11:07:46 2018
\RJ9-5
. D 0 Fri Nov 30 10:34:24 2018
.. D 0 Mon Dec 10 11:07:46 2018
KLR0151_Set023_Files_RJ9_05.xlsx A 182462 Wed Apr 4 02:48:55 2018
KLR0152_Set023_Files_RJ9_05.xlsx A 525309 Wed Apr 4 02:53:57 2018
\ML-Test001
. D 0 Wed Feb 28 09:37:52 2018
.. D 0 Mon Dec 10 11:07:46 2018
WT_Conforming_Format1_1.docx A 500914 Mon Feb 26 08:50:55 2018
Conforming_Format_1_1.xlsx A 130647 Mon Feb 26 08:52:33 2018
DR0135_Dum01_text.xls A 974848 Mon Feb 12 08:11:11 2018
DR0139_Dum02_body.xls A 1061888 Tue Jun 19 13:43:54 2018
DataSet_File_mod0874953.xlsx A 149835 Mon Feb 26 14:17:02 2018
File Path For Dataset-2018.07.11.xlsx A 34661 Mon Feb 12 09:27:17
This is script right here can make the job:
#!/bin/bash
awk -v OFS=, '
BEGIN { print "PATH, FILENAME, SIZE, TIMESTAMP" }
/[\\]/ { path=$0 }
$2 ~ /A/ {print path"\\"$1,$3,$4 " " $5 " " $6 " " $7 " "$8 }
' "$#"
But is ignoring the names with spaces on it, so I need to validate them with something like:
awk -v FS="\t" '{print $1}'
But I could't integrate into the shell script, because the way the shell script is working, so I was thinking on make AWK to start reading by the end, since the end is always the same, and leave the rest.
The output should something like this:
/RJ9-5/KLR0151_Set023_Files_RJ9_05.xlsx,182462,Wed Apr 4 02:48:55 2018
/RJ9-5/KLR0152_Set023_Files_RJ9_05.xlsx,25309,Wed Apr 4 02:53:57 2018
/ML-Test001/WT_Conforming_Format1_1.docx,500914,Mon Feb 26 08:50:55 2018
/ML-Test001/Format_1_1.xlsx,130647,Mon Feb 26 08:52:33 2018
/ML-Test001/DR0135_Dum01_text.xls,974848,Mon Feb 12 08:11:11 2018
/ML-Test001/DR0139_Dum02_body.xls,1061888,Tue Jun 19 13:43:54 2018
/ML-Test001/DataSet_File_mod0874953.xlsx,149835,Mon Feb 26 14:17:02 2018
/ML-Test001/File Path For Dataset-2018.07.11.xlsx,34661,Mon Feb 12 09:27:17 2018
With GNU awk for the 3rd arg to match() (and far less importantly \s shorthand for [[:space:]]):
$ cat tst.awk
BEGIN { OFS="," }
{ gsub(/^\s+|\s+$/,"") }
sub(/^\\/,"/") { path = $0; next }
path == "" { next }
match($0,/^(.*[^ ]) +A +([^ ]+) +(.*)/,a) { print path "/" a[1], a[2], a[3] }
$ awk -f tst.awk file
/RJ9-5/KLR0151_Set023_Files_RJ9_05.xlsx,182462,Wed Apr 4 02:48:55 2018
/RJ9-5/KLR0152_Set023_Files_RJ9_05.xlsx,525309,Wed Apr 4 02:53:57 2018
/ML-Test001/WT_Conforming_Format1_1.docx,500914,Mon Feb 26 08:50:55 2018
/ML-Test001/Conforming_Format_1_1.xlsx,130647,Mon Feb 26 08:52:33 2018
/ML-Test001/DR0135_Dum01_text.xls,974848,Mon Feb 12 08:11:11 2018
/ML-Test001/DR0139_Dum02_body.xls,1061888,Tue Jun 19 13:43:54 2018
/ML-Test001/DataSet_File_mod0874953.xlsx,149835,Mon Feb 26 14:17:02 2018
/ML-Test001/File Path For Dataset-2018.07.11.xlsx,34661,Mon Feb 12 09:27:17
Try this Perl solution:
$ perl -lane ' if(/^\s*$/) { $x=0;$y=0} if(/^\\/) {$x=1 ;($a=$_)=~s/\s*$//g;$a=~s/\\/\//g; } $y++ if $x==1 ; if($y>3) { s/^\s*//g; $_=~s/(.+?)\s+\S+\s+((\d+)\s+.+)/$1 $2/g;print "$a/$_" } ' essparaq.txt
/RJ9-5/KLR0151_Set023_Files_RJ9_05.xlsx 182462 Wed Apr 4 02:48:55 2018
/RJ9-5/KLR0152_Set023_Files_RJ9_05.xlsx 525309 Wed Apr 4 02:53:57 2018
