I'm using GraphQL to query a database that has two data types: User and Group.
Groups have a field users which is an array of User objects which are in that group. I have one field at root named groups which returns an array of all of my groups.
A typical query might look something like this:
{
groups {
id,
name,
users {
id,
name,
address,
email,
phone,
attitude,
job,
favoriteQuote,
favoriteColor,
birthday
}
}
}
The problem is that a lot of those users can belong to multiple groups and, seeing as User has a lot of fields, this can make responses quite large.
Is there any way to get one set of fields for the first instance of an object, and a different set for every other instance in the response?
I only need name, job, email etc etc once per user in the response, and just the id thereafter (I can do my own normalization afterwards).
alternatively
Is there any way to only get id fields for all users in groups and return a separate array of all unique User objects that have been referenced in the query (which is not all User objects)?
Is there any way to get one set of fields for the first instance of an object, and a different set for every other instance in the response?
No. The same set of fields will be returned for each item in a list unless the type of the individual item is different, since a separate selection set can be specified for each type returned at runtime.
Is there any way to only get id fields for all users in groups and return a separate array of all unique User objects that have been referenced in the query (which is not all User objects)?
You could design your schema to accommodate this. Something like
{
groups {
nodes {
id
name
users {
id
}
}
uniqueUsers {
id
# other fields
}
}
}
Your groups resolver would need to handle all the normalization and return the data in the appropriate shape. However, a simpler solution might be to just invert your relationship:
{
users {
id
name
address
email
phone
attitude
job
favoriteQuote
favoriteColor
birthday
groups {
id
name
}
}
}
Generally - usually
... normalization ... of course ... f.e. using apollo and it's normalized cache.
All records returned from API has to be the same shape.
You can get data and render some <MembersList/> component using query for ids and names only (full/paginated).
Later you can render details in some <UserProfile/> component with own query (hook useQuery inside) to fetch additional data from cache/api (controllable).
Your specific requirements - possible
1st option:
Usually response is of one common shape (as requested), but you can decide on resolver level what to return. This requires query structure changes that allows (API, backend) to null-ify some properties. F.e.
group {
id
name
users {
id
name
profile {
photo
email
address
With profile custom json type ... you can construct users resolver to return full data only for 1st record and null for all following users.
2nd option:
You can use 2 slightly different queries in one request. Use aliases (see docs), in short:
groupWithFullMember: group ( groupId:xxx, limitUsers:1 ) {
id
name
users {
id
name
address
email
...
}
}
groupMembers: group ( groupId:xxx ) {
id
name // not required
users {
id
name
}
}
Group resolver can return it's child users ... or users resolver can access limitUsers param to limit response/modify db query.
Related
I'm using Hasura for this.
Say for example I have a users, tags and users_tags table in a many-to-many relationship.
User's can define multiple tags (like a persons hobbies) and each tag can belong to multiple people.
Table users {
id int [pk increment]
}
Table tags {
id int [pk increment]
name text
}
Table users_tags {
id int [pk increment]
user [ref: - user.id]
tag [ref: - tags.id]
}
The users_tags table is a many-to-many table.
When a new user is created, I can create new tags and associate them with users just fine.
But when a user is deleted, what GraphQL mutation can I use to remove tags from both tags and users_tags if they don't point to other users.
This depends on your desired data model. If a tag is always associated with one user only, you can get rid of the users_tags table and add the user to the tags table.
Then, if you've set up a foreign key on the tag table that references the id field on the user table then this can be done automatically.
You will be given 4 options on deletion:
restrict: Does not allow you to delete a user that is referenced on a tag
cascade: Deletes the tag if the user is deleted
set null: Sets this row as null if the user is deleted
set default: Sets this row as the default value if the user is deleted
You'll want to select the cascade option here.
If you want to keep your current data model you will be able to do this cascading on the users_tags table if the tag or user is deleted but will need some process in place to delete tags that have no users associated to them.
The easiest way would probably be to add a custom SQL function but you could also have the following graphql query to find the tags that have 0 users_tags associated with them and then provide a list of primary keys to a delete tags mutation.
query CountOfUsersTagsForTag {
tags {
id
users_tags_aggregate {
aggregate {
count
}
}
}
}
Imagine the condition that I have a query called "users" that returns all the users and these users can be associated with one or more companies, so I have a type UserCompanies (I need it because it saves some more information beyond the relation). I'm using Prisma and I need to force a filter that returns only users that are of the same company as the requester.
I get the information of the company from JWT and need to inject this to the query before sending it to Prisma.
