I am working on a project where I have to create one to many relationships which will get all the list of records referenced by id in another table and I have to display all the selected data in the multi-select field (selectArrayInput). Please help me out in this, if you help with an example that would be great.
Thanks in advance.
Example:
district
id name
1 A
2 B
3 C
block
id district_id name
1 1 ABC
2 1 XYZ
3 2 DEF
I am using https://github.com/Steams/ra-data-hasura-graphql hasura-graphql dataprovider for my application.
You're likely looking for "nested object queries" (see: https://hasura.io/docs/1.0/graphql/manual/queries/nested-object-queries.html#nested-object-queries)
An example...
query MyQuery {
district(where: {id: {_eq: 1}}) {
id
name
blocks {
id
name
}
}
}
result:
{
"data": {
"district": [
{
"id": 1,
"name": "A",
"blocks": [
{
"id": 1,
"name": "ABC"
},
{
"id": 2,
"name": "XYZ"
}
]
}
]
}
}
Or...
query MyQuery2 {
block(where: {district: {name: {_eq: "A"}}}) {
id
name
district {
id
name
}
}
}
result:
{
"data": {
"block": [
{
"id": 1,
"name": "ABC",
"district": {
"id": 1,
"name": "A"
}
},
{
"id": 2,
"name": "XYZ",
"district": {
"id": 1,
"name": "A"
}
}
]
}
}
Setting up the tables this way...
blocks:
districts:
Aside: I recommend using plural table names as they are more standard, "districts" and "blocks"
Related
This is in relation to this question. I'm having this error:
TypeError
Illuminate\Database\Grammar::parameterize(): Argument #1 ($values) must be of type array, int given, called in /var/www/html/vendor/laravel/framework/src/Illuminate/Database/Query/Grammars/Grammar.php on line 920
While inserting data using createMany. This is the form request data:
{
"name": "My Order",
"orders": [
{
"date": "2022-05-17",
"product_id": [1],
"price": 1
},
{
"start_date": "2022-05-18",
"product_id": [2],
"price": 2
}
]
}
This is the store method:
$order = auth()->user()->orders()->create($request->validated());
$order_subs = $order->subOrders()->createMany($request->orders);
$order_sub_items = $request->only('orders')['orders'];
foreach ($order_subs as $key => $value) {
$value->subOrderProducts()->createMany([$order_sub_items[$key]);
}
However, if the product_id is not an array, it will store properly. Sample form request data:
{
"name": "My Order",
"orders": [
{
"date": "2022-05-17",
"product_id": 1,
"price": 1
},
{
"start_date": "2022-05-18",
"product_id": 2,
"price": 2
}
]
}
How to fix this error?
Only articles that contain the EmailMarketing tag are needed.
I'm probably doing the wrong search on the tag, since it's an array of values, not a single object, but I don't know how to do it right, I'm just learning graphql. Any help would be appreciated
query:
query {
enArticles {
title
previewText
tags(where: {name: "EmailMarketing"}){
name
}
}
}
result:
{
"data": {
"enArticles": [
{
"title": "title1",
"previewText": "previewText1",
"tags": [
{
"name": "EmailMarketing"
},
{
"name": "Personalization"
},
{
"name": "Advertising_campaign"
}
]
},
{
"title": "title2",
"previewText": "previewText2",
"tags": [
{
"name": "Marketing_strategy"
},
{
"name": "Marketing"
},
{
"name": "Marketing_campaign"
}
]
},
{
"title": "article 12",
"previewText": "article12",
"tags": []
}
]
}
}
I believe you first need to have coded an equality operator within your GraphQL schema. There's a good explanation of that here.
Once you add an equality operator - say, for example _eq - you can use it something like this:
query {
enArticles {
title
previewText
tags(where: {name: {_eq: "EmailMarketing"}}){
name
}
}
}
Specifically, you would need to create a filter and resolver.
The example here may help.
In my Strapi project, i'm trying to write a Graphql query that filters posts by an array of tags.
The post has to belong to all tags of the given array.
E.g. the post below would not meet the condition if given array is [1,2,3] but would pass the condition if array is [3,5].
Any help would be much appreciated
Example Post:
{
"id": "1",
"title": "Lorem Iopsum",
"created_at": "2021-02-19T22:53:19.204Z",
"tags": [
{
"id": "3",
"tag": "Porte De Gentily"
},
{
"id": "5",
"tag": "Bridges"
},
{
"id": "6",
"tag": "Towers"
}
]
}
I was trying something like:
query {
posts( where: {tags: {id_contains: [3,1]}}) {
title
tags{id},
created_at
}
}
You can do it something like this
query($ids:[ID]) {
posts( where: {tags: {id:$ids}}) {
title
tags{id},
created_at
}
}
And pass your ids as a query variable:
{
"ids": [1,5]
}
The platform has a many to many relationship, where the table assigned_users holds all Users assigned to CalendarEvents.