/ML-Test001/WT_Conforming_Format1_1.docx 500914 Mon Feb 26 08:50:55 2018
/ML-Test001/Conforming_Format_1_1.xlsx 130647 Mon Feb 26 08:52:33 2018
/ML-Test001/DR0135_Dum01_text.xls 974848 Mon Feb 12 08:11:11 2018
/ML-Test001/DR0139_Dum02_body.xls 1061888 Tue Jun 19 13:43:54 2018
/ML-Test001/DataSet_File_mod0874953.xlsx 149835 Mon Feb 26 14:17:02 2018
/ML-Test001/File Path For Dataset-2018.07.11.xlsx 34661 Mon Feb 12 09:27:17
$ cat essparaq.txt
. D 0 Mon Dec 10 11:07:46 2018
.. D 0 Mon Feb 19 11:38:06 2018
RJ9-5 D 0 Fri Nov 30 10:34:24 2018
WorkingOnClass D 0 Wed Feb 28 09:37:52 2018
ML-Test001 D 0 Fri Dec 7 16:38:56 2018
TestML4Testing D 0 Wed Aug 22 08:58:42 2018
ML-NewDataSE SetCases1.xlsx A 1415577 Wed Aug 29 14:00:16 2018
DR0001-Dum01 D 0 Thu Aug 16 08:24:25 2018
DR0002-Dum02 D 0 Thu Aug 16 09:04:50 2018
Readme File for Documentation And Data Description.docx A 16136 Wed Aug 29 14 :00:24 2018
ML Database Prototype D 0 Thu Dec 6 15:11:11 2018
OneNote D 0 Mon Dec 3 09:39:20 2018
Data A 0 Mon Dec 10 11:07:46 2018
\RJ9-5
. D 0 Fri Nov 30 10:34:24 2018
.. D 0 Mon Dec 10 11:07:46 2018
KLR0151_Set023_Files_RJ9_05.xlsx A 182462 Wed Apr 4 02:48:55 2018
KLR0152_Set023_Files_RJ9_05.xlsx A 525309 Wed Apr 4 02:53:57 2018
\ML-Test001
. D 0 Wed Feb 28 09:37:52 2018
.. D 0 Mon Dec 10 11:07:46 2018
WT_Conforming_Format1_1.docx A 500914 Mon Feb 26 08:50:55 2018
Conforming_Format_1_1.xlsx A 130647 Mon Feb 26 08:52:33 2018
DR0135_Dum01_text.xls A 974848 Mon Feb 12 08:11:11 2018
DR0139_Dum02_body.xls A 1061888 Tue Jun 19 13:43:54 2018
DataSet_File_mod0874953.xlsx A 149835 Mon Feb 26 14:17:02 2018
File Path For Dataset-2018.07.11.xlsx A 34661 Mon Feb 12 09:27:17
Is it possible to fetch 5th and/or 6th day of every month in Unix?
I've tried this but it does not give me the desired output:
echo $((($(date +%-d)-1)/5))
Use this:
for month in {1..12}; do date -d "$month/5/2017" +"%c - is a %A"; done
Output:
Thu 05 Jan 2017 12:00:00 AM CET - is a Thursday
Sun 05 Feb 2017 12:00:00 AM CET - is a Sunday
Sun 05 Mar 2017 12:00:00 AM CET - is a Sunday
Wed 05 Apr 2017 12:00:00 AM CEST - is a Wednesday
Fri 05 May 2017 12:00:00 AM CEST - is a Friday
Mon 05 Jun 2017 12:00:00 AM CEST - is a Monday
Wed 05 Jul 2017 12:00:00 AM CEST - is a Wednesday
Sat 05 Aug 2017 12:00:00 AM CEST - is a Saturday
Tue 05 Sep 2017 12:00:00 AM CEST - is a Tuesday
Thu 05 Oct 2017 12:00:00 AM CEST - is a Thursday
Sun 05 Nov 2017 12:00:00 AM CET - is a Sunday
Tue 05 Dec 2017 12:00:00 AM CET - is a Tuesday
For the 6th of the month, it's done in a similar way.
I am not sure if this is what you are looking for: i am assuming you want to get the 5th(or 6th) day of a month sitting on any day. If so, you can make use of the current date and get the 5th day of current month like below:
dd=`date '+%d'`
if(( $dd > 5 )); then
(( diff = dd - 5 ))
myDate=`date -d "-$diff days"`
else
(( diff = 5 - dd ))
myDate=`date -d "+$diff days"`
fi
echo $myDate
For 6th day you can do similarly. Above code should work on Linux distro.