So, query should be like that:
query allUsers {
users {
name
id
status
email
userCompanies{
id
role
}
}
}
and on server side, I should transform it to: (user where is ok, just changing args)
query allUsers {
users(where: {
userCompanies_some: {
companyId: "companyId-from-jwt"
}
}) {
name
id
status
email
userCompanies(where: {
companyId: "companyId-from-jwt"
}){
id
role
}
}
}
I'm seeing a few resolutions to this, but I don't know if it is the best way:
1 - Using addFragmentToInfo, does the job to put conditions on the query, but if the query has a usercompanies already set, it gives me a conflict. Otherwise, it works fine.
2 - I can use an alias for the query, but after DB result I will need to edit all the results in array to overwrite the result.
3 - don't use info on Prisma and filter in js.
4 - Edit info(4th parameter) of type GraphqlResolveInfo
I am building a Graphql Schema and I was wandering what is the best practice of returning single vs collection items of a type. Let's say we want to retrieve users,
One option (if possible somehow) would be to have a query like this where the ID is optional, if ID is passed we return a single item, if not a collection of all users
query {
user (id: 1234) {
name
}
}
// return a single [User]
query {
user (id: null) {
name
}
}
// return a collection [User,User,User,...]
Another option would be to have user and users
query {
user (id: 1234) {
name
}
}
// return a single User
query {
users {
name
}
}
// return a collection [User,User,User,...]
I was wondering what is the best practice, or if you can pin-point me some resources related to that to read.
I am using the singular and plurals nouns to name the query field that return a single object and a list of object respectively. I think this naming style is very natural to most of the developers.
So to return a single user, it is :
type Query {
user(id:Int!) : User
}
It always return a single user. Just make the id input parameter as mandatory such that it cannot accept NULL.
And to return a list of user , normally it is:
type Query {
users : [User]
}
But in case it can have many users , most probably you need to consider something like pagination that allows developers to get the user page by page. For the offset -based pagination , I am doing something like below :
type Query {
users(offset:Int limit:Int) : UserPage
}
type UserPage {
data : [User]
pageInfo : PageInfo
}
type PageInfo {
# When paginating forwards, are there more items?
hasNextPage : Boolean!
# When paginating backwards, are there more items?
hasPreviousPage: Boolean!
# Total number of records in all page
total : Long
}
Depending on the requirements , you can consider to add an orderBy or a filter input parameter to the users query field to provide more options to the developers to get the result set that they are interested.
If you want to return the user list in the cursor-based pagination style, you can take a look on Relay Specification.
I had a question and can't find it in documentation.
For example I have a list
products with ids 1,2,3,4
And I have another list, categories with ids 1,2,3,4.
example query
{
products {
id
name
categories {
id
name
}
}
}
We can see that they both have same ids but different typename inside apollo.
Will it create any problem while caching the data? As Apollo normalizes our data with the id's,
Help would be appreciated.
Apollo normalizes using both the __typename and id (or _id) fields, so having a Product and a Category with the same id will normally not cause any problems.
The client normally appends the __typename for every selection set in your query -- so you do not have to actually add the __typename field yourself.
The config object passed to InMemoryCache includes a addTypename property, which defaults to true. If you set this to false, then the __typename field will not be added and you will see issues with the cache in this scenario unless you have universally unique IDs.
I´m building a SaaS B2B application composed of several different objects. Examples:
Users
Customers
StockItens
StockLevels
PriceList
Sales
Returns
Etc...
I´ll have around 40 different objects, that can be listed and created, edited, and deleted individually.
Facing the GraphQL concepts for the first time, should I build a large schema for all objects, like the example below, or should I keep each object on its own query.
query {
viewer {
Users {
id
firstName
lastName
address
city
...
}
Customers {
id
firstName
lastName
address
city
rating
...
}
StockItens {
id
item_id
sales {
id
dateTime
qty
unitValue
totalValue
...
}
...
}
StockLevels {
...
}
PriceList {
...
}
Sales {
id
dateTime
qty
unitValue
totalValue
...
}
Returns {
...
}
}
}
Looking for the first option (keeping everything into one single query) seens logical as I will be using fragments to access the desired piece of information, but then I will have a huge schema with lots of inter relations.
PLease advice what would be the best practice on that use case.
I suggest you do not write a query where you add all needed data but use the concept of fragments as you already pointed out.
And you fetch only the data which are needed for the current page. So the throughput is kept minimal.
e.g.
If you have a page where you update a user you just fetch the needed data for this user in a specialized query. The query consists of fragments.
The fragments are related to the subcomponents which are used in the page, for example a form where you show the data of the user.
The fragment of the form defines the data it needs from the user and the update page combines the fragments to the query.
// in user form component
const userFormFragments = {
name: "UserForm",
document: `fragment UserForm on User {
id
name
}`
};
// in update user page
const userQuery = `query getUserQuery($userId: ID!) {
getUser(userId: $userId) {
...${userFormFragment.name}
}
${userFormFragment.document}
}`