I need to fetch, through CalendarEvents, the assigned users as an object, showing each user's information. So, I want to access the User through AssignedUsers, because I wanna fetch all the users related to that event.
public function assignedUsers()
{
return $this->hasManyThrough(Users::class, AssignedUsers::class, 'user_id', 'id');
}
It works, but it shows only the first user in the table. I want to show all of them. Currently there are 3.
"assigned_users": [
{ id: 1, ... }
]
If I do the following:
public function assignedUsers()
{
return $this->belongsToMany(Users::class, "assigned_users", "event_id", "event_id");
}
It will fetch 3 results, but all the information will be from the same user. It will repeat the same user 3 times. Changing both the event_id to user_id and id, and id and user_id will have the same result.
"assigned_users": [
{ id: 1, ... },
{ id: 1, ... },
{ id: 1, ... },
...
]
What I am trying to accomplish is the following result:
{
"status": "200",
"success": true,
"data": [
{
"event_id": 1,
"event_key": "EB1M7OGJRPW0",
"calendar_id": 4,
"start_at": "2018-01-01 00:00:00",
"end_at": "2018-01-31 00:00:00",
"location": "123 Lorem, Ipsum",
"event_name": "Event #1",
"description": "Lorem ipsum dolor sit amet",
"added_at": "2018-02-07 09:07:31",
"created_by": {
"id": 4,
"name": "Foo Bar",
"email": "foobar92#gmail.com",
"first_name": "Foo",
"last_name": "Bar",
"status": "active",
"is_activated": 0,
"created_at": "2018-02-07 09:06:49",
"updated_at": "2018-02-07 09:06:49"
},
"assigned_users": [
{
"id": 1,
...
},
{
"id": 2,
...
},
{
"id": 3,
...
},
...
]
}
]
}
This is not the case of hasManyThrough relationship. Here assigned_users is a pivot table so you just need a belongsToMany relationship defined
public function assignedUsers()
{
return $this->belongsToMany(Users::class, 'assigned_users', 'event_id', 'user_id');
}
and for this to work, you may have to change the calendar_events table's primary key to id (instead of event_id)
Let's say I have the following array
var data = [{ id: 0, points: 1 }, { id: 1, points: 2 }]
I would like to update my table which contains
{
"doc-1": {
"id": "abcxyz123",
"entries": [
{ "id": 0, "points": 5 },
{ "id": 1, "points": 3 },
{ "id": 2, "points": 0 }
]
}
}
so that I add the points-field in the data array to the points-field for each element in the "entries" array in "doc-1" that matches the corresponding id in the data array. The end result would look like:
{
"doc-1": {
"id": "abcxyz123",
"entries": [
{ "id": 0, "points": 6 },
{ "id": 1, "points": 4 },
{ "id": 2, "points": 0 }
]
}
}
How do I go about to write such a query in ReQL?
I assume that the actual document in the table looks like this for now:
{
"id": "abcxyz123",
"entries": [{
"id": 0,
"points": 5
}, {
"id": 1,
"points": 3
}, {
"id": 2,
"points": 0
}]
}
That is without the doc-1 nesting.
Then your update can be done like this:
r.table('t1').update(
{
entries: r.row('entries').map(function(e) {
return r.do(r.expr(data)('id').indexesOf(e('id')), function(dataIndexes) {
return r.branch(
dataIndexes.isEmpty(),
e,
{
id: e('id'),
points: e('points').add(r.expr(data)(dataIndexes(0))('points'))
});
});
})
})
I'm using map to map over each entry in entries, and indexesOf to find the corresponding entry in data if it exists.
Note that this doesn't add new entries to the entries list, but only updates existing ones. Please let me know if you need to add new entries as well.
If your documents actually have the doc-1 field first, this query should do the job:
r.table('t1').update(
{ 'doc-1':
{
entries: r.row('doc-1')('entries').map(function(e) {
return r.do(r.expr(data)('id').indexesOf(e('id')), function(dataIndexes) {
return r.branch(
dataIndexes.isEmpty(),
e,
{
id: e('id'),
points: e('points').add(r.expr(data)(dataIndexes(0))('points'))
});
});
})
}
})