Leetcode Oracle - ORA-00923: FROM keyword not found where expected - oracle

Question

I am trying to solve this problem using Oracle SQL but I keep getting this error -
ORA-00923: FROM keyword not found where expected
link to problem - https://leetcode.com/problems/department-top-three-salaries/submissions/
my solution until now - just to query the data -
with temp as
(
select d.Name as Department,
e.Name as Employee,
e.Salary as Salary
from employee e
join department d
on e.DepartmentId = d.Id
)
select *
, rank() over (partition by department order by salary desc) as rr
from temp
but if i simply run this then it works fine -
with temp as
(
select d.Name as Department,
e.Name as Employee,
e.Salary as Salary
from employee e
join department d
on e.DepartmentId = d.Id
)
select *
from temp
And if I run this then it runs okay -
select department, employee, salary
from
(
select A.* , dense_rank() over (partition by department order by salary desc) as rr
from
(
select d.Name as Department,
e.Name as Employee,
e.Salary as Salary
from employee e
join department d
on e.DepartmentId = d.Id
) A
) B
where rr <= 3
does it mean i cannot use the cascading with statements in oracle ?
For instance, cant I write -
with temp as
(
select col1, col2 from table
)
, temp1 as
(
select *, "hello" as col3
from temp
)
select *
from temp1
in Oracle?

Answer 1

If you need to select only all the columns then * without the alias is fine. But if You need to give alias of the table wherever you want to select all the columns of the table using * and also another expression in SELECT clause.
with TEMP AS
( SELECT
COL1,
COL2
FROM table )
, TEMP1 AS
(SELECT
T.*, -- alias here
"hello" AS COL3
FROM TEMP T
)
select * FROM TEMP1;
with temp as
(
select d.Name as Department,
e.Name as Employee,
e.Salary as Salary
from employee e
join department d
on e.DepartmentId = d.Id
)
select T.* -- alias here
, rank() over (partition by department order by salary desc) as rr
from temp T;