how to set custom login page instead of spring security default login page - spring-boot

Question

I integrate Angular with Spring Boot, I want to set my own login
page, but when I run my application it shows spring security default
login page. I change set every thing in my configuration file but it
still shows spring security default login page.
How do I set the custom login page?
SecurityConfig
#Configuration
#EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
#Override
protected void configure(final AuthenticationManagerBuilder auth) throws Exception {
auth.inMemoryAuthentication().withUser("nilmani").password("{noop}akj#159")
.roles("USER");
}
#Override
protected void configure(final HttpSecurity http) throws Exception {
http
.csrf().disable()
.authorizeRequests()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login.component.html")
.loginProcessingUrl("/perform_login")
.defaultSuccessUrl("/dashboard.component.html", true);
//.failureUrl("/login.html?error=true")
}
#Bean
public PasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
}
login.component.html
<div class="app-body">
<main class="main d-flex align-items-center">
<div class="container">
<div class="row">
<div class="col-md-8 mx-auto">
<div class="card-group">
<div class="card p-4">
<div class="card-body">
<form>
<h1>Login</h1>
<p class="text-muted">Sign In to your account</p>
<div class="input-group mb-3">
<div class="input-group-prepend">
<span class="input-group-text"><i class="icon-user"></i></span>
</div>
<input type="text" class="form-control" placeholder="Username" [(ngModel)]="username" [ngModelOptions]="{standalone: true}" autocomplete="username" required>
</div>
<div class="input-group mb-4">
<div class="input-group-prepend">
<span class="input-group-text"><i class="icon-lock"></i></span>
</div>
<input type="password" class="form-control" placeholder="Password"[(ngModel)]="password" [ngModelOptions]="{standalone: true}" autocomplete="current-password" required>
</div>
<div class="row">
<div class="col-6">
<button type="button" (click)="dologin()" class="btn btn-primary px-4">Login</button>
</div>
<div class="col-6 text-right">
<button type="button" class="btn btn-link px-0">Forgot password?</button>
</div>
</div>
</form>
</div>
</div>
<div class="card text-white bg-primary py-5 d-md-down-none" style="width:44%">
<div class="card-body text-center">
<div>
<h2>Sign up</h2>
<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>
<button type="button" class="btn btn-primary active mt-3">Register Now!</button>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</main>
</div>

Answer 1

Your SecurityConfig is fine. I did it the same way. You have to make sure that you have a controller which accepts this url and delivers the correct page. And normally you did not define a html page! A correct url might simply be /login.
So your SecurityConfig looks like:
.formLogin()
.loginPage("/login")
And your controller for example:
#Controller
#RequestMapping(value="/login")
#Scope(value="session")
public class LoginController extends AbstractWebController {
#GetMapping
public ModelAndView loginView() {
ModelAndView mav = this.getModelAndView("login");
return mav;
}
// further code goes here
}
This controller e.g. returns a jsp page which you can style according to your needs with Angular or whatever.